Did you misspell it in your code?
$('p').length
On Dec 13, 2:59 am, manko uha...@gmail.com wrote:
Sometimes
$('p').lenght
returns undefiend property
but when i replace lenght with size() method i get the correct number
of p elements in current dom ??
Check out the live function. It can solve this problem.
http://docs.jquery.com/Events/live
On Dec 5, 2:38 am, mysterious79 gray8...@gmail.com wrote:
This probably isn't a jquery question precisely, but jquery is being
used as my method for making ajax requests.
I'm running into a recurring
One of the scripts or plugins you are using appears to be duplicating
the code for the form creating 2 forms with the same attributes on the
same page. The first form is never being shown at all and is not
accepting input. Using some jQuery like this:
$('[name=yourName]:last').val()
you can
I tried to rebind the event handlers and for some reason that did not
work.
However, the plugin worked perfectly!
Thanks once again, I spent days on this
On Nov 28, 2:17 pm, jpcozart jeremy.coz...@gmail.com wrote:
You can use the Live Query plugin to resolve this problem
I would have to see the structure of the document to know where the
problem lies. It seems as though
country.next(select.state);
is not returning the node you are looking for.
On Dec 3, 1:07 pm, TMNT tmand...@gmail.com wrote:
Matt, thanks for your response.
I had originally posted this on
You can use the Live Query plugin to resolve this problem:
http://docs.jquery.com/Plugins/livequery
Or you can rebind the event handlers after the ajax call has updated
the page. The new nodes do not have event handlers bound to them when
they replace the old nodes:
function refreshcontent(){
You can check out the livequery plugin here which addresses this
issue:
http://docs.jquery.com/Plugins/livequery
or you can rebind the event after the ajax call:
function refreshcontent(){
$.get(mycontent.php, function(data){
$(#container).animate({ opacity: hide }, 200);
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