Dear all,
I'm using R2.8 version, and am trying to do NMDS and calculate other
diversity indices in vegan package.
The problem is that it works with a small set of data (43 X 23; row by
column), but the following error message comes up with a larger data set (43
X 104) (it seems not large to me
Hi,
Zitat von [EMAIL PROTECTED]:
Hi Oliver: if I understood Chris's email correctly , he wanted to
compare all possible row ( row1 with the other 4 rows of the other
matrix,
row 2 with the 4 rows of the other matrix, etc, etc, ) combinations
of
the two matrices,
Oh, I thought he meant
Gabor Grothendieck wrote:
but I think R is stuck with what it has due to compatibility and the large
base of users yet its still possible to add functions in packages or new
functions to R so a new variant of subset would be possible in which
case one could decide to use the new function in
Gabor Grothendieck wrote:
Regarding the convenience it occurs in expressions like this:
iris2 - subset(iris, select = - Species)
to create a data frame without the Species column.
aha! so what's you best guess about the result here:
d = data.frame(a = 1)
d$`-b` = 2
names(d)
# here
On Tue, 2008-11-11 at 09:49 +0100, Wacek Kusnierczyk wrote:
Gabor Grothendieck wrote:
Regarding the convenience it occurs in expressions like this:
iris2 - subset(iris, select = - Species)
to create a data frame without the Species column.
aha! so what's you best guess
Hi Keun-Hyung,
Can you send the data (off list) to me or at least show what
str(gh1)
produces, and show us the output from
require(vegan)
sessionInfo()
Without that it is difficult to help.
G
On Tue, 2008-11-11 at 17:19 +0900, [EMAIL PROTECTED] wrote:
Dear all,
I'm using R2.8 version,
b g wrote:
I must have this file in the wrong directory. I can see it and it's
spelled correctly in my command (including case) but I get:
library(foreign) read.xport(cft2008R)
Error in lookup.xport(file)
:
unable to open file: 'No such file or directory' There are several
subdirectories
Berwin A Turlach wrote:
On Tue, 11 Nov 2008 09:27:41 +0100
Wacek Kusnierczyk [EMAIL PROTECTED] wrote:
but then it might be worth asking whether carrying on with misdesign
for backward compatibility outbalances guaranteed crashes in future
users' programs, [...]
Why is it worth
Gavin Simpson wrote:
d = data.frame(a = 1)
d$`-b` = 2
names(d)
# here we go
subset(d, select = -b)
# to b or not to b?
but -b is not the name of the column; you explicitly called it `-b` and
you should refer to it as such. If you use non-standard names then
expect to do a bit
Gavin Simpson wrote:
On Tue, 2008-11-11 at 11:08 +0100, Wacek Kusnierczyk wrote:
Gavin Simpson wrote:
d = data.frame(a = 1)
d$`-b` = 2
names(d)
# here we go
subset(d, select = -b)
# to b or not to b?
but -b is not the name of the column; you explicitly called it
take a look at aggregate.zoo in the zoo package
good luck
Stephen
On Mon, Nov 10, 2008 at 9:57 PM, tedzzx [EMAIL PROTECTED] wrote:
Hi all
I have some tick-by-tick data and I have calculated the intraday returns. I
want to sum up the intraday squared returns to calculate the daily
Duncan Murdoch wrote:
On 11/11/2008 8:53 AM, hadley wickham wrote:
On Mon, Nov 10, 2008 at 1:04 PM, Wacek Kusnierczyk
[EMAIL PROTECTED] wrote:
pardon me, but does this address in any way the legitimate complaint of
the rightfully confused user?
consider the following:
d = data.frame(a=1,
Dear all,
I have create a new forum for all SSA R users. The forum link is
http://aurass.forum-free.org
The forum language is french beacuse many people in SSA speak french. I hope
that the forum will contribute to increase the number of R user in SSA because
many companies in SSA fall in
I think your analysis is correct, that the goals of casual use and
programming are inconsistent. But in general I think there's always going
to be support for providing alternative ways that are programmer-safe.
For instance, library( foo, character.only=TRUE) says that foo is a
character
On Tue, 2008-11-11 at 15:54 +0100, Wacek Kusnierczyk wrote:
Have you tried? But bear in mind that R Core has more to balance that
just whether you think a design flaw or infelicity etc should be fixed
when it decides whether to accept patches.
my whole posting is an attempt, may you
On Tue, 11 Nov 2008, Wen Huang wrote:
Hi,
I am wondering if there is an option to control how R sort characters on
different machines.
Yes, and it is described on the help page for sort:
The sort order for character vectors will depend on the collating
sequence of the locale in
Thanks a lot Professor Ripley!
I did not go into much of the details in the help page and was hoping
somebody could have a quick answer.
The answer you provided is indeed helpful!
Thank you.
On Nov 11, 2008, at 10:40 AM, Prof Brian Ripley wrote:
On Tue, 11 Nov 2008, Wen Huang wrote:
?dir
Hadley
On Tue, Nov 11, 2008 at 11:06 AM, [EMAIL PROTECTED] wrote:
Dear all,
I am trying to read a bunch of csv files using read.table() that are named
test_xx.csv where xx has no particular pattern. Is there a way
of reading all the files by specifying a truncated file name
G'day Duncan,
On Tue, 11 Nov 2008 09:37:57 -0500
Duncan Murdoch [EMAIL PROTECTED] wrote:
I think this tension is a fundamental part of the character of S and
R. But it is also fundamental to R that there are QC tests that apply
to code in packages: so writing new tests that detect dangerous
Gavin Simpson wrote:
I've found several of these discussions involving Wacek's questions very
enlightening at times; once you get past the it doesn't work as I
expect so is wrong attitude.
just one fix: my attitude is 'it doesn't work as i imagine an average
user would expect it so it's
You could generate all the data as continuous using the idea below, then use
the cut function to change some of the normal continuous variables into binary
or ordinal variables. It is less clear exactly what the correlation means in
this case, but the variables would still have a relationship.
shixin jasonshi510 at hotmail.com writes:
I try to export the outputs of rcorr into excel. but I got error
message,cannot coerce class rcorr into a
data.frame. Actually i just need export part of results of this analysis,e.g.
p-values or stat-values.
library(Hmisc)
x - c(-2, -1, 0, 1, 2)
y -
Gavin Simpson wrote:
my whole posting is an attempt, may you try to notice.
vQ
Did you read what you wrote. And you still wonder why you get little
response from certain quarters?
1) Don't say no further comment - that is quite arrogant to think that
you are right and everyone who
Berwin A Turlach wrote:
G'day Duncan,
On Tue, 11 Nov 2008 09:37:57 -0500
Duncan Murdoch [EMAIL PROTECTED] wrote:
I think this tension is a fundamental part of the character of S and
R. But it is also fundamental to R that there are QC tests that apply
to code in packages: so writing new
Hi,
I am wondering if there is an option to control how R sort characters
on different machines.
For example, on my Mac OS X
sort(c(H, a), decreasing = TRUE)
[1] a H
The same command on a Linux machine gives me
sort(c(H, a), decreasing = TRUE)
[1] H a
I don't know if there is an option
Vincent Goulet wrote:
It seems that R2.8.0 for gutsy is built on a system with tcl8.5 and
tk8.5, which is not available in gutsy?
From the CRAN Ubuntu README:
Installation and compilation of R or some its packages may require
Ubuntu packages from the backports repositories. In
Hi,
I've got a microarray dataset (Illumina) coming from a blood assay with
a case-control factor of interest.
I also have several other covariates (gender, weight, etc...).
I know that the experimental design is highly unbalanced with respect to
Gender:
female male
control
Tom Backer Johnsen wrote:
Greg Snow wrote:
No problem, adjusted R-squared can be negative. If there truly is no
relationship, then the adjusted R-squared should average to 0, so
sometimes it must be negative. All of your R-squared and adjusted
R-squared values suggest that there is not much
On Mon, Nov 10, 2008 at 1:04 PM, Wacek Kusnierczyk
[EMAIL PROTECTED] wrote:
pardon me, but does this address in any way the legitimate complaint of
the rightfully confused user?
consider the following:
d = data.frame(a=1, b=2)
a = c(a, b)
z = a
# that is, both a and z are c(a, b)
On Tue, 2008-11-11 at 08:14 -0600, hadley wickham wrote:
And without wanting to be rude or anything, your opinion carries very
little weight in a project like R. You've arrived on the list and been
very critical of the work of others. Now there is nothing wrong with
being critical if it is
On Mon, Nov 10, 2008 at 9:32 PM, jim holtman [EMAIL PROTECTED] wrote:
Have you tried 'do.call(rbind,)'?
Thanks for the suggestion! This works nicely. Another member of the
list also suggested this approach (in private mail). Another useful
suggestion was matplot.
I'm still working on
Thanks for your help!
Strangely this code (it's not mine), seems to cause deadlock over my
cluster, even if every node of the cluster is tested working.
Anyway I tried a task pull method and that seems to work.
Thanks again,
Daniel
2008/11/7 Markus Schmidberger [EMAIL PROTECTED]
Hi,
there is
Hi list, Im trying to plot lines in the same graphic. There are lots of
similar topic on the list history. Ive read about xyplot (lattice) and
other ways to do that but I only got complex error messages, and wasnt able
even to start a decent R scrip. Well I have some paired information (each H
Philipp you actually solved my problem when you mentioned matplot function.
I hadn't read anything about it before, when you mentioned I searched and
I'm getting what I need, now it's just a question of minor adjustments.
Below is a simple solution that I will now improve.
Hi
[EMAIL PROTECTED] napsal dne 11.11.2008 11:32:27:
Berwin A Turlach wrote:
On Tue, 11 Nov 2008 09:27:41 +0100
Wacek Kusnierczyk [EMAIL PROTECTED] wrote:
but then it might be worth asking whether carrying on with misdesign
for backward compatibility outbalances guaranteed crashes
See ?matplot
On Tue, Nov 11, 2008 at 10:31 AM, mentor_ [EMAIL PROTECTED] wrote:
Hi,
I would like to plot the rows of a matrix.
Is there a better way as doing it in the following way?:
plot(matrix[1,], type=l)
for (i in 2:dim(matrix)[1]) {
lines(matrix[i,], type=l)
}
Cheers
--
Berwin A Turlach wrote:
On Tue, 11 Nov 2008 09:27:41 +0100
Wacek Kusnierczyk [EMAIL PROTECTED] wrote:
but then it might be worth asking whether carrying on with misdesign
for backward compatibility outbalances guaranteed crashes in future
users' programs, [...]
Why is it worth
Dear all
There is some package with generation of truncated multivariate normal
samples?
Best regards,
--
James Dean Oliveira dos Santos Jr.
MsC em Estatística, UNICAMP (2007)
BsC em Estatística, UFAM (2004)
[[alternative HTML version deleted]]
#how do I break these up into first two letters (RM), number, and then
the last part
#is there an easily accessible regex tutorial on the internet?
v = (structure(1:122, .Label = c(RM215Temp, RM215SpCond, RM215DO.Conc,
RM215Depth, RM215pH, RM215ORP, RM215Turbidity., RM215Battery,
RM215DO.,
On Tue, 11 Nov 2008 09:49:31 +0100
Wacek Kusnierczyk [EMAIL PROTECTED] wrote:
(for whatever reason a user may choose to have a column named '-b')
For whatever reason, people also jump from bridges. Does that mean
all bridges have an inherently flawed design and should be abolished?
Wait, then
I need to calculate a hierarchical clustering using the spearman metric. Is
there such functionality within R, and if so can you give me an example on
how to use it?
Thanks,
Bernd
[[alternative HTML version deleted]]
__
On Tue, 2008-11-11 at 11:08 +0100, Wacek Kusnierczyk wrote:
Gavin Simpson wrote:
d = data.frame(a = 1)
d$`-b` = 2
names(d)
# here we go
subset(d, select = -b)
# to b or not to b?
but -b is not the name of the column; you explicitly called it `-b` and
you should refer
Some of the uses of non-standard evaluation are undoubtedly a problem in
R. Probably the worst is in model.frame, because it is much harder to
work around. I have never used subset(,select=) and hence have never
been at risk of confusion (if you don't like how it works, I suggest you
do the
package Hmisc, function varclus, see ?varclus after loading the package.
Examples also in Harrell's book, Regression Modeling Strategies.
Bernd Jagla wrote:
I need to calculate a hierarchical clustering using the spearman metric. Is
there such functionality within R, and if so can you give me
Dear all,
let consider the following function:
Fun1 - function() {
library(lattice)
plot1 - 1:10~1:10
pl1 - xyplot(plot1)
return(pl1$call$x)
}
In R 2.5.0 (or older version) we have
Fun1()
plot1
but starting from R 2.5.1 until the latest R 2.8.0 we obtain instead
Fun1()
NULL
Ummm... as today is still Armistice day (in my time zone, anyway), maybe we
should call a truce and end this flame war...
Cheers,
Bert
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On
Behalf Of Berwin A Turlach
Sent: Tuesday, November 11, 2008 9:31 AM
To: Duncan
Hi all,
Thanks everyone for your advice. They have been helpful.
Just for the record, I am using ...
lapply(dir(path = filePath, pattern = ^test_), function(x){read.table(file
= paste(filePath, x, sep = ), sep = ,, header = TRUE) } )
to load the files
kind regards
Chibisi
On Tue, Nov 11,
Which can be simplified to:
paths - dir(path = filePath, pattern = ^test_, full = T)
lapply(paths, read.csv)
Hadley
On Tue, Nov 11, 2008 at 2:01 PM, [EMAIL PROTECTED] wrote:
Hi all,
Thanks everyone for your advice. They have been helpful.
Just for the record, I am using ...
On Tue, Nov 11, 2008 at 05:11:05PM -0200, Rodrigo Aluizio wrote:
Philipp you actually solved my problem when you mentioned matplot function.
I hadn't read anything about it before, when you mentioned I searched and
I'm getting what I need, now it's just a question of minor adjustments.
Below
Here's how far I've gotten. It's a start, but
I can't so far find a way to extract the actual
thing we want -- the bootstrap confidence intervals
on the predictions.
I apologize for not taking the time to go
read up on the boot library etc. etc. (I *have*
RTFM, but I haven't backtracked to
On 11/11/2008 8:53 AM, hadley wickham wrote:
On Mon, Nov 10, 2008 at 1:04 PM, Wacek Kusnierczyk
[EMAIL PROTECTED] wrote:
pardon me, but does this address in any way the legitimate complaint of
the rightfully confused user?
consider the following:
d = data.frame(a=1, b=2)
a = c(a, b)
z = a
#
On 11/11/2008 2:56 PM, Bert Gunter wrote:
Ummm... as today is still Armistice day (in my time zone, anyway), maybe we
should call a truce and end this flame war...
I haven't seen very many flames -- there have been disagreements, but
generally it's been quite civil. Certainly I don't
hadley wickham wrote:
On Tue, Nov 11, 2008 at 1:58 PM, Wacek Kusnierczyk
[EMAIL PROTECTED] wrote:
hadley wickham wrote:
On Tue, Nov 11, 2008 at 1:42 PM, Wacek Kusnierczyk
[EMAIL PROTECTED] wrote:
hadley wickham wrote:
| is.matrix| returns |TRUE| if |x| is a
On 12/11/2008, at 4:28 AM, Terry Therneau wrote:
I've read the back and forth this morning, and I have to side with
Vince.
Well, I've read back and forth this morning and I have to side
with Berwin Turlach --- whose postings were, I thought, extremely
well
# prepare some example data
x - 1:25
df - data.frame(w1=x, w2=x+0.5, h1=x^2, h2=3*x+1.3)
# use matplot to graph all data at once
matplot(df[,c('w1','w2')], df[,c('h1','h2')], type='l', lty=c('solid',
'dotted'))
Oh - and matplot uses different line types anyway, so specifying
lty is
I am attempting to created colClasses for several tables, then read only
specific columns. There are two different table layouts that I am working with.
If I use exclusively one layout, the script works perfectly, but if I mix the
layouts, it fails to grab the correct columns form layout that
For what it's worth, I found I had to
sudo apt-get install libatlas-base-dev
in order to get libf77blas.so installed on
my system. (Everything had been fine under
Hardy.) Is there a new dependency?
cheers
Ben Bolker
__
R-help@r-project.org
Rolf,
Fair comments, mostly.
By and large the difficulties arise only in obscure contexts, when
the user is trying to do something sophisticated.
But in the case at hand, the user was doing something simple, and got caught
when the function tried to be overly clever. That's rather
Hi,
I would like to plot the rows of a matrix.
Is there a better way as doing it in the following way?:
plot(matrix[1,], type=l)
for (i in 2:dim(matrix)[1]) {
lines(matrix[i,], type=l)
}
Cheers
--
View this message in context:
from:
http://www.royalsociety.org.nz/Site/news/media_releases/2008/honours08full.aspx#90569-36
Pickering Medal
To recognise excellence and innovation in the practical application of
technology.
Awarded by the Royal Society of New Zealand.
Awardee:
Associate Professor Ross Ihaka,
Hello,
A long overdue update to the 'trip' package is now on CRAN.
o New function forceConstraints() to impose the common problems found in
track data of duplicated records, and duplicated time stamps.
o Bug fix to speedfilter() which would never finish for trips of 3
locations.
o Clean up of
Hi,
I would like to simulate data with a binary outcome and a set of predictors
that are correlated. I want to be able to fix the number of event (Y=1) vs.
non-event (Y=0). Thus, I fix this and then simulate the predictors. I have 2
questions:
1. When the predictors are continuous, I can use
Figured out the problem reading the file. Csv files must be ftp'd as ascii and
xpt files as binary. However, both strategies result in the first few columns
being omitted. I'd like to check which variables are on the file, much like
proc contents in SAS, but I can't find the command to do
stephen sefick ssefick at gmail.com writes:
#how do I break these up into first two letters (RM), number, and then
the last part
#is there an easily accessible regex tutorial on the internet?
For regular expressions, the perl man pages at http://perldoc.perl.org/
perlre.html are quite good
Kenn Konstabel wrote:
On the other hand, while there may be ground to complain, it may be easier
to make your own version of subset.data.frame and advertise it to everyone:
sure, but:
a) it may actually increase the mess, and reduce portability
b) is still vulnerable to the
chibco at gmail.com writes:
I am trying to read a bunch of csv files using read.table() that are named
test_xx.csv where xx has no particular pattern. Is there a way
of reading all the files by specifying a truncated file name e.g. test_
with some wild card characters, or would I
On Tue, 11 Nov 2008 11:27:30 +0100
Wacek Kusnierczyk [EMAIL PROTECTED] wrote:
Berwin A Turlach wrote:
Why is it worth asking this if nobody else asks it? Most notably a
certain software company in Redmond, Washington, which is famous for
carrying on with bad designs and bugs all in the
I've read the back and forth this morning, and I have to side with Vince.
1. Functions that re-interpret their arguments are very dangerous. The
original question involved a well formed call to a function, which returned the
wrong answer. Bug, design flaw, whatever -- it's a mistake and
Rolf Turner r.turner at auckland.ac.nz writes:
[snip]
But I think that the best approach would be to include a warning in
the documentation of subset, to the effect: ``There are subtle and
difficult issues involved in the use of this function. If you don't
Hi all,
I have problem reading in a text file as follow.
The following data has not column header. I tried the following
command but failed,
temp-read.table(data.txt,header=F)
An error message stated that line 3 did not have 4 elements.
0.293290E-05 0.117772E-05 -0.645205
I am reading the comprehensive on-line documentation about msm.
The positive side is that it seems it has been designed for biomedical
statistics,
like Clinical Trials.
The bad side is that it does not seem to model observations sequences that
are not
independent but instead are autocorrelated, as
Hi all
I am manipulating a datafram which has 3 variables.Such as:
1 2 3
4 5 6
.
.
.
200 210 300
I also has a row index: index=c(100,200,250..300)
I want to find the sums of first 100 rows, then the sum from row 101 to row
200, then row 201 to row 250... the each end row is indicated
Hi
[EMAIL PROTECTED] napsal dne 11.11.2008 06:59:55:
Hi all
I am manipulating a datafram which has 3 variables.Such as:
1 2 3
4 5 6
.
.
.
200 210 300
I also has a row index: index=c(100,200,250..300)
I want to find the sums of first 100 rows, then the sum from row 101 to
On Tue, 11 Nov 2008 09:27:41 +0100
Wacek Kusnierczyk [EMAIL PROTECTED] wrote:
but then it might be worth asking whether carrying on with misdesign
for backward compatibility outbalances guaranteed crashes in future
users' programs, [...]
Why is it worth asking this if nobody else asks it?
Dear all,
I am trying to read a bunch of csv files using read.table() that are named
test_xx.csv where xx has no particular pattern. Is there a way
of reading all the files by specifying a truncated file name e.g. test_
with some wild card characters, or would I have to laboriously create
on 11/11/2008 03:39 PM phoebe kong wrote:
Hi all,
I have problem reading in a text file as follow.
The following data has not column header. I tried the following
command but failed,
temp-read.table(data.txt,header=F)
An error message stated that line 3 did not have 4 elements.
On Tue, Nov 11, 2008 at 12:27 PM, Wacek Kusnierczyk
[EMAIL PROTECTED] wrote:
it's certainly hard to design and implement a system of the size of r.
it's certainly easier to just complain rather than make a better tool.
but it would really be a pitiful world if all of us were just
developing,
The cenmle function is used to fit two sets of censored data and test if they
are significantly different. I can print out the results of the analysis on
the screen but can't seem to figure out how to access these results in R and
assign them to new variables, e.g., assign the slope calculated
On Windows,
you also can use Gabor Grothendieck's copydir which is part of
his utility set batchfiles available in the Other part of CRAN.
It copies all packages which are available in a source tree
but not available in a target tree from the source tree
to the target tree.
Then you still have to
And without wanting to be rude or anything, your opinion carries very
little weight in a project like R. You've arrived on the list and been
very critical of the work of others. Now there is nothing wrong with
being critical if it is constructive, and additionally with something
like R you
On 11/11/2008 5:00 AM, Berwin A Turlach wrote:
Radford Neal is also complaining on his blog
(http://radfordneal.wordpress.com/) about what he thinks are design
flaws in R. Why don't you two get together and design a good
substitute without any flaws? Or is that too hard? ;-)
I agree with
Try this:
sapply(dir(patt=^test_), read.table, sep = ;, header = TRUE)
On Tue, Nov 11, 2008 at 3:06 PM, [EMAIL PROTECTED] wrote:
Dear all,
I am trying to read a bunch of csv files using read.table() that are named
test_xx.csv where xx has no particular pattern. Is there a way
of
Is the matrix exponential available in some package?
The cannonical reference is Nineteen dubious ways to take the exponential of
a matrix. (Love that title)
Terry T.
__
R-help@r-project.org mailing list
Petr PIKAL wrote:
Well, if somebody does not care what is he/she doing then he/she should
stop immediately.
then many r users should perhaps stop using r.
but seriously, when one buys a complicated device one typically reads a
quick start guide, and makes intuitive assumptions about how
Hi all
I was reading a paper recently in which I was surprised to see an R package of
mine obviously used, without acknowledgement. Indeed, R itself was used
without any acknowledgment. So I contact the author about these issues, who
said (in part):
Regarding the R packages, I used the
Similarly, when I do plot(zph), B(t) is fairly non-constant.
This isn't inherently a problem for me. I don't need a hard single number
to characterize the shape of the excess risk. However, I'd like to be
able to say
something qualitative about the shape of the excess risk for the predictor.
On Tue, 11 Nov 2008 12:53:31 +0100
Wacek Kusnierczyk [EMAIL PROTECTED] wrote:
but seriously, when one buys a complicated device one typically reads
a quick start guide, and makes intuitive assumptions about how the
device will work, turning back to the reference when the expectations
fail.
Ben Bolker wrote:
Sometime soon when I have the time and energy I will start
campaigning for an additional drop argument to subset that
does what one expects (!!??) with subsetted factor variables ...
Not that one again! For at least one other value of one, the expectation
is the
Dear Rlist,
In my work I frequently use functions: HoltWinters() and predict().
Last week I have installed R 2.8.0 and a problem occurs:
# the data
serie-ts(c(3128,3444,3428,3803,3044,3427,3246,3505,3052,3613,3555,3675,3267,3601,3501,3855),
frequency = 4, start = c(1987, 1),end=c(1990,4))
serie
It has nothing to do with your UNIX system. The CRAN mirror at CMU is
currently not available. You may choose another mirror. For example,
install.packages('SASxport', repos = 'http://cran.cnr.berkeley.edu')
Regards,
Yihui
--
Yihui Xie [EMAIL PROTECTED]
Phone: +86-(0)10-82509086 Fax:
Maura E Monville maura.monville at gmail.com writes:
The bad side is that it does not seem to model observations sequences
that are not independent but instead are autocorrelated.
Correct me if I should be sitting on the firehose, but I am eager to hear
about any non-trivial Markov Process
Terry Therneau wrote:
Is the matrix exponential available in some package?
Multiple. At least Matrix and msm. One of Jim Lindsey's too, but I think
that's one of the more dubious ones.
The cannonical reference is Nineteen dubious ways to take the exponential of a
matrix. (Love that
Hi,
I try to export the outputs of rcorr into excel. but I got error
message,cannot coerce class rcorr into a data.frame. Actually i just need
export part of results of this analysis,e.g. p-values or stat-values.
Does anyone have sort of exprience before or you can help on how to export
Ok. I can see everything now. Thanks to everyone for the help. Sending this
as text to try to solve the line wrap problem. This is my hotmail account so I
don't know if this will work.
Date: Tue, 11 Nov 2008 14:41:57 +0100
From: [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
CC: [EMAIL
In 2004 Martyn Plummer said that functionality was available in
packages msm (as MatrixExp) and Lindsey's rmutils (as mexp)
David Firth also offered:
http://www2.warwick.ac.uk/fac/sci/statistics/staff/academic/firth/software/mexp
--
David Winsemius
On Nov 11, 2008, at 5:20 PM, Terry
Peter:
I was reading a paper recently in which I was surprised to see an R
package of mine obviously used, without acknowledgement. Indeed, R
itself was used without any acknowledgment. So I contact the author
about these issues, who said (in part):
Regarding the R packages, I used the
That's why (I think) it should be an *** optional argument
with default set to FALSE *** ... it's clear from the past traffic
on the list (I won't take the time to dig up the thread
references right now) that there is at the very least
a significant minority of users who expect the opposite,
On 12/11/2008, at 11:29 AM, Peter Dalgaard wrote:
Ben Bolker wrote:
Sometime soon when I have the time and energy I will start
campaigning for an additional drop argument to subset that
does what one expects (!!??) with subsetted factor variables ...
Not that one again! For at least one
Thank you for your prompt answer.
The breathing signal observations are the amplitude values as a function of
time and phase.
According to our model the hidden states are the different breathing types.
Subjects, whose respiratiion process is regular, are likely to breathe, keeping
the same
Hi all,
I'm wondering if you know a function that allow me to scan through a whole
text file, extracting words start with rs.
For example, below is format of the text file, I would like to extract those
words start with rs
ORDINARY REGRESSION: BEST LASSO PREDICTORS
PREDICTOR
1 - 100 of 132 matches
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