On 20 March 2010 17:17, David Nolen dnolen.li...@gmail.com wrote:
You can do what you want with the following:
(doseq [[x y] (for [y (range 4) x (range 4)] [x y])]
(println x y))
Or just
(doseq [y (range 4)
x (range 4)]
(println x y))
doseq really has exactly the same syntax as
On Mar 20, 2010, at 13:05 , WoodHacker wrote:
When I run the following:
(for [y (range 4)] (for [x (range 4)] (println x y)))
I get what I expect - 0 0, 1 0, 2 0, 3 0 etc., but at the end of
each y loop I also get 4 nils.
((0 0
1 0
2 0
3 0
nil nil nil nil) (0 1
1 1
2 1
3 1
On 20 March 2010 13:05, WoodHacker ramsa...@comcast.net wrote:
What's going on? And how do I fix it? Adding a :when to test for
nil does not seem to do anything.
You'll want to use 'doseq' in place of 'for'. It uses exactly the same
syntax as for, but is used solely for side effects (the
I guess you want this:
(for [x (range 4) y (range 4)] (str x y))
--
DmitriKo
On Mar 20, 2:05 pm, WoodHacker ramsa...@comcast.net wrote:
When I run the following:
(for [y (range 4)] (for [x (range 4)] (println x y)))
I get what I expect - 0 0, 1 0, 2 0, 3 0 etc., but at the end of
On Sat, Mar 20, 2010 at 8:05 AM, WoodHacker ramsa...@comcast.net wrote:
When I run the following:
(for [y (range 4)] (for [x (range 4)] (println x y)))
I get what I expect - 0 0, 1 0, 2 0, 3 0 etc., but at the end of
each y loop I also get 4 nils.
((0 0
1 0
2 0
3 0
nil nil nil
