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from this address, but then clicked "Accept" in the mistaken sense of
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that is great to see this post . https://bit.ly/3C551OO
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El lun, 11 de oct. de 2021 a la(s) 06:50, Simon Cross
(hodgestar+python...@gmail.com) escribió:
> Multiprocessing sort of added support for this via multiprocessing.Array --
> see
>
El dom, 10 de oct. de 2021 a la(s) 15:20, Gregory P. Smith
(g...@krypto.org) escribió:
>> Is that because my particular case is very uncommon? Or maybe we *do*
>> want this but we don't have it yet? Or do we already have a better way
>> of doing this?
>>
>> Thanks!
>>
>> [0]
On Sun, Oct 10, 2021 at 4:23 PM Facundo Batista
wrote:
>
> struct.pack_into(format, buffer, offset, v1, v2, ...)
I've encountered this wart with pack and pack_into too.
The current interface makes sense when if v1, v2 are a small number of
items from a data record, but it becomes a bit
On Sun, 10 Oct 2021 11:19:44 -0300
Facundo Batista wrote:
> Hello everyone!
>
> I need to pack a long list of numbers into shared memory, so I thought
> about using `struct.pack_into`.
>
> Its signature is
>
> struct.pack_into(format, buffer, offset, v1, v2, ...)
>
> I have a long list of
11.10.21 01:35, MRAB пише:
> Maybe what's needed is to add, say, '*' to the format string to indicate
> that multiple values should come from an iterable, e.g.:
>
> struct.pack_into(f'{len(nums)}*Q', buf, 0, nums)
>
> in this case len(nums) from the nums argument.
See
On 2021-10-10 19:20, Gregory P. Smith wrote:
On Sun, Oct 10, 2021 at 7:25 AM Facundo Batista
mailto:facundobati...@gmail.com>> wrote:
Hello everyone!
I need to pack a long list of numbers into shared memory, so I thought
about using `struct.pack_into`.
Its signature is
10.10.21 19:05, Patrick Reader пише:
> This still isn't a completely direct write - you're still creating an array
> in between which is then copied into shm, whereas struct.pack_into writes
> directly into the shared memory with no intermediate buffer.
>
> And unfortunately you can't do
>
>
On Sun, Oct 10, 2021 at 7:25 AM Facundo Batista
wrote:
> Hello everyone!
>
> I need to pack a long list of numbers into shared memory, so I thought
> about using `struct.pack_into`.
>
> Its signature is
>
> struct.pack_into(format, buffer, offset, v1, v2, ...)
>
> I have a long list of nums
You can take a memory view of the array directly:
memoryview(array.array("Q", range(1000)))
If your exact use-case is writing to a SharedMemory, then I don't think there
is any simple way to do it without creating some intermediate memory buffer.
(other than using struct.pack_into, or packing
This still isn't a completely direct write - you're still creating an array in
between which is then copied into shm, whereas struct.pack_into writes directly
into the shared memory with no intermediate buffer.
And unfortunately you can't do
shm.buf[l_offset:r_offset].cast('Q')[:] = nums
10.10.21 18:18, Facundo Batista пише:
> You mean `array` from the `array` module? The only way I see using it
> is like the following:
>
shm = shared_memory.SharedMemory(create=True, size=total_size)
a = array.array('Q', nums)
shm.buf[l_offset:r_offset] = a.tobytes()
>
> But I
Maybe instead of tobytes() you can use memoryview().
On Sun, Oct 10, 2021 at 08:21 Facundo Batista
wrote:
> El dom, 10 de oct. de 2021 a la(s) 11:50, Serhiy Storchaka
> (storch...@gmail.com) escribió:
> >
> > 10.10.21 17:19, Facundo Batista пише:
> > > I have a long list of nums (several
El dom, 10 de oct. de 2021 a la(s) 11:50, Serhiy Storchaka
(storch...@gmail.com) escribió:
>
> 10.10.21 17:19, Facundo Batista пише:
> > I have a long list of nums (several millions), ended up doing the following:
> >
> > struct.pack_into(f'{len(nums)}Q', buf, 0, *nums)
>
> Why not use
10.10.21 17:19, Facundo Batista пише:
> I have a long list of nums (several millions), ended up doing the following:
>
> struct.pack_into(f'{len(nums)}Q', buf, 0, *nums)
Why not use array('Q', nums)?
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