Goodness to fit can be checked on looking at the PACF and/or ACF of estimated
residuals. Also you might want to see how valid the normality assumption is
on them.
Generally joint normality is assumed on the data, so that innovation are
multivariate white noise process.
Luna Moon wrote:
Hi
On 8/21/2009 3:04 PM, David Winsemius wrote:
On Aug 21, 2009, at 3:41 PM, Alexander Shenkin wrote:
Thanks everyone for their replies, both on- and off-list. I should
clarify, since I left out some important information. My original
dataframe has some numeric columns, which get changed to
Peng Yu schreef:
Hi,
It is easy to understand the types vector and frame.
But I am wondering why the type factor is designed in R. What is the
advantage of factor compare with other data types in R? Can somebody
give an example in which case the type factor is much better than
other data
On Sat, 22-Aug-2009 at 10:00PM -0500, Peng Yu wrote:
| Hi,
|
| It is easy to understand the types vector and frame.
Types of what? Class of object? Doesn't seem likely. What do you
mean by frame? It's a function, and a vector can be a factor,
numeric, logical or character (and probably a
On Fri, 2009-08-21 at 20:59 -0700, Bin1aya wrote:
Dear All,
I do not know how to perform Mann kendall test with climate data. Using
Rclimdex i have got trends of temperature and precipitation. Now I would
like to know how significant is trend at 95% level of significance. So
please suggest
On Fri, 2009-08-21 at 18:27 -0400, Kendra Walker wrote:
I am trying to figure out how to apply a loglog link to a binomial
model (dichotomous response variable with far more zeros than ones).
I am aware that there are several relevant posts on this list, but I
am afraid I need a
I want to draw two density functions on the same graph. One of the densities is
produced by density() and the other one is produced by logspline() . I want to
show one of them by solid line and the other one by dashed line, but both of
them on one graph.
Sorry if this is plane and trivial, I
Its not being stored as an integer. Its being stored as a double.
If it were stored as an integer you would not get the e:
as.character(10L)
[1] 10
as.character(as.integer(10))
[1] 10
On Sat, Aug 22, 2009 at 7:13 PM, Dajiang J. Liudajiang@gmail.com wrote:
my email
assaed...@yahoo.com
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R-help@r-project.org mailing list
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and
sendona essile wrote:
I want to draw two density functions on the same graph. One of the densities is
produced by density() and the other one is produced by logspline() . I want to
show one of them by solid line and the other one by dashed line, but both of
them on one graph.
Sorry if this is
What does the command
c:\progra~1\R\R-2.9.1\bin\Rgui --vanilla
do?
At first I thought that I could run it from R. But then it did not work.
I'm using a mac, and I don't know how access MSDOS in a mac. I actually
installed R on the pc and tried to run the command from MSDOS and it also
didn't
Hi,
In R base graphics, the function mtext can be used to add text to the
margins of a plot. This is very useful for adding notes (such as data
source, sample size, etc.) to the bottom of a graph. How can such notes
be added to the bottom of a graph when using ggplot2?
Thanks,
Walt
--
nsl is not available on all platforms since it is located in
.../Rsources/src/library/utils/R/unix
Please make use of OS functionality in order to do hostname lookup.
Best,
Uwe Ligges
Janko Thyson wrote:
Dear list,
today I stumbled across the function „nsl()” for the first time in order to
The posting guide asks you to:
PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Please also do the latter.
Best,
Uwe Ligges
Bin1aya wrote:
Dear All,
I am trying for indices calculation in
Since I have been clueless about gains chart in Google and found your
question message within the first two pages of output, I have the
impression that not very many other readers hearded about it. Reading
fruther on shows that it might be very related to ROC curves and AUC
calculations,
On Aug 23, 2009, at 2:47 AM, Alexander Shenkin wrote:
On 8/21/2009 3:04 PM, David Winsemius wrote:
On Aug 21, 2009, at 3:41 PM, Alexander Shenkin wrote:
Thanks everyone for their replies, both on- and off-list. I should
clarify, since I left out some important information. My original
Hi;
I have a very basic question about reading element from dataframe T (2
dimentional)
I want to extract element T[1,1] as a string. T[1,1] returns an element with
names, means header.
this i cannot compare with any other list of strings.
how can i fix that?
Thanks
Rami
Hi;
I have a very basic question about reading element from dataframe T (2
dimentional)
I want to extract element T[1,1] as a string. T[1,1] returns an element with
names, means header.
this i cannot compare with any other list of strings.
how can i fix that?
Thanks
Rami
On Aug 23, 2009, at 7:39 AM, rami jiossy wrote:
Hi;
I have a very basic question about reading element from dataframe T
(2 dimentional)
I want to extract element T[1,1] as a string. T[1,1] returns an
element with names, means header.
this i cannot compare with any other list of
On 8/23/2009 9:58 AM, David Winsemius wrote:
I still have problems with this statement. As I understand R, this
should be impossible. I have looked at both you postings and neither of
them clarify the issues. How can you have blanks or spaces in an R
numeric vector?
Just because I search
On Aug 22, 2009, at 7:06 PM, Peng Yu wrote:
Hi,
I see the following package that can help me call perl from R. But the
webpage is about 3 years old. I am wondering what the latest package
that can help calling perl from R.
http://www.omegahat.org/RSPerl/
Regards,
Peng
RSPerl provides the
On Aug 22, 2009, at 7:16 PM, Peng Yu wrote:
Hi,
http://cran.r-project.org/doc/Rnews/Rnews_2003-3.pdf
There is information on how to debug R. But since it is fairly old, I
am wondering what the currently best way for debugging R script.
Regards,
Peng
There are various tools available that
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R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Data Analytics Corp. wrote:
Hi,
In R base graphics, the function mtext can be used to add text to the
margins of a plot. This is very useful for adding notes (such as data
source, sample size, etc.) to the bottom of a graph. How can such notes
be added to the bottom of a graph
Is it possible to change the behavior of RGui/RConsole under MS
Windows so that, if you submit a bunch of commands from a script
window, when they've finished, focus is given to the Console, and not
(as now) to the script?
Philip A. Viton
City Planning, Ohio State
Dear all,
I am trying to run the dudi functions in R (ade4 package) to run an
ecological analysis. In particular it is a traits analysis. I am having
problems at understanding how to make the table to be read prperly by the
software. Example is given in the link below
On Aug 23, 2009, at 10:14 AM, Brittany Hall wrote:
Hello,
I am fairly new to R and having a problem with the lme command. I
have searched on forums, read the Fox 2002 chapter, and R help, but
the suggestions that I have tried have not helped me.
My data file is called Acsdata.
This is
I am still running 2.9.0 and came across a package that was built with 2.9.1. I
got a warning upon loading the package.
I tried to launch a function from such a package. It seems to hang up. I can't
believe it takes forever.
I am resolved to upgrade my R version to the newest one. But on a
On Aug 23, 2009, at 11:28 AM, mau...@alice.it wrote:
I am still running 2.9.0 and came across a package that was built
with 2.9.1. I got a warning upon loading the package.
I tried to launch a function from such a package. It seems to hang
up. I can't believe it takes forever.
I am resolved
Hi all,
I am looking for study resources for (financial) time series? Hopefully I
could find video lectures then it will reduce the learning curve.
Thanks a lot!
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R-help@r-project.org mailing list
Hi,
This concerns lrm in the Design package, which I need for the clustered
errors option with panel data.
I have created a variable (using sign()) that has values -1, 0, and 1
(and some NAs). call this variable x3. lrm does not like
t = lrm(y ~ x1 + x2 + I(x3==-1) + I(x3==1),
On Sat, 22 Aug 2009, Noah Silverman wrote:
And, of course that leads me to another question...
With svm {e1071} I can ask the predict function to give me probabilities
with lrm {Desigh} I can ask the predict function to give me probabilities
I can't see how to do this with clogit.
Would
On Sun, 23 Aug 2009, Charles C. Berry wrote:
On Sat, 22 Aug 2009, Noah Silverman wrote:
And, of course that leads me to another question...
With svm {e1071} I can ask the predict function to give me probabilities
with lrm {Desigh} I can ask the predict function to give me probabilities
Looks like nobody answered so far?
If I understood it correctly, you want something like:
x - 1:36
plot(x, log(x, 1.1), xlab=Number of months, ylab=Visits(1000),
main=webpage visits)
helper.lines - function(x, y, lty=2, col=red, text=TRUE){
segments(par(usr)[1], y, x, y, col=col,
Greg Hirson wrote:
I have noticed an interesting behavior when comparing how the base
plot() function deals with a data argument that downloads data from the
internet vs. how xyplot() in lattice performs the same task.
The goal is to plot hourly temperature data. The data is downloaded and
Looks like nobody answered so far.
If you want help: It is a good idea to say which package you are talking
about. In a clean R session I get:
specprop
Error: object 'specprop' not found
spec
Error: object 'spec' not found
hence no idea which functions from which package we are talking
Since it looks like nobody answered so far:
Your code is not reproducible, we do not have rfc, y, zVals nor NoCols.
You could also try to place a screenshot somewhere on a webpage
including the info about the settings of the corresponding viewer.
Best,
Uwe Ligges
Andreas Fischlin wrote:
Renaud Gaujoux wrote:
Hi,
I'm trying to install Chipster (for microarray analysis:
http://chipster.csc.fi/), which expressly relies on R 2.6.1 (for now).
So I'd like to install automatically (i.e. using a 'install.packages' like
function) the last version of a package compatible with the
Looks like nobody answered so far:
Kelvin Lam wrote:
Hi group,
I have the following error code after submitting library(wordnet) in a
standalone pc. rJava is already in place.
Please read the posting guide and tell us:
- Which version of R?
- Which version of wordnet?
- Which version of
I have suppose a matrix like that
mat - matrix(1:21, 7)
mat
[,1] [,2] [,3]
[1,]18 15
[2,]29 16
[3,]3 10 17
[4,]4 11 18
[5,]5 12 19
[6,]6 13 20
[7,]7 14 21
From this matrix, I want to create a vector like tha :
c(mat[7,],
James Fearon wrote:
Hi,
This concerns lrm in the Design package, which I need for the clustered
errors option with panel data.
I have created a variable (using sign()) that has values -1, 0, and 1
(and some NAs). call this variable x3. lrm does not like
t = lrm(y ~ x1 + x2 + I(x3==-1) +
On Aug 23, 2009, at 2:37 PM, Bogaso wrote:
I have suppose a matrix like that
mat - matrix(1:21, 7)
mat
[,1] [,2] [,3]
[1,]18 15
[2,]29 16
[3,]3 10 17
[4,]4 11 18
[5,]5 12 19
[6,]6 13 20
[7,]7 14 21
From this matrix, I want
No no, I actually want following result :
7, 14, 21, 6, 13, 20, 5, 12, 19,
David Winsemius wrote:
On Aug 23, 2009, at 2:37 PM, Bogaso wrote:
I have suppose a matrix like that
mat - matrix(1:21, 7)
mat
[,1] [,2] [,3]
[1,]18 15
[2,]2
Bogaso wrote:
No no, I actually want following result :
7, 14, 21, 6, 13, 20, 5, 12, 19,
c(t(mat[7:1,])) then.
David Winsemius wrote:
On Aug 23, 2009, at 2:37 PM, Bogaso wrote:
I have suppose a matrix like that
mat - matrix(1:21, 7)
mat
[,1] [,2] [,3]
On Sun, Aug 23, 2009 at 8:53 PM, Bogasobogaso.christo...@gmail.com wrote:
No no, I actually want following result :
7, 14, 21, 6, 13, 20, 5, 12, 19,
How about this?
x = c()
for (i in 7:1) x = c(x,mat[i,])
Guess that would do the trick.
Best,
Michael
--
Michael
On Aug 23, 2009, at 2:53 PM, Bogaso wrote:
No no, I actually want following result :
7, 14, 21, 6, 13, 20, 5, 12, 19,
Ooops. That is what I thought you wanted, but I didn't check very
carefully, did I?
c(apply(mat[7:1,],1,I) )
# the I() function just returns
The problem with David's proposal is revealed by:
mat[7:1,]
# [,1] [,2] [,3]
# [1,]7 14 21
# [2,]6 13 20
# [3,]5 12 19
# [4,]4 11 18
# [5,]3 10 17
# [6,]29 16
# [7,]18 15
which simply reverses the rows. Then:
There is another matrix strategy that succeeds, although it is
clearly less economical that the transpose approach:
matrix(mat[7:1, ], ncol=nrow(mat), byrow=TRUE) # will transpose the
matrix
I offer this only as a reminder that the byrow= parameter is available
when appropriate.
--
FWIW, the R homepage says, R 2.9.2 Release Candidates will appear August
17-24. Final release is scheduled for 2009-08-24. (Tomorrow?) Maybe a
short upgrade delay is in order? ;-)
On Windows, I routinely install new versions without removing the previous
version. They always seem to coexist
Thanks for all the replies!
Steve: I don't know whether my suggestion is a good one. I'm quite new
to programming, have absolutely no experience and this was the only one
I could think of. :-) I'm not sure whether I'm able to put your tips
into practice, unfortunately I had no time for much
On Aug 23, 2009, at 4:14 PM, Michael Kogan wrote:
Thanks for all the replies!
Steve: I don't know whether my suggestion is a good one. I'm quite
new to programming, have absolutely no experience and this was the
only one I could think of. :-) I'm not sure whether I'm able to put
your
Great ! Then I can wait a couple more days.
Anyway, I do not need or want more than one R version at a time. So my question
is:
How can I avoid having coexisting R versions when I install a new one ?
Thank you,
Maura
-Messaggio originale-
Da: Robert Baer [mailto:rb...@atsu.edu]
as.vector(t(mat[7:1,]))
On Aug 23, 2009, at 9:35 PM, David Winsemius wrote:
There is another matrix strategy that succeeds, although it is
clearly less economical that the transpose approach:
matrix(mat[7:1, ], ncol=nrow(mat), byrow=TRUE) # will transpose
the matrix
I offer this only
Hi,
On Sun, Aug 23, 2009 at 4:14 PM, Michael Koganmichael.ko...@gmx.net wrote:
Thanks for all the replies!
Steve: I don't know whether my suggestion is a good one. I'm quite new to
programming, have absolutely no experience and this was the only one I could
think of. :-) I'm not sure whether
Dear list,
I have a two character vector with two different values in them (two
each, that is). Naturally, when I use these vectors as grouping
factors in a lattice plot, I get four panels.
Now, one of the possible four combinations will never have data, so
one panel will always be empty. So now
Hi,
My english isn't briliant and my problem is very dificult to descripe but I
try ;)
My first question is: May I write loop for like this or similar - for (i
in sth : sth[length(sth)], k in sth else : length(sth else) ) - I'd like
to have two independent conditions in the same loop for.
My
Ruey Tsay's Analysis of Financial Time Series is an excellent resource,
along with the associated R package FinTS (
http://lib.stat.cmu.edu/R/CRAN/web/packages/FinTS/). You can also find the
courses that Tsay teaches at U. Chicago on his homepage, such as this recent
course:
Fredrik Karlsson wrote:
Dear list,
I have a two character vector with two different values in them (two
each, that is). Naturally, when I use these vectors as grouping
factors in a lattice plot, I get four panels.
Now, one of the possible four combinations will never have data, so
one
Dear R users,
I have a matrix a and a classification vector b such that
str(a)
num [1:50, 1:80]
and
str(b)
Factor w/ 3 levels cond1,cond2,cond3
I'd like to do an anova on all 80 columns and record the F statistic for
each test; I currently do this using
f.stat.vec -
On Aug 23, 2009, at 4:34 PM, Grzes wrote:
Hi,
My english isn't briliant and my problem is very dificult to
descripe but I
try ;)
My first question is: May I write loop for like this or similar -
for (i
in sth : sth[length(sth)], k in sth else : length(sth else) ) -
I'd like
to have
Oliver Bandel oliver at first.in-berlin.de writes:
Hello,
I want to read jpeg-files to create 2D-histograms of them.
Is there a package available for this binary-input issue?
Ciao,
Oliver
Ok, sorry, I now found something in the archive:
the rimage-package might be the right
Oliver Bandel oliver at first.in-berlin.de writes:
Hello,
I want to read jpeg-files to create 2D-histograms of them.
Is there a package available for this binary-input issue?
Ciao,
Oliver
In install.packages(rimages) : package ‘rimages’ is not available
OK, it's rimage,
Ok, now we can talk.
1. covariates: coon
Your model specification put coon sequentially last, effectively testing
the hypothesis that the slope associated with coon, after
adjusting for all the factors, is zero.
My model place coon sequentially first, effectively testing the
hypotheses that
Dear R users,
I am using subset function to filter out specific conditions and would
like to use the value of subsetted argument as a name of an object.
Specifically, from the following statement:
a - subset(dat, dat$x == A dat$xx == 1 dat$xxx == AB dat$y
== B dat$yy == 2)
I would to
On Aug 23, 2009, at 10:12 PM, David Winsemius wrote:
On Aug 23, 2009, at 9:56 PM, Steven Kang wrote:
Dear R users,
I am using subset function to filter out specific conditions and
would
like to use the value of subsetted argument as a name of an object.
Specifically, from the following
You might find the article Computing Thousands of Test Statistics
Simultaneously in R in
http://stat-computing.org/newsletter/issues/scgn-18-1.pdf helpful.
Hadley
On Sun, Aug 23, 2009 at 7:55 PM, big permiebigper...@gmail.com wrote:
Dear R users,
I have a matrix a and a classification vector
I have a long list of flags with relative values to print out.
If I draw it all on a panel of a (2x2) plot it gets chopped at the bottom.
I wonder whether it is possible to plot it on two columns. Something like:
Flag1 Value1Flag4 Value4
Flag2 Vauel2Flag5 Value5
Flag3 Value3
David, apreciate for your help.
However, the result is not what I was expecting.
Following on from your code, for example say the input is:
a - data.frame(x=rep(1:4,2), y=rep(4:7,2), xx=rep(8:11,2),
xxx=rep(12:15,1))
x y xx xxx
1 1 4 8 12
2 2 5 9 13
3 3
On Mon, 24 Aug 2009, big permie wrote:
Dear R users,
I have a matrix a and a classification vector b such that
str(a)
num [1:50, 1:80]
and
str(b)
Factor w/ 3 levels cond1,cond2,cond3
I'd like to do an anova on all 80 columns and record the F statistic for
each test; I currently
Hi everyone,
I want to plot some pattern. For example, I have some coding as below,
plot(0:11,type=n)
polygon(c(6,8,10), c(7,3,5),bor=6)
polygon(c(2,4,6), c(5,3,7),bor=6)
polygon(c(6,10,8), c(7,9,11),bor=6)
polygon(c(2,6,4), c(9,7,11),bor=6)
This coding will give me four triangles, but how to
On Aug 23, 2009, at 10:51 PM, Steven Kang wrote:
David, apreciate for your help.
However, the result is not what I was expecting.
Following on from your code, for example say the input is:
a - data.frame(x=rep(1:4,2), y=rep(4:7,2), xx=rep(8:11,2),
xxx=rep(12:15,1))
x y xx
On Aug 23, 2009, at 10:51 PM, Steven Kang wrote:
David, apreciate for your help.
However, the result is not what I was expecting.
Following on from your code, for example say the input is:
a - data.frame(x=rep(1:4,2), y=rep(4:7,2), xx=rep(8:11,2),
xxx=rep(12:15,1))
x y
On Aug 23, 2009, at 11:29 PM, Hemavathi Ramulu wrote:
Hi everyone,
I want to plot some pattern. For example, I have some coding as below,
plot(0:11,type=n)
polygon(c(6,8,10), c(7,3,5),bor=6)
polygon(c(2,4,6), c(5,3,7),bor=6)
polygon(c(6,10,8), c(7,9,11),bor=6)
polygon(c(2,6,4),
On Aug 23, 2009, at 7:30 AM, rami jiossy wrote:
Hi;
I have a very basic question about reading element from dataframe T
(2 dimentional)
I want to extract element T[1,1] as a string. T[1,1] returns an
element with names, means header.
this i cannot compare with any other list of
On Aug 24, 2009, at 12:24 AM, Steven Kang wrote:
Hi David,
I have another question regarding the R statement you have provided
which is:
for (zz in unique(a$xx) ) assign( paste(sub.a, zz, sep=.),
sum(subset(a, xx==zz)$xxx) )
If the xx variables were characters instead of
Hello,
I'd like to ask: going on from Richard McElreath's coursework in which he
says(my paraphrase) basically that the constancy with which a parameter
appears satisfactory with respect to its standard error over a series of
different models is a good measure of its usefulness, where is the
When we ran a regular ANOVA we showed that both mice and raccoons respond
positively to cover. So we decided to use raccoons as a co-variate because
those are mouse predators and their presence per se could explain part of
the variation on mice activity. That is the reason why I'm running this
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