On Oct 18, 2011, at 05:36 , David Winsemius wrote:
On Oct 17, 2011, at 9:45 PM, David Wolfskill wrote:
Sorry about the odd terminology, but I suspect that my intent might be
completely missed had I used aggregate or classify (each of which
appears to have some rather special meanings in
i am using quantmod package.it get stock quotes from google finanace. but
unfortunately i am not able to get the quotations of some stocks(e.g.
NSE:TCS,NSE:SAIL ) through the getSymbol command of this package although
they are available in the google finance website. anyone please help me.
thanks
Hi all,
I have a basic plot
MC_P1.DEM.1-qplot(x=Group, y=P1.DEM.UN.WPP.FER.TOT_var,
data=GroupMeans_gr_DEM, geom=bar, stat=identity, fill=Group)+
myScale_fill()+getLabs(MC_P1.DEM.1)
I would like to add a y-lab horizontally ON TOP OF y-axis...and I didn't
understand how it works (with
Hi
I'm trying to analyse some data and need to set the geographic coordinate
system before I can do the analysis. I've been trying to use the project
command in rgdal but keep getting an error message saying:
Error in project(locationsMatrix, PROJECTION.OUT) :
latitude or longitude exceeded
Dear R-helpers,
I am trying to extract two equations from an R code, but I am not being able
to do it. The code is this:
function (x, fullin, fullout, crossover, infz = 0.953, outfz = 0.047,
details = FALSE)
{
if (fullin fullout || crossover fullout || fullin crossover)
Hi all,
I would like to run a function with several nested conditions, which are
completely factorial.
The input data (x1) has two different sample sizes, so:
x1 - dat1
x1 - dat2
Then a can have 3 different values:
a - 0.15
a - 0.35
a - 0.50
Then b can have 2 different values:
b - data.matrix
Hi R-users,
I have a question about testing the difference of skewness parameter between
two arbitrary distributions.
I collect samples in an experiment.
It is a one-independent variable (i.e., goal condition) with two levels
(high goal or low goal).
Now I got two distributions and I would like
Hi Dan,
I've tried the log likelihood, but it reaches zero again, if I work with say
1000 samples.
I need an approach that would scale to quite large sample sizes. Surely I
can't be the first one to encounter this problem, and I'm sure I'm missing
an option that is embarrassingly obvious.
Regards
Hi It as 12 hours since I have posted the question, could you let me
know if it had been approved?
On Mon, Oct 17, 2011 at 11:43 PM, milena milena.s...@gmail.com wrote:
Dear List Members,
I am working on a below piece of code: Initially have created pie
charts with Enlish labels to present
Hello everybody.
My issue arise when I build a package with my functions. This package is for
personal purposes only and it will not submitted to CRAN.
Anyway, this may be an opportunity for myself to clear the S3 methods
concept. I read the R manual and some books about R programming but they
Hello, this question is more suitable for the R-Sig-Geo mailing list,
so you could consider posting there in future. Read the information
for that list here:
https://stat.ethz.ch/mailman/listinfo/r-sig-geo
Comments below.
On Tue, Oct 18, 2011 at 3:11 PM, kalee kathryn.l...@students.mq.edu.au
Hi
I'm performing a PLS
This is my data present in a file
Year Y X2 X3 X4 X5 X6
1960 27.8 397.5 42.2 50.7 78.3 65.8
1960 29.9 413.3 38.1 52 79.2 66.9
1961 29.8 439.2 40.3 54 79.2 67.8
1961 30.8 459.7 39.5 55.3 79.2 69.6
1962 31.2 492.9 37.3 54.7 77.4 68.7
My R-code
Data -
On 18.10.2011 11:03, arunkumar wrote:
Hi
I'm performing a PLS
This is my data present in a file
Year Y X2 X3 X4 X5 X6
1960 27.8 397.5 42.2 50.7 78.3 65.8
1960 29.9 413.3 38.1 52 79.2 66.9
1961 29.8 439.2 40.3 54 79.2 67.8
1961 30.8 459.7 39.5 55.3 79.2 69.6
1962 31.2 492.9 37.3 54.7
On 17.10.2011 20:53, Li, Yan wrote:
Hi All,
I have some data from which I set four points to be breaks. Based on these
points, I cut the dataset into four groups and assign a number to it:
=331.04 assign 0
331.04=476.07 assign data-331.04/(476.07-331.04)
476.07=608.66 assign 1
On 17.10.2011 21:59, Noah Silverman wrote:
Hi,
Looking at the fastICA library. I want to test separating out different sounds
from a recorded wav file.
But, I only have a SINGLE stream of data (one channel wav.) It appears as if
the fastICA won't let me separate more sounds than I have
On 18.10.2011 09:12, filippo gheri wrote:
Hi all,
I have a basic plot
MC_P1.DEM.1-qplot(x=Group, y=P1.DEM.UN.WPP.FER.TOT_var,
data=GroupMeans_gr_DEM, geom=bar, stat=identity, fill=Group)+
myScale_fill()+getLabs(MC_P1.DEM.1)
I would like to add a y-lab horizontally ON TOP OF
On 18.10.2011 10:37, Nicola Sturaro Sommacal wrote:
Hello everybody.
My issue arise when I build a package with my functions. This package is for
personal purposes only and it will not submitted to CRAN.
Anyway, this may be an opportunity for myself to clear the S3 methods
concept. I read
On 11-10-18 4:30 AM, Seref Arikan wrote:
Hi Dan,
I've tried the log likelihood, but it reaches zero again, if I work with say
1000 samples.
I need an approach that would scale to quite large sample sizes. Surely I
can't be the first one to encounter this problem, and I'm sure I'm missing
an
Please see the posting guide, and supply the information you were
asked for (and read the relevant manuals).
What OS?
What locale?
What graphics device?
No extra support is needed: R handles Czech characters perfectly well
in a Czech locale (or any UTF-8 locale provided you have the correct
Thank you very much for your reply. You confirm what I suppose.
Can you give me a reference of that you wrote? I need it for a report.
Thanks again.
PS: sorry Uwe for the previous reply, not to the list.
2011/10/18 Uwe Ligges lig...@statistik.tu-dortmund.de
On 18.10.2011 10:37, Nicola
On 18.10.2011 12:23, Nicola Sturaro Sommacal wrote:
Thank you very much for your reply. You confirm what I suppose.
Can you give me a reference of that you wrote? I need it for a report.
Thanks again.
PS: sorry Uwe for the previous reply, not to the list.
... where I replied it is in
Thank you again.
Nicola
2011/10/18 Uwe Ligges lig...@statistik.tu-dortmund.de
On 18.10.2011 12:23, Nicola Sturaro Sommacal wrote:
Thank you very much for your reply. You confirm what I suppose.
Can you give me a reference of that you wrote? I need it for a report.
Thanks again.
Dear r-helpers,
I have a query regarding use of contrasts in MANOVA.
summary(manova(model))
gives me only result of test for overall difference.
Would you be so kind and give me a hint how to get the same test statistics
(e.g.Pillai's) and P values for the predefined contrasts?
Best regards
Ondrej
Hi,
I am a new user in R.
I wanted to study the code for some R commands.
For example, as I was studying PCA analysis there is a command in R, as
princomp. Normally if we type the command we get the code behind the
function, but I am not able to get for this one.
* princomp
function (x, ...)
Dear R-list,
I currently have to convert a data.frame with several factor-variables to a
numeric matrix.
Now the problem is, that the order of the factor-labels don't match the order I
would like to use.
for example, let's assume I have this factor-variable in my data-frame:
x -
On 11-10-18 7:34 AM, Vikram Bahure wrote:
Hi,
I am a new user in R.
I wanted to study the code for some R commands.
For example, as I was studying PCA analysis there is a command in R, as
princomp. Normally if we type the command we get the code behind the
function, but I am not able to get
I have a data set like this in one .txt file (cols separated by !):
APE!KKU!684!
APE!VAL!!
APE!UASU!!
APE!PLA!1!
APE!E!10!
APE!TPVA!17122009!
APE!STAP!1!
GG!KK!KK!
APE!KKU!684!
APE!VAL!!
APE!UASU!!
APE!PLA!1!
APE!E!10!
APE!TPVA!17122009!
APE!STAP!1!
GG!KK!KK!
APE!KKU!684!
APE!VAL!!
APE!UASU!!
D_Tomas tomasmeca at hotmail.com writes:
I have fitted a Negative Binomial model (glm.nb) and a Poisson model (glm
family=poisson) to some count data. Both have the same explanatory variables
dataset
When I call sum(fitted(model.poisson)) for my GLM-Poisson model, I obtain
exactly the
Let me rephrase your question:
How do I get the results that are printed by print(survfit())
Answer: read the help file ?print.survfit
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting
Let's do it in two parts: first create all the separate files (which
if this what you are after, we can stop here). You can change the
value on readLines to read in as many lines as you want; I set it to 2
just for testing.
x - textConnection(APE!KKU!684!
APE!VAL!!
APE!UASU!!
APE!PLA!1!
Thanks Jim,
I tried to convert this solution into my situation (.txt file as an input);
zz - file(myfile.txt, r)
fileNo - 1 # used for file name
buffer - NULL
repeat{
input - read.csv(zz, as.is=T, nrows=100, sep='!',
row.names=NULL, na.strings=)
if (length(input) == 0) break # done
Rui,
I suggest you read the following tutorial to give you an introduction to
foreach:
http://cran.r-project.org/web/packages/doMC/vignettes/gettingstartedMC.pdf
Regarding your question I could would suspect that you can not assign values to
some variable inside foreach and use them outside
Use 'readLines' instead of 'read.table'. We want to read in the text
file and convert it into separate text files, each of which can then
be read in using 'read.table'. My solution assumes that you have used
readLines. Trying to do this with data frames gets messy. Keep it
simple and do it in
I believe it's because they are not made available for download as a csv file.
Compare:
https://www.google.com/finance/historical?q=NSE:TCS
with
https://www.google.com/finance/historical?q=NASDAQ:AAPL
You'll see that for AAPL, there is an option to export prices on the
right hand side: that's
Dear Ondrej,
You might use the linearHypothesis() function in the car package.
Best,
John
John Fox
Senator William McMaster
Professor of Social Statistics
Department of Sociology
McMaster University
Hamilton, Ontario, Canada
http://socserv.mcmaster.ca/jfox
Without knowing the calculation you want to run, I can't give you any
more direction than this, but it sounds like you need to take a step
back and rethink your problem in terms of vectorization. If you can do
so, outer() might be able to help as well as direct vectorwise
calculation.
If it's
Duncan Murdoch murdoch.duncan at gmail.com writes:
On 11-10-18 4:30 AM, Seref Arikan wrote:
Hi Dan,
I've tried the log likelihood, but it reaches zero again, if I work with say
1000 samples.
I need an approach that would scale to quite large sample sizes. Surely I
can't be the first
Hi
How to get p-value and the standard error in PLS
I have used the following function to calculate PLS
fit1 - mvr(formula=Y~X1+X2+X3+X4, data=Dataset, comp=4)
Please help me
--
View this message in context:
*Dear experts,*
Please excuse me for disturbing... Right now I am struggling with GLM a
bit... Would you be so kind to provide me a solution on using nuisance
variables. The problem is that I have data on Depression (volumetric
measurements of different brain regions) and I want to include age,
Dear Ben,
First of all, many thanks for your reply. I am highly appreciative of that.
I am still unsure about some issues
The dispersion parameter is that which is estimated by
sum(residuals(fit,type=pearson)^2)/fit$df.res. This is what a quasipoisson
model estimates. This corresponds
Sorry,
I didn't notice a mistake... Sepal.Length is a dependent variable
and Sepal.Width is an independent one...
---
Regards
Alex
2011/10/18 Alexander Lebedev alexander.vl.lebe...@gmail.com
*Dear experts,*
Please excuse me for disturbing... Right now I am struggling with GLM a
bit... Would
Ben,
this is a continuation of the query i posted on:
http://r.789695.n4.nabble.com/GLM-and-Neg-Binomial-models-td3902173.html
I cannot give you a direct example (big dataset) of what i did aside from
what i have written:
fitpoisson - glm((RESPONSE) ~ A + B +
offset(log(LENGTH)) +
Dear R users,
Apologies for the total beginner's question. I was wondering whether
you could tell me if there is a structural equation modelling function
that can handle binary data i.e. in similar manner to the GLM function
with a binomial family.
Best wishes,
Mario
Thanks Micheal,
that's what I wanted, I did not quite catch which variable is unused.
Another part is I have my variable values in log scale so it generates '0's'
instead of '1', how do i get rid of those cols.
Thanks for you patience
Sharad
--
View this message in context:
Add levels= to your factor() call.
E.g.,
x1 - factor(rep(1:4, 5), labels=c(slightly disagree, disagree,
agree, slightly agree), levels = c(2,1,4,3))
as.numeric(x1)
[1] 2 1 4 3 2 1 4 3 2 1 4 3 2 1 4 3 2 1 4 3
Michael
On Tue, Oct 18, 2011 at 7:35 AM, Martin Batholdy
batho...@googlemail.com
Dear all,
I know there have been various questions posted over the years about loops but
I'm afraid that I'm still stuck. I am using Windows XP and R 2.9.2.
I am generating some data using the multivariate normal distribution (within
the 'mnormt' package). [The numerical values of sanad and
Thanks Jim for your help. I tried this code using readLines and it
works but not in way I wanted. It seems that this code is trying to
separate all records from a text file so that I'm getting over 14 000
000 text files. My intention is to get only 15 text files all expect
one containing 1 000 000
Ok, I think that would work – thanks!
However, in my case I read a data.frame via read.table().
So some of the columns get transformed to factors automatically –
I don't generate the factor-variables as in the example, so I can't control how
the levels are ordered (or can I?).
On 18.10.2011,
On Oct 18, 2011, at 7:35 AM, Martin Batholdy wrote:
Dear R-list,
I currently have to convert a data.frame with several factor-
variables to a numeric matrix.
Now the problem is, that the order of the factor-labels don't match
the order I would like to use.
for example, let's assume
Thanks for your reply.
Let me make an example then:
m- c(150, 400, 500,750,800, NA)
How can I use cut to generate the m_group as c(0,0.4755,1, 0.2275,0,0):
Breaks 331.04 476.07 608.66 791.5
NA
m_group0 x 1
In your code you had a loop over the variable col, but it was never used.
Anyways, just modify the line:
n - n[-length(n)] # Throwout unwanted columns
to also throw out values with 0's. Perhaps:
idxZeros - apply(d, 1, function(x) any( abs(x-0) 1e-08)) # Identify
rows with zeros
n -
Hello all R users
I want to calculate this univariate integral:
exp(-x)*sum(y^x) respect to x from 0 to 3 where y is a vector y=(2,3,5).
In fact, the original y vector has a large number of elements but I propose
with 3 elements.
I know that I can resolve this problem doing
fun - function(x)
On Tue, Oct 18, 2011 at 03:40:27PM +0200, Martin Batholdy wrote:
Ok, I think that would work – thanks!
However, in my case I read a data.frame via read.table().
So some of the columns get transformed to factors automatically – I don't
generate the factor-variables as in the example, so I
Use the stringsAsFactors = FALSE argument for read.table() so the
strings will remain factors and then you can convert them directly
yourself.
Michael
On Tue, Oct 18, 2011 at 9:40 AM, Martin Batholdy
batho...@googlemail.com wrote:
Ok, I think that would work – thanks!
However, in my case I
Hi
I'm using filled.contour in R with matrix 19x19. Therefore the plot isn't
very smooth Are there any functions in R to make it smooth? I can't have
more observations because it takes to long.
Thanks, Knut
--
View this message in context:
How about adding an additional argument to fun?
R fun - function(x, y) exp(-x)*sum(y^x)
R y - c(2,3,5)
R integrate(fun, 0, 3, y)
[1] 346.853 with absolute error 3.9e-12
Michael
On Tue, Oct 18, 2011 at 10:01 AM, Freddy Hernandez Barajas
fhern...@gmail.com wrote:
Hello all R users
I want to
I'm not sure how to easily get that data from google (see Michael's
message), but it's available from yahoo.
getSymbols('TCS.NS', src='yahoo')
I've found that historical stock data from Yahoo is typically cleaner and
more reliable than from Google. The other main difference is that Yahoo
dear listers,
right now, we are trying to use r to implement sas dde function, e.g.
interact with excel. however, we can't find a way to call vba from rï¼
any insight is appreciated.
[[alternative HTML version deleted]]
__
Dear R users, need help with my heatmap. I will really approciate some help.
Given the matrix:
head(x)
A B C D time
[1,] 0 8 0 01
[2,] 0 160 0 02
[3,] 0 175 0 03
[4,] 0 253 0 04
[5,] 79 212 0 05
[6,] 6 105 0 06
and call:
## Heatmap
I thought that you wanted a separate file for each of the breaks
GG!KK!KK!. If you want to read in some large number of lines and
then break them so that they have that many lines, you can do the same
thing, except scanning from the back for a break. So if your input
file has 14M breaks in it,
Hello ,
I was taking a look at your website and I noticed that one of the links you
suggest in http://www.daba.lv/Adreses/RS_GPS.shtml isn't working properly. The
link in question is this one:
http://instruct1.cit.cornell.edu/~agl1/Hexagone.html. You'll find a similar
resource published
thanks for the help and pointer.
I am modifying it like this
x=which(n[,1]==n[,2])
n=n[-x,]
to get rid of combinations which will generate '0' or ratio of 1.
Thanks once again.
sharad
--
View this message in context:
Hello everybody
I want to use rls() on a multi-dimensional function, where parts of it are
modeled using a spline.
I tried to condense my problem into the following code example,
which tries to fit the y-values of a spline interpolation:
Your original code was not directly vectorizible (and I should have
noted that): this should work:
fnc - function(x, y) {
z - outer(y, x, FUN = ^)
exp(-x) * colSums(z)
}
y - c(2,3,5)
integrate(fnc, 0, 3, y)
This should work and sorry for the initial confusion.
Michael
On Tue, Oct 18,
Dear R helpers,
I have a ts object, dadosvar, and want to run a VAR.
These are my data:
dadosvar[1:15,]
dl rp igpm ereal crescpib jurosreal
[1,] 32.31 NA 39.07 419.59 NA 7025.95
[2,] 32.00 NA 40.78 596.57 NA 13401.25
[3,] 32.70 NA 45.71
Dear R People:
Do you know who the contact person is for UseR 2012, please?
I'm trying to get together some numbers for funding (sorry for the tackiness).
Thanks,
Erin
--
Erin Hodgess
Associate Professor
Department of Computer and Mathematical Sciences
University of Houston - Downtown
On Oct 18, 2011, at 12:25 PM, Erin Hodgess wrote:
Dear R People:
Do you know who the contact person is for UseR 2012, please?
I'm trying to get together some numbers for funding (sorry for the
Funny, it was the first hit on a Google search with term useR2012
The contact person is:
Stephania McNeal-Goddard
email: stephania.mcneal-godd...@vanderbilt.edu
phone: (615)322-2768
Vanderbilt University School of Medicine
Department of Biostatistics
S-2323 Medical Center North
Nashville, TN 37232-2158
On Tue, 2011-10-18 at 12:41 -0400, David Winsemius wrote:
Please look at the RExcel project
rcom.univie.ac.at
followup should probably be on that mailing list.
Rich
On Tue, Oct 18, 2011 at 10:32 AM, Wensui Liu liuwen...@gmail.com wrote:
dear listers,
right now, we are trying to use r to implement sas dde function, e.g.
interact with excel.
Dear all,
i have done some regression analyses but i do not understand the p value.
These are the results
t-value p value
geno.1 -0.229 0.978 -0.234 8.15e-01
geno.50.647 1.146 0.565 5.73e-01
stress:geno.5-1.337 1.022 -1.307
Hello,
I have two numeric vectors in R and used cor.test function with them.
Is it possible in R to know how much contributed a particular row of the
vectors to the total correlation value and significance?
Of course I just could take out that row from the vectors and run the test
again to see
I am analyzing the spatial distribution of fish in a stream. The stream is
divided into equally sized units, and the number of fish in each unit is
counted. My problem is that my dataset is missing rows where the count in a
unit equals zero. I need to create zero data for the missing units.
For
Thank you Jim for your kind reply. My intention was to split one 14M
file into less than 15 text files, each of them having ~1M lines. The
idea was to make sure that one sequence
GG!KK!KK! --sequence start
APE!KKU!684!
APE!VAL!!
APE!UASU!!
APE!PLA!1!
APE!E!10!
APE!TPVA!17122009!
APE!STAP!1!
Hi Jonny,
On Tue, Oct 18, 2011 at 1:02 PM, Jonny Armstrong
jonny5armstr...@gmail.com wrote:
I am analyzing the spatial distribution of fish in a stream. The stream is
divided into equally sized units, and the number of fish in each unit is
counted. My problem is that my dataset is missing rows
Here is one option:
a- data.frame(day=c(rep(4,8),rep(6,8)),unit=
c((1:8),seq(2,16,2)),value=round(runif(16,1,34),0)) #approx your data
b- data.frame(day=c(rep(4,16),rep(6,16)),unit= 1:16) #fake df
b1-merge (a,b, by=c('day','unit'),all.y=T)
b1$value[is.na(b1$value)]-0
On Oct 18, 2011, at 2:24 PM, Sarah Goslee wrote:
Hi Jonny,
On Tue, Oct 18, 2011 at 1:02 PM, Jonny Armstrong
jonny5armstr...@gmail.com wrote:
I am analyzing the spatial distribution of fish in a stream. The
stream is
divided into equally sized units, and the number of fish in each
unit is
This is just scientific notation, so
8.15e-01 is the same as:
8.15*10^-1
[1] 0.815
niki wrote:
Dear all,
i have done some regression analyses but i do not understand the p value.
These are the results
t-value p value
geno.1
Prompted by David's xtabs() suggestion, one way to do what I think the
OP wants is to
* define day and unit as factors whose levels comprise the full range
of desired values;
* use xtabs();
* return the result as a data frame.
Something like
x - data.frame( day = factor(rep(c(4, 6), each = 8),
Hello,
# Full disclosure. I am not sure if my problem is a bug(s) in the code, or a
fundamental misunderstanding on my part about what I am trying to do with
these statistics. I am not familiar with maximum likelihood tests.
# I currently have two vectors
Aequipecten-c(0, 0, 1, 0, 0, 0, 0, 0,
Then read in a million lines, scan back for the break, write out the data,
delete from the buffer, then read the next million lines into the buffer.
On Tuesday, October 18, 2011, johannes rara johannesr...@gmail.com wrote:
Thank you Jim for your kind reply. My intention was to split one 14M
Thanks you for the quick and helpful replies. Problem solved.
Jonny
On Tue, Oct 18, 2011 at 11:33 AM, David Winsemius dwinsem...@comcast.netwrote:
On Oct 18, 2011, at 2:24 PM, Sarah Goslee wrote:
Hi Jonny,
On Tue, Oct 18, 2011 at 1:02 PM, Jonny Armstrong
jonny5armstr...@gmail.com wrote:
hi all,
i have a file of the following format that i want to read into a matrix:
010101001110101
10101001010
01001010010
...
it has no headers or row names.
I tried to use read.table(), but it doesn't allow me to specify nothing as
the column separator (specifying sep='' means
Would readLines() work?
Michael
On Tue, Oct 18, 2011 at 3:09 PM, Brian Tsai btsa...@gmail.com wrote:
hi all,
i have a file of the following format that i want to read into a matrix:
010101001110101
10101001010
01001010010
...
it has no headers or row names.
I tried to use
Hi Brian,
Take a look at ?scan
x - scan(file.choose(), what = 'list')
Read 3 items
x
[1] 010101001110101 10101001010 01001010010
as.matrix(x)
[,1]
[1,] 010101001110101
[2,] 10101001010
[3,] 01001010010
HTH,
Jorge
On Tue, Oct 18, 2011 at 3:09 PM, Brian Tsai wrote:
hi
On Oct 18, 2011, at 2:53 PM, Dennis Murphy wrote:
Prompted by David's xtabs() suggestion, one way to do what I think the
OP wants is to
* define day and unit as factors whose levels comprise the full range
of desired values;
* use xtabs();
* return the result as a data frame.
Something like
x
Or do you want each number separated?
data - textConnection(010101001110101
+ 10101001010
+ 01001010010
+ )
result - as.matrix(read.fwf(data, rep(1, 15)))
result
V1 V2 V3 V4 V5 V6 V7 V8 V9 V10 V11 V12 V13 V14 V15
[1,] 0 1 0 1 0 1 0 0 1 1 1 0 1 0 1
[2,] 1 0
Hi, all,
I'm running multiple imputation to handle missing data and I'm running into a
problem. I can generate the MI data sets in both amelia and the mi package
(they look fine), but I can't figure out how to get pooled results. The
examples from the mi package, zelig, etc., all seem to go
I am looking for a way to bucket data in 2 dimensions using a weighting that
will linearly allocate based on the proximity of the reference value. I'm
sure the functionality probably already exists but couldn't find an example:
Example Data
Yrs,strike,value
0.75,105,100
1.25,102.5,200
Time
Tena koe Erin
http://biostat.mc.vanderbilt.edu/wiki/Main/UseR-2012 has the contact person on
the front page ...
Peter Alspach
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
project.org] On Behalf Of Erin Hodgess
Sent: Wednesday, 19 October 2011
Mike,
You can retrieve each of imputed data sets and use Rubin's rule for
combined analysis. I am not sure how to do combined analysis of cov,
but mean and SE would be estimiable.
For mi package to get individual copies of imputed data
?mi.completed
HTH
Weidong Gu
On Tue, Oct 18, 2011 at
Hi,
Thanks! So, you're saying I should output the descriptives from the individual
data files, and manually do the stats to get the combined estimates (or, I can
use the files in mplus or spss to run it in those programs)? Is there no
automated process in any of the mi or mi-related packages
Dear R People:
Suppose I have the following character string:
f1
[1] (1/30)*(20-x)
My goal is to end up with
y - (1/30)*(20-x)
How would I do this, please?
I've been experimenting with eval, but no good so far.
As usual, I have the feeling that this is something really simple, but
I can't
On 19/10/11 13:57, Erin Hodgess wrote:
Dear R People:
Suppose I have the following character string:
f1
[1] (1/30)*(20-x)
My goal is to end up with
y- (1/30)*(20-x)
How would I do this, please?
I've been experimenting with eval, but no good so far.
As usual, I have the feeling that this
Hello all,
I am quite new to R, with the goal of using it for a project in my business
course. I am attempt to run a Monte Carlo simulation of futures prices based
on a random walk whereby the given volatility (I will use historical
volatility in this case, say 12%) is Levy-distributed , equally
Hello,
I cannot access the r-help website although after
registration I am getting all the posts sent to the side. Each time I click
on the Visit Subscriber List on the
https://stat.ethz.ch/mailman/listinfo/r-help site, I get R-help roster
authentication failed. error. Any
Hi Mike
Thanks for your comments. I had the code trying to project() the lat, long
so all fixed now.
Thanks for your help and pointing out the R-sig-Geo mailing list which I'll
use in the future should I have other questions.
Thanks
Kate
--
View this message in context:
I'm trying to reproduce the 3rd graph on the page of this site:
http://learnr.wordpress.com/2009/03/17/ggplot2-barplots/ . However, the data
below produces a ggplot with the stacks sorted in alphabetical order from
the bottom up. I'd like the stacks to be in the order Europe, Asia,
Americas,
hello, i am so glad to write you.
i am dealing now with writing my M.Sc in Applied Statistics thesis, titled
Data Mining Classifiers and Predictive Models Validation and Evaluation.
I am planning to compare several DM classifiers like NN, kNN, SVM, Dtree, and
Naïve Bayes according to their
Dear R-Help listers,
I am trying to estimate an proportional odds logistic regression model
(or ordered logistic regression) and then make predictions by
supplying a hypothetical x vector. However, somehow this does not
work. I guess I must have missed something here. I first used the polr
On Oct 18, 2011, at 6:27 PM, Cem Girit wrote:
Hello,
I cannot access the r-help website although after
registration I am getting all the posts sent to the side. Each time
I click
on the Visit Subscriber List on the
https://stat.ethz.ch/mailman/listinfo/r-help site, I get
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