Hi, i have result from other program.
Original serie have 225 observing, but program use only 224.
the most domain frequencies are f1=1/224 f2=1/122 f3=1/74,66 f4=1/56
f5=1/24,88
When i know these frequencies a can do, new variable ,nubmers of variavle is
2*nubmer of frequencies:
t-1:225
I would have used
1) != rather than ! ... ==
2) !(names(my.df) %in% DrHorrible) since that handles NA names
(possible, but not easy to get) better.
and note that
3) subset(my.df, select = -DrHorrible) works.
On Mon, 23 Feb 2009, Petr PIKAL wrote:
Hi
r-help-boun...@r-project.org napsal
Dear R user,
I try to build R-2.8.1 on SunOS 5.9, and use following command:
CC=cc -xarch=v9
CFLAGS=-xO5 -xlibmil -dalign
F77=f95 -xarch=v9
FFLAGS=-xO5 -xlibmil -dalign
CXX=CC -xarch=v9
CXXFLAGS=-xO5 -xlibmil -dalign
FC=f95 -xarch=v9
FCFLAGS=-xO5
Excel stores times of the day as fractions of a day so I wrote a function to
convert the fraction to a number of seconds, extract the hours, minutes and
seconds and output it in ISO standard format (%H:%M:%S).
What about the 'colClasses' or 'dateTimeAs' argument in 'read.xls'
which gives back
Hi,
thanks for the link.
In the bottom part of the relevant section, you say:
Standard advice is to avoid using '=' when you mean '-'
Is this a formal, generally accepted (R community) advice, or does it
reflect you personal opinion?
Note I am not asking this question as to criticize by
Thanks, worked like a charm.
Greg.
On Feb 22, 1:58 pm, Gavin Simpson gavin.simp...@ucl.ac.uk wrote:
On Sun, 2009-02-22 at 20:52 +1100, Jim Lemon wrote:
Greg wrote:
I'm trying to write a simple function with a data parameter.
tfun - function(x, y, data = NULL) {
Hello,
This forum has been very helpful to me in the past, and I've run out of ideas
on how to solve my problem.
I had been using R and MySQL (and Perl) together for quite some time
successfully on my Windows XP machine. However, I recently had some problems
with MySQL (the ibdata file had
Hi
Is there any package in R that allow me to do IV probit, just like the
ivprobit command in stata.
or do i have to carry out the newey's two-step estimator myself?
Regards,
Julian
[[alternative HTML version deleted]]
__
Please do read the posting guide:
1) It says this is not the list for problems about compiled code.
2) It asks you to try the current patched version before posting.
(That works for me.)
If that is not the solution, the problem is in the lines before the
one you showed us, e.g. I get
Hi Philipp,
# Sorry - perhaps I wasn't being very clear. For example, creating the
data frame:
df-data.frame(y=rnorm(100), x=array(1:100))
# gives 2 elements, the last of which has a dim attribute
lapply(df, dim)
# I would like some way of changing the dim attribute to NULL for all
Since this topic came up, I've been thinking that
that sentence needs more work.
The standard is not from me -- I'm a bit more
agnostic than the statement although I personally
always use '-'. I'm thinking a revised version
might be something along the lines of:
Standard advice from most
On Sun, 2009-02-22 at 23:42 -0500, Alexy Khrabrov wrote:
I've had a very long file written out by R with write.table, with
fields of time values, converted from POSIXlt as.numeric. Among 2.5
million values, very few had 6 trailing zeroes, and those were output
in scientific notation as
Hi nicro,
There's a way that we use a lot in our projects which allows Java to call R
and capture the text/table/image outputs. In Java We call 'Rscript
exampleScript.R' via shell command. The R script should generate an XML file
when it finishes, describing what output was generated, then java
R/Finance 2009: Applied Finance with R
April 24 25, Chicago, IL, US
The first annual R/Finance conference for applied finance using R , the
premier free software system for statistical computation and graphics,
will be held this spring in Chicago, IL, USA on Friday April 24 and
On Mon, 23 Feb 2009, Patrick Burns wrote:
Since this topic came up, I've been thinking that
that sentence needs more work.
The standard is not from me -- I'm a bit more
agnostic than the statement although I personally
always use '-'. I'm thinking a revised version
might be something along
Cheers guys,
yeah, I was using this bit of code as my work around:
filter.col - which(names(my.df)!=DrHorrible)
my.df[filter.col]
but you guys had better solutions :-)
Is there an R wish list somewhere? I tried google but couldn't find a
specific location, just various threads here and
the man page for relational operators (see, e.g., ?'') says:
Binary operators which allow the comparison of values in atomic vectors.
Arguments:
x, y: atomic vectors, symbols, calls, or other objects for which
methods have been written.
it is somewhat surprizing that the
Thomas Lumley wrote:
Although it's probably true that most long-time R users use -, this
is at least in part because a long-time R user would initially have
had to use -, since = wasn't available in the distant past.
I would say that it's entirely a matter of taste -- the things that
Dear useRs,
the new R package exams provides Sweave-based automatic generation of
exams with multiple-choice questions and arithmetic problems. The
package is available from CRAN:
http://CRAN.R-project.org/package=exams
It includes a vignette giving an overview of the main design aims and
Peterko lanikpeter at gmail.com writes:
Original serie have 225 observing, but program use only 224.
the most domain frequencies are f1=1/224 f2=1/122 f3=1/74,66 f4=1/56
f5=1/24,88
When i know these frequencies a can do, new variable ,nubmers of variavle is
2*nubmer of frequencies:
t-1:225
Stefan Evert wrote:
Dear vQ,
vectors (can-be-considered-lists),
can you please stop repeating this nonsense? I don't think anybody
ever claimed that vectors can be considered list.
yes, it is nonsense. yes, there is one person who repeatedly made this
claim. please read the archives;
Dieter Menne wrote:
Peterko lanikpeter at gmail.com writes:
Original serie have 225 observing, but program use only 224.
the most domain frequencies are f1=1/224 f2=1/122 f3=1/74,66 f4=1/56
f5=1/24,88
When i know these frequencies a can do, new variable ,nubmers of variavle
is
Wacek Kusnierczyk Waclaw.Marcin.Kusnierczyk at idi.ntnu.no writes:
Thomas Lumley wrote:
Although it's probably true that most long-time R users use -, this
is at least in part because a long-time R user would initially have
had to use -, since = wasn't available in the distant past.
Ken Knoblauch wrote:
Wacek Kusnierczyk Waclaw.Marcin.Kusnierczyk at idi.ntnu.no writes:
Thomas Lumley wrote:
Although it's probably true that most long-time R users use -, this
is at least in part because a long-time R user would initially have
had to use -, since = wasn't
It's easier to read. Better machine-human interaction.
ergonomic: (esp. of workplace design) intended to provide optimum
comfort and to avoid stress or injury.
Quoting Wacek Kusnierczyk waclaw.marcin.kusnierc...@idi.ntnu.no:
Ken Knoblauch wrote:
Wacek Kusnierczyk
RExcel (the addin package for RExcel I wrote)
tries very hard to transfer dates and times
from Excel to R.
David Scott wrote:
I have used xlsReadWrite to read data from an Excel spreadsheet.
I had a problem with converting times of the day so that I could create
POSIXct date-time
can you please stop repeating this nonsense? I don't think anybody
ever claimed that vectors can be considered list.
yes, it is nonsense. yes, there is one person who repeatedly made
this
claim. please read the archives; specifically, [1]. note this
statement:
Note that any
Stefan Evert wrote:
can you please stop repeating this nonsense? I don't think anybody
ever claimed that vectors can be considered list.
yes, it is nonsense. yes, there is one person who repeatedly made this
claim. please read the archives; specifically, [1]. note this
statement:
Hi All,
Sorry to bother everyone again.Ofcourse Prof Ripley ,Yihui and Uwe had
replied to my email.But this segmentation fault error was not solved.I agree
with Prof Ripley,as he said my R and all other configurations,are very
old.But what i don't understand is ,i was able to run analysis till
Storer and Crowley (JASA 1985) presented an approach for approximating the
changes in maximum partial-likelihood parameter estimates for the Cox model
when a single observation is deleted. Is there an R implementation of this
approach?
I found that the approximation of Reid and Crepeau
Paul Murrell's book provides such an example using Grid (figure 5.22).
A short example is available on his website:
http://www.stat.auckland.ac.nz/~paul/grid/doc/moveline.pdf
It may be possible to use this in conjunction with gridBase.
baptiste
On 22 Feb 2009, at 20:43, Eik Vettorazzi
Dear all
I am very intersted in writing my own function to deal with some complicated
task, but I don't know how to start. I can't find detial material with
examples teaching me how to write my own functions. Can anyone help me and
recommend me some learning material?
Many Thanks
Ted
--
View
I have the following error:
library(RMySQL)
Error in fun(...) :
A MySQL Registry key was found but the folder C:\Program Files\MySQL\MySQL
Tools for 5.0\/. doesn't contain a bin or lib/opt folder. That's where we
need to find libmySQL.dll.
Error : .onLoad failed in 'loadNamespace' for
Dear Forum,
I´ve imported a prn file with read.table
(file(E:/test.prn),sep=\t,skip=3). My problem is now, that my file has a
complicated structure: It is not tabstop seperated, it looks like that:
JEAR JAN FEB MAR APR
1938154 912
19396 71014
Dear R users,
First of all, thank you for your help about goodness of fit tests.
I have another set of data and i am sure it is incomplete. I searched for
incomplete data analysis with R but I could not find any suggestion, or
method. Lets say (totally hypothetical situation) from a distribution
On Mon, Feb 23, 2009 at 05:18:28AM -0800, canadiangirl19 wrote:
My problem is now, that my file has a
complicated structure: It is not tabstop seperated, it looks like that:
JEAR JAN FEB MAR APR
1938154 912
19396 71014
19409
If there
Hello dear R-users,
I have a tricky problem of data manipulation with R. Although it seems
very easy, I can not solve it by myselves.
The problem is a variable in my dataset is usually be readed as
factor (variable mode), however I want it be a numeric one. I want
to know how can I define an
First of all when read in you can define the class of each column. It
sounds like you have a non-numeric in that column. If you are not
using factors, then putting 'as.is=TRUE' will make sure that they are
read in as characters. If you want to convert a column to numeric, do
the following:
That is covered in chapter 10 of the Intro to R document included in
the distribution.
On Mon, Feb 23, 2009 at 7:56 AM, tedzzx zengzhenx...@gmail.com wrote:
Dear all
I am very intersted in writing my own function to deal with some complicated
task, but I don't know how to start. I can't find
On 2/23/2009 7:56 AM, tedzzx wrote:
Dear all
I am very intersted in writing my own function to deal with some complicated
task, but I don't know how to start. I can't find detial material with
examples teaching me how to write my own functions. Can anyone help me and
recommend me some
Hi I have managed to do a paired t-test with a data set
i have 5 colums of data im dealing with
GENEÂ Â Â Â Â Â Â Â Â Â Â Â Â SampAÂ Â Â Â Â Â Â Â Â Â Â Â Â
SampBÂ Â Â Â Â Â Â Â Â Â Â Â Â SampCÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â
SampVehicle
ctcc                 Â
859Â Â
hello R users
strange behavior of the integrate function!
i assume this occurs because of the way in which the quadriture is set up! (any
comments.)
f=function(x){exp(-exp(-x)-5*x)/gamma(5)}
xx=seq(from=-20, to=20, length.out=1000)
plot(xx,f(xx),type=l)
integrate(f, lower=-Inf, upper= 1)
I´ve tried with:
write.fwf(test,file=E:/test.prn,widths=6),
but get the error:
Fehler in write.table(t(as.matrix(colnamesMy)), file = file, append =
append, :
unbenutzte(s) Argument(e) (widths = 6)
My matrix hast only one column (so it is a vector), and many rows, I want to
seperate
WK == Wacek Kusnierczyk waclaw.marcin.kusnierc...@idi.ntnu.no
on Mon, 23 Feb 2009 12:06:32 +0100 writes:
Thank you, Wacek,
though .. wrong mailing list
WK the man page for relational operators (see, e.g., ?'') says:
WK
WK Binary operators which allow the comparison of values
On Mon, Feb 23, 2009 at 06:24:33AM -0800, canadiangirl19 wrote:
write.fwf(test,file=E:/test.prn,widths=6),
but get the error:
Fehler in write.table(t(as.matrix(colnamesMy)), file = file, append =
append, :
unbenutzte(s) Argument(e) (widths = 6)
My matrix hast only one column (so
Yakub wrote:
I have the following error:
library(RMySQL)
Error in fun(...) :
A MySQL Registry key was found but the folder C:\Program Files\MySQL\MySQL
Tools for 5.0\/. doesn't contain a bin or lib/opt folder. That's where we
need to find libmySQL.dll.
Error : .onLoad failed in
When the limits are infinite, it is not a good idea to use large but
finite real numbers as approximate limits. It is best to use -Inf and/or
+Inf. See the examples on the help page. Sometimes, setting a more
stringent convergence criterion, i.e. decreasing rel.tol, helps, but it is
best to use
Aaron Barzilai wrote:
Hello,
This forum has been very helpful to me in the past, and I've run out of ideas
on how to solve my problem.
I had been using R and MySQL (and Perl) together for quite some time
successfully on my Windows XP machine. However, I recently had some problems
with MySQL
Hi,
I would like to try using a Support Vector Machine on a classification
problem that I'm dealing with. Does such a package exit in R?
Thanks
Meir
Meir Preiszler - Research Engineer
I t a m a r M e d i c a l Ltd.
Caesarea, Israel:
Tel: +(972) 4
Dear R users,
my dataframe looks like this
head(dat)
Id sex byear age
1 300 m 2003 50
2 300 m 2003 36
3 402f 2003 29
4 402f 2003 21
5 402f 2003 64
6 150 m 2005 43
...
...(where Id is just the Identification number of Individual, sex (male or
female), byear
say 'dat' is your data frame, then one way is the following:
f - factor(dat$Id, levels = unique(dat$Id))
dat$Number - unclass(f)
dat
I hope it helps.
Best,
Dimitris
clion wrote:
Dear R users,
my dataframe looks like this
head(dat)
Id sex byear age
1 300 m 2003 50
2 300 m 2003
Hi,
I use ksvm() in the kernlab package. If I recall correctly it's quite easy to
implement, and has a choice of different kernals.
Dan
Daniel Crouch
Research Student
Department of Medical Molecular Genetics
King's College London
8th Floor, Tower Wing
Guy's Hospital
London SE1 9RT
United
Hi,
I'm trying to use an offset with glm. According to the glm man
page
offset ... This should be NULL or a numeric vector of length either
one or equal to the number of cases. ...
but with the following example, I get an error if the offset is of length 1
c1 - structure(list(Contr =
The simplest to use is probably svm() in package e1071 or svmlight()
in klaR, both interfaces to well respected SVM code (but e1071
includes the C++ code it uses).
See also
help.search(support vector)
MAclinical::svm_x Classification based on support vector machines
Dear Bertina,
This is an interesting solutions to generate unique tests for every student,
and there are also some more possible approaches.
We also faced this problem and our solution was to adopt the Moodle e-learning
platform (http://www.moodle.org), create a large pool of exercises and
There's loads of packages in the Machine Learning R Task View:
http://cran.r-project.org/web/views/MachineLearning.html
for example: package e1071 (http://cran.r-project.org/web/packages/
e1071/index.html) has a function called svm()
On 23 Feb, 15:16, Meir Preiszler pm...@itamar-medical.com
THANKS so very much for your help (previous and future!). I have a two
follow-up questions.
1) You say that dispersion = 1 by definition dispersion changes from 1
to 13.5 when I go from binomial to quasibinomialdoes this suggest that
I should use the binomial? i.e., is the dispersion
I like the mi package, or when it's too large I use the Amelia package.
evrim akar wrote:
Dear R users,
First of all, thank you for your help about goodness of fit tests.
I have another set of data and i am sure it is incomplete. I searched for
incomplete data analysis with R but I
Dear Kingsford
Thank you very much for your suggestion. It turns out I had downloaded an old
version of raster. I also got a reply from the R-forge website with other
suggestions.
In case anybody using the R-help list is interested, here is the link:
I have used the insurance data from R library and I have 2 questions:
I use the following:
library(MASS)
data(Insurance)
m1=glm(Claims ~ District + Group + Age + offset(log(Holders)),data =
Insurance, family = poisson)
summary(m1)
Call:
glm(formula = Claims ~ District + Group + Age +
You may want to look at the examples for the cnvrt.coords function in the
TeachingDemos package for some ideas on how to draw lines between plots.
However, it is better to use the grconvertX and grconvertY functions rather
than the cnvrt.coords function (it will be deprecated one of these
right now I have a vector of about 1000 points. I'd like to iterate through
each of these points and and test if it is greater than a certain value and
if not, throw it out.
x=vector
y=empty vector
j=0
for i (0..length[vector])
if x[i] 10
y[j] = x[i]
j++
Thats
Hi there,
Try this:
x-your.vector
x[x10]
HTH,
Jorge
On Mon, Feb 23, 2009 at 12:31 PM, bioinformatics_guy
wwwhite...@gmail.comwrote:
right now I have a vector of about 1000 points. I'd like to iterate through
each of these points and and test if it is greater than a certain value and
if
In the Insurance dataset both Age and Group are ordered factors so the default
encoding for them is orthogonal polynomials (assuming that the user has not
changed the default). In the output below the .L indicates that line is for
the Linear piece of the encoding or the Linear contrast on the
You are asking about support software for a book, and the book
contains the answers And it should be given due credit.
On Mon, 23 Feb 2009, choonhong ang wrote:
I have used the insurance data from R library and I have 2 questions:
I use the following:
library(MASS)
data(Insurance)
Hi,
I posted a question a few days ago and got extremely well response.
https://stat.ethz.ch/pipermail/r-help/2009-February/188225.html. Now I
have a somewhat related question:
I have a correlation matrix of about 3000 items, with 1 on diagonal (
for example, cor.mat -
Dear R-users,
I coded two equivalent ways to perform (in a simplified version)
some matrix multiplications I would like to use in a more general
framework.
In the first case I used Kronecker product and vectorization of a
certain matrix. This approach takes less time, but, as you may
You might want to compare the performance of your version to the kronecker
method of Matrix (Matrix package) that has appropriate versions for sparse
matrices etc.
-Christos
-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of
Martin Maechler wrote:
WK == Wacek Kusnierczyk waclaw.marcin.kusnierc...@idi.ntnu.no
on Mon, 23 Feb 2009 12:06:32 +0100 writes:
Thank you, Wacek,
though .. wrong mailing list
apologies. i was actually asking for explanation, assuming that it
might be my
Hi Dear Alex, A few years ago you sent this email to R list:
Hello,
I was wondering how one could obtain LSM for fixed factors in a
mixed-effect model using lme. In other words, if I have model such as:
model-lme(yield~period+treatment+period*treatment,
data=data,random=~1|cow)
how can I get LSM
Hi Ted,
I strongly recommend a book: S programming by W.N Venables and B.D Ripley ISBN:
0387-989668
It is easy to read. I love this book so much. Maybe someone has better idea.
Super
Chunhao
Date: Mon, 23 Feb 2009 04:56:18 -0800
From: zengzhenx...@gmail.com
To:
Hello -
How do I simulate multivariate ARIMA data?
I am familiar with the arima.sim function, which I have used several
times to generate univariate data, but when I type help(arima.sim), the
information I get back reveals nothing about possible multivariate
options.
Please reply when you get a
Hi Bernardo,
the systemfit package cannot be used to estimate a system of logistic
equations.
Arne
On Friday, 20. February 2009 05:19:40, Bernardo Rangel Tura wrote:
Hi R-masters
I need yours help about a problema in one of may ongoing researchers.
In my research the subjects (20 in
I am trying to display a set of listboxes in a systematic manner.
For instance, I display Listbox 1, let the user pick the parameters of
interest then destroy it.
Now I display Listbox 2
and so on.
So in essence I would like to create listboxes in a for -loop.
When I try to loop - all the
Look at the tkwait.window function as one possibility.
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-
project.org] On Behalf Of
I have what should be a simple question but I've been unable to solve
it in a reasonable length of time. For example with data like
ge
product response scenario
1wine5 base
2 steel 10 base
3 sugar4 base
4wine -10 policy
5 steel1
If I understand your example correctly, I think you're looking for a
dot-chart like this one from the R Graph Gallery:
http://addictedtor.free.fr/graphiques/RGraphGallery.php?graph=150
You'd just need to replace the green/blue circles with X's and O's,
respectively. Provided you reorganize your
Date: Mon, 23 Feb 2009 14:03:07 -0500 (EST)
From: otu...@clemson.edu
Sender: r-help-boun...@r-project.org
Importance: Normal
Precedence: list
User-Agent: SquirrelMail/1.4.13
Hello -
How do I simulate multivariate ARIMA data?
You can use package dlm. There is a function --
Hi R users,
Is there an easy way in R to generate the results table below using table 1
and the formula (simplified version of the real problem)? It would be easy
if I knew the R equivalent of SAS's retain function, but could not find one.
Thanks in Advance for any help!
table1:
ID X2
Consider the following little benchmark
require(Matrix)
tmp - Matrix(c(rep(1,1000),rep(0,9000)),ncol=1)
ind - sample(1:1,1)
system.time(tmp[ind,])
user system elapsed
0.004 0.001 0.005
ind - sample(1:1000,1,replace=TRUE)
system.time(tmp[ind,])
user system elapsed
Dear Pele,
Probably not the best way to proceed but it works:
X-read.table(textConnection(ID X2
1.001.00
2.000.00
3.001.00
4.003058
5.000.00
6.006.00),header=TRUE)
closeAllConnections()
X
x3-0
for(i in 2:(nrow(X)+1)) x3-c(x3, X$X2[i-1]+0.24*x3[i-1])
X$x3-x3[-1]
X
Here's a way without a loop:
x - read.table(textConnection(ID X2
1.001.00
2.000.00
3.001.00
4.003058
5.000.00
6.006.00),header=TRUE)
closeAllConnections()
x$X3 - append(x$X2, 0, 0)[-nrow(x)]
x$X4 - as.matrix(x[,2:3]) %*% c(1, 0.24)
x
ID X2 X3 X4
1 1
Niels Richard Hansen wrote:
Consider the following little benchmark
require(Matrix)
tmp - Matrix(c(rep(1,1000),rep(0,9000)),ncol=1)
ind - sample(1:1,1)
system.time(tmp[ind,])
user system elapsed
0.004 0.001 0.005
ind - sample(1:1000,1,replace=TRUE)
How about:
x3 - cumsum( x2* 0.24^(5:0) ) / 0.24^(5:0)
with the 5 replaced by the length -1 for the more general case.
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111
-Original Message-
From:
Hi,
In my analysis of impacts of insecticide-treated bednets on malaria, I
look at the relationship between malaria incidence and mosquito
behaviors. The condensed data set is copied here. Ordinary regression
(lm) shows that Incidence was negatively related to Mortality. This
makes sense because
You did not read the tree graph correctly. Mortality is **not** positively
related to incidence. You're reading the tree backwards. Read the output
of summary() on your rpart fit object for clarity.
-- Bert Gunter
Genentech
-Original Message-
From: r-help-boun...@r-project.org
Hi
I am estimating the following coxph function with stratification and
frailty where each person had multiple events.
m-coxph(Surv(dtime1,status1)~gender+cage+uplf+strata(enum)+frailty(id),xmodel)
head(xmodel)
id enumdtime status gender cage uplf
1 10086661
Hi Bert,
Thanks for your prompt response. Yeah, summary() shows the correct
answer, seemingly, plot() and text() reverse the direction of = sign, a
bit confusion.
Weidong Gu
-Original Message-
From: Bert Gunter [mailto:gunter.ber...@gene.com]
Sent: Monday, February 23, 2009 5:14 PM
Hi Greg - this is perfect - Thank You!
Also, thanks to everyone for the other suggestions
Greg Snow-2 wrote:
How about:
x3 - cumsum( x2* 0.24^(5:0) ) / 0.24^(5:0)
with the 5 replaced by the length -1 for the more general case.
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data
Hi there,
I am pretty new to R. Actually I started using it yesterday. I have two
questions:
1. Suppose I have a-c(1:10) (or a-array(c(1:10),dim=c(1,10)))
and I want to end up with vector b=[0 0 0 0 0 1 1 1 1 1]. i.e. I want to
substitute alla elements that are 5 with 0 and 5 with 1.
I am trying to load a .csv file in the R commander, but the output window
always showed that Error: bad restore file magic number(file may be
corrupted)--no data loaded. Did any one know why does this happen? btw, I
can open this file in commander by open script file.
Many thanks!
--
View this
Hi all, thanks in advance for the help.
Can someone explain to me the following result, and what I'm doing wrong
in the second case?
seq(-43.7,-43.69,.001)[3]==-43.698
[1] TRUE
seq(-43.7,-43.69,.001)[2]==-43.699
[1] FALSE
seq(-43.7,-43.69,.001)[1]==-43.7
[1] TRUE
Dan
Well, I found out part of the confusion:
The modern versions of MatLab renamed their function from 'step' to
'stepz' .
Stepz(num,den) provides a calculation of the time-response to a step
function based on the system state equation defined by the num and den
coefficients.
So, is there
On 24/02/2009, at 2:29 PM, Daniel G Polhamus wrote:
Hi all, thanks in advance for the help.
Can someone explain to me the following result, and what I'm doing
wrong
in the second case?
seq(-43.7,-43.69,.001)[3]==-43.698
[1] TRUE
seq(-43.7,-43.69,.001)[2]==-43.699
[1] FALSE
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of Duncan Murdoch
Sent: Sunday, February 22, 2009 4:13 PM
I think this was posted to the wrong list, so my followup is going to
R-devel.
On 22/02/2009 3:42 PM, Stavros Macrakis wrote:
Inspired by
Hello and thanks in advance for any advice.
I am not clear how, in practice, the multinom() function in nnet and the
multinomial() function in VGAM differ in terms of interpretation. I
understand that they are fit differently. Are there certain scenarios where
one is more appropriate than the
Dear R users:
Analysis of the impact of a time-dependent covariate (GVHD or use of
steroid after bone marrow transplantation) on two competing endpoints (invasive
fungal infection and death) is frequently encountered in the setting of BMT
data. Coxph package can be used as the following:
Dear R users:
Analysis of the impact of a time-dependent covariate (GVHD or use of
steroid after bone marrow transplantation) on two competing endpoints (invasive
fungal infection and death) is frequently encountered in the setting of BMT
data. Coxph package can be used as the following:
Thanks Jeff, that was exactly the problem. When I unzipped the version at the
page below for my version of MySQL (5.1), it worked fine. The version I
downloaded through install.packages() must have been for 5.0.
Thanks so much for the help and quick response,
Aaron
Λεωνίδας Μπαντής wrote:
1. Suppose I have a-c(1:10) (or a-array(c(1:10),dim=c(1,10)))
and I want to end up with vector b=[0 0 0 0 0 1 1 1 1 1]. i.e. I want to
substitute alla elements that are 5 with 0 and 5 with 1.
I think you mean =5, not 5. In that case, try this:
b -
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