[R] xls.getshlib() error in xlsReadWrite package under W7

2010-07-06 Thread milton ruser
Dear all,

I installed xlsReadWrite package under Windows 7, and got error when trying
to run xls.getshlib().
Please, see the errors below:

 require(xlsReadWrite)
Loading required package: xlsReadWrite
xlsReadWrite version (cran shlib)
Copyright (C) 2010 Hans-Peter Suter, Treetron, Switzerland.

!! Your installation contains the cran placeholder shlib (dll/so).
Please get the regular shlib (420 KB) by executing the following command:

   xls.getshlib()

Info, forum, issue tracker and manual download at http://www.swissr.org.

BACKGROUND: Our own xlsReadWrite code is free, but we also use proprietary
code
(Flexcel, tmssoftware.com) which can only be distributed legally in
precompiled,
i.e. binary form. As CRAN 'generally does not accept submissions of
precompiled
binaries due to security reasons' we only provide a placeholder and you can
download the binary shlib separately. NO GUARANTEES: We have done thorough
tests
initially and there are integrity checks, but we do _not_ give any
guarantees.
You can check/clone the source code at http://github.com/swissr/xlsreadwrite
,
in case of any issues we are happy to hear about them (bug
tracker/forum/email).

 xls.getshlib()
Loading required package: tools
--- xls.getshlib running... ---
  - zipped shlib has been downloaded from '
http://dl.dropbox.com/u/2602516/swissrpkg/bin/win32/shlib/xlsReadWrite_1.5.1_dll.zip'
to 'C:\Users\Miltinho\AppData\Local\Temp\Rtmp2cUZxb/xlsReadWrite.zip'
  - md5 hash value has been read from '
http://dl.dropbox.com/u/2602516/swissrpkg/bin/win32/shlib/xlsReadWrite_1.5.1_dll.zip.md5.txt'

  - zipped shlib has correct md5 hash
  - zipped shlib has been extracted
to'C:\Users\Miltinho\AppData\Local\Temp\Rtmp2cUZxb/xlsReadWrite.dll'
  - try to unload existing shlib
'C:\Users\Miltinho\Documents/R/win-library/2.11/xlsReadWrite/libs/xlsReadWrite.dll'
- try to unload existing shlib
'C:/PROGRA~2/R/R-211~1.0/library/xlsReadWrite/libs/xlsReadWrite.dll'
Error in file.rename(fp, fp.backup) : 'source' must be a single string
In addition: Warning messages:
1: In if (!file.exists(fp)) stop(existing (cran) shlib could not be found
at ',  :
  the condition has length  1 and only the first element will be used
2: In if (file.exists(fp.backup)) file.remove(fp.backup) :
  the condition has length  1 and only the first element will be used

 sessionInfo()
R version 2.11.0 (2010-04-22)
i386-pc-mingw32

locale:
[1] LC_COLLATE=English_United States.1252  LC_CTYPE=English_United
States.1252LC_MONETARY=English_United States.1252
[4] LC_NUMERIC=C   LC_TIME=English_United
States.1252

attached base packages:
[1] tools stats graphics  grDevices utils datasets  methods
base

other attached packages:
[1] xlsReadWrite_1.5.1


Cheers

milton

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[R] avoiding reinstall already installed library

2010-05-18 Thread milton ruser
Dear R-experts,

I am installing new libraries using
install.packages(ggplot2,dependencies=T).
But I perceive that many dependencies are already installed. As I am using
a low-band internet, how can avoid reinstall installed libraries?

cheers

milton

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Re: [R] Re: Change class factor to numeric

2010-05-18 Thread milton ruser
Try

arcilla-as.numeric(as.character(clay))

best

milton

On Tue, May 18, 2010 at 12:36 PM, Arantzazu Blanco Bernardeau 
aramu...@hotmail.com wrote:



 sorry I had a mistake sending my question without a subject. I do resend
 again. Please excuse me.
  Hello
  I have a data array with soil variables (caperf), in which the variable
 clay is factor (as I see entering str(caperf)) . I need to do a regression
 model, so I need to have arcilla (=clay) as a numeric variable.  For that I
 have entered
 
  as.numeric(as.character(arcilla))
 
  and even entering
  'as.numeric(levels(arcilla))[arcilla]'the variable is resting as factor,
 and the linear model is not valid (for my purposes).
  The decimal commas have been converted to decimal points, so I have no
 idea of what to do.
  Thanks a lot
 
 
  Arantzazu Blanco Bernardeau
  Dpto de Química Agrícola, Geología y Edafología
  Universidad de Murcia-Campus de Espinardo
 
 
 
 
 
 
  _
  Diseñar aplicaciones tiene premio. ¡Si eres desarrollador no esperes más!
  http://www.imaginemobile.es

 _
 Recibe en tu HOTMAIL los emails de TODAS tus CUENTAS. + info

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Re: [R] avoiding reinstall already installed *package*

2010-05-18 Thread milton ruser
Hi Martin,

thanks for your reply, and very thanks for your kind tips about package
and library
So, I was trying to understand *why* we load packages using library().
I suggest that developers killl the problem on its root, deleting library
function :-)
Good to know already installed packages will not be reinstalled.

cheers

milton

On Tue, May 18, 2010 at 12:49 PM, Martin Maechler 
maech...@stat.math.ethz.ch wrote:

 { I've modified the subject; I can't stand it hitting square into
  my face ... }

  mr == milton ruser milton.ru...@gmail.com
  on Tue, 18 May 2010 12:36:23 -0300 writes:

mr Dear R-experts,
mr I am installing new libraries using
mr install.packages(ggplot2,dependencies=T).
mr But I perceive that many dependencies are already installed. As I am
 using
mr a low-band internet, how can avoid reinstall installed libraries?

 There's no problem with installed libraries, as ...
 they DO NOT EXIST.

 These are *PACKAGES* !
 Why do you think are you talking about the function

  install.packages()  
 

 ---
 To answer the question you did want to ask:

 Do not be afraid:  Depedencies are only installed when needed,
 i.e., no package will be downloaded and installed if it already
 is there.

 Martin Maechler, ETH Zurich

mr cheers

mr milton

mr [[alternative HTML version deleted]]

 (another thing you should learn to avoid, please)



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Re: [R] avoiding reinstall already installed *package*

2010-05-18 Thread milton ruser
*but* going back to my question, is not true
that already installed packages will not be
reinstaled. I ran:

install.packages(c(ggplot2),dependencies=T)
install.packages(c(mgcv,bbmle,akima,drc,sensitivity,tgp),dependencies=T)

and several packages installed during the first install.packages
were reinstalled on the second install.packages.

cheers

milton

On Tue, May 18, 2010 at 5:38 PM, William Dunlap wdun...@tibco.com wrote:

  -Original Message-
  From: r-help-boun...@r-project.org
  [mailto:r-help-boun...@r-project.org] On Behalf Of Martin Maechler
  Sent: Tuesday, May 18, 2010 1:25 PM
  To: milton ruser
  Cc: r-help@r-project.org
  Subject: Re: [R] avoiding reinstall already installed *package*
 
  On Tue, May 18, 2010 at 18:06, milton ruser
  milton.ru...@gmail.com wrote:
 
   Hi Martin,
  
   thanks for your reply, and very thanks for your kind tips
  about package
   and library
   So, I was trying to understand *why* we load packages using
  library().
  
 
  I've started to use and suggest using   require(.) instead
  {as my efforts to introduce  use() or usePackage() *and* deprecating
   library()  where met with strong opposition}

 I hate to get into arguments over function names, but
 I would have thought that require(pkg) would throw
 an error if the required pkg was not available.  It seems
 like require() can be used when pkg is not really required
 but library(pkg) is easiest when pkg is required to
 continue:

   { require(noSuchPackage); functionFromNoSuchPackage() }
  Loading required package: noSuchPackage
  Error: could not find function functionFromNoSuchPackage
  In addition: Warning message:
  In library(package, lib.loc = lib.loc, character.only = TRUE,
 logical.return = TRUE,  :
there is no package called 'noSuchPackage'
   { library(noSuchPackage); functionFromNoSuchPackage() }
  Error in library(noSuchPackage) :
there is no package called 'noSuchPackage'

 Bill Dunlap
 Spotfire, TIBCO Software
 wdunlap tibco.com

 
 
   I suggest that developers killl the problem on its root,
  deleting library
   function :-)
   Good to know already installed packages will not be reinstalled.
  
   cheers
  
   milton
  
   On Tue, May 18, 2010 at 12:49 PM, Martin Maechler 
   maech...@stat.math.ethz.ch wrote:
  
   { I've modified the subject; I can't stand it hitting square into
my face ... }
  
mr == milton ruser milton.ru...@gmail.com
on Tue, 18 May 2010 12:36:23 -0300 writes:
  
  mr Dear R-experts,
  mr I am installing new libraries using
  mr install.packages(ggplot2,dependencies=T).
  mr But I perceive that many dependencies are already
  installed. As I
   am using
  mr a low-band internet, how can avoid reinstall
  installed libraries?
  
   There's no problem with installed libraries, as ...
   they DO NOT EXIST.
  
   These are *PACKAGES* !
   Why do you think are you talking about the function
  
install.packages()  
   
  
   ---
   To answer the question you did want to ask:
  
   Do not be afraid:  Depedencies are only installed when needed,
   i.e., no package will be downloaded and installed if it already
   is there.
  
   Martin Maechler, ETH Zurich
  
  mr cheers
  
  mr milton
  
  mr [[alternative HTML version deleted]]
  
   (another thing you should learn to avoid, please)
  
  
  
 
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Re: [R] rcolorbrewer

2010-05-03 Thread milton ruser
?rev

On Mon, May 3, 2010 at 4:06 PM, Steve Hempell sthemp...@gmail.com wrote:

 Can you reverse the color scheme order in rcolorbrewer.  If so, how?

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Re: [R] sensitivity analysis, input factors

2010-04-13 Thread milton ruser
Hi Szalai

I had used only src function, and on that case you need to
have a vector with your Y variable, and a data-frame with all
your X (i.e. explanatory) variables.

I have interest on stay in touch with others that have been using
sensitivity package!

bests

milton

On Tue, Apr 13, 2010 at 11:08 AM, Szalai Márk szalai.m...@mkk.szie.huwrote:

 Hi,


 I'm trying to conduct sensitivity analysis in R using the 'sensitivity'
 package. Although the description of functions seem straightforward, I can’t
 succeed. The definition of input factors can be the problem.

 library(sensitivity)
 #A simple model with 4 input factor to test the morris function:
 model01=function(a1,a2,a3,a4)
 {
 Z-numeric(10)
 Z[1]-runif(1)
 Z[2]-runif(1,a1,30)
 Z[3]-6*runif(1,min(a1,a2),max(a1,a3))
 Z[4]-runif(1,2,5)*runif(1,min(a2,a4),max(a2,a4))
 Z[5]-0.5*runif(1,min(a3,a4),max(a3,a4))
 Z[6]-2*runif(1,min(a1,a4),max(a1,a4))
 Z[7]-runif(1)
 Z[8]-2*runif(1,min(2*a1,5*a4),max(10*a1,100*a4))
 Z[9]-2.5*runif(1,min(a2,a3),max(a2,a3))
 Z[10]-rnorm(1,10*a1,1)
 mean(Z)
 }

 xx=morris(model = model01, factors=c(a1,a2,a3,a4), r=4,
 design=list(type=oat, levels = 5, grid.jump = 3), binf =1,bsup=20,
 scale=F)


 Error message suggests that the second input factor is not used
 How should I define the input factors?


 Thanks in advance,
 Mark
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Re: [R] reading excel into R

2010-04-01 Thread milton ruser
Dear Cheba

Please, install the package xlsReadWrite
I suppose that read.csv is to read csv files, not xls ones.

cheers

milton

On Thu, Apr 1, 2010 at 6:19 AM, cheba meier cheba.me...@googlemail.comwrote:

 Dear all,

 I am new R user and I am sure that this question has been asked quite often
 and I have also googled it and read about it! I understood that in order to
 read excel sheet into R you need to open it and saved it as csv or text, is
 this true? or you can use read.delim2 and read.csv2 to do this without the
 following error

  dat - read.csv2(file=C:\\Dokumente und
 Einstellungen\\Cheba\\Desktop\\Rtemp\\ Results2010.xls,header = TRUE)
 Warnmeldung:
 In read.table(file = file, header = header, sep = sep, quote = quote,  :
  unvollständige letzte Zeile von readTableHeader gefunden in 'C:\\Dokumente
 und Einstellungen\\Cheba\\Desktop\\Rtemp\\ Results2010.xls'
  dat
 [1] ÐÏ.à..
 0 Zeilen (oder row.names mit Länge 0)

 Thes same error I get when I use read.delim and demlim2!

 Is library(gdata) the solution?

 Sorry for any inconvenience caused.

 Regards,
 Cheba

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[R] barplot with error bar in lattice

2010-04-01 Thread milton ruser
Dear all,

I have a data.frame like below and I need
to plot horizonal with error bar only for upper limit.
On the code below I am able to plot the bars within
groups, but I need (1) change from vertical to horizonal
plot and (2) add the error bar.

any hint are welcome.

milton


mydf-read.table(stdin(),head=T,sep=,)
mygroup,xlabel,yvalue,error
Gr1,Bar1,1,0.5
Gr1,Bar2,2,0.7
Gr1,Bar3,2,1.0
Gr1,Bar4,2.5,0.5
Gr2,Bar1,1,2
Gr2,Bar2,1,1
Gr2,Bar3,3,1
Gr2,Bar4,4,0.5
require(lattice)
barchart(yvalue~xlabel|mygroup, data=mydf)

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[R] qplot(ggplo2): axis label sizes/colors

2010-03-23 Thread milton ruser
Dear all,

How can I change the size and the color of axis?
I would like that the xlab to be larger, xvalues to be
larger, and xvalues in black instead of grey.

x=runif(10)
y=runif(10)
require(ggplo2)
qplot(x,y)

cheers

milton

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Re: [R] labels gone

2010-03-15 Thread milton ruser
Hi Zhongyi,

I must confess I not understood completely what you need, but...

Tau-seq(0.05,0.95,0.05);
Pi - seq(0.19,0.01,-0.01);
par(cex.axis=0.8,ps=9,mar=c(1.5,1,0.5,1), oma=c(1,1,0.2,1) ,tck=-0.01);
plot(Tau,Pi, type='l', xlab=Tau,ylab=Pi,col=4, xaxt=n, yaxt=n);
axis(1,labels=F)
axis(1,line=-1, lwd=0)
axis(2,labels=F)
axis(2,line=-0.5, lwd=0)
mtext(x_txt,side=1, line=0.5)
mtext(y_txt,side=2, line=1.2)

cheers

milton
On Tue, Mar 16, 2010 at 12:28 AM, Zhongyi Yuan zhongyi-y...@uiowa.eduwrote:

 Dear R users:

 I am drawing a graph with the following code:

 Tau-seq(0.05,0.95,0.05);
 Pi - seq(0.19,0.01,-0.01);
 par(cex.axis=0.8,ps=9,mar=c(1.5,1,0.5,1), oma=c(1,1,0.2,1) ,tck=-0.01);
 plot(Tau,Pi, type='l', xlab=Tau,ylab=Pi,col=4);

 I want to make the graph take as little space as possible. Here I run into
 two problems. One is that the labels are gone, the other is the scale
 numbers of axises are a little too far from my axises. Can anyone help me
 with this? I am new to graphics and have spent a lot of time on par but
 still not yet got it.
 Thanks.

 best,
 Zhongyi

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Re: [R] barplot with a probability density curve

2010-03-14 Thread milton ruser
Hi Olga,

may be you can work around with the suggestions below, while other
provide the best solution for your:

barplot(c(1,2,3,5,2,3,1),names.arg=c(100,200,300,400,500,600,700),
 xlab=diameter,ylab=flow,main=some title,space=0.1)
lines(lowess(c(1,2,3,5,2,3,1),f=1), type=b, lwd=2, lty=3, col=blue)
cheers

milton

On Sun, Mar 14, 2010 at 5:32 PM, Olga Lyashevska o...@herenstraat.nlwrote:

 Dear all,

 I am making a barplot as following:

 barplot(c(1,2,3,5,2,3,1),names.arg=c(100,200,300,400,500,600,700),xlab=diameter,ylab=flow,main=some
 title,space=0.1)

 I am also trying to add a probability density curve, however using
 lines(density(c(1,2,3,5,2,3,1))) does not give a desired result.

 Any tips?
 Thanks

 Olga

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Re: [R] modify the levels of a variable

2010-03-10 Thread milton ruser
Try

data2$X-factor(data2$X)

By the way, avoid call data as data, matrix as matrix, vector as
vector.

cheers

milton

On Wed, Mar 10, 2010 at 4:35 PM, clee cheel...@gmail.com wrote:


 If anyone can help with this, I would greatly appreciate it.

 When I subset a dataframe, and then create a table of on of the column
 variables, the levels of that variable are retained from the parent
 dataframe.  Anyone know how to


 for example, say I have data like so:

 data:
 X Y
 a 2
 b 2
 a 3
 b 3
 a 5

 if I do

 data2=subset(data,X==a)

 I get the new data frame:

 data2:
 X Y
 a 2
 a 3
 a 5

 but if I do this...

 table(data2$X)

 I would get this:

 X Y
 3 0

 additionally when I write...

 levels(data2$X)

 I get...
 Factors w/ 2 levels: a, b

 I want it to be...
 Factors w/ 1 level: a

 Normally I would just move on and won't even bother but I'm working with a
 variable that has 204 levels and only 84 of those are meaningful to me.
  How
 can I reset the levels of a column variable?  help please!  Thanks!
 --
 View this message in context:
 http://n4.nabble.com/modify-the-levels-of-a-variable-tp1588089p1588089.html
 Sent from the R help mailing list archive at Nabble.com.

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Re: [R] how to convert character variables into numeric variables directly

2010-03-08 Thread milton ruser
Try: as.numeric(as.character( typec))

milton
On Mon, Mar 8, 2010 at 12:55 PM, Xumin Zeng xumin.z...@abbott.com wrote:

 Here is the example.

  age=18:29
  height=c(76.1,77,78.1,78.2,78.8,79.7,79.9,81.1,81.2,81.8,82.8,83.5)
  type=c(A, B, C, D,A, B, C, D,A, B, C, D)
  typec=c(0,4,2,9,0,7,2,3,0,1,2,3)
  typen=c(0,1,2,3,0,1,2,3,0,1,2,3)
  data1=data.frame(age=age,height=height, type=type, typec=typec,
 typen=typen)

  data1[,3]=as.numeric(data1[,3])
  data1[,4]=as.numeric(data1[,4])
  data1[,5]=as.numeric(data1[,5])

  print(data1)

 and I got the output as:

   age height type typec typen
 1   18   76.11 1 0
 2   19   77.02 5 1
 3   20   78.13 3 2
 4   21   78.24 7 3
 5   22   78.81 1 0
 6   23   79.72 6 1
 7   24   79.93 3 2
 8   25   81.14 4 3
 9   26   81.21 1 0
 10  27   81.82 2 1
 11  28   82.83 3 2
 12  29   83.54 4 3

 The typec is not what I expected. How can I get the direct conversion
 from character to numeric and get the following output?

   age height type typec typen
 1   18   76.11 0 0
 2   19   77.02 4 1
 3   20   78.13 2 2
 4   21   78.24 9 3
 5   22   78.81 0 0
 6   23   79.72 7 1
 7   24   79.93 2 2
 8   25   81.14 3 3
 9   26   81.21 0 0
 10  27   81.82 1 1
 11  28   82.83 2 2
 12  29   83.54 3 3

 Thanks.

 Xumin
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[R] parsing strings between [ ] in columns

2010-02-18 Thread milton ruser
Dear all,

I have a data.frame with a column like the x shown below
myDF-data.frame(cbind(x=c([[1, 0, 0], [0, 1]],
   [[1, 1, 0], [0, 1]],[[1, 0, 0], [1, 1]],
   [[0, 0, 1], [0, 1]])))
 myDF
x
1 [[1, 0, 0], [0, 1]]
2 [[1, 1, 0], [0, 1]]
3 [[1, 0, 0], [1, 1]]
4 [[0, 0, 1], [0, 1]]

As you can see my x column is composed of some
strings between [[]], and using colon to separate
some fields.

I need to identify the numbers of
groups inside the main [ ] and call each
group with different sequential string.
On the example above I would like to have:

  A B
1 [1, 0, 0] [0, 1]
2 [1, 1, 0] [0, 1]
3 [1, 0, 0] [1, 1]
4 [0, 0, 1] [0, 1]
Although here I have only two groups, my
real dataset will have much more (~30).
After identify the groups I would like
to idenfity the subgroups:
  A1 A2 A3  B1 B2
1 1  0  0   0  1
2 1  1  0   0  1
3 1  0  0   1  1
4 0  0  1   0  1

Any hint are welcome.

milton ribeiro

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Re: [R] Separating columns, and sorting by rows

2010-02-14 Thread milton ruser
Hi Raging Jim

may be this is a starting point.

myDF-read.table(stdin(),head=T,sep=,)
mm,Rainfall
1977-02,17.4
1977-03,34.0
1977-04,26.2
1977-05,42.6
1977-06,58.6
1977-07,23.2
1977-08,26.8
1977-09,48.4
1977-10,47.0
1977-11,37.2
1977-12,15.0
1978-01,2.6
1978-02,6.8
1978-03,9.0
1978-04,46.6

myDF$-substr(myDF$mm,1,4)
myDF$mm-substr(myDF$mm,6,7)
myDF-subset(myDF, select=c(,mm,Rainfall))
myDF.reshape-reshape(myDF,v.names=Rainfall,idvar=,
 timevar=mm,direction=wide)
myDF.reshape
best regards

milton

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Re: [R] release memory

2010-02-08 Thread milton ruser
Try gc()

best
milton

On Mon, Feb 8, 2010 at 5:16 PM, dys0022 dys0...@yahoo.com wrote:


 I am a new R user with the latest Ubuntu release.
 My executions consume large amount of memory (up to 1.6 GB). When I try to
 release the memory using rm(list=ls()), R still occupies 1.6GB. (I also
 tried to use rm on the specific arrays which I know to be large).
 What could be the reason for that?

 BTW I am using the randomForest package.

 Thanks


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 http://n4.nabble.com/release-memory-tp1473643p1473643.html
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Re: [R] How to choose seed in set.seed(seed, ...)?

2010-02-03 Thread milton ruser
Hi Michael,

Experts will answer you better than me, but IMHO
there is no best practices. In general you deal with set.seed()
when you want that others (or yourself) reproduce the
same sequence of random numbers generation as you
run on a moment.

Best regards

milton




On Wed, Feb 3, 2010 at 10:57 PM, Michael Hannon jm_han...@yahoo.com wrote:

 Greetings.  I understand that to generate distinct sequences of random
 numbers
 in R one can initialize the calculation of each sequence by calling the
 set.seed() function with a distinct value for seed the (integer) first
 argument to the function.

 I'd like to know if there are any guidelines or best practices for
 choosing seed.

 I.e., is it OK just to choose seed as any consecutive integers (1, 2, 3,
 ...),
 or should the integers be, say, relatively prime (7, 9, 13, ...), or
 disjoint
 sequences of digits from pi (14159, 26535, 89793, ...) or ...?

 Thanks.

 -- Mike

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Re: [R] R Output and ArcGIS

2010-01-25 Thread milton ruser
Hi Steve,

As I have no problem with this because I run windows, I prefere to use .txt
files.
But may be on your case you install xlsReadWrite (or WriteRead), because
.xls file works fine for ArcGis.

Remember not use complex (like having dots) or large names because some
times you get error on ArcGis.

Good luck,

milton

On Mon, Jan 25, 2010 at 12:54 PM, Steve Murray smurray...@hotmail.comwrote:


 Dear all,

 I've been using R on a Mac to process some data for export to ArcMap GIS
 (which only runs on Windows). ArcMap seems to require tab-delimited data (my
 data are in 3 columns), so I've been using the sep=\t argument. However,
 this resulted in strange end-of-line characters when displayed on a PC. I
 looked in the write.table help file to find that eol=\r\n can be used to
 get around this problem, and it does indeed prevent these unwanted
 characters from appearing.

 However, the data still aren't properly recognised by ArcMap when created
 on a Mac (the exact same code works fine from a PC). In ArcMap, when I
 select 'Display XY Data', the X (Longitude) and Y (Latitude) columns aren't
 available to select. It's as if Arc isn't correctly interpreting the output
 from R - this is despite me using col.names=TRUE in the write.table command.

 Any light shed on this will be very gratefully received.

 Many thanks for your help,

 Steve


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Re: [R] 3d trend line

2010-01-21 Thread milton ruser
Hi mlcarte3 (it is you?)

?contour

Try algo google R graph gallery

bests

milton

On Thu, Jan 21, 2010 at 2:43 PM, mlcarte3 mlcar...@ncsu.edu wrote:


 I have a 3d scatter plot and I need to add a trend line. I can add a
 regression plane, but I need a line, not a plane.

 Thanks.
 --
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Re: [R] What is the difference between S and R?

2010-01-21 Thread milton ruser
Hi There,

If you are starting with S or R, don't be worried.
If you just started (I suppose with R), don't be worried too.
Just enjoy and be happy :-)

bests

milton

On Thu, Jan 21, 2010 at 10:44 AM, Peng Yu pengyu...@gmail.com wrote:

 On Thu, Jan 21, 2010 at 9:07 AM, Giovanni Petris gpet...@uark.edu wrote:
 
  I have found a good refernce to be S Programming by Venables and
  Ripley.

 I'll take a look at this book.

 Since S and R are not completely the same, there are delicate
 differences between S and R, which an S book may be confusing if I
 want to learn R. One example is Statistical Models in S by Chambers
 and Hastie, where some examples in this book is not applicable in R as
 I pointed in my previous message to this mailing list some time ago.

 Could somebody let me know if there is  a detailed comparison between
 S and R to help me understand R better even if I use books for S?


  I don't find a tutorial on S3. Bengtsson.pdf cites MASS (1999
  edition). However, I don't think that MASS (2002 edition) clearly
  explain what S3 is and help a user who knew very little about S3 to
  quickly understand it. Could somebody let me know if there are some
  better learning materials to help me smooth the learning curve?
 
  __
  R-help@r-project.org mailing list
  https://stat.ethz.ch/mailman/listinfo/r-help
  PLEASE do read the posting guide
 http://www.R-project.org/posting-guide.htmlhttp://www.r-project.org/posting-guide.html
  and provide commented, minimal, self-contained, reproducible code.
 
 
  --
  Giovanni Petris
  Dept of Mathematical Sciences
  University of Arkansas
  definetti.uark.edu/~gpetris
  (479) 575-6324, 575-8630 (Fax)
 

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Re: [R] How to write '' to a csv with the default setting of write.csv?

2010-01-21 Thread milton ruser
Hi Peng,

May be write.table(...,quote=F)

bests

milton

On Thu, Jan 21, 2010 at 6:29 PM, Peng Yu pengyu...@gmail.com wrote:

 Please see the following example. I can not write '' to a csv file
 successfully. Could somebody let me if it is possible to write '' to
 a csv file with the default setting of write.csv?

 my_home$ Rscript main_quote.R
  x=rbind(
 +   \A\
 +   , \B\
 +   )
  x
 [,1]
 [1,] \A\
 [2,] \B\
 
  write.csv(x, main_quote.csv, row.names=F)
 
 my_home$ cat main_quote.csv
 V1
 A
 B

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Re: [R] How to write '' to a csv with the default setting of write.csv?

2010-01-21 Thread milton ruser
Peng,

Are you having doble quotes? It is what you want?
Did you tried the suggestion?
bests

milton
On Thu, Jan 21, 2010 at 6:38 PM, Peng Yu pengyu...@gmail.com wrote:

 On Thu, Jan 21, 2010 at 5:32 PM, milton ruser milton.ru...@gmail.com
 wrote:
  Hi Peng,
 
  May be write.table(...,quote=F)
 
  bests
 
  milton

 Would this cause some trouble when filed is missing, etc.? Although I
 don't have a concrete example, I think that it might happen. So I
 prefer to have quote=T.

 I have looking for a way so that the resulted csv file can be read by
 excel.

 http://www.creativyst.com/Doc/Articles/CSV/CSV01.htm#FileFormat


  On Thu, Jan 21, 2010 at 6:29 PM, Peng Yu pengyu...@gmail.com wrote:
 
  Please see the following example. I can not write '' to a csv file
  successfully. Could somebody let me if it is possible to write '' to
  a csv file with the default setting of write.csv?
 
  my_home$ Rscript main_quote.R
   x=rbind(
  +   \A\
  +   , \B\
  +   )
   x
  [,1]
  [1,] \A\
  [2,] \B\
  
   write.csv(x, main_quote.csv, row.names=F)
  
  my_home$ cat main_quote.csv
  V1
  A
  B
 
  __
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Re: [R] Logistic regression

2010-01-21 Thread milton ruser
Dear someone,

Take a look at drc and Hmisc/Design packages.
Next time could be polite you identify yourself

bests

milton

On Thu, Jan 21, 2010 at 4:17 PM, DispersionMap frenc...@btinternet.comwrote:


 can you do Logistic regression in R, if so how do you do it and how do you
 test the fit of a model?
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Re: [R] concatenate 2 column vectors

2010-01-20 Thread milton ruser
Hi Magali,

I confess that I still not figured out what you want,
but try this:

datatry2=transform(datatry,DIS=as.numeric(as.character(paste(datatry[,1],datatry[,2],sep=

bests

milton

On Wed, Jan 20, 2010 at 11:14 PM, teurlai magali teurlai...@yahoo.frwrote:

 Sorry I forgot the subject in my previous post

 Here is an example of data : province and district code of 4 locations

 datatry=matrix(c(8,12,3,3,1,1,16,1),4,2)
 colnames(datatry)-c(PROCODE,DISCODE)

 DISCODE is not unique for each location (there is a distrcit nb 1 in each
 province)
 I want to create a third column (DIS) which would contain a unique district
 code for each location that would be the appended values of the province
 code and the district code, and that would be a numeric value (not a
 character)

 here is my try (thanks to Henrique Dallazuanna!)

 DIS=rep(0,nrow(datatry))
 datatry=cbind(datatry,DIS)
 datatry2=transform(datatry,DIS=paste(datatry[,1],datatry[,2]));

 However it creates a string, and the 2 codes are separated by an empty
 space, which I didn't manage to supress using different values for arguments
 sep and collapse.

 i'll try to see other options to concatenate 2 numeric values into a third
 one.

 Thanks


 --- En date de : Jeu 21.1.10, Henrique Dallazuanna www...@gmail.com a
 écrit :

 De: Henrique Dallazuanna www...@gmail.com
 Objet: Re: [R] (no subject)
 À: teurlai magali teurlai...@yahoo.fr
 Cc: r-help@r-project.org
 Date: Jeudi 21 Janvier 2010, 3h41

 transform(DF, District_Unique = paste(Province, District, collapse = ''))

 On Thu, Jan 21, 2010 at 12:34 AM, teurlai magali teurlai...@yahoo.fr
 wrote:
  Hi
 
  is there a way in R to create a new column vector with the numbers of 2
 others columns simply appended?
 
  Example : I have a column with provinces codes (1 to 19)
  I have a second column with districts codes (1 to ##, depending on the
 province)
  I want to create a third column with a code that would be unique for each
 district:
 
  Province  District   District_Unique
  1 111
  1 212
  13   2132
 
  I can create a loop, but it becomes complicated with numerous data
 
  Thanks for your help
 
 
 
 
 
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 --
 Henrique Dallazuanna
 Curitiba-Paraná-Brasil
 25° 25' 40 S 49° 16' 22 O




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Re: [R] How to detect and exclude outliers in R?

2010-01-19 Thread milton ruser
Hi V.S.,


Did you search first on r-repositories about this issue prior to ask?
May be not. RSiteSearch(outliers)
bests

milton



On Tue, Jan 19, 2010 at 1:08 AM, vikrant vikrant.shi...@tcs.com wrote:


 Suppose I am reading data from a file and the data contains some outliers.
 I
 want to know if it is possible in R to automatically detect outliers in a
 dataset and remove them
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Re: [R] how to open excel 2007 (.xlsx) file in R

2010-01-19 Thread milton ruser
Dear V.K.,

1. 
http://www.R-project.org/posting-guide.htmlhttp://www.r-project.org/posting-guide.html
2. it is - in general - good someone that write to the list identify your
self. It is a polite way of participate of the list.

bests

milton

On Tue, Jan 19, 2010 at 12:15 AM, vikrant vikrant.shi...@tcs.com wrote:


 i am unable to open a file which is saved as .xlsx format in R . The file
 contains approximately  1,50,000
 rows. So I m not able to save it as csv file.Please suggest ways to open
 this file
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Re: [R] (no subject)

2010-01-15 Thread milton ruser
Saleem,

I have no idea about this, but may be you can use other data.frame name
instead of data because data is a name of a function (see ?data).

good luck

milton
On Fri, Jan 15, 2010 at 3:33 PM, saleem mukhtar saleem...@yahoo.com wrote:

 Hello,

 I am running R on cygwin for windows.

 File R1234 contains

 data - read.table(data)
 q()

 On the command line I type

 R --no-save -q R_PROFILE=R1234

 returns

 Error: could not find function read.table

 THanks.

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Re: [R] Linear regression - R^2

2010-01-09 Thread milton ruser
Dear Csanad,

PLEASE do read the posting guide
http://www.R-project.org/posting-guide.htmlhttp://www.r-project.org/posting-guide.html
Reproducible code/problem are welcome.
By the way, who you believe is right?

bests

milton
On Sat, Jan 9, 2010 at 5:40 PM, Csanád Bertók bertok.csa...@gmail.comwrote:

 Hello,

 I was doing a linear regression with the following formula:
 *lm(y~x+0)*, so it passes through the origin. But when I called the summary
 of the regression i saw that R squared is abnormally high (it's a lot lower
 in other programs such as SigmaPlot and MS Excel).The manual explained the
 cause of the difference (because of the different computing method), but
 what should I do to get the same R^2 in excel and R?

 WITHOUT PASSING THROUGH THE ORIGIN:
 R^2: Multiple R-squared: 0.9711, Adjusted R-squared: 0.9654
 In MS Excel: 0,9711

 *So it's OK.*


 WITH PASSING THROUGH THE ORIGIN:
 Multiple R-squared: 0.9848, Adjusted R-squared: 0.9822
 In MS Excel: 0,8907

 *So almost 10% difference.*

 Thank you for your help.

 Csanad Bertok, Hungary

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Re: [R] February 2010***New R Courses*** by XLSolutions Corp at 9 USA Cities: San Francisco, New York, Washington DC, Houston, Boston, Las Vegas, Seattle, etc

2010-01-07 Thread milton ruser
Dear Sue,

Happy new your to you too.
You will offer the course on R or S-Plus? If S-plus is the case, how deal
with license?

bests

milton

On Wed, Jan 6, 2010 at 3:24 PM, Sue Turner s...@xlsolutions-corp.com wrote:

 Happy New Year !

 XLSolutions February 2010 R courses schedule is now available online at
 9
 USA cities for with 13 new courses: *** Suggest a future course
 date/city

 (1) R-PLUS: A Point-and-Click Approach to R
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 (5) S/R-PLUS Programming 3: Advanced Techniques and Efficiencies.
 (6) R/S+ System: Advanced Programming.
 (7) R/S-PLUS Graphics: Essentials.
 (8) R/S-PLUS Graphics for SAS Users
 (9) R/S-PLUS Graphical Techniques for Marketing Research.
 (10) Multivariate Statistical Methods in R/S-PLUS: Practical Research
 Applications
 (11) Introduction to Applied Econometrics with R/S-PLUS
 (12) Exploratory Analysis for Large and Complex Problems in R/S-PLUS
 (13) Determining Power and Sample Size Using R/S-PLUS.
 (14) R/S-PLUS: Data Preparation for Data Mining
 (15) Data Cleaning Techniques in R/S-PLUS
 (16) R/S-PLUS: Applied Clustering Techniques


 More on website

 http://www.xlsolutions-corp.com/rplus.asp

 Ask for group discount and reserve your seat Now - Earlybird Rates.
 Payment due after the class! Email Sue Turner:  sue at
 xlsolutions-corp.com

 Phone: 206-686-1578


 Please let us know if you and your colleagues are interested in this
 class to take advantage of group discount. Register now to secure your
 seat.

 Cheers,
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 206 686 1578
 www.xlsolutions-corp.com
 elvis at xlsolutions-corp.com

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Re: [R] Fwd: string

2010-01-06 Thread milton ruser
Hi Robert,

I use something like this with grass-R:

myvar-paste(questionspan style=,color: #FF; font-weight: bold;
font-size: 14pt,,sep=\)
myvar
May be it works for you.

bests

milton

On Wed, Jan 6, 2010 at 6:22 AM, robert-mcfad...@o2.pl wrote:

 I would like to assign a variable y the string: questionspan
 style=color: #FF; font-weight: bold; font-size: 14pt
 How can I do it - is it possible?

 Best,
 Robert


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Re: [R] how to draw abline correctly?

2010-01-04 Thread milton ruser
You can also try:

axis(1)
axis(2, las=1)
axis(2,at=c(0.1361), las=1)

bests

milton




On Sun, Jan 3, 2010 at 9:26 PM, aegea gche...@gmail.com wrote:


 Hello, I am frastruated with this graph, just cannot get what I need. Thank
 you for any suggestions or help. I really appreciate it. I wrote the
 following code, but there are 3 problems

 1, the red line is added on the graph but without any marker on the y-axis.
 I want to display the number '.1361' on the y-axis. So people can easily
 tell 'method 2' gets a constant estimate, which is 0.1361.

 2, since 'method2' is a constant. I prefer in the legend area, it just
 shows
 'method2' as a short red bar instead of a knot/spot in the middle of the
 red
 bar  in the legend area. How can I delete that spot?

 3, when I draw 'method1' in blue one, I prefer a filled/shaded circle
 instead of the unshaded circle. I tried pch='.', seems it does not really
 work.

 Hopefully I make my question clear. Thanks a lot for any help!



 size=c(80, 40, 20, 16, 10, 8, 4, 2)
 estimate=c(0.1353, 0.1337, 0.1237, 0.1164,  0.1058, 0.0983, 0.0759 ,
 0.0607)
 plot(size, estimate, type=o, lwd=1.5, col=blue, ylim=c(0, 0.2),
 xlim=c(0,80))
 abline(h=0.1361, col=red, lwd=1.5)
 legend(0, 0.2,c(method1,method2), cex=0.8,col=c(blue,red),
 pch=21:1, lty=1);

 --
 View this message in context:
 http://n4.nabble.com/how-to-draw-abline-correctly-tp998018p998018.html
 Sent from the R help mailing list archive at Nabble.com.

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Re: [R] Artificial Neural Networks

2010-01-03 Thread milton ruser
Hi Alex,

I am not a NN user, but I would suggestion you
give more information about what are you planning to do.
May be it helps the helper.

Happy New Year.

miltinho

On Sun, Jan 3, 2010 at 3:54 PM, Alex Olafson alex.olaf...@yahoo.com wrote:

 Hi! I am studying to use some R libraries which are applied for working
 with artificial neural neworks (amore, nnet). Can you recommend some
 useful, reliable and easy to get example data to use in R for creating
 and testing a neural network? And what library will you advise?



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Re: [R] function in aggregate applied to specific columns only

2010-01-03 Thread milton ruser
You want this?

 basicSubMean - aggregate(basicSub[c(score)], by=list(basicSub$student),
FUN=mean, na.rm=TRUE)
 basicSubMean
  Group.1 score
1   1  55.0
2   2  60.0
3   3  67.5

bests
milton

On Sun, Jan 3, 2010 at 10:46 PM, david hilton shanabrook 
dhsha...@acad.umass.edu wrote:

 I want to use aggregate with the mean function on specific columns

 gender - factor(c(m, m, f, f, m))
 student - c(0001, 0002, 0003, 0003, 0001)
 score - c(50, 60, 70, 65, 60)
 basicSub - data.frame(student, gender, score)
 basicSubMean - aggregate(basicSub, by=list(basicSub$student), FUN=mean,
 na.rm=TRUE)

 This doesn't work, one cannot take the mean of a factor (gender).  Is there
 any way of specifying which columns to use for the mean?  I want to
 aggregate by student, obtaining mean scores, and assume any other factors
 are unchanging in a specific student, ie. gender.

 Thanks
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Re: [R] how to draw abline correctly?

2010-01-03 Thread milton ruser
Hi there,


May be part of your problem is solved.

size=c(80, 40, 20, 16, 10, 8, 4, 2)
estimate=c(0.1353, 0.1337, 0.1237, 0.1164,  0.1058, 0.0983, 0.0759 , 0.0607)
plot(size, estimate, type=o, lwd=1.5, col=blue, ylim=c(0, 0.2),
xlim=c(0,80), pch=19, axes=F)
abline(h=0.1361, col=red, lwd=1.5)
legend(0, 0.2,c(method1,method2), cex=0.8,  col=c(blue,red),
pch=c(19,NA), lty=1);
axis(1)
axis(2,at=c(0,0.10,0.1361,0.2))

bests

milton



On Sun, Jan 3, 2010 at 9:26 PM, aegea gche...@gmail.com wrote:


 Hello, I am frastruated with this graph, just cannot get what I need. Thank
 you for any suggestions or help. I really appreciate it. I wrote the
 following code, but there are 3 problems

 1, the red line is added on the graph but without any marker on the y-axis.
 I want to display the number '.1361' on the y-axis. So people can easily
 tell 'method 2' gets a constant estimate, which is 0.1361.

 2, since 'method2' is a constant. I prefer in the legend area, it just
 shows
 'method2' as a short red bar instead of a knot/spot in the middle of the
 red
 bar  in the legend area. How can I delete that spot?

 3, when I draw 'method1' in blue one, I prefer a filled/shaded circle
 instead of the unshaded circle. I tried pch='.', seems it does not really
 work.

 Hopefully I make my question clear. Thanks a lot for any help!



 size=c(80, 40, 20, 16, 10, 8, 4, 2)
 estimate=c(0.1353, 0.1337, 0.1237, 0.1164,  0.1058, 0.0983, 0.0759 ,
 0.0607)
 plot(size, estimate, type=o, lwd=1.5, col=blue, ylim=c(0, 0.2),
 xlim=c(0,80))
 abline(h=0.1361, col=red, lwd=1.5)
 legend(0, 0.2,c(method1,method2), cex=0.8,col=c(blue,red),
 pch=21:1, lty=1);

 --
 View this message in context:
 http://n4.nabble.com/how-to-draw-abline-correctly-tp998018p998018.html
 Sent from the R help mailing list archive at Nabble.com.

 __
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Re: [R] Question on Reduce + rollmean

2010-01-02 Thread milton ruser
Dear M.Rahiz,

Unfortunatelly I can't reproduce your example.
PLEASE do read the posting guide
http://www.R-project.org/posting-guide.htmlhttp://www.r-project.org/posting-guide.html

bests

milton
On Sat, Jan 2, 2010 at 9:26 AM, Muhammad Rahiz muhammad.ra...@ouce.ox.ac.uk
 wrote:

 Hello useRs,

 I'd like to perform a moving average on the dataset, xx. I've tried
 combining the functions Reduce and rollmean but it didn't work.

  r - function(n) rollmean(n, 2) # where 2 = averaging interval
  output  - Reduce(r, x)
 Error in f(init, x[[i]]) : unused argument(s) (x[[i]])

 Is there anything wrong with the code in the first place?

 where
  x

 [[1]]
V1 V2 V3
 [1,]  1  1  1
 [2,]  2  2  2
 [3,]  3  3  3

 [[2]]
V1 V2 V3
 [1,]  4  4  4
 [2,]  5  5  5
 [3,]  6  6  6

 [[3]]
V1 V2 V3
 [1,]  7  7  7
 [2,]  8  8  8
 [3,]  9  9  9

 The moving average is to be performed on

 1,4,7 = (1+4)/2 , (4+7)/2
 2,5,8 = ..
 3,6,9 = ..

 Thanks

 Muhammad

 --
 Muhammad Rahiz  |  Doctoral Student in Regional Climate Modeling
 Climate Research Laboratory, School of Geography  the Environment
 Oxford University Centre for the Environment, University of Oxford
 South Parks Road, Oxford, OX1 3QY, United Kingdom
 Tel: +44 (0)1865-285194  Mobile: +44 (0)7854-625974
 Email: muhammad.ra...@ouce.ox.ac.uk

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Re: [R] How to use read.table with Hebrew column names ?

2010-01-01 Thread milton ruser
Hi Tal,

You want the colnames in hebrew? Case not, may be you
can use colnames() to attrib new colnames.

bests

milton

On Fri, Jan 1, 2010 at 4:47 PM, Tal Galili tal.gal...@gmail.com wrote:

 Hello dear R help group,

 I am trying to read a .txt file, with Hebrew column names, while keeping
 the
 column names looking well in R - but without success.

 I uploaded an example file to:
 http://www.talgalili.com/files/aa.txt

 And am trying the command:
 read.table(http://www.talgalili.com/files/aa.txt;, header = T, sep =
 \t)

 This returns me with:

  X.ª X...ª.. X...œ
 1  12  97 6
 2 123 35444
 3   6   1 3

 Instead of:

 אחת שתיים   שלוש
 12  97  6
 123 354 44
 6   1   3


 Any suggestion or clarification will be appreciated.

 Best,
 Tal







 Contact
 Details:---
 Contact me: tal.gal...@gmail.com |  972-52-7275845
 Read me: www.talgalili.com (Hebrew) | www.biostatistics.co.il (Hebrew) |
 www.r-statistics.com/ (English)

 --

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Re: [R] How to not to terminate read.table if the input file is empty?

2010-01-01 Thread milton ruser
?try()




On Fri, Jan 1, 2010 at 3:41 PM, Peng Yu pengyu...@gmail.com wrote:

 read.table terminates the program if the input file is empty. Is there
 way to let the program continue and return me a NULL instead of
 terminating the program?

 $ Rscript read_empty.R
  read.table(empty_data.txt)
 Error in read.table(empty_data.txt) : no lines available in input
 Execution halted
 $ cat read_empty.R
 read.table(empty_data.txt)
 $ cat empty_data.txt; echo EOF
 EOF

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Re: [R] How to calculate density function of Bivariate binomial distribution

2010-01-01 Thread milton ruser
Hi Nykee,

I checked out ??bivariate on my R installed libraries,
and found about a hundred of occurrences of bivariate.
If nobody reply you with a streigth answer, give a look at:
VGAM; splancs; sm; prada; geoR; fUtilities; fBasics;
akima; adehabitat; vegan; ade4 and spatstat packages.

bests

milton

On Fri, Jan 1, 2010 at 5:36 PM, nykee rairai...@hotmail.com wrote:


 Am trying to do some study on bivariate binomial distribution. Anyone knows
 if there is package in R that I can use to calculate the density function
 of
 bivariate binomial distribution and to generate random samples of it.
 Thanks,


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Re: [R] Boxplot- input the median point and the median value

2010-01-01 Thread milton ruser
Dear Elaine,

The posting guide is
http://www.R-project.org/posting-guide.htmlhttp://www.r-project.org/posting-guide.html

bests

milton

On Fri, Jan 1, 2010 at 8:53 PM, elaine kuo elaine.kuo...@gmail.com wrote:

  Dear,

 I am a newbie to R.

 Now I am learning to draw boxplot using graphics().

 I want to highlight the median position

 with a round point and the value left (or on the top of)to the point.



 Please kindly share the command and thank you.

 Elaine

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Re: [R] joining two lists...

2009-12-31 Thread milton ruser
Dear Steve,

If I undertood you have a list of data.frame?.

Have you tried:

NewData-rbind(data.frame(myData[1]),data.frame(myData[2]))

Please, send us a str(object) so the experts can help you
bests
milton




On Thu, Dec 31, 2009 at 1:05 AM, stevemew steve@alphaedge.org wrote:


 My R problem..

 I want to join two lists but am so for not having any luck. Can anyone
 assist ?


 Variable:  myData[1]

 Data.Id   Data.Length Data.Weight
 1 12  12
 2 45  23



 Variable:  myData[2]

 Data.Id   Data.Length Data.Weight
 3 25  56
 4 55  288


 How do I join them together to get this ?  ;


 Variable:  NewData[1]

 Data.Id   Data.Length Data.Weight
 1 12  12
 2 45  23
 3 25  56
 4 55  288



 I have tried rbind,cbind,append, merge no luck so far...
 Any help greatly appreciated...

 Thanks

 Steve
 --
 View this message in context:
 http://n4.nabble.com/joining-two-lists-tp991285p991285.html
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Re: [R] How x[, 'colname1'] is implemented?

2009-12-31 Thread milton ruser
Hi Peng,

If I undertood your point, try this:

x-runif(10)
y-runif(10)
z-runif(10)
w-runif(10)

myDF-data.frame(cbind(x,y,z,w))
myDF

myDF[,c(w,z)]


Happy new year

miltinho


On Thu, Dec 31, 2009 at 5:15 PM, Peng Yu pengyu...@gmail.com wrote:

 I don't see where describes the implementation of '[]'.

 For example, if x is a matrix or a data.frame, how the lookup of
 'colname1' is x[, 'colname1'] executed. Does R perform a lookup in the
 a hash of the colnames? Is the reference O(1) or O(n), where n is the
 second dim of x?

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Re: [R] Negbin Error Warnings

2009-12-30 Thread milton ruser
Dear Clara,

could you, please, share the summary() of your data.

bests

milton

2009/12/30 Clara Brück clara_bru...@web.de

 Hi,

 I ran a negative binomial regression (NBR) using the Zelig-package and the
 negbin model.
 When I then try to use the simumlation approach using the setx () and sim()
 functions to calculate expected values
 and first difference for different levels of one of my independent
 variables, I get 50 errors warnings, telling me that the calculation rpois
 produced NAs. However, the data I use doesn't have any NAs.
 Does this mean that the NBR-model is the wrong model for this data?

 Thanks in advance.



 ___
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[R] Fwd: Negbin Error Warnings

2009-12-30 Thread milton ruser
Dear Clara,

Thanks for the reply. I am forwarding your message to the list, ok.
When I wrote was a way of get further information to help the helpers.

happy holidays,

milton

-- Forwarded message --
From: Clara Brück clara_bru...@web.de
Date: 2009/12/30
Subject: Re: [R] Negbin Error Warnings
To: milton ruser milton.ru...@gmail.com




Dear Milton,

Thanks for your email. I ran the NBR-model and then tried to compute the
first differences of some
expected values:
m3.x1 -setx(m3, advisory=1)
m3.x2 -setx(m3, advisory=0)
m3.s1 -sim (m3,x=m3.x1, x1=m3.x2)

However, I then get 50 error warnings, and there all like this:
In rpois(k, (mu * rgamma(k, theta))/theta) : NAs produced


Bests
Clara

 -Ursprüngliche Nachricht-
 Von: milton ruser milton.ru...@gmail.com
 Gesendet: 30.12.09 15:06:04
 An: Clara Brück clara_bru...@web.de
 CC: r-help@r-project.org
 Betreff: Re: [R] Negbin Error Warnings

Dear Clara,

 could you, please, share the summary() of your data.

 bests

 milton

 2009/12/30 Clara Brück clara_bru...@web.de
  Hi,

 I ran a negative binomial regression (NBR) using the Zelig-package
 and the negbin model.
 When I then try to use the simumlation approach using the setx () and
 sim() functions to calculate expected values
 and first difference for different levels of one of my independent
 variables, I get 50 errors warnings, telling me that the calculation
 rpois produced NAs. However, the data I use doesn't have any NAs.
 Does this mean that the NBR-model is the wrong model for this data?

 Thanks in advance.

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Re: [R] (no subject)

2009-12-29 Thread milton ruser
Hi Hao,

I suggest you try again, starting by read posting guide at footnote of this
email.
How about a title for the message? How about identify yourself?

bests

milton

On Tue, Dec 29, 2009 at 2:59 PM, Hao Cen h...@andrew.cmu.edu wrote:

 Hi,

 I wonder how to pass several functions and their arguments as arguments to
 a function. For example, the main function is

 f = function(X  ) {
   process(X)
   ...


 process(X)
 }

 I have a few functions that operate on X, e.g. g1(X, par1), g2(X, par2),
 g3(X, par3).  par1, par2 and par3 are parameters and of different types.

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Re: [R] pass functions and arguments to function

2009-12-29 Thread milton ruser
Hi Hao,

Ok.

Sorry for my last post.
bests

milton

On Tue, Dec 29, 2009 at 3:08 PM, Hao Cen h...@andrew.cmu.edu wrote:

 Hi,

 I wonder how to pass several functions and their arguments as arguments to
 a function. For example, the main function is

 f = function(X  ) {
   process1(X)
   ...


   process2(X)
 }

 I have a few functions that operate on X, e.g. g1(X, par1), g2(X, par2),
 g3(X, par3).  par1, par2 and par3 are parameters and of different types. I
 would like to pass g1, g2, g3 and their arguments to f and g1, g2, g3 may
 appear to be in different orders. So that final effect of the passing is

 f = function(X  ) {
   process1(X)
   g1(X, par1)
   g2(X, par2)
   g3(X, par3)
   process2(X)
 }

 If I pass g2(X, par2),g3(X, par3), g1(X, par1) to f, I would expect to get
 the effect of
 f = function(X  ) {
   process1(X)
   g2(X, par2)
   g3(X, par3)
   g1(X, par1)
   process2(X)
 }

 Appreciate any suggestions.

 thanks

 Jeff


 ps please ignore my previous blank subject email. It was accidentally sent
 before the letter was completed.

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Re: [R] 2D array of strings

2009-12-28 Thread milton ruser
Hi Francesco,

Be carefull with create a object named str, because you crash str()
function. I don't know if it have implications on any package or functions.

bests

milton

On Mon, Dec 28, 2009 at 4:32 PM, Francesco Napolitano
franap...@gmail.comwrote:

 Sorry for the dumb question, but I couldn't figure this out myself.

 Consider the following:

  str - c(abc,def)
  array(str, c(2,1))
 [,1]
 [1,] abc
 [2,] def

 How can i obtain the outcome of the second instruction without
 specifying the number of rows?

 Thank you in advance,
 Francesco.

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Re: [R] help: creating a unified histogram

2009-12-27 Thread milton ruser
Hi Yael,

Have you tried to find it on google R graph gallery ?

bests

milton

On Sun, Dec 27, 2009 at 2:45 PM, Yael Yohai yael.yo...@gmail.com wrote:

 Good evening,

 I would like to put the histograms of several matrices on the same graph,
 together on a unified histogram (instead of having one bar per value on the
 x-axis, have multiple bars: one representing each matrix, with different
 colored bars for example to distinguish between the matrices). I couldn't
 find a function doing that involving hist,  plot nor other plotting
 functions. Is there a function which does this?

 Thank you,

 Yael Yohai
 (Bioinformatics research)

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Re: [R] aggregate binary response data

2009-12-24 Thread milton ruser
?aggregate ?

On Thu, Dec 24, 2009 at 7:56 AM, Graham Leask grahamle...@btinternet.comwrote:

 Dear list

 I have a response variable coded 0/1 i.e. a binary response. There are
 20,000 individual responses that I would like to aggregate into numbers of
 each category (i.e. 0/1) by
 group called dn (350 different groups) and by month mth (there are several
 hundred responses per month.

 What is the simplest way to perform this operation in R?

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Re: [R] aggregate binary response data

2009-12-24 Thread milton ruser
may be ?table ?

On Thu, Dec 24, 2009 at 7:56 AM, Graham Leask grahamle...@btinternet.comwrote:

 Dear list

 I have a response variable coded 0/1 i.e. a binary response. There are
 20,000 individual responses that I would like to aggregate into numbers of
 each category (i.e. 0/1) by
 group called dn (350 different groups) and by month mth (there are several
 hundred responses per month.

 What is the simplest way to perform this operation in R?

 __
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 https://stat.ethz.ch/mailman/listinfo/r-help
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 http://www.R-project.org/posting-guide.htmlhttp://www.r-project.org/posting-guide.html
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Re: [R] help in merging

2009-12-24 Thread milton ruser
Hi there,

You can add a order column on x or y and after use this field to order z.
Like

z-z[order(z$orderfield),]

To generate a order on x or y you can do something like

x$xorder-1:nrow(x)

cheers

milton
On Thu, Dec 24, 2009 at 2:26 PM, utkarsh.sing...@global-analytics.comwrote:


   Hi All,
   I want to merge two datasets by column ID and I don't want the result
 to
   be sorted by ID. I am doing the following:
z = merge(x, y, by = ID, sort=F)
   The result is not sorted by ID. But (as oppose to what I expected) it
 is
   not even in the original order of either x or y.
   Can somebody tell what to do if I wanted it to be in the original order
 of
   x.

   P.S.: As my dataset is very huge and I couldn't find the right subset of
 the
   data which explains the above problem, so I can't attach it at the
 moment.
   If anybody knows the answer, please reply; or else I will try to get the
   right subset.

   Thanks in advance

   Utkarsh
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[R] prcomp : plotting only explanatory axis arrows

2009-12-23 Thread milton ruser
Dear all,

I have a very large dataset (1712351 , 20) and would like
to plot only the arrows that represent the
contribution of each variables.
On the sample below I woild like to plot
only the explanatory variables (Murder, Assault..)
and not the sites.

prcomp(USArrests)  # inappropriate
prcomp(USArrests, scale = TRUE)
prcomp(~ Murder + Assault + Rape, data = USArrests, scale = TRUE)
plot(prcomp(USArrests))
summary(prcomp(USArrests, scale = TRUE))
biplot(prcomp(USArrests, scale = TRUE))
Thanks a lot,

milton

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[R] removing rows with NAs in anywere

2009-12-22 Thread milton ruser
Dear all,

I have a data.frame with some NAs that can
happens anywere, and I would like to keep
only rows without NAs. Thanks in advance
for your help, and Merry Xmas.

myvect-runif(100)
myvect[sample(1:100)[1:5]]-NA
myDF-data.frame(matrix(myvect,ncol=5))
myDF
miltinho

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Re: [R] Help,Suggest me some methods to identify tr aining set and test set!!!

2009-12-21 Thread milton ruser
 Not ellegant.. but...

MyDF-data.frame(cbind(x=runif(10), y=rnorm(10)))
TrainingSize=5
TrainingSize_list-sample(1:nrow(MyDF))[1:TrainingSize]
TrainingSize_list
MyDF.training-MyDF[(1:nrow(MyDF) %in% TrainingSize_list),]
 MyDF.training

 MyDF.test-MyDF[ ! (1:nrow(MyDF) %in% TrainingSize_list),]
 MyDF.test

bests

milton
On Mon, Dec 21, 2009 at 9:09 AM, bbslover dlu...@yeah.net wrote:


 I want to split my whole dateset to training set and test set, building
 model
 in training set, and validate model using test set. Now, How can I split my
 dataset to them reasonally. Please give me a hand, It is better to give me
 some R code.

 and I see some ways like using SOM to project whole independents to
 2-dimensions and find some to be training set and others are test set.
  like
 below. I also want to do this. and my date is in xls accessory. Please help
 me.  and excel file is 218*47 matrix, 47 are indepents. I want to project
 it
 to 2D and label the corresponding sample label like that picture below.

 thank you!

 http://n4.nabble.com/file/n976245/SOM%2Btraining%2Bset%2Band%2Btest%2Bset.jpg
 SOM+training+set+and+test+set.jpg
 http://n4.nabble.com/file/n976245/matlab218x47.xls matlab218x47.xls
 --
 View this message in context:
 http://n4.nabble.com/Help-Suggest-me-some-methods-to-identify-training-set-and-test-set-tp976245p976245.html
 Sent from the R help mailing list archive at Nabble.com.

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Re: [R] how to import data from excel to R

2009-12-17 Thread milton ruser
Hi Sarath, try

C:\\Documents and Settings\\admin\\Desktop\\data.txt
or
C:/Documents and Settings/admin/Desktop/data.txt

or yet

setwd(your path)
mydata-read.table(data.txt)
cheers

miltinho

On Thu, Dec 17, 2009 at 12:24 PM, sta_2...@spectrum.net.in wrote:

 Hi,
   I am using R and I want to know how data can be transferred from Excel
 Spread sheet to R for analyzing. I have done like this

 mydata-read.table(C:\Documents and Settings\admin\Desktop\data.txt);


 but its not working how can i do it

  regards

Sarath Sankar V
   Spectrum Softtech Solution

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Re: [R] write.csv and col.names=F

2009-12-17 Thread milton ruser
?write.table

On Thu, Dec 17, 2009 at 6:52 PM, kayj kjaj...@yahoo.com wrote:


 Hi All,

 I always have a problem with write.csv when I want the column names to be
 ignored, when I specify col.names=F, I get a header of V1 V2 V3 V4 etc.

 for example I tried

 write.csv(mydata, file=data.csv, quote=FALSE, row.names=F, col.names=F)
 Warning message:
 In write.csv(mydata, file = data.csv, quote = FALSE,  :
  attempt to set 'col.names' ignored
 

 how can I get rid of this problem ? I do not want the header of V1 V2 V3...
 to appear in my output file,

 Thanks
 --
 View this message in context:
 http://n4.nabble.com/write-csv-and-col-names-F-tp974477p974477.html
 Sent from the R help mailing list archive at Nabble.com.

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Re: [R] help with graphing -- Points in my graph are not apparent, always displayed in steps

2009-12-12 Thread milton ruser
Hi Philip,

I must confess that I not understood what is the problem.
Could you clarify it a little bit more?

Cheers

miltinho
brazil=toronto

On Sat, Dec 12, 2009 at 12:39 AM, philip robinson robin...@students.wwu.edu
 wrote:


 I am trying to graphically represent a large set of data who's result is
 not
 strictly uniform.
 http://n4.nabble.com/file/n961629/egraph_rules_list_2.png
 The scatter plot to the left has all of the data rising in steps however I
 know that there are cases within my data that do not fit the dotted line.


 temp-edat[edat$R1SC0,,]
 png(egraph_rules_list_1.png,width=800,height=700,res=72);
 par(mfrow=c(2,2));
 qqplot(x=temp$words,y=temp$R1SC,ylab=With Rules applied SC
 Shortlist,xlab=Number of Words,col=blue,main=Subordinating
 Conjunctions\n(Number of Words),type=p);

 hist(temp$R1SC/temp$words,col=heat.colors(max(temp$R1SC)),main=Subortinating
 Conjunctions \n/ Number of Words);
 temp-edat[edat$R1CC0,,]
 qqplot(x=temp$words,y=temp$R1CC,ylab=With Rules applied CC
 Shortlist,xlab=Number of Words,col=purple,main=Coordinating
 Conjunctions\n(Number of Words),type=p);

 hist(temp$R1CC/temp$words,col=heat.colors(max(temp$R1CC)),main=Coordinating
 Conjunctions \n/ Number of Words);
 dev.off();



 your help is much appreciated
 --
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Re: [R] how to creat a matrix

2009-12-11 Thread milton ruser
Hi Him.

Did you read the Help/Manual in PDF/A Instroduction to R.PDF?


MyVect-scan()
0 0 0 0 1
1 0 0 0 0
0 1 0 0 0
0 0 1 0 0
0 0 0 1 0

MyVect
MyMat-matrix(MyVect, ncol=5, byrow=T)
MyMat

bests
milton



On Fri, Dec 11, 2009 at 10:47 AM, Moohwan Kim kmhl...@gmail.com wrote:

 Dear R family

  I am attempting to create a matrix. e.g.,
  0 0 0 0 1
  1 0 0 0 0
  0 1 0 0 0
  0 0 1 0 0
  0 0 0 1 0
  How could I write a R program?
  Later I want to extend it to a N by N case.
  Thanks in advance

  best
  Moohwan

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Re: [R] Population Histogram

2009-12-09 Thread milton ruser
1. Read the posting guide:
http://www.R-project.org/posting-guide.htmlhttp://www.r-project.org/posting-guide.html
2. Did you installed R?
2.1. Case yes, go to the help, click on Manual in PDF

bests

miltinho

On Wed, Dec 9, 2009 at 1:47 PM, terry johnson
terry.johnson@gmail.comwrote:

 How would I make a population histogram in R from an excel file? Thanks

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Re: [R] 4D plotting

2009-12-06 Thread milton ruser
Hi Jared,

google R graph library 4d or
http://addictedtor.free.fr/graphiques/RGraphGallery.php?graph=90

bests

milton

On Sun, Dec 6, 2009 at 7:31 AM, Jared Nance nanc...@phys.washington.eduwrote:

 Hello list,
 Thanks in advance for whatever help you can give me.  I have a data set
 that I want to visualize that has four important dimensions (x,y,z,t).
 What I would like to be able to do is plot the three spatial coordinates
 using, say, scatterplot3d (or similar), and have the color of the plotted
 points be determined by the time coordinate.  I've tried using
 scatterplot3d to do this, but without much success.  Thanks again.

 --
 Jared Nance
 University of Washington
 Center For Experimental Nuclear Physics and Astrophysics
 nanc...@phys.washington.edu

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Re: [R] hi there!

2009-12-06 Thread milton ruser
Hi Dave,

May be a good idea you (1) use subjects avoiding help, Hi there,
problem, etc. The list is archived for future search, and nobody with
problems with MCMC, Metropholis Hasting algorithm will search Hi there;
(2) how about minimum reproducible problem? If you are needing use this kind
of stuff (mcmc, more sophisticated distributions) you know you can do
better.

bests

milton

On Sun, Dec 6, 2009 at 5:53 AM, dave dan daved...@gmail.com wrote:

 hi there!
 how u doin?...hope fine.
 look, i've a difficulty in simulation especially for the bayesian analysis
 using R. Using the famous Markov Chain Monte Carlo (MCMC) method,
 Methropolis hasting algorithm i want to simuate different distrbution like:
 1/ Weibull-exponential
 2/Gamma-Gamma
 3/Poisson-Gamma
 4/Normal-Normal
 5/Normal-Gamma
 6/ Negative binomial - Jeffrey's prior
   Especially, i need the Gamma-Gamma case. with all due respect, can u
 please help and send me them b/c  i don't have enough reference material to
 refer and understand in detail. will look for ur posetive response!!
 thank a lot!
 Bye!
 Dave from Ethiopia.

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Re: [R] length of a density curve (or any curve)

2009-12-04 Thread milton ruser
hi Sylvain,

did you try ?density

regards

milton

On Fri, Dec 4, 2009 at 7:19 AM, sylvain willart
sylvain.will...@gmail.comwrote:

 Hello R users,

 When I type

 d - density(MyData$x)

 I obtain a density object I can plot,

 But I wonder if there is a way to easily compute the length of the
 density curve ?

 ( I imagine I could compute the distances between the 512 equally
 spaced points using their x and y, but does it exist a smarter way ?)

 Regards,

 SW

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Re: [R] how to seperate a matrix

2009-12-03 Thread milton ruser
Hi there,


mymat-matrix(c(6,8,1,
5,9,2,
20,10,3,
7,11,4,
8,12,5,
25,13,6,
14,14,7), byrow=T, ncol=3)

mymat1-mymat[mymat[,1]mymat[,2],]
mymat1

mymat2-mymat[mymat[,1]=mymat[,2],]
mymat2

bests
milton
On Thu, Dec 3, 2009 at 10:12 PM, aegea gche...@gmail.com wrote:


 Hello,

 I am working on seperate the matrix to two matrices but got trouble on
 doing
 it. Please give me some suggestions on doing this. Thanks a
 lot!

 My original matrix m is as follows for example,

 [,1] [,2] [,3]
 [1,]681
 [2,]592
 [3,]20  103
 [4,]7   114
 [5,]8   125
 [6,]25   136
 [7,]   14   147

 I want to generate two matrix m1 and m2
 if m[i, 1] m[i,2], then the row is stored in new matrix m1, (i =1, ..., 7)
 if m[i,1]=m[i,2], then the row is stored in new matrix m2.

 m1 supposed to be like:
 [,1] [,2] [,3]
 [1,]681
 [2,]592
 [3,]7   114
 [4,]8   125

 m2 supposed to be like:
 [,1] [,2] [,3]
 [1,]20  103
 [2,]25   136
 [3,]   14   147


 How can I code the if statement? Thank you very much

 --
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Re: [R] Normal tests disagree?

2009-12-01 Thread milton ruser
Hi there,

Could you provide a minimum reproducible code, please.
Bests

milton

On Tue, Dec 1, 2009 at 6:11 PM, rkevinbur...@charter.net wrote:

 If I have data that I feed into shapio.test and jarque.bera.test yet they
 seem to disagree. What do I use for a decision?

 For my data set I have p.value of 0.05496421 returned from the shapiro.test
 and 0.882027 returned from the jarque.bera.test. I have included the data
 set below.

 Thank you.

 Kevin


 Category,Period,Residual
 CHILD HATS, WIGS  MASKS,1/1/2005,-0.449735723758323
 CHILD HATS, WIGS  MASKS,2/1/2005,0.281461045050074
 CHILD HATS, WIGS  MASKS,3/1/2005,0.591383050911335
 CHILD HATS, WIGS  MASKS,4/1/2005,0.239998659520616
 CHILD HATS, WIGS  MASKS,5/1/2005,0.00343879474063987
 CHILD HATS, WIGS  MASKS,6/1/2005,-2.64372061292663
 CHILD HATS, WIGS  MASKS,7/1/2005,0.381630655290173
 CHILD HATS, WIGS  MASKS,8/1/2005,-1.79543281552347
 CHILD HATS, WIGS  MASKS,9/1/2005,1.90631012440313
 CHILD HATS, WIGS  MASKS,10/1/2005,-0.256232543929779
 CHILD HATS, WIGS  MASKS,11/1/2005,1.83452602676812
 CHILD HATS, WIGS  MASKS,12/1/2005,-1.06869719416837
 CHILD HATS, WIGS  MASKS,1/1/2006,1.04378655286183
 CHILD HATS, WIGS  MASKS,2/1/2006,0.232655831328322
 CHILD HATS, WIGS  MASKS,3/1/2006,-0.939084802643773
 CHILD HATS, WIGS  MASKS,4/1/2006,0.854132879285335
 CHILD HATS, WIGS  MASKS,5/1/2006,-1.71217066877156
 CHILD HATS, WIGS  MASKS,6/1/2006,1.28040273099582
 CHILD HATS, WIGS  MASKS,7/1/2006,-0.386415431325857
 CHILD HATS, WIGS  MASKS,8/1/2006,-0.769127669783483
 CHILD HATS, WIGS  MASKS,9/1/2006,-0.810996835089867
 CHILD HATS, WIGS  MASKS,10/1/2006,0.0477292147635991
 CHILD HATS, WIGS  MASKS,11/1/2006,0.294672848750557
 CHILD HATS, WIGS  MASKS,12/1/2006,-0.0841330473924862
 CHILD HATS, WIGS  MASKS,1/1/2007,0.231663729192233
 CHILD HATS, WIGS  MASKS,2/1/2007,-0.601790650547443
 CHILD HATS, WIGS  MASKS,3/1/2007,0.285635768516625
 CHILD HATS, WIGS  MASKS,4/1/2007,-0.963154959558619
 CHILD HATS, WIGS  MASKS,5/1/2007,1.52188112949994
 CHILD HATS, WIGS  MASKS,6/1/2007,-0.826092842933196
 CHILD HATS, WIGS  MASKS,7/1/2007,1.91937201229077
 CHILD HATS, WIGS  MASKS,8/1/2007,-0.317789483136924
 CHILD HATS, WIGS  MASKS,9/1/2007,-0.865011007394312
 CHILD HATS, WIGS  MASKS,10/1/2007,-0.0281604973711276
 CHILD HATS, WIGS  MASKS,11/1/2007,-0.123887049811822
 CHILD HATS, WIGS  MASKS,12/1/2007,-0.0327727730592468
 CHILD HATS, WIGS  MASKS,1/1/2008,-0.0654939600771254
 CHILD HATS, WIGS  MASKS,2/1/2008,0.279247739913908
 CHILD HATS, WIGS  MASKS,3/1/2008,0.167606602923418
 CHILD HATS, WIGS  MASKS,4/1/2008,0.189533097427477
 CHILD HATS, WIGS  MASKS,5/1/2008,0.402062194225847
 CHILD HATS, WIGS  MASKS,6/1/2008,1.97150984262995
 CHILD HATS, WIGS  MASKS,7/1/2008,-2.27538477532968
 CHILD HATS, WIGS  MASKS,8/1/2008,1.89091792097945
 CHILD HATS, WIGS  MASKS,9/1/2008,0.0251732151287081
 CHILD HATS, WIGS  MASKS,10/1/2008,-0.2349741808124
 CHILD HATS, WIGS  MASKS,11/1/2008,-0.659332058368173
 CHILD HATS, WIGS  MASKS,12/1/2008,0.127284768034285
 CHILD HATS, WIGS  MASKS,1/1/2009,-1.42838560676513
 CHILD HATS, WIGS  MASKS,2/1/2009,0.617689775286461
 CHILD HATS, WIGS  MASKS,3/1/2009,-0.034243005247084
 CHILD HATS, WIGS  MASKS,4/1/2009,-0.304574261133836
 CHILD HATS, WIGS  MASKS,5/1/2009,0.128679369916751
 CHILD HATS, WIGS  MASKS,6/1/2009,-0.657479389968652
 CHILD HATS, WIGS  MASKS,7/1/2009,0.608766068692517
 CHILD HATS, WIGS  MASKS,8/1/2009,1.92814770869400
 CHILD HATS, WIGS  MASKS,9/1/2009,-0.172644961366165
 CHILD HATS, WIGS  MASKS,10/1/2009,-0.453255508263169
 CHILD HATS, WIGS  MASKS,11/1/2009,-1.09903330959344

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Re: [R] sort a data frame by a vector

2009-12-01 Thread milton ruser
not ellegant.. but...

vecDF = data.frame(A1=c(C, A, B))
vecDF$A1.order=1:dim(vecDF)
vecDF
dataDF = data.frame(A1 = c(B, A, C), A2 = c(1,2,3))
dataDF2-merge(vecDF, dataDF,
by=intersect(colnames(vecDF),colnames(dataDF)))
dataDF2
dataDF2.ord-dataDF2[order(dataDF2$A1.order),]
dataDF2.ord

milton

On Tue, Dec 1, 2009 at 10:36 PM, Hao Cen h...@andrew.cmu.edu wrote:

 Hi,



 I have a a vector  and a data frame with two columns

 vec = c(C, A, B)

 dataDF = data.frame(A1 = c(B, A, C), A2 = c(1,2,3))



 I would like to sort the data frame by column A1 such that the order of
 elements in A1 is as the same as in vec.



 After the ordering, the data frame would be

 A1   A2

 C 3

 A 2

 B 1



 Any suggestions would be appreciated.



 Thanks in advance



 Jeff


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Re: [R] Ggplot2: Elegant Graphics for Data Analysis (Use R) (2009 Paperback)

2009-11-30 Thread milton ruser
I agree with Ista.

The book is very interesting. I put my 2cents too.

milton

On Mon, Nov 30, 2009 at 6:20 PM, Ista Zahn istaz...@gmail.com wrote:

 Depends on what you want. It's possible to find most of the
 information contained in the book in other places (the ggplto2
 website, Hadley's dissertation, the ggplot2 mailing list archive).
 Personally I really appreciate having all that information in one
 place, and in an easy to read format. It's worth it for me.

 -Ista

 On Mon, Nov 30, 2009 at 5:35 PM, DispersionMap frenc...@btinternet.com
 wrote:
 
 
  Is this book worth its dollar? If so, why?, if not, why not?
 
  Cheers.
  --
  View this message in context:
 http://n4.nabble.com/Ggplot2-Elegant-Graphics-for-Data-Analysis-Use-R-2009-Paperback-tp931702p931702.html
  Sent from the R help mailing list archive at Nabble.com.
 
  __
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  PLEASE do read the posting guide
 http://www.R-project.org/posting-guide.htmlhttp://www.r-project.org/posting-guide.html
  and provide commented, minimal, self-contained, reproducible code.



 --
 Ista Zahn
 Graduate student
 University of Rochester
 Department of Clinical and Social Psychology
 http://yourpsyche.org

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Re: [R] Arrhenius plot with lattice

2009-11-25 Thread milton ruser
Hi Markus,

PLEASE do read the posting guide
http://www.R-project.org/posting-guide.htmlhttp://www.r-project.org/posting-guide.html
Your example is not reproducible. Help your helper :-)

bests

miltinho

On Wed, Nov 25, 2009 at 5:54 PM, Markus Häge markus_ha...@gmx.de wrote:

 hello there,

 I like to print a theoretical function into my data. It would work with
 panel.curve when it's all normal. but unfortunately it's an
 arrhenius plot and I need 1000/Temperature(70-300K) at the x-axis.
 With my data it wasn't a Problem but now I have to add this function to
 the plot and don't know how to turn around the variable in the function
 and adapt the plot to this.

 log(n)=log(f(T^.5))-const/T

 thanks

 Markus

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Re: [R] 11 distinguishable colors

2009-11-24 Thread milton ruser
Hi there,

I picked it up from r.colors' grass manual:

http://colorbrewer2.org/

The code bellow cold be usefull for you explore simbols and colors.

x11(900,500)
par(mfrow=c(1,2))
x-runif(20)
y-runif(20)
plot(y~x, type=n)
Number.of.symbols-20
for (i in 1:Number.of.symbols)
 {
 points(y[i]~x[i], pch=i, cex=1.5)
 text((x[i]+0.02),y[i], i)
 }

colors.list-colors()
Number.of.colors-100
colors.list-colors.list[1:Number.of.colors]
plot(0:1,0:1, type=n)
for (i in colors.list)
 {
 x-runif(1)
 y-runif(1)
 text(x,y, i, col=i)
 }

cheers

miltinho

On Tue, Nov 24, 2009 at 6:01 PM, phoebe kong sityeek...@gmail.com wrote:

 It should be 11 different groups, not 8.

 On Tue, Nov 24, 2009 at 3:00 PM, phoebe kong sityeek...@gmail.com wrote:

  Hi,
 
  I want to draw a plot where the data set has 8 different groups. Could
 you
  suggest 8 combination of colors and symbols that are distinguishable? If
 the
  colors are too close, it would be hard to differentiate from the plot.
 
  Thanks,
 

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[R] (ecological) model sensitivity analysis book

2009-11-20 Thread milton ruser
Dear all,

I know that my question may be so general,
but I would like to know if is there a good book
for model sensitivity analysis (applied to ecology?)
that use R? Is there any package dedicated
to model sensitivity analysis on R?

Cheers

milton

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Re: [R] Presentation of data in Graphical format

2009-11-15 Thread milton ruser
Google R graph grallery
Google R ggplot2
Google R lattice

and good luck

milton
On Sun, Nov 15, 2009 at 7:48 AM, Sunita22 sunita...@gmail.com wrote:


 Hello

 My data contains following columns:

 1st column: Posts (GM, Secretary, AM, Office Boy)
 2nd Column: Dept (Finance, HR, ...)
 3rd column: Tasks (Open the door, Fix an appointment, Fill the register,
 etc.) depending on the post
 4th column: Average Time required to do the task

 So the sample data would look like
 PostsDeptTask   Average time
 Office Boy  HR   Open the door  00:00:09
 Secretary   FinanceFix an appointment00.00.30
 .  ..

 I am trying to represent this data in Graphical format, I tried graphs like
 Mosaic plot, etc. But it does not represent the data correctly. My aim is
 to
 check the amount of time and its variability for groups of tasks

 Thank you in advance
 Regards
 Sunita

 --
 View this message in context:
 http://old.nabble.com/Presentation-of-data-in-Graphical-format-tp26358857p26358857.html
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Re: [R] LINEAR MIXED EFFECT

2009-11-13 Thread milton ruser
Hi Ana, you did again :-)

 require(fortunes)
 fortune(dog)
Firstly, don't call your matrix 'matrix'. Would you call your dog 'dog'?
Anyway, it might clash with the function 'matrix'.
   -- Barry Rowlingson
  R-help (October 2004)
if you call your data data you will crach data() function.

cheers

milton

On Fri, Nov 13, 2009 at 8:30 AM, ANARPCG a.gouvei...@imperial.ac.uk wrote:




 Douglas Bates-2 wrote:
 
  On Thu, Nov 12, 2009 at 10:14 AM, milton ruser milton.ru...@gmail.com
  wrote:
  Hi Ana,
 
  I am not quite sure if it is the problem, but if you call your
 data.frame
  as
  exp,
  you will crash exp() function... try use another name for your
  data.frame.
 
  By the way, I suggest you not use attach().
 
  Try something like model-lme(weight~date*diet, data=yourdataframe)
 
  good luck
 
  and include the random specification in the call to lme, not as a
  separate assignment.
 
  milton
 
  On Thu, Nov 12, 2009 at 5:43 AM, ANARPCG a.gouvei...@imperial.ac.uk
  wrote:
 
 
 
 
 
  Milton's point is dead-on, and I would highly encourage you to give the
  posting guide a look.
 
  That said... you might try na.action = na.omit in your call to...
  actually, we don't know what function you are using (see first point).
  Regardless, sounds like you have missing data and na.action is set to
  na.fail (ie, fail if any missing data).
 
  cheers, Dave
 
 
  milton ruser wrote:
  
   Dear Ana Golveia,
  
   It is completelly impossible someone realise what kind or help you
  need
  or
   what is happening. I suggest you give a look on the posting guide,
  mainly
   that part about a minimum reproducible code with self explaining
   information, etc.
  
   Cheers
  
   milton
  
   On Wed, Nov 11, 2009 at 7:22 AM, ANARPCG a.gouvei...@imperial.ac.uk
 
   wrote:
  
  
   CAN ANYONE PLEASE HELP ME WITH THIS
   i HAVE TO DO A MIXED EFFECT LINEAR MODEL WITH MY DATA DUE TO THE
 FACT
   THAT
   I
   have pseudoreplication!
   Although after reading and trying it for several times can get
 around
  due
   to
   Error in na.fail.default(list(date = c(1L, 2L, 3L, 4L, 5L, 6L, 7L,
  8L,
   :
   missing values in object
   I uploaded my data file
   Thank you so much
   Kind regards
   AG
  
 http://old.nabble.com/file/p26300394/rawoctobercalciumexperiment2.txt
   rawoctobercalciumexperiment2.txt
  
   --
   View this message in context:
   http://old.nabble.com/LINEAR-MIXED-EFFECT-tp26300394p26300394.html
   Sent from the R help mailing list archive at Nabble.com.
  
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  http://www.R-project.org/posting-guide.htmlhttp://www.r-project.org/posting-guide.html
 http://www.r-project.org/posting-guide.html
  http://www.r-project.org/posting-guide.html
   and provide commented, minimal, self-contained, reproducible code.
  
  
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 http://www.r-project.org/posting-guide.html
   and provide commented, minimal, self-contained, reproducible code.
  
   sorry I am new on this things
   the point is after trying to run the model all that happens is:
   exp-read.table(file=file.choose(),header=T)
   attach(exp)
   names(exp)
   [1] group date  diet  weightthickness
  length
   [7] width liplength lipwidth
  
 
 exp$diet=factor(exp$diet,levels=c(zeropercent,tenpercent,twentypercent,thirtypercent,fortypercent,cuttleprecent))
   exp=na.omit(exp)
   library(nlme)
   random=~date
   model-lme(weight~date*diet)
   Error in na.fail.default(list(date = c(1L, 2L, 3L, 4L, 5L, 6L, 7L,
 8L,
   :
 missing values in object
  
I have pseudoreplications due to the fact that the measurements of
  the
   replicates have different starting points so I was advised to do lme.
  I
   never used it before and I cant get arround with it! the help I
 wanted
   from you is to help me to understand how to do a runable model!
  
  
  
  http://old.nabble.com/file/p26315302/rawoctobercalciumexperiment2.txt
  rawoctobercalciumexperiment2.txt
  --
  View this message in context:
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   Sent from the R help mailing list archive at Nabble.com.
 
  __
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 http://www.r-project.org/posting-guide.html
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Re: [R] refactoring in R

2009-11-13 Thread milton ruser
Hi Peng,

If that information is preliminary, so I guess you
have a more clear problem and may be you are able to
state a minimally reproducible code/example with
what you really need.

Bests

milton



On Fri, Nov 13, 2009 at 9:30 PM, Peng Yu pengyu...@gmail.com wrote:

 I'm wondering if there are some tips for refactoring in R. I found the
 following website, which is still preliminary. Is there any program
 that can help me do refactoring in R?

 http://www.r-developer.org/projects/show/refactoring

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Re: [R] LINEAR MIXED EFFECT

2009-11-11 Thread milton ruser
Dear Ana Golveia,

It is completelly impossible someone realise what kind or help you need or
what is happening. I suggest you give a look on the posting guide, mainly
that part about a minimum reproducible code with self explaining
information, etc.

Cheers

milton

On Wed, Nov 11, 2009 at 7:22 AM, ANARPCG a.gouvei...@imperial.ac.uk wrote:


 CAN ANYONE PLEASE HELP ME WITH THIS
 i HAVE TO DO A MIXED EFFECT LINEAR MODEL WITH MY DATA DUE TO THE FACT THAT
 I
 have pseudoreplication!
 Although after reading and trying it for several times can get around due
 to
 Error in na.fail.default(list(date = c(1L, 2L, 3L, 4L, 5L, 6L, 7L, 8L,  :
 missing values in object
 I uploaded my data file
 Thank you so much
 Kind regards
 AG
 http://old.nabble.com/file/p26300394/rawoctobercalciumexperiment2.txt
 rawoctobercalciumexperiment2.txt

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[R] trend thresholds on time series

2009-11-07 Thread milton ruser
 Dear all,

I have several response variables estimated from some simulations,
and I would like to identify the thresholds for trend changes.
Fro example, below I forced two different response behaviours
and on x is time unit.

x-1:1500
y-x/exp(x^0.2)
smaller15-y[y15]
y-ifelse(y15,y+rnorm(length(smaller15)), 15+rnorm(1000-length(smaller15),
0, 0.9))
myDF1-data.frame(cbind(x,y))
plot(y~x, data=myDF1)
k1-1:10
l1- -65*k1*k1+750*k1-500
k2-12:25
l2-2.6299*k2*k2- 104.39*k2 + 1000
myDF2-data.frame(cbind(k=c(k1,k2),l=c(l1,l2)))
plot(l~k, data=myDF2)
As one can see, the first simulation we have a non-linear ascendent
y-response, and after ~500 time steps the simulation change
the behaviour to almost stable results.

By other side, on second example I get a fast increasing, subsequent
decreasing and ~11 time steps I get a different trend.

For the first case I think that segmented package could do the
job, and for second case I think that it will not work properly.
But as my simulations is for time-series, I was thinking if we
can have a ts-like way of identify trend changes on the outcome results.

Cheers

miltinho
University of Sao Paulo, br

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Re: [R] counting frequencies across two columns

2009-11-01 Thread milton ruser
Hi Jason,

As your example is not reproducible, may be something like:

myFreq-data.frame(table(articleID, author))

if you want to know only those articles with 1 author, you can try

subset(myFreq, Freq==1)

or something like.

bests

milton

On Sun, Nov 1, 2009 at 2:20 AM, Jason Priem pr...@email.unc.edu wrote:

 I've got a data frame describing comments on an electronic journal, wherein
 each row is a unique comment, like so:

  commentID  author articleID
 1 1   smith 2
 2 2   jones 3
 3 3 andrews 2
 4 4   jones 1
 5 5 johnson 3
 6 6   smith 2

 I want know the number of unique authors per article.  I can get a table of
 article frequencies with table(articleID), but I can't figure out how to
 count frequencies in a different column.  I'm sure there's an easy way, but
 I guess I'm too new at this to find it.  Thanks for your help!

 Jason Priem
 PhD student, School of Information and Library Science, University of North
 Carolina-Chapel Hill

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Re: [R] x-y plot as an histogram

2009-10-29 Thread milton ruser
Hi Federico,

Have you checked google R graph library?

bests

milton

On Thu, Oct 29, 2009 at 3:12 PM, Federico Abascal fedeabas...@yahoo.eswrote:

 Hi,

 I am investigating a problem for which I found no solution.
 I have a matrix with two columns. I have plotted it as an x-y plot
 (plot(matrix[,1],matrix[,2])
 But this is not apropriate for my purposes. I need to group the data in
 matrix[,1] into groups (as an histogram would do). Then I have to calculate
 the average of matrix[,2] for each group.

 Before starting with loops and loops I would like to know if is there some
 way to do this easily with R.

 Thanks in advance!
 Federico

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Re: [R] rotate levelplot

2009-10-24 Thread milton ruser
Hi Kang,


Could you send a reproducible sample-code?

Bests

miltinho

On Sat, Oct 24, 2009 at 11:32 PM, Kang Min ngokang...@gmail.com wrote:

 Hi all,

 I have a matrix with 5 rows and 10 columns, which represent the grids
 on a rectangular map.
 I used the code below to plot, but it gives me the map with the 10
 columns as y-axis, and the 5 rows as the x-axis, and the (0,0) point
 is at the usual bottom left hand corner. My map starts with the (0,0)
 at the top left hand corner.

 How can I rotate the map 90 degrees clockwise so the (0,0) starts at
 the top left? That means I need the 10 columns to be x-axis. I cannot
 transpose the matrix because the map would be laterally flipped over.

 levelplot(quadsec.mat, colorkey=list(space=bottom), scales=list
 (tick.number=10), aspect=c(iso))

 Thanks, I'm ready to give more information if needed.

 Kang Min

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[R] updating columns using other column as reference

2009-10-19 Thread milton ruser
Dear R-gurus,

Just supose I have a dara.frame that looks like

myDF-read.table(stdin(),head=T,sep=,)
codID,namesp,k1,k2,k3,k4
1,spA,2,5,6,3
2,spB,4,5,4,6
3,spC,2,1,5,6
4,spC,5,4,3,2
5,spD,1,2,3,4
6,spE,2,4,3,1

I need to update the columns k1-k4 with the namesp, but
considering the math between Kx and codID.

My desired output must looks like:

codID,namesp,k1,k2,k3,k4
1,spA,spB,spD,spE,spC
2,spB,...
3,spC,...
4,spC,...
5,spD,...
6,spE,...

Any help are welcome.

cheers

milton

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Re: [R] updating columns using other column as reference

2009-10-19 Thread milton ruser
Amazing.
 Thanks a lot

milton

On Mon, Oct 19, 2009 at 12:55 PM, Henrique Dallazuanna www...@gmail.comwrote:

 Milton,

 Try this:

 myDF[grep(k, names(myDF))] - sapply(myDF[grep(k, names(myDF))],
 function(idx)myDF$namesp[idx])


 On Mon, Oct 19, 2009 at 2:03 PM, milton ruser milton.ru...@gmail.com
 wrote:
  Dear R-gurus,
 
  Just supose I have a dara.frame that looks like
 
  myDF-read.table(stdin(),head=T,sep=,)
  codID,namesp,k1,k2,k3,k4
  1,spA,2,5,6,3
  2,spB,4,5,4,6
  3,spC,2,1,5,6
  4,spC,5,4,3,2
  5,spD,1,2,3,4
  6,spE,2,4,3,1
 
  I need to update the columns k1-k4 with the namesp, but
  considering the math between Kx and codID.
 
  My desired output must looks like:
 
  codID,namesp,k1,k2,k3,k4
  1,spA,spB,spD,spE,spC
  2,spB,...
  3,spC,...
  4,spC,...
  5,spD,...
  6,spE,...
 
  Any help are welcome.
 
  cheers
 
  milton
 
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 --
 Henrique Dallazuanna
 Curitiba-Paraná-Brasil
 25° 25' 40 S 49° 16' 22 O


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Re: [R] Filtering on a dataframe- newbie question

2009-10-18 Thread milton ruser
Hi there,

Try ?subset
?str may also be useful..

bests

milton

On Sun, Oct 18, 2009 at 11:10 PM, ANJAN PURKAYASTHA 
anjan.purkayas...@gmail.com wrote:

 Hi,
 newbie question. I have a data-frame with 3 named columns: Name, Obs1,
 Obs2.
 The Name column members are made of alphanumeric characters: T1, T2, T3
 etc.
 I would like to acess only that subset of the data-frame with Name == T44.
 X - dataframe[dataframe$Name=='T44'] does not work.
 Any ideas on how to do this?
 I'm sure I'm missing a simple concept here.

 Thanks,
 Anjan


 --
 =
 anjan purkayastha, phd
 bioinformatics analyst
 whitehead institute for biomedical research
 nine cambridge center
 cambridge, ma 02142

 purkayas [at] wi [dot] mit [dot] edu
 703.740.6939

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Re: [R] is that possible to graph 4 dimention plot

2009-10-04 Thread milton ruser
How about : google r graph gallery 4d ?

abs

On Sun, Oct 4, 2009 at 3:31 PM, Duncan Murdoch murd...@stats.uwo.ca wrote:

 On 04/10/2009 3:14 PM, gcheer3 wrote:

 Suppose there are 4 variables
 d is a function of a , b and c
 I want to know how a, b and c change will make d change
 It will be straightforward to see it if we can graph the d surface

 if d is only a function of a and b, I can use 'persp' to see the surface
 of
 d. I can easily see at what values of a and b, d will get the maxium or
 minium or multiple modes, etc

 But for 4 dimention graph, is there a way to show the surface of d
 Will use color help


 contour3d in the misc3d package can do something like that.

 Duncan Murdoch


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Re: [R] Can You Recommend Books for Linear Mixed Models in R

2009-10-01 Thread milton ruser
Hi Pat,

I am happy with the book Mixed Effects Models and Extensions in Ecology
with R
by Zuur, Ieno, Walker, Saveliev and Smith. In fact I am reading chapter by
chapter,
and the reading is very digestible, as well as the examples are quite easy
to understand
and to be reference for our real world.

Cheers

milton
brazil=toronto

On Thu, Oct 1, 2009 at 12:10 PM, Pat Schmitz pschm...@illinois.edu wrote:

 All

 I have been looking into the books on performing statistics in R, in
 particular I am interested in General Linear Mixed Models, for Randomized
 Complete Block Design Experiments

 The list I have come away with so far is:

 Mixed Effects Models in S and S-plus by Pinheiro (2002)

 http://www.amazon.com/Mixed-Effects-Models-S-S-Plus/dp/0387989579/ref=wl_itt_dp_o?ie=UTF8coliid=I1WXOBRXMHD30Vcolid=38N475HUK5VPJ

 Linear Models with R by Faraway (2004)

 http://www.amazon.com/Linear-Models-Texts-Statistical-Science/dp/1584884258/ref=sr_1_1?ie=UTF8s=booksqid=1254412763sr=1-1

 Extending the Linear Model with R by Faraway (2005)

 http://www.amazon.com/Extending-Linear-Model-Generalized-Nonparametric/dp/158488424X/ref=pd_sim_b_7

 Which of these would you as statisticians, researchers, scientists most
 recommend?
 Are there others in this realm of statistics that I have not discovered,
 that might be more effective?

 Thanks
 Pat



 --
 Patrick Schmitz
 Graduate Student
 Plant Biology
 1206 West Gregory Drive
 RM 1500

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Re: [R] Deleting a column in a dataframe by name

2009-09-29 Thread milton ruser
May be this:

FRAME   - FRAME[-c(NAME1, NAME2)]
or
FRAME- subset(FRAME, select=(-NAME1, -NAME2))

bests

milton
On Tue, Sep 29, 2009 at 4:12 PM, Dennis Fisher fis...@plessthan.com wrote:

 Colleagues,

 Hopefully a simple problem: I want to delete a column with a known name
 from a dataframe.  I could write:

FRAME   - FRAME[, names(FRAME) != NAMETODELETE]
 or
FRAME   - FRAME[, !names(FRAME) %in% c(NAME1, NAME2, ETC)]

 Is there some simpler means to accomplish this?

 Dennis


 Dennis Fisher MD
 P  (The P Less Than Company)
 Phone: 1-866-PLessThan (1-866-753-7784)
 Fax: 1-415-564-2220
 www.PLessThan.com http://www.plessthan.com/

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Re: [R] Deleting a column in a dataframe by name

2009-09-29 Thread milton ruser
x=runif(12)
y=runif(12)
w=runif(12)

mydf-data.frame(cbind(x,y,w))
head(mydf)

mydf-subset(mydf, select=c(-x,-w))
head(mydf)


On Tue, Sep 29, 2009 at 4:27 PM, Rolf Turner r.tur...@auckland.ac.nzwrote:


 On 30/09/2009, at 9:15 AM, milton ruser wrote:

 May be this:

 FRAME   - FRAME[-c(NAME1, NAME2)]
 or
 FRAME- subset(FRAME, select=(-NAME1, -NAME2))


 This is ridiculous advice.  Try things out before you suggest them.

cheers,

Rolf Turner

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Re: [R] Deleting a column in a dataframe by name

2009-09-29 Thread milton ruser
Peace on your heart... it is still Tuesday, and Friday is away... :-)



On Tue, Sep 29, 2009 at 4:54 PM, Rolf Turner r.tur...@auckland.ac.nzwrote:


 On 30/09/2009, at 9:32 AM, milton ruser wrote:

 x=runif(12)
 y=runif(12)
 w=runif(12)

 mydf-data.frame(cbind(x,y,w))
 head(mydf)

 mydf-subset(mydf, select=c(-x,-w))
 head(mydf)


But this doesn't work if NAME1 and NAME2 are ***names***,
as the terminology would apply.  And that is precisely the
situation in which one would wish to apply this sort of
technique.

cheers,

Rolf Turner

 On Tue, Sep 29, 2009 at 4:27 PM, Rolf Turner r.tur...@auckland.ac.nz
 wrote:

 On 30/09/2009, at 9:15 AM, milton ruser wrote:

 May be this:

 FRAME   - FRAME[-c(NAME1, NAME2)]
 or
 FRAME- subset(FRAME, select=(-NAME1, -NAME2))

 This is ridiculous advice.  Try things out before you suggest them.

   cheers,

   Rolf Turner

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Re: [R] Count number of zeros in a collumn

2009-09-27 Thread milton ruser
Hi Marcio,

How about if (min(dart[,1977])==0)...

cheers
milton

On Sun, Sep 27, 2009 at 4:54 PM, Marcio Resende mresende...@yahoo.com.brwrote:


 I have a matrix 700x2000 which is sampled in each cycle from another matrix
 788x2000 with the numbers 0,1 and 9

 There is one specific collumn of this matrix, dart[,1977], that usually,
 after the samplimg procedure has only 1 and 9 (because the zero frequency
 in
 this collumn is low).
 However, when this happens, I want to include an IF conditional in my code.
 so basically what i wanted to do was to count the number of zeros in this
 collumn to use this information in my conditional:

 something like:

 if (the number of zeros in collumn [,1977] is zero) ... else ...

 I tried to find out indirectly by the rowsum but because of the sampling
 procedure the rowsum is not always the same

 Thank you very much
 --
 View this message in context:
 http://www.nabble.com/Count-number-of-zeros-in-a-collumn-tp25637516p25637516.html
 Sent from the R help mailing list archive at Nabble.com.

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Re: [R] Teach me how to transpose in R

2009-09-26 Thread milton ruser
*Hum*

bbb=t(as.matrix(data2)) ?

good luck

milton




On Sun, Sep 27, 2009 at 12:39 AM, Hyo Lee totem...@gmail.com wrote:

 Hi guys,
 I need your help!!

 My goal is to make a csv file from ncdf file.
 This is the code i've used :

  hyo=open.ncdf(C:/CRUTEM3.nc)
  hyo
 [1] file C:/CRUTEM3.nc has 4 dimensions:[1] longitude   Size: 72
 [1] latitude   Size: 36
 [1] unspecified   Size: 1
 [1] t   Size: 1916
 [1] 
 [1] file C:/CRUTEM3.nc has 1 variables:
 [1] float temp[longitude,latitude,unspecified,t]  Longname:Temperature T
 Missval:2.0004008175e+20
  data2=get.var.ncdf(hyo)
  write.csv(data2,file=C:/ple.csv)


 But the problem is, I expected this data would be 17000 * 72  (row* col) ;
 but, it is the other way around. 72*17000
 Because the maximum col number in excel is 16383, this cvs file doesn't
 show
 all data. Obviously, I need to transpose the matrix..
 I tried to use transpose function but failed.

  bbb=t(data2)
 Error in t.default(data2) : argument is not a matrix
  ccc=t(hyo)
  ccc
 [1] file  has  dimensions:
 Error in if (nc$ndims  0) for (i in 1:nc$ndims) { :
  argument is of length zero

 Teach me how to deal with this problem.
 Thank you very much.

 -Hyo

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Re: [R] Create directory and copy files in R

2009-09-22 Thread milton ruser
Tammy

Try avoid directories with spaces... may be this solve your problem.
Case not, write us again.

bests
milton

On Mon, Sep 21, 2009 at 10:05 AM, Tammy Ma metal_lical...@live.com wrote:



 HI, All R users,

 My problem is:

  fn
 [1] C:/Documents and
 Settings/lma/Desktop/FamilyAEntrepreneurs/Entrepreneurs/Juha/book_log-20041210T095019.txt
  dpath
 [1] C:/Documents and Settings/lma/My Documents/Juha/book


 I want to make  a function cyfun to copy all files in dir to deskdir
 but I always got the following problem:

 Error in file.exists(to) : invalid 'file' argument.
 Whats the problem??




 cyfun-function(fn,dpath){
 dir-dirname(fn)
 fn-basename(fn)

 deskdir-dir.create(dpath)
 file.copy(fn, deskfile)

 }

 Thanks!

 Tammy

 _
 Drag n’ drop—Get easy photo sharing with Windows Live™ Photos.

 http://www.microsoft.com/windows/windowslive/products/photos.aspx
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Re: [R] Superimposing (aligning) two graphs

2009-09-22 Thread milton ruser
Hi Maggie:

1) plot() combined with lines() may do the job.
2) google R graph gallery

bests

milton

On Tue, Sep 22, 2009 at 5:23 PM, Maggie la.f...@gmail.com wrote:

 Hello, I need to superimpose two graphs (plotted representations of
 waver files) so I can see how much they align. Is   there a quick and
 dirty way to do it in R?

 thanks so much for your help!

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Re: [R] Correlate two time series

2009-09-22 Thread milton ruser
Have you looked at ts() ?

On Tue, Sep 22, 2009 at 5:49 PM, Maggie la.f...@gmail.com wrote:

 I was wondering how to correlate two time series in R? I have to
 plotted waver files I need to correlate to one another to see how well
 they align..

 Any guidance would be very much appreciated!

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Re: [R] plotting least-squares regression against x-axis

2009-09-19 Thread milton ruser
By the way, how about:

plot(y,mylm$residuals)

So you can have an idea of your error distribution across your response
variable domain. :-)

milton
toronto=brazil
On Sat, Sep 19, 2009 at 9:02 PM, Sunil Suchindran sunilsuchind...@gmail.com
 wrote:

 x - seq(50)

 y - 10 + x * 2 + rnorm(50,0,10)

 plot(y~x)

 mylm = lm(y~x)

 # Use str(mylm) to see how to get the residuals

 plot(x,mylm$residuals)


 On Sat, Sep 19, 2009 at 8:35 PM, Jason Priem pr...@email.unc.edu wrote:

  Hi,
  I want to plot the residuals of a least-squares regression.
 
  plot(lm(y~x), which=1)
 
  does this, but it plots the y-axis of my data on the x-axis of the
  residuals plot.  That is, it plots the residual for each y-value in the
  data.  Can I instead use the x-axis of my data as the x-axis of the
  residuals plot, showing the residual for a given x?
 
  Thanks!
 
  Jason Priem
  University of North Carolina at Chapel Hill
  School of Information and Library Science
 
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 http://www.r-project.org/posting-guide.html
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Re: [R] (no subject)

2009-09-13 Thread milton ruser
Hi Karen,

As you are just starting (I guess), I suggest you take a shortcut:
1. copy and paste the data from Excel to the notepad, and
save it as .TXT
2. If all is ok, you will have a tab-delimited file.
3. Be sure that your variables have its names on first line
4. read your data using

setwd(c:\\temp)
myDF-read.table(myfile.txt, head=T, sep=\t)
myDF   #here you will see all your data.frame (i.e. your table)

hist(myDF$VARNAME)
or
hist(myD[,1]) #to plot 1st collumn
 hist(myD[,2]) #to plot 2nd collumn


good luck..

milton

On Sun, Sep 13, 2009 at 7:44 PM, Karen Federico kfede...@stevens.eduwrote:

 How would I make a histogram using R from a table in excel that has 4
 variables, but I only want to use 2 of the columns to make the histogram?


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Re: [R] fitting nonlinear model

2009-09-09 Thread milton ruser
Hi Bill,

I am not sure what you want, but...

mydf-read.table(stdin(), head=T, sep=,)
Np,year
96,2
91,5
89,7
85,10

plot(Np~year, data=mydf)
mymodel-lm(Np~year, data=mydf)
abline(mymodel, col=red)

bests
milton

On Wed, Sep 9, 2009 at 2:27 PM, Bill Hyman billhym...@yahoo.com wrote:

 My data look like:

 Np year
 962
 915
 897
 85   10



 - Original Message 
 From: Bill Hyman billhym...@yahoo.com
 To: r-help@r-project.org
 Sent: Wednesday, September 9, 2009 11:23:26 AM
 Subject: [R] fitting nonlinear model

 I only have 4 data points and want to fit a curve. It does not work in
 modreg due to too few data. Do you have any idea? Many thanks!

 __
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 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide
 http://www.R-project.org/posting-guide.htmlhttp://www.r-project.org/posting-guide.html
 and provide commented, minimal, self-contained, reproducible code.

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 R-help@r-project.org mailing list
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Re: [R] fitting nonlinear model

2009-09-09 Thread milton ruser
May be this:

mydf-read.table(stdin(), head=T, sep=,)
Xvar,Yvar
0,1
2,0.9
5,0.5
7,0.1
10,0.01
mymodel-loess(Yvar~Xvar, data=mydf)

plot(mymodel)
mydf.new-data.frame(cbind(Xvar=seq(from=0, to=10, by=0.1)))
mydf.new$Yvar-predict(mymodel, newdata=mydf.new)
lines(Yvar~Xvar, data=mydf.new, lty=2)

cheers

milton

On Wed, Sep 9, 2009 at 3:01 PM, milton ruser milton.ru...@gmail.com wrote:

 Hi Bill,

 I am not sure what you want, but...

 mydf-read.table(stdin(), head=T, sep=,)
 Np,year
 96,2
 91,5
 89,7
 85,10

 plot(Np~year, data=mydf)
 mymodel-lm(Np~year, data=mydf)
 abline(mymodel, col=red)

 bests
 milton

   On Wed, Sep 9, 2009 at 2:27 PM, Bill Hyman billhym...@yahoo.com wrote:

 My data look like:

 Np year
 962
 915
 897
 85   10



 - Original Message 
 From: Bill Hyman billhym...@yahoo.com
 To: r-help@r-project.org
 Sent: Wednesday, September 9, 2009 11:23:26 AM
 Subject: [R] fitting nonlinear model

 I only have 4 data points and want to fit a curve. It does not work in
 modreg due to too few data. Do you have any idea? Many thanks!

 __
 R-help@r-project.org mailing list
 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide
 http://www.R-project.org/posting-guide.htmlhttp://www.r-project.org/posting-guide.html
 and provide commented, minimal, self-contained, reproducible code.

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 R-help@r-project.org mailing list
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Re: [R] Joining Characters in R {issue with paste}

2009-09-09 Thread milton ruser
You not tryed ?paste  :-)

paste(a,b,sep=)

bests

milton

On Wed, Sep 9, 2009 at 5:08 PM, Abhishek Pratap abhishek@gmail.comwrote:

 Hi Guys
 I am want to join to strings in R. I am using paste but not getting
 desirable result.

 For the sake of clarity, a quick example:

  a=Bio
  b=iology
  paste(a,b)
 [1] Bio iology


 *There is a SPACE in the word biology which is what I dont want *


 Thanks,
 -Abhi

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Re: [R] (no subject)

2009-09-06 Thread milton ruser
Hi Roslina,

x-runif(1000,min=0, max=600)
hist(x)

x2-ifelse(x=300,x,300)
summary(x2)
hist(x2, ,breaks = c(0,50,100,150,200,250,300))
 good luck

milton

On Mon, Sep 7, 2009 at 12:51 AM, Roslina Zakaria zrosl...@yahoo.com wrote:

 Hi r-users,

 I would like to know how to put all the data that is greater than certain
 value in certain cell for my histogram.  For example, since maximum value of
 p1 is 588 it doesn't fit in the breaks that we specified.  Can we write
 breaks 300?

 max(p1[,2])
 pre.hist - hist(p1[,2],breaks = c(0,50,100,150,200,250,300),right=FALSE)

  max(p1)
 [1] 587.2761
  pre.hist - hist(p1[,2],breaks = c(0,50,100,150,200,250,300),right=FALSE)
 Error in hist.default(p1[, 2], breaks = c(0, 50, 100, 150, 200, 250, 300),
 :
   some 'x' not counted; maybe 'breaks' do not span range of 'x'
  max(p1[,2])
 [1] 587.2761

 Thank you.





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Re: [R] (no subject)

2009-09-06 Thread milton ruser
May be you also want:

x-runif(1000,min=0, max=600)

 x3-x[x=300]
summary(x3)
 hist(x3, ,breaks = c(0,50,100,150,200,250,300))

bests

milton

On Mon, Sep 7, 2009 at 1:01 AM, milton ruser milton.ru...@gmail.com wrote:

 Hi Roslina,

 x-runif(1000,min=0, max=600)
 hist(x)

 x2-ifelse(x=300,x,300)
 summary(x2)
 hist(x2, ,breaks = c(0,50,100,150,200,250,300))
  good luck

 milton

   On Mon, Sep 7, 2009 at 12:51 AM, Roslina Zakaria zrosl...@yahoo.comwrote:

  Hi r-users,

 I would like to know how to put all the data that is greater than certain
 value in certain cell for my histogram.  For example, since maximum value of
 p1 is 588 it doesn't fit in the breaks that we specified.  Can we write
 breaks 300?

 max(p1[,2])
 pre.hist - hist(p1[,2],breaks = c(0,50,100,150,200,250,300),right=FALSE)

  max(p1)
 [1] 587.2761
  pre.hist - hist(p1[,2],breaks =
 c(0,50,100,150,200,250,300),right=FALSE)
 Error in hist.default(p1[, 2], breaks = c(0, 50, 100, 150, 200, 250,
 300),  :
   some 'x' not counted; maybe 'breaks' do not span range of 'x'
  max(p1[,2])
 [1] 587.2761

 Thank you.





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Re: [R] to istall packages such as 'stats'

2009-09-03 Thread milton ruser
Hi Ajay,

To install new packages try:
install.packages(package_name, dependencies=T)

But stats is part of base R. :-)

bests

miltinho

On Thu, Sep 3, 2009 at 6:01 AM, Ajay Singh ajayvi...@yahoo.co.in wrote:

 Dear All,
 I have to install 'stats' package in my windows machine, could you let me
 know how to install the package?
 Look forward to your assistance,

 Ajay.

 -

 Ajay Singh, Ph.D.   |Tel: +91-22 25764785

 Research Scientist, |Fax: 091-22-25722872

 S.J.M. School of Management,|Telex:011-71923 IITB IN



 INDIA.  |




  See the Web's breaking stories, chosen by people like you. Check
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Re: [R] variable selection in logistic

2009-09-03 Thread milton ruser
Hi Annie,

What kind of data (response and explanatory) you have?
As a ecological modeller, I always think first what
is my (our) mind models. After that I analyze a set of
concorrent - *but with ecological meaning* - models.
It helps me to test hypothesis as well as to discuss
the results. If you lump your data, they will tell you anything,
and you will find a `why` for every results (positive or
negative, good or bad)...

good luck

miltinho
On Thu, Sep 3, 2009 at 4:20 PM, annie Zhang annie.zhang2...@gmail.comwrote:

 Hi, Frank,

 If I want to do prediction as well as to select important predictors, which
 may be the best function to use when I have 35 samples and 35 predictors
 (penalized logistic with variable selection)? I saw there is a 'fastbw'
 function in the Design package. And there is a 'step.plr' function in the
 'stepPlr' package.

 Thank you,

 Annie

 On Thu, Sep 3, 2009 at 10:11 AM, Frank E Harrell Jr 
 f.harr...@vanderbilt.edu wrote:

  annie Zhang wrote:
 
  Thank you for all your reply.
  Actually as Bert said, besides predicion, I also need variable selection
  (I need to know which variables are important). As far as the sample
 size
  and number of variables, both of them are small around 35. How can I get
  accurate prediction as long as good predictors?
  Annie
 
 
  It is next to impossible to find a unique list of 'important' variables
  without having 50 times as many subjects as potential predictors, unless
  your signal:noise ratio is stunning.
 
  Frank
 
 
  On Thu, Sep 3, 2009 at 8:28 AM, Bert Gunter gunter.ber...@gene.com
 mailto:
  gunter.ber...@gene.com wrote:
 
 But let's be clear here folks:
 
 Ben's comment is apropos: As many variables as samples is
 particularly
 scary.
 
 (Aside -- how much scarier then are -omics analyses in which the
 number of
 variables is thousands of times the number of samples?)
 
 Sensible penalization (it's usually not too sensitive to the details)
  is
 only another way of obtaining a parsimonious model with good (in the
 sense
 of minimizing overall prediction error: bias + variance) prediction
 properties. Alas, this is often not what scientists want: they use
 variable
 selection to find the right covariates, the most important
  variables
 affecting the response. But this is beyond the power of empirical
 modeling
 here: as many variables as samples almost guarantees that there
 will be
 many different and even nonoverlapping subsets of variables that
 are, within
 statistical noise, equally optimal predictors. That is, variable
 selection
 in such circumstances is just a pretty sophisticated random number
 generator
 -- ergo Frank's Draconian warnings. Penalization produces better
 prediction
 engines with better properties, but it cannot overcome the as many
 variables as samples problem either. Entropy rules. If what is
 sought is a
 way to determine the truly important variables, then the study must
  be
 designed to provide the information to do so. You don't get
 something for
 nothing.
 
 Cheers,
 
 Bert Gunter
 Genentech Nonclinical Biostatistics
 
 
 -Original Message-
 From: r-help-boun...@r-project.org
 mailto:r-help-boun...@r-project.org
 [mailto:r-help-boun...@r-project.org
 mailto:r-help-boun...@r-project.org] On
 Behalf Of Frank E Harrell Jr
 Sent: Wednesday, September 02, 2009 9:07 PM
 To: annie Zhang
 Cc: r-help@r-project.org mailto:r-help@r-project.org
 Subject: Re: [R] variable selection in logistic
 
 annie Zhang wrote:
   Hi, Frank,
  
   You mean the backward and forward stepwise selection is bad? You
  also
   suggest the penalized logistic regression is the best choice? Is
 there
   any function to do it as well as selecting the best penalty?
  
   Annie
 
 All variable selection is bad unless its in the context of
  penalization.
  You'll need penalized logistic regression not necessarily with
 variable selection, for example a quadratic penalty as in a case
 study
 in my book, or an L1 penalty (lasso) using other packages.
 
 Frank
 
  
   On Wed, Sep 2, 2009 at 7:41 PM, Frank E Harrell Jr
   f.harr...@vanderbilt.edu mailto:f.harr...@vanderbilt.edu
 mailto:f.harr...@vanderbilt.edu mailto:f.harr...@vanderbilt.edu
 
 wrote:
  
   David Winsemius wrote:
  
  
   On Sep 2, 2009, at 9:36 PM, annie Zhang wrote:
  
   Hi, R users,
  
   What may be the best function in R to do variable
 selection
   in logistic
   regression?
  
  
   PhD theses, and books by famous statisticians have been
 pursuing
   the answer to that question for decades.
  
   I have the same number of variables as the 

Re: [R] Easy way to get top 2 items from vector

2009-09-03 Thread milton ruser
Hi Noah,

Next time try, please, send a short reproducible code/example.

May be this can be (not so elegant but) helpfull


myDF-data.frame(cbind(a=runif(5),b=runif(5)))
myDF
N=2
a.order-rev(order(myDF$a))[1:N]
b.order-rev(order(myDF$b))[1:N]

myDF.max2a-myDF[a.order,]
myDF.max2a
myDF.max2b-myDF[b.order,]
myDF.max2b


milton

On Thu, Sep 3, 2009 at 7:17 PM, Noah Silverman n...@smartmediacorp.comwrote:

 Hi,

 I use the max function often to find the top value from a matrix or column
 of a data.frame.

 Now I'm looking to find the top 2 (or three) values from my data.

 I know that I could sort the list and then access the first two items, but
 that seems like the long way.  Is there some way to access max_2 or
 similar?


 Thanks!

 --
 Noah

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