Dear all,
I've recently thought of a possible syntax extension for (Perl5's)
[un]pack() and I posted my RFC to clpmisc where it didn't have much
success, I must say. However I'm not interested in proposing it here, only
I would like to investigate a possible Perl6 technique inspired by those
I was thinking about removing files this morning, and realized that I
wish rm supported inclusion/exclusion.
In particular, I wanted to remove * but not Makefile (since my
Makefile uses lwp-download to re-fetch the source code, etc.)
It occurred to me to wonder: can P6's cbut do the same
On Tue, 14 Sep 2004, Austin Hastings wrote:
I was thinking about removing files this morning, and realized that I
wish rm supported inclusion/exclusion.
In particular, I wanted to remove * but not Makefile (since my
Makefile uses lwp-download to re-fetch the source code, etc.)
It occurred
On 2004-09-14 at 08:40:55, Austin Hastings wrote:
In particular, I wanted to remove * but not Makefile (since my
Makefile uses lwp-download to re-fetch the source code, etc.)
Well, you can, depending on your shell:
in ksh: rm !(Makefile)
in bash: ditto, but you have to turn on the extglob
Abhijit Mahabal writes:
On Tue, 14 Sep 2004, Austin Hastings wrote:
I was thinking about removing files this morning, and realized that I
wish rm supported inclusion/exclusion.
In particular, I wanted to remove * but not Makefile (since my
Makefile uses lwp-download to re-fetch the
Luke Palmer wrote:
Judging from this, maybe we ought to have :not.
Anyway, it's still possible:
$my_rex = rx/fo*/ none(rx/^foo$/);
For sure. On a side note, there should be a negating match operator for
use inside:
rx/\d+/ none(rx/1984/)
could get awfully long if you had to handle
On Tue, 2004-09-14 at 10:11, Abhijit Mahabal wrote:
On Tue, 14 Sep 2004, Austin Hastings wrote:
That is, can I say:
$my_rex = qr/fo*/ but not 'foo';
The word junction came to my mind as I read your mail.
$my_rex = qr/fo*/ qr:not/foo/;
Of course, the regex itself can do this:
On Tue, 2004-09-14 at 06:45, Michele Dondi wrote:
[... snip ...]
Now I want to take a list of templates, say $t1, ... $tn and get the
result of
$result = pack $tn, ... pack $t2, pack $t1, @input;
Assuming Perl 6 has a pack, which it may not:
for @t {
$result =
Aaron Sherman skribis 2004-09-14 14:02 (-0400):
qr{(fo*) ({$1 ne 'foo'})}
What is the second set of parens for? Will the following suffice?
rx/ (fo*) { $1 ne 'foo' } /
And it is because of the lack of anchors that this won't work as
expected?
rx/ !before foo fo* /
Juerd
On Tue, Sep 14, 2004 at 02:02:22PM -0400, Aaron Sherman wrote:
: Of course, the regex itself can do this:
:
: qr{(fo*) ({$1 ne 'foo'})}
Er, at the moment bare closures don't care about their return value,
so as it currently stands, you'd want something more like:
rx/(fo*) {fail if $1
On Tue, Sep 14, 2004 at 08:30:45PM +0200, Juerd wrote:
: Aaron Sherman skribis 2004-09-14 14:02 (-0400):
: qr{(fo*) ({$1 ne 'foo'})}
:
: What is the second set of parens for? Will the following suffice?
:
: rx/ (fo*) { $1 ne 'foo' } /
Bare closures are used only for their side effects
On Tue, 2004-09-14 at 14:40, Larry Wall wrote:
On Tue, Sep 14, 2004 at 02:02:22PM -0400, Aaron Sherman wrote:
: Of course, the regex itself can do this:
:
: qr{(fo*) ({$1 ne 'foo'})}
Er, at the moment bare closures don't care about their return value,
so as it currently stands, you'd
On Tue, 14 Sep 2004, Aaron Sherman wrote:
Assuming Perl 6 has a pack, which it may not:
I know: this is one of the reasons why I wrote (hopefully *clearly*
enough) that I was just using it as an example. A user defined pack()
whoud do just the same here, anyway.
for @t {
On Tue, 14 Sep 2004 12:45:17 +0200 (CEST), Michele Dondi
[EMAIL PROTECTED] wrote:
Now I want to take a list of templates, say $t1, ... $tn and get the
result of
$result = pack $tn, ... pack $t2, pack $t1, @input;
without actually writing the whole thing. To my knowledge and great
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