[symfony-users] Re: Question about choice widget
Thanks Tom. Anyway, I want to add this link below to the links that
you gave in your first post:
http://www.thatsquality.com/articles/7-days-of-symfony-1-1-forms-widgets-and-validators-day7
I find it interesting about formatting forms.
Javi
On May 12, 11:38 am, Tom Ptacnik to...@tomor.cz wrote:
What about something like
ul.radio_list li {display: inline}
On 10 kvě, 15:41, Javier Garcia tirengar...@gmail.com wrote:
On Mar 29, 3:09 pm, Massimiliano Arione garak...@gmail.com wrote:
You jsut need to customize your css, forcing your li's as inline.
No need to modify your template or your formatter.
I'd like to force the li's as inline as you say, but the generated
li's don't have the 'id' attribute defined.
For example, this line li?php echo $form['sexo']-renderLabel() ?/
li
generates this:
li
label for=usuario_sexoSexo/label
ul class=radio_list
li !-- this li doesn't have any id--
input type=radio checked=checked id=usuario_sexo_0 value=0
name=usuario[sexo]nbsp;label for=usuario_sexo_0Chico/label
/li
li !-- this li doesn't have any id--
input type=radio id=usuario_sexo_1 value=1
name=usuario[sexo]nbsp;label for=usuario_sexo_1Chica/label
/li
/ul
/li
Javi
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[symfony-users] Re: Question about choice widget
What about something like
ul.radio_list li {display: inline}
On 10 kvě, 15:41, Javier Garcia tirengar...@gmail.com wrote:
On Mar 29, 3:09 pm, Massimiliano Arione garak...@gmail.com wrote:
You jsut need to customize your css, forcing your li's as inline.
No need to modify your template or your formatter.
I'd like to force the li's as inline as you say, but the generated
li's don't have the 'id' attribute defined.
For example, this line li?php echo $form['sexo']-renderLabel() ?/
li
generates this:
li
label for=usuario_sexoSexo/label
ul class=radio_list
li !-- this li doesn't have any id--
input type=radio checked=checked id=usuario_sexo_0 value=0
name=usuario[sexo]nbsp;label for=usuario_sexo_0Chico/label
/li
li !-- this li doesn't have any id--
input type=radio id=usuario_sexo_1 value=1
name=usuario[sexo]nbsp;label for=usuario_sexo_1Chica/label
/li
/ul
/li
Javi
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[symfony-users] Re: Question about choice widget
On Mar 29, 3:09 pm, Massimiliano Arione garak...@gmail.com wrote: You jsut need to customize your css, forcing your li's as inline. No need to modify your template or your formatter. I'd like to force the li's as inline as you say, but the generated li's don't have the 'id' attribute defined. For example, this line li?php echo $form['sexo']-renderLabel() ?/ li generates this: li label for=usuario_sexoSexo/label ul class=radio_list li !-- this li doesn't have any id-- input type=radio checked=checked id=usuario_sexo_0 value=0 name=usuario[sexo]nbsp;label for=usuario_sexo_0Chico/label /li li !-- this li doesn't have any id-- input type=radio id=usuario_sexo_1 value=1 name=usuario[sexo]nbsp;label for=usuario_sexo_1Chica/label /li /ul /li Javi -- Symfony 1.3 -- If you want to report a vulnerability issue on symfony, please send it to security at symfony-project.com You received this message because you are subscribed to the Google Groups symfony users group. To post to this group, send email to symfony-users@googlegroups.com To unsubscribe from this group, send email to symfony-users+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en
[symfony-users] Re: Question about choice widget
You jsut need to customize your css, forcing your li's as inline. No need to modify your template or your formatter. cheers Massimiliano On 25 Mar, 20:03, Javier Garcia tirengar...@gmail.com wrote: Hi, i have an edit form with a choice widget with radio buttons. Symfony renders the options in a column, but I wanted the choices in the same line this way: Sexo: Chico (o) Chica () So i have modified the code from the line ?php echo $form['sexo']? to this: ul li id=chico label class=etiqueta_opcion_sexo for=usuario_sexo_0Chico/label input type=radio id=usuario_sexo_0 value=0 name=usuario[sexo] /li li label class=etiqueta_opcion_sexo for=usuario_sexo_1Chica/label input type=radio id=usuario_sexo_1 value=1 name=usuario[sexo] /li /ul But now, how can i set the checked one? Using if's? or is there any more elegant way? Regards Javi -- If you want to report a vulnerability issue on symfony, please send it to security at symfony-project.com You received this message because you are subscribed to the Google Groups symfony users group. To post to this group, send email to symfony-users@googlegroups.com To unsubscribe from this group, send email to symfony-users+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en To unsubscribe from this group, send email to symfony-users+unsubscribegooglegroups.com or reply to this email with the words REMOVE ME as the subject.
[symfony-users] Re: Question about choice widget
Why not use jquery and onclick and show/hide the two different li On Mar 25, 2:08 pm, Javier Garcia tirengar...@gmail.com wrote: Well, what i mean is, if the genre stored of a member is male, it should be active in Chico, so how can i do it? using if's and functions that retrieve the genre of the member to set the radio button state ? Javi On Mar 25, 7:03 pm, Javier Garcia tirengar...@gmail.com wrote: Hi, i have an edit form with a choice widget with radio buttons. Symfony renders the options in a column, but I wanted the choices in the same line this way: Sexo: Chico (o) Chica () So i have modified the code from the line ?php echo $form['sexo']? to this: ul li id=chico label class=etiqueta_opcion_sexo for=usuario_sexo_0Chico/label input type=radio id=usuario_sexo_0 value=0 name=usuario[sexo] /li li label class=etiqueta_opcion_sexo for=usuario_sexo_1Chica/label input type=radio id=usuario_sexo_1 value=1 name=usuario[sexo] /li /ul But now, how can i set the checked one? Using if's? or is there any more elegant way? Regards Javi -- If you want to report a vulnerability issue on symfony, please send it to security at symfony-project.com You received this message because you are subscribed to the Google Groups symfony users group. To post to this group, send email to symfony-users@googlegroups.com To unsubscribe from this group, send email to symfony-users+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en To unsubscribe from this group, send email to symfony-users+unsubscribegooglegroups.com or reply to this email with the words REMOVE ME as the subject.
[symfony-users] Re: Question about choice widget
Maybe you can look for decorator(formatter), with that you can still use ?php echo $form['sexo']? it's decorator or formatter, I'm not sure for now ;) There is some official tutorial on Symfony pages, but I can't find it now Try this adresses or google http://bluehorn.co.nz/2009/08/31/symfony-12-sfform-formatter-to-add-stars-on-required-fields/ http://erisds.co.uk/symfony/snippet-symfony-forms-setting-the-form-formatter On 25 bře, 19:08, Javier Garcia tirengar...@gmail.com wrote: Well, what i mean is, if the genre stored of a member is male, it should be active in Chico, so how can i do it? using if's and functions that retrieve the genre of the member to set the radio button state ? Javi On Mar 25, 7:03 pm, Javier Garcia tirengar...@gmail.com wrote: Hi, i have an edit form with a choice widget with radio buttons. Symfony renders the options in a column, but I wanted the choices in the same line this way: Sexo: Chico (o) Chica () So i have modified the code from the line ?php echo $form['sexo']? to this: ul li id=chico label class=etiqueta_opcion_sexo for=usuario_sexo_0Chico/label input type=radio id=usuario_sexo_0 value=0 name=usuario[sexo] /li li label class=etiqueta_opcion_sexo for=usuario_sexo_1Chica/label input type=radio id=usuario_sexo_1 value=1 name=usuario[sexo] /li /ul But now, how can i set the checked one? Using if's? or is there any more elegant way? Regards Javi -- If you want to report a vulnerability issue on symfony, please send it to security at symfony-project.com You received this message because you are subscribed to the Google Groups symfony users group. To post to this group, send email to symfony-users@googlegroups.com To unsubscribe from this group, send email to symfony-users+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en To unsubscribe from this group, send email to symfony-users+unsubscribegooglegroups.com or reply to this email with the words REMOVE ME as the subject.
[symfony-users] Re: Question about choice widget
Well, what i mean is, if the genre stored of a member is male, it should be active in Chico, so how can i do it? using if's and functions that retrieve the genre of the member to set the radio button state ? Javi On Mar 25, 7:03 pm, Javier Garcia tirengar...@gmail.com wrote: Hi, i have an edit form with a choice widget with radio buttons. Symfony renders the options in a column, but I wanted the choices in the same line this way: Sexo: Chico (o) Chica () So i have modified the code from the line ?php echo $form['sexo']? to this: ul li id=chico label class=etiqueta_opcion_sexo for=usuario_sexo_0Chico/label input type=radio id=usuario_sexo_0 value=0 name=usuario[sexo] /li li label class=etiqueta_opcion_sexo for=usuario_sexo_1Chica/label input type=radio id=usuario_sexo_1 value=1 name=usuario[sexo] /li /ul But now, how can i set the checked one? Using if's? or is there any more elegant way? Regards Javi -- If you want to report a vulnerability issue on symfony, please send it to security at symfony-project.com You received this message because you are subscribed to the Google Groups symfony users group. To post to this group, send email to symfony-users@googlegroups.com To unsubscribe from this group, send email to symfony-users+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en To unsubscribe from this group, send email to symfony-users+unsubscribegooglegroups.com or reply to this email with the words REMOVE ME as the subject.
