[R] Replacing text with a carriage return

I have a comma separated data file with no carriage returns and what I'd like to do is 1. read the data as a block text 2. search for the string that starts each record record_start, and replace this with a carriage return. Replace will do, or just add a carriage return before it. The

Re: [R] Replacing text with a carriage return

Hello, Instead of replacing record_start with newlines, you can split the string by it. And use 'gsub' to make it prettier. x - readLines(test.txt) x y - gsub(\, , x) # remove the double quotes y - unlist(strsplit(y, record_start,)) # do the split, with comma # remove leading blanks and

[R] Replacing text

Sorry, another newbie question :-( I loaded a data set with 10 rows and 30 columns. The first column is characters for names of car manufacturers: Jeep Nissan Toyota1 Toyota2 Etc. How can I replace Toyota2 with Scion? Thanks again [[alternative HTML

[R] Replacing text

Hi Luciana, Try this: yourData[,1] - sapply(yourData[,1], function(x){ x=as.character(x) x[which(x==Toyota2)]-Scion x } ) # Example set.seed(123) x=c(Jeep,Nissan, Toyota1, Toyota2) y=rnorm(4) DATA=data.frame(x,y) DATA x y 1Jeep -0.56047565 2 Nissan -0.23017749 3

Re: [R] Replacing text

If the column is factor: levels(DATA$x)[levels(DATA$x) == Toyota2] - Scion or character: DATA$x[DATA$x == Toyota2] - Scion On 11/03/2008, Suran, Luciana @ Torto Wheaton Research [EMAIL PROTECTED] wrote: Sorry, another newbie question :-( I loaded a data set with 10 rows and 30