Thanks for your answer. But I have a strange question that I don't
know how to explain and I really don't know how to spot the
problematic part.
Suppose I have a long list of age, gender and bmi from a data.frame
called msltdata.
age - msltdata$age
gender - msltdata$data
bmi -msltdata$bmi
Hi,
If I have two vectors x and y and I do lm(y~x) and now I want to define
variables that are the standard errors of the slope and intercept, how do I
do that?
Thanks,
Alex
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing
stderr_int - summary(lm(y ~ x))$coefficients[1,2]
stderr_slope - summary(lm(y ~ x))$coefficients[2,2]
Jeff.
On Oct 3, 2007, at 3:01 AM, Alexander Moreno wrote:
Hi,
If I have two vectors x and y and I do lm(y~x) and now I want to
define
variables that are the standard errors of the slope
Yes, I tried. Wrong calculation.
On 10/3/07, Stefan Grosse [EMAIL PROTECTED] wrote:
On Wednesday 03 October 2007 08:23:15 Chung-hong Chan wrote:
CC
CC Suppose I have a long list of age, gender and bmi from a data.frame
CC called msltdata.
CC
CC age - msltdata$age
CC gender -
BL == Birgit Lemcke [EMAIL PROTECTED]
on Mon, 1 Oct 2007 17:30:16 +0200 writes:
BL When I try to load the DCluster package I get the
BL following error message (R 2.5.1; PowerBook G4; Mac OS X
BL 10.4.10)
BL (Load needed package) Lade n�tiges Paket: spdep
BL (error:
On Tuesday 02 October 2007 22:54:48 Matthew Dubins wrote:
MD in what respects do R routines work faster/more efficiently/more
MD accurately than those of MATLAB/SPSS.
There has been a benchmark:
http://www.sciviews.org/benchmark/index.html
but thats quite old old, it would be interesting to
I found you online...
Can you help with empirical probability?
Hi Partha. I really liked your email that you sent me, it really inspired me. I
have been breezing through the chapters, and doing quite well, You should be a
teacher. After all the time my college instructor spent with the
Dear listers,
I'm using gam(from mgcv) for semi-parametric regression on small datasets(10 to
200 observations), and facing a problem of overfitting.
According to the help, it is suggested to avoid overfitting by inflating the
effective degrees of freedom in GCV evaluation with increased gamma
I don't think it is so much that the R routines
work faster/more efficiently/more accurately
but that the user works faster/more efficiently/
more accurately.
Patrick Burns
[EMAIL PROTECTED]
+44 (0)20 8525 0696
http://www.burns-stat.com
(home of S Poetry and A Guide for the Unwilling S User)
On 03/10/2007 2:23 AM, Chung-hong Chan wrote:
Thanks for your answer. But I have a strange question that I don't
know how to explain and I really don't know how to spot the
problematic part.
Suppose I have a long list of age, gender and bmi from a data.frame
called msltdata.
age -
Dear All,
Some simple interpretation assistance.
I am producing regression trees, based on a set of 10 continuous predictors.
Have cross validated to fit the model to minimum deviance, prior to summary
output.
I have not found a source that clearly states the meaning of the residual
mean
zhijie zhang wrote:
Dear friends,
The following is an example to explain my question. I want to get a
legend which will show the z-values according to different colors in image()
function.
x-sort(runif(10)) #x-coordinates
y-sort(runif(10)) #y-coordinates
z-matrix(runif(100),nrow=10)
Yeah, it works fine now.
I think I need to modify my function to check for factor.
Regards,
C
On 10/3/07, Duncan Murdoch [EMAIL PROTECTED] wrote:
On 03/10/2007 2:23 AM, Chung-hong Chan wrote:
Thanks for your answer. But I have a strange question that I don't
know how to explain and I
On Wed, 3 Oct 2007, Patrick Burns wrote:
I don't think it is so much that the R routines
work faster/more efficiently/more accurately
but that the user works faster/more efficiently/
more accurately.
And in particular a user can do many informative/insightful/penetrating
Hi R-list members,
Could somebody explain to me the meaning of the '.' in the formula
SumTL~. below? I could not find it in the help pages. I'm guessing it is
substituted by v1+v2+v3+.. for all independent variables vi.
Furthermore, I would like to add interaction effects to the model,
is this
How can i print only the P-Value of the kolmogorov smirnov test?
ks.test(VeriSeti1, VeriSeti2)
Two-sample Kolmogorov-Smirnov test
data: VeriSeti1 and VeriSeti2
D = 0.5, p-value = 0.4413
alternative hypothesis: two-sided
This expression gives me the whole test results, i need only
I appreciate your quick reply.
I am using the model of the following structure :
fit - gam(y~x1+s(x2))
,where y, x1, and x2 are quantitative variables.
So the response distribution is assumed to be gaussian(default).
Now I understand that the data size was too small.
Thank you.
Best Wishes,
I've rolled up R-2.6.0.tar.gz a short while ago. This is a development
release which contains a number of new features. In particular, the handling
of data with a large number of identical strings should be more
memory-efficient.
Also, a number of mostly minor bugs have been fixed. See the
I want to use the plot(model) function to generate Tukey-anscomb and Q-Q plots
of a lm(). I manage to change all labels but the main one which apparently is
neither main or sub. So far I have tried as par setting: cex (changes symbol
size within the plot), cex.main (no effect), cex.sub (no
ks.test(x,y)[2]
On 10/3/07, Emre Unal [EMAIL PROTECTED] wrote:
How can i print only the P-Value of the kolmogorov smirnov test?
ks.test(VeriSeti1, VeriSeti2)
Two-sample Kolmogorov-Smirnov test
data: VeriSeti1 and VeriSeti2
D = 0.5, p-value = 0.4413
alternative hypothesis:
Thanks for sending the data...
The problem is triggered by only having one observation per district, so that
you have a random effect for each datum. This causes the correlation of the
parameter estimates/predictions for the smooth term to become so high that
covariance matrix of the smooth
On Wednesday 03 October 2007 10:49, Ariyo Kanno wrote:
I appreciate your quick reply.
I am using the model of the following structure :
fit - gam(y~x1+s(x2))
,where y, x1, and x2 are quantitative variables.
So the response distribution is assumed to be gaussian(default).
Now I understand
On 03/10/2007 5:41 AM, [EMAIL PROTECTED] wrote:
I want to use the plot(model) function to generate Tukey-anscomb and Q-Q
plots of a lm(). I manage to change all labels but the main one which
apparently is neither main or sub. So far I have tried as par setting: cex
(changes symbol size
On Wed, 3 Oct 2007, [EMAIL PROTECTED] wrote:
I want to use the plot(model) function to generate Tukey-anscomb and Q-Q
plots of a lm(). I manage to change all labels but the main one which
apparently is neither main or sub. So far I have tried as par setting:
cex (changes symbol size within
Try
str(ks.test(VeriSeti1, VeriSeti2)) # see ?str
then
ks.test(VeriSeti1, VeriSeti2)$p.value
Med venlig hilsen
Frede Aakmann Tøgersen
-Oprindelig meddelelse-
Fra: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] På vegne af Emre Unal
Sendt: 3. oktober 2007 11:32
Til:
Hi
Paul Smith wrote:
Dear All,
With the following code:
pdf(file=figure.pdf,family=URWPalladio)
plot(0,0,type=n)
text(0,0,expression(integral(f(x)*dx, a, b)))
dev.off()
the integral symbol gets horrible. With other fonts, the same does not
occur. Is there some way of using
On 10/3/07, Paul Murrell [EMAIL PROTECTED] wrote:
With the following code:
pdf(file=figure.pdf,family=URWPalladio)
plot(0,0,type=n)
text(0,0,expression(integral(f(x)*dx, a, b)))
dev.off()
the integral symbol gets horrible. With other fonts, the same does not
occur. Is there some
I want to get a sample of some arbitrary size from a population having only two
values 0 and 1 with replacement, but with different probability for selection.
For example 0 will be selected with probability 0.4 and 1 with 0.6. I could use
sample function i.e. sample(c(0,1), 30, T) to get this,
Hello,
I have a script in R language that makes sorting using the order() method of
R language. What I need is to reimplement this method in any other language
(PHP, Perl, Python, Java maybe).
First I tried to reimplement it in php, here is some numbers that i need to
sort:
I am using R.2.4.1 on Windows XP 5.1 (SP 2).
I have the following line in my R code.
Analysis=anova(lm(PM ~ x))
It works the first 60 or so times it is called but
then I get the following error message.
Error in lm.fit(x, y, offset = offset, singular.ok =
singular.ok, ...) : 0 (non-NA) cases
hi,
i was trying to perform a function from the RDCOMClient package. to make
it short: i tried to run the example in ?.COM, namely
e - COMCreate(Excel.Application)
books - e[[Workbooks]]
as soon as e[[Workbooks]] is called, the RGUI crashes. debugging the
function .COM reveals that somehow the
I have generally found that both RDCOMClient and rcom do work although
around the time of new R versions one might be ready for it before the other
so try both.
On 10/3/07, Marcin Kopaczynski [EMAIL PROTECTED] wrote:
hi,
i was trying to perform a function from the RDCOMClient package. to make
Hello, Thierry
Thank you for the fast reply
actually my php script is not correct, the correct logic is R script, by
writing this peace of code in php I tried to do the same logic that R script
does. But this php programm algorirm probably is not correct so results are
incorrect also.
I am
Sorry, let me fix 1 sentence.
Here I try to mean by overfitting that GCV was significantly SMALLER
than the mean square error of prediction of the validation data, which
was randomly selected and not used for regression.
Thank you for valuable advices.
I'm sorry Dr. N. Wood that by mistake I
Here I try to mean by overfitting that GCV was significantly SMALLER
than the mean square error of prediction of the validation data, which
was randomly selected and not used for regression.
--- so you could try increasing gamma until this is no longer the case.
--
Simon Wood,
1. you could place the commands in a file and source the file each
time you want to run it or it might be good enough to place it on the
clipboard and then just do source(clipboard)
2. Thomas Lumley's defmacro in R News 1/3 could be used
Neither of these two require that you do anything special
Thank you for valuable advices.
I'm sorry Dr. N. Wood that by mistake I sent this reply firstly to
your personal e-mail address.
I will use the min.sp argument when the data size is very small. I'd
like to know if there is any criteria for selecting min.sp.
I compared gamma=1.0 and 1.4, and I
Hello Randy
I get emails like this quite a lot.
The most likely problem is in the installation of
the gsl library. To verify that it is in fact installed,
try to compile and run the little Bessel function
example given in gsl-ref, section 2.1.
Get this working first. If it works, this means
Thank you for your advices.
I will try even increased gamma values, and all-out cross-validations.
2007/10/3, Frank E Harrell Jr [EMAIL PROTECTED]:
Ariyo Kanno wrote:
Sorry, let me fix 1 sentence.
Here I try to mean by overfitting that GCV was significantly SMALLER
than the mean square
Ariyo Kanno wrote:
Sorry, let me fix 1 sentence.
Here I try to mean by overfitting that GCV was significantly SMALLER
than the mean square error of prediction of the validation data, which
was randomly selected and not used for regression.
Thank you for valuable advices.
If your test
Newbie here (to R) and running Linux...
install.packages(gsl,~/R)
...
trying URL 'http://cran.wustl.edu/src/contrib/gsl_1.8-4.tar.gz'
Content type 'application/x-tar' length 57051 bytes
opened URL
==
downloaded 55Kb
* Installing *source* package
Dae-Jin,
Thanks for your (offline) persistance: you are right the problem is with
`gamm'. There was a dimension dropping error in `formXtViX' (called by
`gamm') for group sizes of 1 (as occurs when you have a random effect per
observation). This will be fixed in mgcv_1.3-28.
best,
Simon
On
Thanks for the suggestions, Gabor!
On 03-Oct-07 12:52:51, Gabor Grothendieck wrote:
1. you could place the commands in a file and source the file each
time you want to run it or it might be good enough to place it on the
clipboard and then just do source(clipboard)
Using the file solution is
Vladimir Eremeev wrote:
XpeH wrote:
I am trying to understand how the order method in R language works, and
then I'd like to do the same in some other language.
1. Type order in R command prompt (without ( and )) and press enter.
This will print you the body of this function, so
Hi
[EMAIL PROTECTED] napsal dne 03.10.2007 14:56:19:
I am using R.2.4.1 on Windows XP 5.1 (SP 2).
Upgrade R. Version 2.6.0 is imminent.
I have the following line in my R code.
Analysis=anova(lm(PM ~ x))
It works the first 60 or so times it is called but
then I get the following
Dear all
Sorry to bother you.
I have a GLS model:
modela-gls(pop2~pop1-1 + ccs + pop1:ccs,data=data2,corr = corSpher(c(5, 0.5
),form = ~ latitude + longitude, nugget = TRUE), method = ML)
I was wondering how I can work out how much variance is explained by the model
AND by each term.
Any
Hello,
I have a question regarding the use of an offset term with survreg(),
in the Survival library. In particular, I am trying to figure out on
what scale the offset term should be.
Here's a simple example with no censoring and no coefficients:
-
y = rlnorm(1000, meanlog = 10, sdlog
--- Farrel Buchinsky [EMAIL PROTECTED] wrote:
How do you create a table from a data frame? I tried
as.table(
name.of.data.frame) but it bombed out.
I will include the exact error message in my next
posting. If I recall
correctly, it said that the data.frame could not be
coerced to a
Did you check whether 'junk4.RData' was created and what its length was
- maybe an empty file is being created. Is there some sort of quota or
permissions problem? My suggestion would be to look at the size and
permissions on the directory and the file. If you need more help, I
would
Hi list,
I'm currently processing textual data and I would really appreciate some
help with one off my problems.
I have a set of strings and I want to count how often each of this
strings appears in this set.
This is not very difficult and can be done as:
TB-table(my_set)
plot(TB)
However, I
How do you determine if one string is a subset of another? Does it
only match at the beginning, or anywhere? How large is your set of
strings? Can you use table as you describe and then determine what
the groupings of subsets are and then just add the numbers together?
You can use grep/regexpr
Hi all,
I am using R trying to get a inverse matrix of (X^T)X , but I keep getting
the error
message like: no b argument and no default value for sprintf(gettext(fmt,
domain = domain), ...) .
# my code
To everyone who answered
Many thanks for the explanations. I think I see what
is happening now
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
Tony,
Thanks for return. Actually, the data object 'junk4.RData' was created but
have size 0. It seems no data was saved. But the real data that I
want to load have data in it, which I can't load use my own user account.
But if using other people's user account under the same system, it can be
I thought about this some more, and I'm not sure that possibility is
to blame. In my time-dependent model, I don't think I'm doing
anything different than is done for transplant in the Stanford
Heart Study (the often used example for this kind of time-dependent
covariate). As in my case,
Robin,
Thanks much for the reply. It turns out, for reasons which are still
unknown to me, that on this machine, doing the following:
% g++ bessel.cpp -o bessel -lgsl -lgslcblas
will tell me it can't find -lgsl, in spite of its path being on my
LD_LIBRARY_PATH. So, being explicit solves
Sounds like you are having permissions problems. And as you're using a
mix of Unix and WinXP, you might be suffering from some strange
permissions settings. WinXP allows a very rich set of permissions which
for many exotic combinations have no corresponding mapping to the much
simpler
On 3 October 2007 at 12:25, Randy Heiland wrote:
| Thanks much for the reply. It turns out, for reasons which are still
| unknown to me, that on this machine, doing the following:
|
| % g++ bessel.cpp -o bessel -lgsl -lgslcblas
|
| will tell me it can't find -lgsl, in spite of its path
On 10/3/2007 7:56 AM, (Ted Harding) wrote:
Hi Folks,
The question I'm asking, regarding the use of function
definitions in the context described below, is whether
there are subtle traps or obscure limitations I should
watch out for. It is probably a rather naive question...
Quite often,
Hi all,
I have run into what appears to be a bug in ggplot2; however, I am new
to the ggplot syntax, so I might be missing a key element. The main
issue is that I cannot get geom_abline to plot when colour is used to
identify group in the main plot. When I remove colour, geom_abline
works
Metrum Institute and Random Technologies LLC are pleased to announce
the availability of the SASxport package.
The new SASxport package provides the ability to directly read, list,
and write SAS 'xport' files, including proper handling of custom SAS
formats. (This extends existing
This is reproducible with R-2.6.0 for me. You might want to report it to
R-Core, the maintainer of that package.
Uwe Ligges
Benjamin Tyner wrote:
R-helpers,
n - 100
arcoefs - c(0.8)
macoefs - c(-0.6)
p - length(arcoefs)
q - length(macoefs)
require(nlme)
tmp -
Hi, all,
(version info at end)
I'm running a script which takes input files, does some analysis, and
writes the output to csv files. Last night I ran the script (it took
~6.5 hours) thinking all would go well since it ran on a subset of the
data without issue. However, when I returned this
On 10/3/07, Duncan Murdoch [EMAIL PROTECTED] wrote:
On 10/3/2007 7:56 AM, (Ted Harding) wrote:
Hi Folks,
The question I'm asking, regarding the use of function
definitions in the context described below, is whether
there are subtle traps or obscure limitations I should
watch out for.
It shouldn't be hard, using the definition of GARCH(1,1).
Giovanni
Date: Tue, 02 Oct 2007 17:14:27 -0400 (EDT)
From: [EMAIL PROTECTED]
Sender: [EMAIL PROTECTED]
Importance: Normal
Precedence: list
User-Agent: SquirrelMail/1.4.6
Hey,
Is there any way to simulate a GARCH(1,1) data
On Wed, 3 Oct 2007, skylab gupta wrote:
Hello,
I have been playing around with the statistical distributions in R, and
overall I think the accuracy is very good. However, it seems that for the
Student's t distribution, the CDF loses accuracy when evaluated at values
close to zero. For
It looks like you can pass a vector of neighbourhoods to nndist.
nndist(rpp, k=2:10)
Although you get some warnings, the answers appear to be the same.
all.equal(t(sapply(2:10, function(i) nndist(rpp, k=i))), nndist(rpp, k=2:10))
This might be quite a lot faster, depending on how much work is
I use Windows, R version 2.5.1
When I try to run stepclass (klaR) I get an error message/warning saying:
1: error(s) in modeling/prediction step in: cv.rate(vars = c(model, tryvar),
data = data, grouping = grouping, ...
Actually, I look 16 warnings of this type. Can anyone tell me what this
On 3/10/2007, at 5:48 PM, Peter Dalgaard wrote:
Rolf Turner wrote:
I have factors with levels ``Unit, Achieved, and Scholarship;
I wish to replace these with
U, A, and S.
So I do
fff - factor(fff,labels=c(U,A,S))
This works as long as all of the levels are actually present in
On 3/10/2007, at 8:30 PM, Patrick Burns wrote:
I don't think it is so much that the R routines
work faster/more efficiently/more accurately
but that the user works faster/more efficiently/
more accurately.
Well said, O Wise and Ancient One!!! :-) :-) :-)
On 4/10/2007, at 7:50 AM, Peter Dalgaard wrote:
Rolf Turner wrote:
Does it even work? (What if it is the first or the 2nd level that
is absent?
Yes it works. What's the problem?
To beat it to death: if the second level of fff is absent
then fff will consist entirely of 1's
Rolf Turner wrote:
P.S. ***Are*** there any risks/dangers in following Christos
Hatzis' suggestion of simply doing
levels(fff) - c(U,A,S) ???
Not if the levels are right to begin with.
Problems only arise if fff somehow becomes a two-level factor, e.g. if
you do
Hi R users.
I have a model of cox that already it is estimated (I have only the
model estimated, I haven't data), how can I determine a nomogram with
R? Is it posible to do nomograms in Design package? I think that's
only when the model (Cox Regression in this case) is before estimated
I have found how to reimplement order method from R language in PHP:
?php
$str = 0 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 10 10 10 10 10 10 10 10 10
10 10 10 10 10 10 10 10 10 10 11 11 11 11 11 11 11 11 11 11 11 11 11 11 11
11 11 11 11 12 12 12 12 12 12 12 12 12 12 12 12 12 12 12 12 12 12 12 13
Hello,
I have a question regarding shading regions under curves to display
95% confidence intervals. I generated bootstrap results for the slope
and intercept of a simple linear regression model using the following
code (borrowed from JJ Faraway 2005):
attach(allposs.nine.d)
When one is doing simple regression and needs to force a zero intercept
( for whatever reason. I realize it's a controversial issue ),
then subtracting the means of the left hand side and the right hand side
from themselves does the trick. Does anyone know if there is a
similar trick when the
On Wed, 2007-10-03 at 14:21 -0700, [EMAIL PROTECTED] wrote:
Hello,
I have a question regarding shading regions under curves to display
95% confidence intervals. I generated bootstrap results for the slope
and intercept of a simple linear regression model using the following
code
No. Not really.What you have done seems to be similar to what I could do
with the reshape library.
rawer-melt(coinfection,id.var=study) # please refer to my post
immediately before this.
I am still unable to make use of prop.table and margin.table functions.
On 10/3/07, Deepayan Sarkar [EMAIL
[EMAIL PROTECTED] wrote:
Hi R users.
I have a model of cox that already it is estimated (I have only the
model estimated, I haven't data), how can I determine a nomogram with
R? Is it posible to do nomograms in Design package? I think that's
only when the model (Cox Regression in
On 10/3/07, Farrel Buchinsky [EMAIL PROTECTED] wrote:
Thank you. It comes close but not exactly what I wanted. I had to
scrap my column that contained character values. That column noted the
name of the study. Let me try show you here
Best if viewed in courier font
coinfection
Dear all,
I am attempting to model some one-dimensional data using Gaussian
mixture model with mclust. Generally, the data that I have have 3
overlapping populations (with one of them being the majority, and the
other two combining to less than 15%) and for some reason, mclust
consistently
Hi john : I just checked it with a simple example before I saw your
email and that does work. Thanks and I apologize to you
and the list for the question.
-Original Message-
From: John Fox [mailto:[EMAIL PROTECTED]
Sent: Wednesday, October 03, 2007 6:06 PM
To: Leeds, Mark (IED)
Cc:
Thank you. It comes close but not exactly what I wanted. I had to
scrap my column that contained character values. That column noted the
name of the study. Let me try show you here
Best if viewed in courier font
coinfection
study HPV6 HPV11 CoInfect other
1 Wiatrak 2004 3123
I am trying to normalize a dataframe of dimensions(1,1) using znorm
from the dprep package. What I get back is the same data, and nothing
has been normalized. Wondering if there is a known bug I am running into
or am I missing something?
Cheers!
Harshal
[[alternative HTML version
No HTML this time. Sorry
Dear all,
I am attempting to model some one-dimensional data using Gaussian mixture model
with mclust. Generally, the data that I have have 3 overlapping populations
(with one of them being the majority, and the other two combining to less than
15%) and for some
Incidentally, the feature becomes really powerful when one uses
functions such as addmargins together with prop.table as in
coinf.table -as.matrix(coinfection)
prop.table(coinf.table,1) # to see proportions from each HPV type per study
addmargins(coinf.table)# to see totals within study and
James D Forester wrote:
Hi all,
I have run into what appears to be a bug in ggplot2; however, I am new
to the ggplot syntax, so I might be missing a key element. The main
issue is that I cannot get geom_abline to plot when colour is used to
identify group in the main plot. When I
Hi there,
I want to do classify some 2-dimensional points into four clusters by
pam() in the cluster package. However, I encountered some problems.
1. How can I change the xlab and ylab instead of the default
Component 1 and Component 2? When I put xlab option in the
function, it always
Hi,
I checked my code and found that it was actually a
subsequent call to lm.fit() (which only gets called
occasionally) where the problem occurred. I found
that I was accidentally passing a matrix called PMs
instead of the vector PM.
Sorry about that.
Thanks,
Peter.
--- Petr PIKAL [EMAIL
I'm an Rgraphviz newbie trying to figure out how to do some things/whether
they are possible.
Apparently graphviz does allow you to modify line widths of edges: see
https://mailman.research.att.com/pipermail/graphviz-interest/2001q2/51.html
(although it looks a little obscure even in
Dear all,
is this a bug?
as.numeric(FALSE)
[1] 0
library(Matrix)
Loading required package: lattice
as.numeric(FALSE)
Error in UseMethod(as.double) : no applicable method for as.double
Regards,
Bernd
version
_
platform i386-pc-mingw32
arch i386
os
Is there any requirement for TclTk support for R? When I tried to
call the tcltk library, it failed with the following message:
library(tcltk)
Error in firstlib(which.lib.loc, package) :
Tcl/Tk support is not available on this system
Error in library(tcltk) : .First.lib failed for
Bernd Weiss schrieb:
Dear all,
is this a bug?
as.numeric(FALSE)
[1] 0
library(Matrix)
Loading required package: lattice
as.numeric(FALSE)
Error in UseMethod(as.double) : no applicable method for as.double
After doing a complette reinstallation (uninstalling R, deleting all
Hi Ken,
I know your question was specifically about the mclus, but you can
also try to fit a univariate gaussian mixture using the normalmixEM
in the mixtools package.
library(mixtools)
out = normalmixEM(data, k=3)
That's what I got for your sample:
out$lambda
[1] 0.119 0.647 0.234
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