Hello,
I have to compute the pooled z-value and I would like to know which way is
more appropriate
b - c( -0.205,1.040,0.087)
s - c(0.449,0.167,0.241)
n - c(310, 342, 348)
z - b/s
Z - sum(z)/sqrt(length(n))
P - 2*(1-pnorm(abs(Z)))
P
w - sqrt(n)
Zw - sum(w * z)/sqrt(sum(w^2))
Pw - 1 -
6200 MD Maastricht, The Netherlands
Tel: +31 (43) 368-5248
Fax: +31 (43) 368-8689
Web: http://www.wvbauer.com
From: r-help-boun...@r-project.org [r-help-boun...@r-project.org] On
Behalf Of cheba meier [cheba.me...@googlemail.com]
Sent: Thursday, April
and Neuropsychology
School for Mental Health and Neuroscience
Maastricht University, P.O. Box 616
6200 MD Maastricht, The Netherlands
Tel: +31 (43) 368-5248
Fax: +31 (43) 368-8689
Web: http://www.wvbauer.com
--
*From:* cheba meier [cheba.me...@googlemail.com
I installed R 2.12 and it works now, thank you Wolfgang.
Servus
Cheba
library(metafor)
Error: This is R 2.11.0, package 'metafor' needs = 2.12.0
2011/4/8 cheba meier cheba.me...@googlemail.com
I have just installed the package as
install.packages(metafor)
--- Please select a CRAN mirror
:
limits - aes(ymax = OR + (OR - 95%LCI), ymin = OR - (OR - 95%LCI))
ggplot(dataframe, aes(x = Study.Name, y = OR)) + geom_point() +
geom_errobar(limits)
Best,
Scott
On Wednesday, April 6, 2011 at 11:53 AM, cheba meier wrote:
Dear all,
I have a four variable: Stuy.Name, OR, 95%LCI and 95%UCI
Dear all,
I have a four variable: Stuy.Name, OR, 95%LCI and 95%UCI and I would like to
create a meta analysis plot. I can't use meta.MH function in metaplot
because I do not have
n.trt, n.ctrl, col.trt, col.ctrl are not available! Is there an alternative
way to do it?
Many thanks in advance,
Dear all,
I am doing
library(survival)
fit - coxph(Surv(futime,fustat) ~ rx, ovarian)
plot(survfit(fit,newdata=ovarian),col=c(1,2))
legend(bottomleft, legend=c(rx = 0, rx = 1),
lty=c(1,2),col=c(1,2))
Is this correct to compare these two groups? Is the 0.31 the p-value that
the median f
Hello,
I have a data set which is similar to the following data
mice - rep(letters[1:4],10)
outcome - sample(c(0,1),length(mice),replace=T)
group - c(rep(A,length(mice)/2),rep(B,length(mice)/2))
my.data - data.frame(mice,outcome,group)
my.sort.data - my.data[order(my.data[,1]),]
I would like
of both plots...)
HTH
Jannis
cheba meier schrieb:
Hello,
I am using
library(gplots)
to do something like
data(state)
x1 - state.area/1
x2 - x1+round((rnorm(length(state.area),3,3)))
plotmeans(x1 ~ state.region)
Is it possible to plot x2 to x1 in the same graph, something
Hello,
I am using
library(gplots)
to do something like
data(state)
x1 - state.area/1
x2 - x1+round((rnorm(length(state.area),3,3)))
plotmeans(x1 ~ state.region)
Is it possible to plot x2 to x1 in the same graph, something like:
linesmeans(x2 ~ state.region)
Best wishes,
Cheba
Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-
project.org] On Behalf Of cheba meier
Sent: Monday, May 10, 2010 3:02 AM
To: Bert Gunter
Cc: R-help@r
-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
On
Behalf Of cheba meier
Sent: Friday, May 07, 2010 12:46 PM
To: Joris Meys
Cc: R-help@r-project.org; Thomas Lumley
Subject: Re: [R] median of two groups
Hi all,
Thank you for your reply.
if done properly! What does
samples.
median.test-function(x,y){
z-c(x,y)
g - rep(1:2, c(length(x),length(y)))
m-median(z)
fisher.test(zm,g)$p.value
}
Like most exact tests, it is quite conservative at small sample sizes.
-thomas
On Tue, 6 Apr 2010, cheba meier wrote:
Dear all,
What is the right
:
On Fri, 7 May 2010, cheba meier wrote:
Dear Thomas,
I have been running simulations in order me to understand this problem! I
have found something online where the absolute median difference is
computed
and permutations are ran to compute a p-value. Is such a test (if I can
call
it a test
, c(length(x),length(y)))
m-median(z)
fisher.test(zm,g)$p.value
}
Like most exact tests, it is quite conservative at small sample sizes.
-thomas
On Tue, 6 Apr 2010, cheba meier wrote:
Dear all,
What is the right test to test whether the median of two groups are
statistically
Dear all,
What is the right test to test whether the median of two groups are
statistically significant? Is it the wilcox.test, mood.test or the ks.test?
In the text book I have got there is explanation for the Wilcoxon (Mann
Whitney) test which tests ob the two variable are from the same
Dear all,
I am new R user and I am sure that this question has been asked quite often
and I have also googled it and read about it! I understood that in order to
read excel sheet into R you need to open it and saved it as csv or text, is
this true? or you can use read.delim2 and read.csv2 to do
Dear R people,
Is it possible to save three data sets in an R object and to call each data
from this object independently!
Regards,
Cheba
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=test.Rda)
#load them in another session
load(test.Rda)
df1
letter number
1 a 1
2 b 2
3 c 3
df2
letter number
1 d 4
2 e 5
3 f 6
Is that what you're looking for?
Ivan
Le 3/17/2010 11:56, cheba meier a écrit :
Dear R
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