Re: [Matplotlib-users] Overlapping labels in pie charts
Hello again, and thanks.
I did not have a chance to look at this until now but using arc instead of
angle worked out great.
2010/3/24 Jae-Joon Lee lee.j.j...@gmail.com
You should not use angle style if you change the x,y position (this
is due to the algorithm of how the line connecting two points are
create).
Try something like below instead.
if foo:
if theta - foo 10:
print sys.stderr, Overlapping, offsetting a little bit
y1 = y1 + 0.1
if x1 0 :
cstyle=arc,angleA=180,armA=30,armB=10,angleB=%f%(-theta,)
else:
cstyle=arc,angleA=0,armA=30,armB=10,angleB=%f%(theta,)
There is not much documentation of how each algorithm works (it is
beyond my english skill). They are loosely based on the latex pstrick
package and the screenshot in the following link may be useful to get
some idea though.
http://matplotlib.sourceforge.net/users/annotations_guide.html#annotating-with-arrow
Regards,
-JJ
2010/3/24 Rune V. Sjøen rvsj...@gmail.com:
Hello again, and thank you very much for the answer, suddenly it all got
much clearer to me. The only 'issue' I am having is (from screenshot)
what
happens to the line pointing to Logs when I try to offset it a little bit
on
the Y axis. It looks like either the angleA or angleB is wrong, but I
don't
see and reason why it would be as the X coordinates does not change.
Another thing I do not quite understand is what that patchB does.
figure(1, figsize=(6,6))
ax = axes([0.1, 0.1, 0.8, 0.8])
labels = 'Frogs', 'Hogs', 'Dogs', 'Logs'
fracs = [45, 135 ,1, 1]
p = pie(fracs)
foo = None
for p1, l1 in zip(p[0], labels):
r = p1.r
dr = r*0.1
t1, t2 = p1.theta1, p1.theta2
theta = (t1+t2)/2.
xc = cos(theta/180.*pi)*r
yc = sin(theta/180.*pi)*r
x1 = cos(theta/180.*pi)*(r+dr)
y1 = sin(theta/180.*pi)*(r+dr)
if x1 0 :
x1 = r+2*dr
ha, va = left, center
cstyle=angle,angleA=180,angleB=%f%(-theta,)
print sys.stderr, ha, ,A,, va
else:
x1 = -(r+2*dr)
ha, va = right, center
cstyle=angle,angleA=0,angleB=%f%(theta,)
print sys.stderr, ha, ,B,, va
if foo:
if theta - foo 10:
print sys.stderr, Overlapping, offsetting a little
bit
y1 = y1 + 0.1
foo = theta
annotate(l1,
(xc, yc), xycoords=data,
xytext=(x1, y1), textcoords=data, ha=ha, va=va,
arrowprops=dict(arrowstyle=-,
connectionstyle=cstyle,
patchB=p1))
- Rune
2010/3/23 Jae-Joon Lee lee.j.j...@gmail.com
This should be doable using the annotation. Here is a simple cook-up I
just did. it uses a naive algorithm to place the labels, but I guess
it gives you an idea how things work.
a screenshot is attached.
Regards,
-JJ
from pylab import *
# make a square figure and axes
figure(1, figsize=(6,6))
ax = axes([0.1, 0.1, 0.8, 0.8])
labels = 'Frogs', 'Hogs', 'Dogs', 'Logs'
fracs = [15,30,45, 10]
explode=(0, 0.05, 0, 0)
p = pie(fracs, explode=explode, shadow=True)
title('Raining Hogs and Dogs', bbox={'facecolor':'0.8', 'pad':5})
for p1, l1 in zip(p[0], labels):
r = p1.r
dr = r*0.1
t1, t2 = p1.theta1, p1.theta2
theta = (t1+t2)/2.
xc, yc = r/2.*cos(theta/180.*pi), r/2.*sin(theta/180.*pi)
x1, y1 = (r+dr)*cos(theta/180.*pi), (r+dr)*sin(theta/180.*pi)
if x1 0 :
x1 = r+2*dr
ha, va = left, center
tt = -180
cstyle=angle,angleA=0,angleB=%f%(theta,)
else:
x1 = -(r+2*dr)
ha, va = right, center
tt = 0
cstyle=angle,angleA=0,angleB=%f%(theta,)
annotate(l1,
(xc, yc), xycoords=data,
xytext=(x1, y1), textcoords=data, ha=ha, va=va,
arrowprops=dict(arrowstyle=-,
connectionstyle=cstyle,
patchB=p1))
show()
--
Download Intel#174; Parallel Studio Eval
Try the new software tools for yourself. Speed compiling, find bugs
proactively, and fine-tune applications for parallel performance.
See why Intel Parallel Studio got high marks during beta.
http://p.sf.net/sfu/intel-sw-dev___
Matplotlib-users mailing list
Matplotlib-users@lists.sourceforge.net
https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] Overlapping labels in pie charts
Hello again, and thank you very much for the answer, suddenly it all got
much clearer to me. The only 'issue' I am having is (from screenshot) what
happens to the line pointing to Logs when I try to offset it a little bit on
the Y axis. It looks like either the angleA or angleB is wrong, but I don't
see and reason why it would be as the X coordinates does not change.
Another thing I do not quite understand is what that patchB does.
figure(1, figsize=(6,6))
ax = axes([0.1, 0.1, 0.8, 0.8])
labels = 'Frogs', 'Hogs', 'Dogs', 'Logs'
fracs = [45, 135 ,1, 1]
p = pie(fracs)
foo = None
for p1, l1 in zip(p[0], labels):
r = p1.r
dr = r*0.1
t1, t2 = p1.theta1, p1.theta2
theta = (t1+t2)/2.
xc = cos(theta/180.*pi)*r
yc = sin(theta/180.*pi)*r
x1 = cos(theta/180.*pi)*(r+dr)
y1 = sin(theta/180.*pi)*(r+dr)
if x1 0 :
x1 = r+2*dr
ha, va = left, center
cstyle=angle,angleA=180,angleB=%f%(-theta,)
print sys.stderr, ha, ,A,, va
else:
x1 = -(r+2*dr)
ha, va = right, center
cstyle=angle,angleA=0,angleB=%f%(theta,)
print sys.stderr, ha, ,B,, va
if foo:
if theta - foo 10:
print sys.stderr, Overlapping, offsetting a little
bit
y1 = y1 + 0.1
foo = theta
annotate(l1,
(xc, yc), xycoords=data,
xytext=(x1, y1), textcoords=data, ha=ha, va=va,
arrowprops=dict(arrowstyle=-,
connectionstyle=cstyle,
patchB=p1))
- Rune
2010/3/23 Jae-Joon Lee lee.j.j...@gmail.com
This should be doable using the annotation. Here is a simple cook-up I
just did. it uses a naive algorithm to place the labels, but I guess
it gives you an idea how things work.
a screenshot is attached.
Regards,
-JJ
from pylab import *
# make a square figure and axes
figure(1, figsize=(6,6))
ax = axes([0.1, 0.1, 0.8, 0.8])
labels = 'Frogs', 'Hogs', 'Dogs', 'Logs'
fracs = [15,30,45, 10]
explode=(0, 0.05, 0, 0)
p = pie(fracs, explode=explode, shadow=True)
title('Raining Hogs and Dogs', bbox={'facecolor':'0.8', 'pad':5})
for p1, l1 in zip(p[0], labels):
r = p1.r
dr = r*0.1
t1, t2 = p1.theta1, p1.theta2
theta = (t1+t2)/2.
xc, yc = r/2.*cos(theta/180.*pi), r/2.*sin(theta/180.*pi)
x1, y1 = (r+dr)*cos(theta/180.*pi), (r+dr)*sin(theta/180.*pi)
if x1 0 :
x1 = r+2*dr
ha, va = left, center
tt = -180
cstyle=angle,angleA=0,angleB=%f%(theta,)
else:
x1 = -(r+2*dr)
ha, va = right, center
tt = 0
cstyle=angle,angleA=0,angleB=%f%(theta,)
annotate(l1,
(xc, yc), xycoords=data,
xytext=(x1, y1), textcoords=data, ha=ha, va=va,
arrowprops=dict(arrowstyle=-,
connectionstyle=cstyle,
patchB=p1))
show()
attachment: tmpkZslt5.png--
Download Intel#174; Parallel Studio Eval
Try the new software tools for yourself. Speed compiling, find bugs
proactively, and fine-tune applications for parallel performance.
See why Intel Parallel Studio got high marks during beta.
http://p.sf.net/sfu/intel-sw-dev___
Matplotlib-users mailing list
Matplotlib-users@lists.sourceforge.net
https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] Overlapping labels in pie charts
You should not use angle style if you change the x,y position (this
is due to the algorithm of how the line connecting two points are
create).
Try something like below instead.
if foo:
if theta - foo 10:
print sys.stderr, Overlapping, offsetting a little bit
y1 = y1 + 0.1
if x1 0 :
cstyle=arc,angleA=180,armA=30,armB=10,angleB=%f%(-theta,)
else:
cstyle=arc,angleA=0,armA=30,armB=10,angleB=%f%(theta,)
There is not much documentation of how each algorithm works (it is
beyond my english skill). They are loosely based on the latex pstrick
package and the screenshot in the following link may be useful to get
some idea though.
http://matplotlib.sourceforge.net/users/annotations_guide.html#annotating-with-arrow
Regards,
-JJ
2010/3/24 Rune V. Sjøen rvsj...@gmail.com:
Hello again, and thank you very much for the answer, suddenly it all got
much clearer to me. The only 'issue' I am having is (from screenshot) what
happens to the line pointing to Logs when I try to offset it a little bit on
the Y axis. It looks like either the angleA or angleB is wrong, but I don't
see and reason why it would be as the X coordinates does not change.
Another thing I do not quite understand is what that patchB does.
figure(1, figsize=(6,6))
ax = axes([0.1, 0.1, 0.8, 0.8])
labels = 'Frogs', 'Hogs', 'Dogs', 'Logs'
fracs = [45, 135 ,1, 1]
p = pie(fracs)
foo = None
for p1, l1 in zip(p[0], labels):
r = p1.r
dr = r*0.1
t1, t2 = p1.theta1, p1.theta2
theta = (t1+t2)/2.
xc = cos(theta/180.*pi)*r
yc = sin(theta/180.*pi)*r
x1 = cos(theta/180.*pi)*(r+dr)
y1 = sin(theta/180.*pi)*(r+dr)
if x1 0 :
x1 = r+2*dr
ha, va = left, center
cstyle=angle,angleA=180,angleB=%f%(-theta,)
print sys.stderr, ha, ,A,, va
else:
x1 = -(r+2*dr)
ha, va = right, center
cstyle=angle,angleA=0,angleB=%f%(theta,)
print sys.stderr, ha, ,B,, va
if foo:
if theta - foo 10:
print sys.stderr, Overlapping, offsetting a little
bit
y1 = y1 + 0.1
foo = theta
annotate(l1,
(xc, yc), xycoords=data,
xytext=(x1, y1), textcoords=data, ha=ha, va=va,
arrowprops=dict(arrowstyle=-,
connectionstyle=cstyle,
patchB=p1))
- Rune
2010/3/23 Jae-Joon Lee lee.j.j...@gmail.com
This should be doable using the annotation. Here is a simple cook-up I
just did. it uses a naive algorithm to place the labels, but I guess
it gives you an idea how things work.
a screenshot is attached.
Regards,
-JJ
from pylab import *
# make a square figure and axes
figure(1, figsize=(6,6))
ax = axes([0.1, 0.1, 0.8, 0.8])
labels = 'Frogs', 'Hogs', 'Dogs', 'Logs'
fracs = [15,30,45, 10]
explode=(0, 0.05, 0, 0)
p = pie(fracs, explode=explode, shadow=True)
title('Raining Hogs and Dogs', bbox={'facecolor':'0.8', 'pad':5})
for p1, l1 in zip(p[0], labels):
r = p1.r
dr = r*0.1
t1, t2 = p1.theta1, p1.theta2
theta = (t1+t2)/2.
xc, yc = r/2.*cos(theta/180.*pi), r/2.*sin(theta/180.*pi)
x1, y1 = (r+dr)*cos(theta/180.*pi), (r+dr)*sin(theta/180.*pi)
if x1 0 :
x1 = r+2*dr
ha, va = left, center
tt = -180
cstyle=angle,angleA=0,angleB=%f%(theta,)
else:
x1 = -(r+2*dr)
ha, va = right, center
tt = 0
cstyle=angle,angleA=0,angleB=%f%(theta,)
annotate(l1,
(xc, yc), xycoords=data,
xytext=(x1, y1), textcoords=data, ha=ha, va=va,
arrowprops=dict(arrowstyle=-,
connectionstyle=cstyle,
patchB=p1))
show()
--
Download Intel#174; Parallel Studio Eval
Try the new software tools for yourself. Speed compiling, find bugs
proactively, and fine-tune applications for parallel performance.
See why Intel Parallel Studio got high marks during beta.
http://p.sf.net/sfu/intel-sw-dev
___
Matplotlib-users mailing list
Matplotlib-users@lists.sourceforge.net
https://lists.sourceforge.net/lists/listinfo/matplotlib-users
[Matplotlib-users] Overlapping labels in pie charts
Hello, I am having some issues generating pie charts, when some of the slices become very small, their labels will draw on top of each other, making it impossible to distinguish between them. And I am trying to avoid using a legend. Does anyone know if there is a way to properly position labels of pie charts to avoid overlapping. (By for example distributing them vertically with lines pointing to their respective slices) Similar to what is done here: http://chart.apis.google.com/chart?cht=pchd=s:Uf9achs=250x100chl=January|February|March|April -- Regards Rune V. Sjoen -- Download Intel#174; Parallel Studio Eval Try the new software tools for yourself. Speed compiling, find bugs proactively, and fine-tune applications for parallel performance. See why Intel Parallel Studio got high marks during beta. http://p.sf.net/sfu/intel-sw-dev___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] Overlapping labels in pie charts
This should be doable using the annotation. Here is a simple cook-up I
just did. it uses a naive algorithm to place the labels, but I guess
it gives you an idea how things work.
a screenshot is attached.
Regards,
-JJ
from pylab import *
# make a square figure and axes
figure(1, figsize=(6,6))
ax = axes([0.1, 0.1, 0.8, 0.8])
labels = 'Frogs', 'Hogs', 'Dogs', 'Logs'
fracs = [15,30,45, 10]
explode=(0, 0.05, 0, 0)
p = pie(fracs, explode=explode, shadow=True)
title('Raining Hogs and Dogs', bbox={'facecolor':'0.8', 'pad':5})
for p1, l1 in zip(p[0], labels):
r = p1.r
dr = r*0.1
t1, t2 = p1.theta1, p1.theta2
theta = (t1+t2)/2.
xc, yc = r/2.*cos(theta/180.*pi), r/2.*sin(theta/180.*pi)
x1, y1 = (r+dr)*cos(theta/180.*pi), (r+dr)*sin(theta/180.*pi)
if x1 0 :
x1 = r+2*dr
ha, va = left, center
tt = -180
cstyle=angle,angleA=0,angleB=%f%(theta,)
else:
x1 = -(r+2*dr)
ha, va = right, center
tt = 0
cstyle=angle,angleA=0,angleB=%f%(theta,)
annotate(l1,
(xc, yc), xycoords=data,
xytext=(x1, y1), textcoords=data, ha=ha, va=va,
arrowprops=dict(arrowstyle=-,
connectionstyle=cstyle,
patchB=p1))
show()
attachment: new_piechart.png--
Download Intel#174; Parallel Studio Eval
Try the new software tools for yourself. Speed compiling, find bugs
proactively, and fine-tune applications for parallel performance.
See why Intel Parallel Studio got high marks during beta.
http://p.sf.net/sfu/intel-sw-dev___
Matplotlib-users mailing list
Matplotlib-users@lists.sourceforge.net
https://lists.sourceforge.net/lists/listinfo/matplotlib-users
