Dear all,
I would like to underline only the colnames in a table as e.g.
grid.draw(tableGrob(head(iris, 10), name=test))
I can imagine you should use grid.edit or so, bu I can't figure out how...
Does anyone have a suggestion?
Thanks Robbert
windows xp
R 2.10.1
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2010/10/29 Chitra cbban...@gmail.com
£ukasz Rêc³awowicz,
Thanks.
I got this p-value.
It's exact upper tail (=), for lower you have to add ((-test.statistic))
to obtain two-sided p-vaule.
test()
[1] P-value: 0.00139
I still could not figure out how to plot 5000 permuted Qtot vs Itot.
Dear Cuckovic,
although you got already an answer to your post that relates a little bit more
on the time series characteristics of your data in question; I will take up on
your initial question. Basically, you got trapped by the word 'time series' in
the documentation for adf.test(). What is
Hi all, I want to club different objects (character type) to a single one and
using paste() function that can be done happily. However the problem with paste
function is the separator field is unique for all underlying objects. If I put
separator as - then this will come in between all
On 10/28/2010 10:38 PM, Gonzalo Garcia-Perate wrote:
Jim, thanks for your reply, it works! but the results are not what I
expected. What the code does now is completely reverse the central
chart area, so what was coloured before now is white, see here
http://www.flickr.com/photos/gonzillaaa/
Hi,
It would be interesting to have such behavior, but I think you would
then need to specify every separator, for example like this:
paste(a, b, c, sep=c(,, ,, :))
Otherwise, R cannot know where to put each separator.
So at the end, it's not much different from several paste() calls, isn't
That's helpful but the reason I'm using clusters in evd is that I need to
specify a time condition to ensure independence.
I therefore have an output in the form Cluster[[i]][j-k] where i is the
cluster number and j-k is the range of values above the threshold taking
account of the time
Hi
Is there any way to check an certain command or procedure's RAM usage?
Im after something similar to system.time(bla) that gives me the time the
command took to preform but for RAM usage.
Hope you understand what i mean.
Best regards
Joel
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Hello, I want to maximize a likelihood function expressed as an
integral that can not be symbolically evaluated. I expose my problem
in a reduced form.
g- function(x){
integrand-function(y) {exp(-x^2)*y}
g-integrate(integrand,0,1)
}
h-function(x) log((g(x)))
g
Jan Theodore Galkowski bayesianlogic at acm.org writes:
I'm interested in the Rsolnp package. For their primary function
solnp, one example is given, and there is a reference to unit
tests. Anyone know where these can be found? Also, Rsolnp is
used in a few other packages (e.g.,
G'day Jose,
On Fri, 29 Oct 2010 11:25:05 +0200
José Manuel Gavilán Ruiz g...@us.es wrote:
Hello, I want to maximize a likelihood function expressed as an
integral that can not be symbolically evaluated. I expose my problem
in a reduced form.
g- function(x){
integrand-function(y)
Dear Henrik,
sorry for bothering you with a report hastily pasted together and not
particularly nice for you as I used my toy data flu from a non-standard package.
I should have better used e.g. the iris.
I'm aware that writeMat doesn't deal with S4 objects. In fact, if I'd overlook
the
G'day Jose,
On Fri, 29 Oct 2010 11:25:05 +0200
José Manuel Gavilán Ruiz g...@us.es wrote:
Hello, I want to maximize a likelihood function expressed as an
integral that can not be symbolically evaluated. I expose my problem
in a reduced form.
g- function(x){
integrand-function(y)
Hello
Could anyone explain me the difference between strftime vs strptime, please
?
I've read the help but it's a little bit cionfusing for me.
cheers
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Hi all
I have 7 responses that I want to fit with MANOVA. I have accumulated the
responses into a matrix Y and each response has a weight vector associated with
it, so I have accumulated the weights into a matrix WT of the same dimensions
as Y. When I try
fit - manova( Y ~ X1 + X2
Hi all, I am wondering is there any way to check whether some Directory exists
or not, given the parent path of that directory? After searching for a while I
found that there is a function dir.create() to create some directory. However I
need to know whether such directory already exists or
Hi
I am fitting an arima model to some time series X. When I was comparing
the fitted values of the model to the true time series I realized that
the true time series lags one time step behind the fitted values of the
arima model. And this is the case for any model. When I did a simple
Perhaps the following construct does what you need:
paste(c(a, b, c), c(,, :, ), sep=,collapse=)
Regards,
Jan
On 29-10-2010 10:49, Ron Michael wrote:
Hi all, I want to club different objects (character type) to a single one and
using paste() function that can be done happily. However the
Hi, something like this perhaps,
if(myfolder%in%dir()==FALSE) dir.create(myfolder)
Command dir.create() is not overwriting an existing folder.
Best regards,
Andris
On Fri, Oct 29, 2010 at 12:08 PM, Ron Michael ron_michae...@yahoo.com wrote:
Hi all, I am wondering is there any way to check
Try this:
if(!file.info('myfolder')$isdir) dir.create('myfolder')
On Fri, Oct 29, 2010 at 9:08 AM, Ron Michael ron_michae...@yahoo.comwrote:
Hi all, I am wondering is there any way to check whether some Directory
exists or not, given the parent path of that directory? After searching for
a
-BEGIN PGP SIGNED MESSAGE-
Hash: SHA1
On 29/10/10 13:08, Ron Michael wrote:
Hi all, I am wondering is there any way to check whether some Directory
exists or not, given the parent path of that directory? After searching for a
while I found that there is a function dir.create() to
On Fri, Oct 29, 2010 at 4:49 AM, Ron Michael ron_michae...@yahoo.com wrote:
Hi all, I want to club different objects (character type) to a single one and
using paste() function that can be done happily. However the problem with
paste function is the separator field is unique for all
?memory.size
use before/after a sequence of commands to get an idea of the memory usage.
On Fri, Oct 29, 2010 at 5:21 AM, Joel joda2...@student.uu.se wrote:
Hi
Is there any way to check an certain command or procedure's RAM usage?
Im after something similar to system.time(bla) that gives
Dear R users
I would like to group my barplot graph (see example on the R help link). The
proposed R code, adding individual bars to the plot, looks really overwhelming.
My specific dataset just consists of five groups and three different levels
within each groups (the individual bars). The
Hello,
I have a question about relsurv package particularly rsadd function:
Rsadd(Surv(time,cens)~sex+ratetable(age=age*365.24,sex=sex,year=year),data=,=ratetable=,int=5,method=”max.lik”).
In the tutorial, it is indicated that the age and year must be given in the
date format, i.e. in number of
Hello,
I would like to run a script in which a loop is included. Since I'm new to
R, I cannot manage the following problem. I really hope someone could help
me out.
Data in the variable Y should be removed from the simulated data set with
probability 0.50 if the variable X has a value below
I have just installed R 12.
I have Windows 7, 64-bit verison.
I currently have IE as my default browser. The internet connection is very good.
Whenever I try to run a help command (?lm, for example), I get this error:
Error in shell.exec(url) : access to
Hi,
I have a data frame with two factors (well, more, but 2 for simple
consideration), and I want to display the different combinations of
the them that actually occur in the data. In reality, there are too
many of them to do to do a 'table' call and have one col vertical and
one col horizontal
Hi Sarah,
There is one thing you need to think about: how do you choose which
values should not be removed if you have more than 20 and which should
be if you have less than 20. In my code, I've just done it with
sample(), which might not be what you need.
Here is what I have:
if
Matt,
Below are three (of the probably many more) possible ways of doing this:
aggregate(1:nrow(df), df, length)
ftable(1 ~ f1 + f2, data=df)
library(plyr)
ddply(df, .(f1,f2), nrow)
Regards,
Jan
On 29-10-2010 15:53, Matthew Pettis wrote:
Hi,
I have a data frame with two factors (well,
Perhaps, the following construct does what you need:
paste(c(a, b, c), c(,, :, ), sep=,collapse=)
Regards,
Jan
On 29-10-2010 10:49, Ron Michael wrote:
Hi all, I want to club different objects (character type) to a single one and using
paste() function that can be done happily. However the
Hi all,
I've been trying to find a solution for the problem of reading
multiple files and storing them in a variable that contains the names
by which I want to call the datasets later on.
For example (5 filenames):
- The filenames are stored in one variable:
filenames = paste(paste('name', '_',
Hi to all!
When I use the example from kernlab::ksvm this works fine.. Give me the
result…
filter -
ksvm(type~.,data=spamtrain,kernel=rbfdot,kpar=list(sigma=0.05),C=5,cross=3)
But as soon as I change the type data as follows
type_train-spamtrain[,ncol(spamtrain)]
filter -
Read them into a list; much easier to handle:
myList - lapply(filenames, read.csv)
On Fri, Oct 29, 2010 at 5:16 AM, Sarah Moens sara...@telenet.be wrote:
Hi all,
I've been trying to find a solution for the problem of reading
multiple files and storing them in a variable that contains the
On Oct 29, 2010, at 5:14 AM, dpender wrote:
That's helpful but the reason I'm using clusters in evd is that I
need to
specify a time condition to ensure independence.
I believe this is the first we heard about any particular function or
package.
I therefore have an output
We
On Fri, 29 Oct 2010, Ron Michael wrote:
Hi all, I am wondering is there any way to check whether some
Directory exists or not, given the parent path of that directory?
After searching for a while I found that there is a function
dir.create() to create some directory. However I need to know
strptime() takes a character vector and makes a date-time object.
That is input.
strftime() takes a date-time object and makes an character vector.
That is output, and it is normally called via format() or print().
Let's see what the help says (slightly edited to refer just to these
two):
Is this what you want:
df
f1 f2
1 Maj I Minor A
2 Maj I Minor A
3 Maj I Minor A
4 Maj II Minor A
5 Maj II Minor B
6 Maj II Minor B
7 Maj III Minor B
8 Maj III Minor C
9 Maj III Minor C
df[!duplicated(df),]
f1 f2
1 Maj I Minor A
4 Maj II Minor A
5 Maj II
On Oct 29, 2010, at 6:55 AM, skan wrote:
Hello
Could anyone explain me the difference between strftime vs strptime,
please
?
I've read the help but it's a little bit cionfusing for me.
You should focus on the Value section of the help page. They return
vectors of different classes.
I think that'll work... thanks!
matt
On Fri, Oct 29, 2010 at 9:45 AM, jim holtman jholt...@gmail.com wrote:
Is this what you want:
df
f1 f2
1 Maj I Minor A
2 Maj I Minor A
3 Maj I Minor A
4 Maj II Minor A
5 Maj II Minor B
6 Maj II Minor B
7 Maj III Minor B
8 Maj
On Fri, Oct 29, 2010 at 5:16 AM, Sarah Moens sara...@telenet.be wrote:
Hi all,
I've been trying to find a solution for the problem of reading
multiple files and storing them in a variable that contains the names
by which I want to call the datasets later on.
For example (5 filenames):
-
Job: Scientific programmer at Merck, Biostatistics, Rahway, NJ, USA
[Job Description]
This position works closely with statisticians to process and analyze
ultrasound, MRI, and radiotelemetry longitudinal studies using a series
of programs developed in R and Mathworks/Matlab. This position
Hello all,
I am trying to use clim.pact package for my work, but since this is the
beginning for me to use gridded datasets in R, I am having some trouble.
I want to do seasonal analyses like trends, anomalies, variograms, EOF and
probably kriging too to downscale my 1 degree
Thanks for your help.
May be I can not make clear by my writing. The statement which I am going to do
is like this
To test such null hypotheses we used the Monte Carlo test, i.e. we chose
randomly (5000 times) a value for the
current dependent characteristic (richness or actual species pool) in
Apologies for being vague,
The structure of the output is as follows:
$ cluster1 : Named num [1:131] 3.05 2.71 3.26 2.91 2.88 3.11 3.21 -1 2.97
3.39 ...
..- attr(*, names)= chr [1:131] 6667 6668 6669 6670 ...
With 613 clusters. What I require is abstracting the first and last value
of
Hi dear Mi³ego dnia,
I am sorry I got lost here.
May be it it sound if I write you about what I am going to do.
To test such null hypotheses we used the Monte Carlo test, i.e. we chose
randomly (5000 times) a value for the
current dependent characteristic (richness or actual species pool) in the
You could do a weighted cox ph model, with possible haplotype
configurations for each subject weighted by their posterior
probabilities given genotype data.
Are your markers SNPs? If so you can use a utility function from the
hapassoc package to get started. For example, if your data is in a
Dear John,
Thank you very much for your help! I appreciate it.
eshi
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__
On Oct 29, 2010, at 11:37 AM, dpender wrote:
Apologies for being vague,
The structure of the output is as follows:
Still no code?
$ cluster1 : Named num [1:131] 3.05 2.71 3.26 2.91 2.88 3.11 3.21
-1 2.97
3.39 ...
..- attr(*, names)= chr [1:131] 6667 6668 6669 6670 ...
With 613
Hello, dear R-community.
This is a question about TukeyHSD between factor combinations of a Three-Way
ANOVA, which is - since it is a multi measure ANOVA - not a simple ANOVA but
a Generalised Linear Mixed Model (GLMM), calculated with lmer.
growth -
On Oct 29, 2010, at 12:08 PM, David Winsemius wrote:
On Oct 29, 2010, at 11:37 AM, dpender wrote:
Apologies for being vague,
The structure of the output is as follows:
Still no code?
$ cluster1 : Named num [1:131] 3.05 2.71 3.26 2.91 2.88 3.11 3.21
-1 2.97
3.39 ...
..- attr(*,
Hello all,
Is there an r function that exists that will perform repeated measures MANOVAs?
For example, let's say I have 3 DVs, one between-subjects IV, and one
within-subjects IV. Based on the documentation for the manova command, a
function like that below is not appropriate because it
I had a look:
I fixed it 5 months ago and forgot to make a new release.
The version on R-forge contains the fix already.
New release on its way to CRAN.
Best wishes;
Uwe
On 28.10.2010 11:28, John Coulthard wrote:
Hi
I'm trying to scale the point symbols on a 3d plot so that the ones at
Dear Chris,
See the examples in ?Anova in the car package (but it works with a model fit
by lm).
I hope this helps,
John
John Fox
Senator William McMaster
Professor of Social Statistics
Department of Sociology
McMaster University
Hamilton, Ontario, Canada
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
On Behalf Of govin...@msu.edu
Sent: Friday, October 29, 2010 8:33 AM
To: r-help@r-project.org
Subject: [R] doubt in climate variability analysis in R!
Hello all,
I am trying to use
How do I plot two time series plots on the same chart?
Thanks,
Jason
[[alternative HTML version deleted]]
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https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
Thanks a lot for your answers, Dennis and Bernhard!
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On Fri, Oct 29, 2010 at 1:41 PM, Jason Kwok jayk...@gmail.com wrote:
How do I plot two time series plots on the same chart?
Try this:
example(plot.ts)
example(ts.plot)
library(zoo)
example(plot.zoo)
library(lattice)
example(xyplot.zoo)
--
Statistics Software Consulting
GKX Group, GKX
Thanks. 1 more question.
When I use
Plot(series1)
lines(series2)
The graph will use the y axis scaling for series 1 so some of series 2 is
cut off. How do I control the y axis scaling?
Thanks,
Jason
On Fri, Oct 29, 2010 at 2:10 PM, Gabor Grothendieck ggrothendi...@gmail.com
wrote:
On
On Fri, Oct 29, 2010 at 2:30 PM, Jason Kwok jayk...@gmail.com wrote:
Thanks. 1 more question.
When I use
Plot(series1)
lines(series2)
The graph will use the y axis scaling for series 1 so some of series 2 is
cut off. How do I control the y axis scaling?
Plot them together as a
the following code was used
library(akima)
library(clim.pact)
nc.1 - RF_80-05.nc
nc.rf.in - open.ncdf(nc.1)
x1 - retrieve.nc(nc.1, v.nam=Rainfall,l.scale=FALSE, x.rng=c(70, 80),
y.rng=c(10, 13.5))
#dimension is checked for the subset. (lon, lat, time) is changed as (time,
lat, lon)
Hello, dear R-community.
This is a question about TukeyHSD between factor combinations of a Three-Way
ANOVA, which is - since it is a multi measure ANOVA - not a simple ANOVA but
a Generalised Linear Mixed Model (GLMM), calculated with lmer.
growth -
Dear R Users
I have two questions about how R makes use of memory on a Windows computer.
On my machine certain R jobs seem to stop with messages such as...
Error: cannot allocate vector of size 215.0 Mb
...when, according to Windows Task Manager, there are still hundreds of
megabytes of
I tried one more thing - I uninstalled R again, and this time
installed it under:
C:\Users\Myname\R\R-2.12.0
And again - am gettting the same error:
Error in shell.exec(url) :
access to 'http://127.0.0.1:30111/library/stats/html/lm.html' denied
Any help is greatly appreciated!
Dimitri
On Fri,
Does any R package support one-class SVM?
I'm trying to develop an application to detect anomalies in genome
sequencing.
Thanks in advance.
Anjan
--
===
anjan purkayastha, phd.
research associate
fas center for systems biology,
harvard university
52 oxford street
Problem solved. It turned out I had to reset my IE as my default
browser for all extentions (like .html). Now, R help is working!
Dimitri
On Fri, Oct 29, 2010 at 4:20 PM, Dimitri Liakhovitski
dimitri.liakhovit...@gmail.com wrote:
I tried one more thing - I uninstalled R again, and this time
Hi Dimitri,
The help pages should be loaded from a local server (which is
corroborated by the 127...ip), so the internet connection should not
matter.
I would check whether IE is the default application for .html
extensions, and you could also try running R as an admin (though I do
not really
Question: I installed R verison 2-12.0 on my Windows 7 (64 bit) PC.
When I was installing it, it did not ask me anything about 32 vs. 64 bit.
So, if I run R now - is it running as a 32-bit or a 64-bit?
thank you!
--
Dimitri Liakhovitski
Ninah Consulting
www.ninah.com
G'day Dimitri,
On Fri, 29 Oct 2010 16:45:00 -0400
Dimitri Liakhovitski dimitri.liakhovit...@gmail.com wrote:
Question: I installed R verison 2-12.0 on my Windows 7 (64 bit) PC.
When I was installing it, it did not ask me anything about 32 vs. 64
bit. So, if I run R now - is it running as a
Hi,
On Fri, Oct 29, 2010 at 4:24 PM, ANJAN PURKAYASTHA
anjan.purkayas...@gmail.com wrote:
Does any R package support one-class SVM?
I'm trying to develop an application to detect anomalies in genome
sequencing.
I'm pretty sure kernlab supports this:
***Summary:***
I'm setting up a cluster using netWorkSpace, and I'm having issues
with the sleigh initialization. My R function to initialize the sleigh
succeeds and the sleigh appears to be ready, but I get apparently
conflicting information from status(s), rankCount(s), and s; and
basic sleigh
On 29/10/2010 4:45 PM, Dimitri Liakhovitski wrote:
Question: I installed R verison 2-12.0 on my Windows 7 (64 bit) PC.
When I was installing it, it did not ask me anything about 32 vs. 64 bit.
So, if I run R now - is it running as a 32-bit or a 64-bit?
If it didn't ask you about it, then it
On 29/10/2010 12:46 PM, DM2010 wrote:
Dear R Users
I have two questions about how R makes use of memory on a Windows computer.
On my machine certain R jobs seem to stop with messages such as...
Error: cannot allocate vector of size 215.0 Mb
...when, according to Windows Task Manager, there
Thank you for your suggestion, Juan. However, I have tried to specify
the innovations and this doesn't seem to solve the problem.
Are there really no opportunities to simulate from a (S)ARIMA model
using past observations in R, besides to make the whole script from
the ground?
Knut
Hi, everyone. I am using a fair amount of closures in my code. Problem i am
experiencing is i cannot figure out how to mtrace functions defined within a
function. There must be some way to name such function for mtrace to see it
and let me step into it. For example, say i have code
Actually, Berwin - you are right. I also did get 2 shortcuts. I just
thought that one of them was old - from my previous R installations.
And indeed the 4th line tells what version is running.
Great!
Thank you!
Dimitri
On Fri, Oct 29, 2010 at 5:02 PM, Berwin A Turlach
ber...@maths.uwa.edu.au
On 29/10/2010 5:19 PM, Andre Zege wrote:
Hi, everyone. I am using a fair amount of closures in my code. Problem i am
experiencing is i cannot figure out how to mtrace functions defined within a
function. There must be some way to name such function for mtrace to see it
and let me step into it.
I want to plot the unstadardized version of a normal plot. Can you explain
why that is not working?
Dev.set(1)
xcrit=-1.645
cord.x - c(-3,seq(-3,xcrit,0.01),xcrit)
cord.y - c(0,dnorm(seq(-3,xcrit,0.01)),0)Â Â Â Â Â Â Â Â Â Â Â # what does
final 0 do here?
Hi R-helpers,
I need to read some file with different lines (I don't know the number of
lines to skip) and I would like to find a way to start reading the
data.frame from the word source.
ex:
djhsafk
asdfhkjash
shdfjkash
asfhjkash #those lines contain numbers and words, I want to skip
Sorry, the explanation wasn't very good...just to explain better.
I am writing a loop to read and process different files in the same script.
And what I want to load into a variable is a data.frame that is above the
word source in all of my files.
So I would like to recognize the word Source in
Sorry, the explanation wasn't very good...just to explain better.
I am writing a loop to read and process every time a different file in the
same script.
And what I want to load into a variable each time is a data.frame that is
bellow the word source in all of my files.
So I would like to
Hi Everyone,
I have a list of vectors like this (in this case it's 3 vectors but assume the
vector count and the length of each vector is not known):
[[1]]
[1] 9 5 7 2 14 4 4 3
[[2]]
[1] 3 6 25 2 14 3 3 4
[[3]]
[1] 28 4 14 3 14 2 4 5
What I want to do is take the average
So, I am having a tricky reference file to extract information from.
The format of the file is
x 1 + 4 * 3 + 5 + 6 + 11 * 0.5
So, the elements that are not being multiplied (1, 5 and 6) and the elements
before the multiplication sign (4 and 11) means actually the reference for
the row in a
Hi Greg,
Here are two ways of doing it:
mylist - list(x = rpois(10, 10), y = rpois(10, 20), z = rpois(10, 5))
mylist
$x
[1] 3 13 14 16 10 7 3 5 12 14
$y
[1] 17 16 26 13 23 24 16 28 23 12
$z
[1] 2 6 5 5 5 1 9 11 6 4
colMeans(do.call(rbind, mylist), na.rm = TRUE)
[1]
It might be easier to preprocess the file before passing it
to R, but you an do what you want using a connection:
f = file('s.dat','r')
while(1){
+ txt = readLines(f,1)
+ if(length(grep('Source',txt)))break;
+ }
while(1){
+ more = readLines(f,1)
+ if(nchar(more) == 0)break;
+ txt =
Sorry, this isn't really an R solution, but here it goes anyway. You
can isolate the block from Source to the first following blank line by
the following unix/linux/cygwin command, assuming inFile is your input
file and outFile is the output file:
cat inFile | grep -A 100 Source | grep -m 1 -B
Hi Jorge
I tried your methods for all (which work for complete rows) and then I
remove the first value of $y and repeated; both fail because of
the unequal numbers
The problem is when there are unequal numbers in the rows and trying to
make a matrix of them.
I was trying some things with
Aplogies to the original poster - I got names wrong in a cut and paste
Hi Jorge
I tried your methods for all (which work for complete rows) and then I
remove the first value of $y and repeated; both fail because of
the unequal numbers
The problem is when there are unequal numbers in the
On Fri, Oct 29, 2010 at 6:34 PM, M.Ribeiro mresende...@yahoo.com.br wrote:
Hi R-helpers,
I need to read some file with different lines (I don't know the number of
lines to skip) and I would like to find a way to start reading the
data.frame from the word source.
ex:
djhsafk
asdfhkjash
Hi list,
Could someone explain to me why the following result is not a integer?
difftime(strptime(24NOV2004, format=%d%b%Y), strptime(13MAY2004,
format=%d%b%Y), units=days)
Time difference of 195.0417 days
I'm using R2.12.0 on WinXP.
Thanks!
...Tao
Tao -
The documentation for the difftime function says:
Function ‘difftime’ calculates a difference of two date/time
objects and returns an object of class ‘difftime’ with an
attribute indicating the units.
So that answers your question.
If you want it to be an integer, you're
Hi,
Ah! Thanks for your help! I have even seen Reduce before but for some reason
just didn't make the connection. This helps a ton! Thanks again.
Kind regards,
Greg
On Oct 29, 2010, at 6:53 PM, Jorge Ivan Velez wrote:
Hi Greg,
Here are two ways of doing it:
mylist - list(x = rpois(10,
Hi.
On Fri, Oct 29, 2010 at 3:31 AM, Claudia Beleites cbelei...@units.it wrote:
Dear Henrik,
sorry for bothering you with a report hastily pasted together and not
particularly nice for you as I used my toy data flu from a non-standard
package. I should have better used e.g. the iris.
I'm
Hi Duncan,
If vectors of unequal length is the problem, one way to go, using your
example, would be:
# your example
x - list(c(9, 5, 7, 2, 14, 4, 4, 3), c(3, 6, 25, 2, 14, 3, 3, 4),
c(28, 4, 14, 3, 14, 2, 4, 5), 28)
x
# maximum number of components
k - max(sapply(x, length))
k
# expanding
Hi Mary,
I am not sure off hand why savePlot() is not doing what you expect,
but hopefully my inline comments answer your other questions and at
least get you the graphs you want.
Cheers,
Josh
On Fri, Oct 29, 2010 at 3:18 PM, mms...@comcast.net wrote:
I want to plot the unstadardized
Hello
I have what is probably a very simple grouping question however, given my
limited exposure to R, I have not found a solution yet despite my research
efforts and wild attempts at what I thought might produce some sort of
result.
I have a very simple list of integers that range between 1
try this:
x
[1] 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24
y - cut(x, breaks=c(-Inf,6,18, Inf), labels=c('a','b','c'))
levels(y) - c('night','day','night')
y
[1] night night night night night night night day day day day
day day day day day day
Hi Will,
One way would be:
x
[1] 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23
24
factor(ifelse(x6 x18, 'day', 'night'))
[1] night night night night night night night day day day day day
day day day
[16] day day day night night night night night
Hello Jim
Wow. I tried cut but i see you have an interim step with labels a,b,c but
levels night and day. i was really close to this. i have labels
night,day,night and it wouldn't let me duplicate labels. I am very greatful
for your input
Will
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Hello Jorge,
Thank you for the reply. I tried a few different things with if/else but
couldn't get them to go. I really appreciate your feedback. I learned
something new from this
Will
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