On Tue, 26-Jun-2012 at 11:57PM -0500, Erin Hodgess wrote:
| Hello again:
|
| Here is a solution to the dates without leading zeros:
|
| pou1 - function(x) {
| #Note: x is a data frame
| #Assume that Column 1 has the date
| #Column 2 has station
| #Column 3 has min
|
Hi All,
I have a whole lot of *.raw files in my working folder and I am doing the same
analysis on each of those and want to save all the results in a single file. I
am making some mistake here and can't figure out how to solve it.
Say, the *.raw files are ABCD.raw, EFGH.raw, IJKL.raw ...
Hi guys
i need some help to build choropleth.
Basically i am trying to colour regions on the map by population.
I possess the shape file of the country, and also the population data,
however, i am having trouble to create the plot, below is my code:
population=read.csv(nz2.csv)
population
On Thu, 28-Jun-2012 at 06:27PM +1200, Patrick Connolly wrote:
| On Tue, 26-Jun-2012 at 11:57PM -0500, Erin Hodgess wrote:
|
| | Hello again:
| |
| | Here is a solution to the dates without leading zeros:
| |
[...]
|
| | This is not particularly elegant, but it does the trick.
|
| It's also
Hi Kat,
On Thu, Jun 28, 2012 at 8:22 AM, kat_the_great k...@hotmail.com wrote:
Dear R Users:
I'm a STATA user converting to R, and I'd like to be to do the following.
#Assign var_1 and var_2 a value
10-var1
20-var2
#Now I'd like to print the values of var_1 and var_2 by looping through
I believe chambers book has an example using S4 classes. which isnt much
help for a beginner.
you can do it the old school way. build it by hand with one vector of
pointers and another data structure of leaf nodes. there is nothing magical
about a tree. you can build one in basic or fortran.
Hello,
You can find some hints there:
http://geography.uoregon.edu/geogr/topics/index.html
Regards
Le 12/06/28 14:26, iverson a écrit :
Hi guys
i need some help to build choropleth.
Basically i am trying to colour regions on the map by population.
I possess the shape file of the country,
Hi James,
On Thu, Jun 28, 2012 at 12:33 AM, James Holland holland.ag...@gmail.com wrote:
I need to look through a dataset with two factor variables, and depending
on certain criteria, create a new variable containing the data from one of
those other variables.
The problem is, R keeps making
Hello,
Try the following.
txt - TheWeatherIsVeryNice
Up - strsplit(txt, [[:lower:]]*)
Up[Up != ]
Hope this helps,
Rui Barradas
Em 27-06-2012 20:15, mdvaan escreveu:
t - TheWeatherIsVeryNice
How do I extract the upper case letters? - TWIVN
Thanks!
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Hello all,
When I wanted to use package foreach, I got the Error.
That is:
library(foreach)
Error in get(Info[i, 1], envir = env) :
internal error -3 in R_decompress1
Error: package/namespace load failed for foreach
I am using R-2.14.2, 64 bit. Even I reinstalled R and package foreach,
the
Hello,
Another way is to use index vectors:
v1.factor - c(S,S,D,D,D,NA)
v2.factor - c(D,D,S,S,S,S)
td2 - test.data - data.frame(v1.factor,v2.factor)
for (i in 1:nrow(test.data) ) {
[... etc ...]
} #End FOR
# Create index vectors
na1 - is.na(v1.factor)
na2 - is.na(v2.factor)
# Create
-BEGIN PGP SIGNED MESSAGE-
Hash: SHA1
On 27/06/12 22:02, Xuefeng Gao wrote:
Hello,
I have R script my_script.R . It loads a large input file data.txt and then
outputs a large
matrix out. (the command of running it on cluster using my.cmd is put at
the end)
You will get much more
Hello,
Did you try by upgrading your version of R?
Regards
Le 12/06/28 16:27, Zhipeng Wang a écrit :
Hello all,
When I wanted to use package foreach, I got the Error.
That is:
library(foreach)
Error in get(Info[i, 1], envir = env) :
internal error -3 in R_decompress1
Error:
Dear Oettli,
I installed three ver R in my machine, 2.14.2, 2.15.0 and 2.15.1. foreach
could be called in the latter 2, though in 2.15.0, there is a warning
message: package foreach was built under R version 2.15.1 .
Maybe it is OK to just use R 2.15.1, but at present I have problem to use R
Hello,
I use neither Eclipse nor StatET. Thus, I can't help you further.
Good luck
Regards
Le 12/06/28 17:14, Zhipeng Wang a écrit :
Dear Oettli,
I installed three ver R in my machine, 2.14.2, 2.15.0 and 2.15.1. foreach
could be called in the latter 2, though in 2.15.0, there is a warning
What is the size of the boostrapped subsample in ecodist mantel()
thanks
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
Hello,
I'm trying to fit experimental data with a model and nls.
For some experiments, I have data with x from 0 to 1.2 and the fit is quite
good.
But it can happen that I have data only the [0,0.8] range (see the example
below) and, then, the fit is not correct.
I would like to add a
Hello,
You are replacing the values of runif each time through the loop. And
it's not just that, every time through, you are setting outcome[, 1] and
outcome[, 2] to the same values. Simply put, the loop is not needed.
Corrected:
n - 100 ## patients per trial
trials - 3 ## 3 trials
med -
Uwe, sorry for the HTML. In answer to your post: I did try to contact
the developer, no response. but a colleague pointed me to a way out
yesterday through the RCurl and XML packages:
library(RCurl)
library(XML)
endpoint - http://qcrumb.com/sparql;
query - PREFIX sdmx-measure:
Hello,
This seems simple:
# 100 Bernoulli trials
x - sample(c(0,1), 100, replace = TRUE)
image(1:10, 1:10, matrix(x, 10), col=0:1)
Hope this helps,
Rui Barradas
Em 27-06-2012 17:06, vp726 escreveu:
Hi,
I'm wondering if I can do this in R. I have a data set with questions
(x-value) and
Hi
Do I have to load/download the whole package over and over again everytime
when I use the R-Project?
It often prompt me the error message could not find function- but I'm
rather sure I have used the function before so I'm not entirely sure it
couldn't find it again when I shut down the
On 28/06/2012 08:27, Zhipeng Wang wrote:
Hello all,
When I wanted to use package foreach, I got the Error.
That is:
library(foreach)
Error in get(Info[i, 1], envir = env) :
internal error -3 in R_decompress1
Error: package/namespace load failed for ‘foreach’
I am using R-2.14.2, 64 bit.
Dear list,
I have a small feature request regarding the implementation of
'file.path()':
It'd be great if 'file.path()' would allow to specify an input *vector*
instead of solely rely on a specification via the three dot argument.
AFAIU, currently it's only possible to manually specify
Hello,
Which function?
Regards
Le 12/06/28 18:29, codec cat a écrit :
Hi
Do I have to load/download the whole package over and over again everytime
when I use the R-Project?
It often prompt me the error message could not find function- but I'm
rather sure I have used the function before so
Dear list-members,
I have done optimization of 3 parameters by maximum likelihood method using
conjugate gradient as optimizer. Since I have the reported value of the
parameters from an article, I can validate the result of the optimized
parameters. The problem is that optimizer converges to
On 28/06/2012 10:40, Janko Thyson wrote:
Dear list,
I have a small feature request regarding the implementation of
'file.path()':
Clearly you have not read where and how to make feature requests
(R-devel list or Wishlist on bugs.r-project.org).
It'd be great if 'file.path()' would allow to
Clearly you're right - and polite... as always
I asked the question because I wanted to avoid 'paste(x, collapse=/)'
and 'do.call(file.path, as.list(x))' because it's less efficient than
'file.path()' and '?file.path()' explicitly recommends *not* using
'paste()' for putting together file
Hello,
Can't you just use vectors? Untested example:
var[1] - 10
var[2] - 20
y - 1
while(y 3) {
print(var[y])
y - y+1
}
Take care
Oliver
On Wed, Jun 27, 2012 at 8:22 PM, kat_the_great k...@hotmail.com wrote:
Dear R Users:
I'm a STATA user converting to R,
Dear codec cat,
Once you installed an R package, you do not have to install it again.
But, you have to load the package when you change your workspace.
Best
Ozgur
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Dear Kathie,
Try
c(filter(1:10, rep(1, 3)))
Best
Ozgur
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__
You can set it using the pboot argument.
Sarah
On Thursday, June 28, 2012, nevil amos wrote:
What is the size of the boostrapped subsample in ecodist mantel()
thanks
[[alternative HTML version deleted]]
__
R-help@r-project.org
On 06/28/2012 03:26 PM, iverson wrote:
Hi guys
i need some help to build choropleth.
Basically i am trying to colour regions on the map by population.
I possess the shape file of the country, and also the population data,
however, i am having trouble to create the plot, below is my code:
Hi,
I don't see how this is an R question. You add references in whatever way
is appropriate for your word processor or document preparation method and
your bibliographic software. R is neither of those things, though
citation() is rather underused.
Sarah
On Wednesday, June 27, 2012, quantum
Dear all,
I have a vector of length 1 but within this vector there are 9 elements
vectorNOcorrection
[1] (O, O, O, H, L, O, O, O, O)
can someone help me with how I can have it as with 9 element separated
such that it will have length 9 as O, O, O, H,L, O, O, O,
O
Kind regards,
Jessy
You can use gsub() to eliminate the parentheses, and strsplit() to separate
the elements.
Sarah
On Thursday, June 28, 2012, Jessy wrote:
Dear all,
I have a vector of length 1 but within this vector there are 9 elements
vectorNOcorrection
[1] (O, O, O, H, L, O, O, O, O)
can someone help
summary(model.avg(...)) gives much more information.
pozdrowienia,
kamil
Dnia 2012-06-28 12:00, KKulmakatarzyna.ku...@ebc.uu.se pisze:
Message: 60
From: KKulmakatarzyna.ku...@ebc.uu.se
To:r-help@r-project.org
Subject: Re: [R] MuMIn Problem getting adjusted Confidence intervals
Hello,
I seem
Hello,
Try
x - (O, O, O, H, L, O, O, O, O)
strsplit(gsub(\\(|\\)|[[:blank:]], , x), ,)
Note that the result is a list, not a vector. You can then use `[[` or
unlist().
Hope this helps,
Rui Barradas
Em 28-06-2012 11:42, Jessy escreveu:
Dear all,
I have a vector of length 1 but within
I was using omega function
How do I load the package again (install it from server again?) and is
there a way to check which workspace was used in history?
On 28 June 2012 10:45, Pascal Oettli kri...@ymail.com wrote:
Hello,
Which function?
Regards
Le 12/06/28 18:29, codec cat a écrit :
Hello,
To load the package:
library(name_of_package)
Regards
Le 12/06/28 20:02, codec cat a écrit :
I was using omega function
How do I load the package again (install it from server again?) and is
there a way to check which workspace was used in history?
On 28 June 2012 10:45, Pascal
How do I load the package again (install it from server again?)
library(omega)
there a way to check which workspace was used in history?
Unless you do not save it, you will use a fresh one.
Ozgur
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Samantha Sifleet Sifleet.Samantha at epamail.epa.gov writes:
Hi List,
I am hoping some of you have experience with the spdep package.
I have had success with lm.morantest and lm.LMtests.
I am trying to run a spatial error model and I keep getting the following
error
This is not a criticism of R, but R runs much slower on one of my machines than
it does on the others, so something is wrong with that machine, but I don't
know where to look for a remedy. Here are the details:
I have a 32-bit win xp machine running at 2.66Ghz and a 64-bit win 7 machine
On Jun 27, 2012, at 3:11 AM, ericlsh wrote:
I would like to compare the incidence rates of three groups. They are
supposed to have different risks so I would like to test whether there is a
increasing trend in the incidence rates. Does R or any packages provide a
trend test for incidence
PtitBleu ptit_bleu at yahoo.fr writes:
Hello,
I'm trying to fit experimental data with a model and nls.
For some experiments, I have data with x from 0 to 1.2 and the fit is quite
good.
But it can happen that I have data only the [0,0.8] range (see the example
below) and, then, the fit
Hello everyone I am new to R
I need to plot 3 indifference curve for the level 100, 200 and 300
my utility function is of the form u(x,y)=3x^2+2y
I also need to draw contour line on it
can any one please tell me how to do it
[[alternative HTML version deleted]]
Hi, all together. I have - a maybe trivial - problem with aggregating a
list of weights.
Here is the problem:
- At first I have set of nodes (X/Y-coordinates) and associated weights,
where the set
of nodes is typically not unique
- I want to get a set of unique nodes and the sum of
Dear all,
I have two highly correlated variables (y and x), and both of them depend
on a third variable (A, for Area). Multiple regression (y=a+(b*x)+(c*A))
would have collinearity problems, so I decided to do a partial regression
to predict y. I did it this way:
- I regressed y to A, and
Yeah, the reason I didn't use ifelse is because I've got multiple variables
to manipulate based on the if statement, some factors and some numeric. I
have to look at the factor variables, and based on that, either use one
series of variables or another.
With the multiple if statements I need to
Dear R users,
I'd like to remove some descriptions when I use filter.
filter(1:10, rep(1, 3))
Time Series:
Start = 1
End = 10
Frequency = 1
[1] NA 6 9 12 15 18 21 24 27 NA
That is, I want only this
[1] NA 6 9 12 15 18 21 24 27 NA
Thank you in advance.
Kathie
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Greetings,
I am trying to understand how to making a subset assignment function.
Take the example where of making a last generic function.
last - function(x,...) UseMethod(last);
last.numeric - function(x, ...) x[length(x)]
last.list - function(x, ...) x[[length(x)]]
.
Now we run into
Hi
Newbie question:
I have a set of data frames that I want to do the same calculations on each.
I've found out that I can put them in a list and loop through the list
to do the calculation, but not put the results back into each
data.frame..
For example three data frames cats, dogs, birds
That is very helpful, and exactly what I was looking for!
However, I seem to have some problems. When I ran the following line:
aggregate(SunScore ~ h, data=dat, mean)
I got the following output:
h SunScore
1 0 136.01389
2 1 135.27632
3 2 127.03704
4 3 127.17105
5 4 129.94545
6
Hi friends,
I need to generate a list, that should contain the quantile value of one
column in a data frame. while I am compiling this one i am facing one bug,,
Really I cannot find out that where the problem has occurred? Could any one
help me to come out from this bug??
Here is the code,
Hi,
It isn't surprising that convergence results depend on initial par
values in a nonlinear optimization problem. There might be local maxima
in the landscape defined by your likelihood function and you have to
explore it for the proper starting places.
One suggestion is to try many
- Forwarded Message -
From: arun smartpink...@yahoo.com
To: mdvaan mathijsdev...@gmail.com
Cc: R help r-help@r-project.org
Sent: Thursday, June 28, 2012 1:44 AM
Subject: Re: [R] Extract upper case letters
Hi,
Try this:
t - TheWeatherIsVeryNice
t1-gsub([:A-Z:],,t)
t1
[1]
Hi,
You could also use rollapply () from zoo
library(zoo)
t2-as.numeric(rollapply(1:10,3,sum))
[1] 6 9 12 15 18 21 24 27
t1-c(filter(1:10, rep(1, 3)))
t1-t1[!is.na(t1)]
identical(t1,t2)
[1] TRUE
A.K.
- Original Message -
From: Özgür Asar oa...@metu.edu.tr
To:
data? We really should see some sample data. See ?dput for a way to supply
some.
John Kane
Kingston ON Canada
-Original Message-
From: sureshmallika...@gmail.com
Sent: Thu, 28 Jun 2012 01:58:30 -0700 (PDT)
To: r-help@r-project.org
Subject: [R] How can I make a list using
Dear All,
I have a question of how to export S4 class specification to
clusters/workers in parallel computing. The package I used is snowfall. The
problem is reproducible as follows. Any hint is greatly appreciated.
Edwin Sun
=== begin ===
library(snowfall)
sfInit(parallel = TRUE, cpus
I am executing the following loops in R 15.1.0 and the first one works and
produces results. However, the second one is not with initiating the object
as x[i]. Further, I was able to get the second loop work in R 15.0. Am I
missing something here?
for(i in 1:length(b))
{y[i]-paste(a,b[i],c,sep=)
Something like this may do it.
http://stackoverflow.com/questions/6919025/how-to-assign-colors-to-categorical-variables-in-ggplot2-that-have-stable-mappin
John Kane
Kingston ON Canada
-Original Message-
From: david_ly...@yahoo.com
Sent: Wed, 27 Jun 2012 09:07:53 -0700 (PDT)
To:
I think the big mystery is how you got hold of R 15.1.0. :-)
(sorry, couldn't resist. Presumably you mean R2.15.x)
More seriously, I thinkwe would need to be told more, e.g. what are a, b,
and c? My guess is that you either have x or y defined already, so check to
see if they exist at the point
Workspaces do not store loaded packages. It is necessary to re-execute the
library functions for each session, even if you re-load the workspace. Also,
environment variables defined within R must be redefined using the same R
Sys.setenv() function calls as originally used. This is why keeping
Hello all,
I have a txt file with some data which isn't in any organized form like a
table, but just simple text.
Is there any way to read the file char by char and store the necessary
characters?
Regards,
Himanshu Mittal
[[alternative HTML version deleted]]
On 28/06/2012 10:39, dj hawthorne wrote:
Greetings,
I am trying to understand how to making a subset assignment function.
Take the example where of making a last generic function.
last - function(x,...) UseMethod(last);
last.numeric - function(x, ...) x[length(x)]
last.list - function(x,
I see at least 4 issues with trying this.
1) I am on record several times that CG was the LEAST SUCCESSFUL of the codes I
put in my
1979 book and which is CG in optim().
2) Rcgmin is better (I implemented this, but the method is Yuan/Dai), and there
may be
other CG codes that can squeeze a bit
Hi Jan,
You can do it in two ways. The simplest one is the following.
The first option is to use $. Here is how:
dogs - data.frame(a = 1:10, b = 10:1)
dogs$c - dogs$a+dogs$b
dogs
The second way it to use
?within
Contact
Try: survfit(Surv(Time, 1-Status)~1)
On Wed, Jun 27, 2012 at 5:37 AM, niloo javan niloo_ja...@yahoo.com wrote:
Hello
In (survfit(Surv(Time,Status)~1))
I want to have status=0 as Failure and status=1 as Censore.
Changing above formula to (survfit(Surv(Time,Status)~0)) doesnot help!!
What
Thank you, Sina,
thank you, David,
I knew how to access the code of sunflowerplot.formula() and that
sunflowerplot() does work in the default version, i.e., w/o formula (but
your suggestions triggered my ambition ;-)).
Below is my -- slightly commented -- version (the search for which was
On Thu, Jun 28, 2012 at 8:47 PM, James Holland holland.ag...@gmail.com wrote:
With the multiple if statements I need to check for, I though for statements
with the if/else if conditional statement was better than nested ifelse
functions.
for () gives you a lot of flexibility at the expense of
Hello,
The only explanation I'm seeing is you are computing the SunScore
averages using different datasets. With the dataset oyu've dput-ed I get
your hand results.
aggregate(SunScore ~ h, data=dat, mean)
h SunScore
1 0 131.0167
2 1 107.7436
# Another way of doing the same
Take a look at scan and/or readLines
Michael
On Jun 28, 2012, at 9:02 AM, HIMANSHU MITTAL hm3...@gmail.com wrote:
Hello all,
I have a txt file with some data which isn't in any organized form like a
table, but just simple text.
Is there any way to read the file char by char and store the
Hi!
I am getting a lot of numbers in the background of the pca screeplots if i use
call(plot) and eval(somecall).
Til now, creating the calls and plotting later on this way worked fine. Example:
pcaI-prcomp(iris[,1:4])
plot(pcaI)
x-call(plot,pcaI)
eval(x)
Anyone got an idea how i can
Hi Jessica,
x - call(plot, quote(pcaI))
eval(x)
that said, I suspect you would be better off avoiding this idiom
altogether. Storing unevaluated calls is akin to putting tomatoes on
your sandwich before packing it for work---you can do it but you end
up with a soggy sandwich by the time you are
Hello,
Sorry if I've misread your original post.
See answer inline
Em 28-06-2012 05:15, Mohan Radhakrishnan escreveu:
Not being the expert I have looked at papers like 'simpleR { Using R for
Introductory Statistics' by John Verzani. Some sample Code is in these
papers. Looks like I have to
Thanks Josh,
that soggy sandwhich saves me a LOT of code by the way,
I'll keep it for the time being ;)
greetings
Jessica
On 28.06.2012, at 17:15, Joshua Wiley wrote:
Hi Jessica,
x - call(plot, quote(pcaI))
eval(x)
that said, I suspect you would be better off avoiding this idiom
Yes. One usually creates a call object when one need to modify it in some
way -- e.g. alter arguments, change the function -- prior to evaluation.
That doesn't seem to be the case here.
Why isn't plot(pcal) acceptable?
?do.call
is also a more straightforward way to create and evaluate a call
Hello Marcin,
did you get the answer to your questions. I have the same questions and
would appreciate your help if you found the answers.
Thanks,
Ankur
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I am having problems installing package rggobi. I have spent days reading
other people's questions about this topic but could not get any useful info
out of previous answers. I am running 32-bit Windows 7 and have successfully
installed GGobi version 2.1.8.
My error looks like this:
colors - c(red, blue, darkgreen, gold, black)
labels - c(3/02/2012,12/30/2011,4/20/2012)
In plot I use
{
plot(x, hx1 , type=l, lwd=2, tck=1, col=colors[1], ylim=c(0, maxhx), xlab=x
value, ylab=Density, main=AAPL)
.
.
.
labels, lwd=2, lty=c(1, 1, 1, 1, 2), col=colors)
}
It looks like qplot
Thanks for your reply Jon.
I need to actually do more than print the name of the variable (I just made
the example simpler). I need to manipulate var_1, var_2 etc. but setting
values of NA to 0.
So as you said, 1. if you want to display the variable, just type it
var_1
But how do I do this
Hi Oliver,
Thank you for your reply.
I can't use vectors as each var_1, var_2 is a new column/variable, not a new
observation within a vector.
But thank you,
Kat
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Dear R Users,
I ask the following question in order to learn more on the use of 'assign' and
'paste' functions and for loop; otherwise what I am asking could be solved by
binding the various first differences of the series using the 'ts.union'
operator.
The problem is:
I have several
On Thu, Jun 28, 2012 at 8:27 AM, Jessica Streicher
j.streic...@micromata.de wrote:
Thanks Josh,
that soggy sandwhich saves me a LOT of code by the way,
I'll keep it for the time being ;)
There may be other ways. With no knowledge of your context, obviously
I cannot say absolutely that
Hi freind,
My data seems to be like , and data frame name is comb.data
sequence weight rsat. zFEl
1CCTTGTT4.6 0.00058 -7.452 3.237
2ACTTTGAGGTG4.1 0.00077 -7.169 3.114
3GTCTTGAACTC4.8 0.00055 -7.506 3.260
4 GCTTTGAAGAA
Hello,
Try the following.
dd - data.frame(A=letters[1:10], var_1=1:10, var_2=11:20)
index - grep(var_, names(dd))
for(i in index)
print(dd[[ i ]]) # or dd[, i]
#
vars - paste(var, 1:2, sep=_)
for(v in vars)
print(dd[, v]) # or dd[[ v ]]
There's nothing you can do in Stata
Hello,
Your data is a mess, with more columns than column names.
Use
# 20 to 100
dput(head(comb.data, 30)) # paste the output of this in a post.
Anyway, it seems that what you want is (untested)
aggregate(zFEl~sequence, data=comb.data, quantile, probs=c(0.5,0.8,0.9),
na.rm=T)
Hope this
Hi
Thanks for your reply Jon.
I need to actually do more than print the name of the variable (I just
made
the example simpler). I need to manipulate var_1, var_2 etc. but setting
values of NA to 0.
Why? R has pretty strong system for handling NAs. The only exception AFAIK
is cumsum
Hi
I use R for quite a long time and as I remember I did not use such assign
paste i loop yet. Insted of such construct with polluting environment with
plenty of objects named something(i)somethingelse it is always advisable
to use lists.
When you want to shorten variables to some common
Well, you didn't tell us anything about your data, but plot() has to create
space to draw ncol(mydataSNc)^2 plots. Depending on your graphics device, if
you have more than about 45 columns in mydataSNc, you will hit the limit -
although the plots will be illegible well before that.
On 28/06/2012 15:09, YTP wrote:
I am having problems installing package rggobi. I have spent days reading
other people's questions about this topic but could not get any useful info
But not apparently the rw-FAQ, which would only take minutes. See the
posting guide
out of previous
Hello.
I have 5 measurement points, my dependent variable is ordinal (0 - 3), and
I want to visualize my data. I'm pretty new to R.
What I want is to find out whether people with different baseline
covariates have different trajectories, so I want a plot with the means
trajectory of my dependent
You can be sure that it is reliable!
Ozgur
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