You can take a look at AUC in the PK package
stephen sefick wrote:
I would like to integrate the area under a curve without any smoothing or
the like- just on the raw numbers. I looked at integrate() but it
requires
a function which I assume means something like x+x^2+x^3
is there a
There is an integrate.xy in sfsmic. Limitations discussed there.
Also see trap.rule in Hmisc
Vikas
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
Yes. Because the slopes are supposed to be the same.
Level shifts are needed to be modeled.
Moshe Olshansky-2 wrote:
Do you have a reason to treat all 3 levels together and not have a
separate regression for each level?
--- On Tue, 1/7/08, rlearner309 [EMAIL PROTECTED] wrote:
From:
Hi
Kathi [EMAIL PROTECTED] napsal dne 01.07.2008 18:48:47:
On Tue, 1 Jul 2008 14:33:12 +0200, Petr PIKAL wrote
Kathi [EMAIL PROTECTED] napsal dne 01.07.2008 13:39:18:
Thanks, Petr.
After fiddling around some more with my code I found out that this
seems
to
have something
Mayukh Dass wrote:
Hi,
I am trying to load the library(ks), but I am getting the following error:
Loading required package: KernSmooth
KernSmooth 2.22 installed
Copyright M. P. Wand 1997
Loading required package: mvtnorm
Loading required package: rgl
Loading required package: misc3d
Error in
Gavin Simpson [EMAIL PROTECTED] writes:
Ok, lets sort this out. [Not tested as I don't have your data]
df - data.frame(resp = cancerv1[, 408],
VARS = as.matrix(cancerv1[, 2:407])
Actually, you _do_ need an I() here:
df - data.frame(resp = cancerv1[, 408],
Dear R Users,
Can someone point me to a R package which will help me optimally choose a
lag for Granger Causality testing ?
Many thanks in advance,
Tolga
Generally, this communication is for informational purposes only
and it is not intended as an offer or solicitation for the purchase
or sale
RSiteSearch(Granger Causality, restrict = functions) yields two
hits.
ir. Thierry Onkelinx
Instituut voor natuur- en bosonderzoek / Research Institute for Nature
and Forest
Cel biometrie, methodologie en kwaliteitszorg
Dear helpers,
I'm using a R script on several different datasets, which makes that
axis scales may vary quite a lot from dataset to dataset. So what I'm
looking for now, is how to automagically find out how to position the
legend (horizontal) in the space below the x-axis title, and how to
make
First of all, I was not aware of the RSiteSearch function. Cool. Thanks
for that.
That having been said, I could not find anything here that helps with
optimal lag selection.
I can see:
- grangertest,
- granger.test and
- the causality functions which actually implement the tests, but
Hi,
I have the following problem:
library(playwith)
x-ts(rnorm(100))
y-ts(cumsum(x))
playwith({
par(mfrow=c(2,1))
plot(x)
plot(y)})
I can't make playwith identify (using the button top left) datapoints on
multiple graph plots (eg. par(mfrow=c(2,2) for a 2 x
On Wed, 2008-07-02 at 10:32 +0200, Bjørn-Helge Mevik wrote:
Gavin Simpson [EMAIL PROTECTED] writes:
Ok, lets sort this out. [Not tested as I don't have your data]
df - data.frame(resp = cancerv1[, 408],
VARS = as.matrix(cancerv1[, 2:407])
Actually, you _do_ need an
Hello to all who have helped me on this topic,
first I need to apologize for apparently replying only now... In fact
I use the Pan Newsreader to read the list, and I posted a reply to
the thread a week after your suggestions through Pan, and I only now
realised that the posting never arrived on
On Wed, 2008-07-02 at 10:27 +1200, Rolf Turner wrote:
On 2/07/2008, at 10:15 AM, Bert Gunter wrote:
Ow ow ow. I can't stand it any longer! Weird is one of those weird
exceptions in English to the i before e except after c rule and
is spelled
W-E-I-R-D .
In case you're interested,
The inset= argument to legend does not depend on usr coordinates.
On Wed, Jul 2, 2008 at 5:41 AM, Anne-Marie Ternes [EMAIL PROTECTED] wrote:
Dear helpers,
I'm using a R script on several different datasets, which makes that
axis scales may vary quite a lot from dataset to dataset. So what I'm
Hi R people:
I have huge files with as many as 5000 columns. I'd really like to read
only certain columns of those files. I know column names I want to read.
I looked at the documentation of read.csv . Although there is a
col.names option, it allows users to specify the names of the columns,
On Jul 2, 2008, at 6:53 AM, Philip James Smith wrote:
Hi R people:
I have huge files with as many as 5000 columns. I'd really like to
read only certain columns of those files. I know column names I
want to read.
I looked at the documentation of read.csv . Although there is a
col.names
Gavin Simpson [EMAIL PROTECTED] writes:
df - data.frame(resp = dat[,1], VARS = I(as.matrix(dat[, 2:101])))
class(df$VARS)
[1] AsIs
The class is AsIs for $VARS. But if I look at your yarn data set for
example, the NIR component is of class matrix:
class(yarn$NIR)
[1] matrix
How did you
And: Eight!!! (8)
Rolf Turner wrote:
On 2/07/2008, at 10:15 AM, Bert Gunter wrote:
Ow ow ow. I can't stand it any longer! Weird is one of those weird
exceptions in English to the i before e except after c rule and is
spelled
W-E-I-R-D .
In case you're interested, the other exceptions are
Rolf,
And what's even more weird, there is a 'weir' (pronounced just as
'weird', but without the 'd'), a structure over which water flows. All
of this make good fodder for humorists…
Cheers,
Tom
Thomas Adams wrote:
And: Eight!!! (8)
Rolf Turner wrote:
On 2/07/2008, at 10:15 AM, Bert
You can do this plot saying to R that your file is a time series with the
ts() function.
serie=ts(x,)
and then you use plot(serie)
-Mensagem original-
De: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
nome de Petr PIKAL
Enviada em: quarta-feira, 2 de julho de 2008 05:04
Para: Kathi
Gundala Viswanath gundalav at gmail.com writes:
Hi all,
I've tried to plot a vector which has two peaks in the density.
This link shows the figure.
http://docs.google.com/View?docid=dcvdrfrh_1dk9r2rc7
The red line is normal curve and green line is gamma curve.
Notice that red line
I have a data matrix like this:
data[1:10,]
aaname grp cluster count
1 Ala All Singleton 432
2 Arg All Singleton 1239
3 Asn All Singleton 396
4 Asp All Singleton 152
5 Cys All Singleton 206
6 Gln All Singleton 370
7 Glu All Singleton 211
8 Gly
Hi,
I am trying include a spatial correlation structure into a gls model but
keep getting the following error:
ocean-read.table(C:\\oceanography2.txt,header=TRUE)
library(nlme)
YEAR-as.factor(ocean$YEAR)
group-groupedData(san_dens~temp_grad*pyc_grad*start_thermo|YEAR,data=ocean)
Thanks to all who replied on list and to me directly.
You are right, FAQ 7.22 is the answer. For any others who get caught
by this it's important to print(..) a plot with a function, not just
create it, i.e.
print( xyplot(... ) )
not just
xyplot(... )
..otherwise it
Instead of
x-seq(as.Date(2004-01-01), as.Date(2008-06-01),by=month)
from=iso2chron(2004-01-01)
to= iso2chron(2008-06-01)
from -chron2UTCsecs(from)
to-chron2UTCsecs(to)
delta##how many secs i.e month time in secs
xx - seq(from=from, to=to, by=delta)
x - UTCsecs2chron(xx)
I think
I'm using package Matrix, which I have installed on several flavours of linux
system. But on an important solaris install, I can't make it work.
Initially, I thought the problem was using 'make' instead of 'gmake', but I
masked around that, and still get errors. Those new errors seem to be
Emma,
It looks like there is at least one location that has been sampled at
least twice in some year. A co-worker of me got similar errors. After
checking his data carefully he found a duplicate row. Removing the
duplicate row solved his problem.
HTH,
Thierry
Hello again
I recently downloaded the gcl package, which computes a fuzzy rules or tree
classifier from data. It is very interesting and is giving good results.
However, rather than return a list, it returns a function. Per the example in
the documentation:
library(gcl)
library(datasets)
Hi
[EMAIL PROTECTED] napsal dne 02.07.2008 14:17:00:
You can do this plot saying to R that your file is a time series with
the
ts() function.
serie=ts(x,)
and then you use plot(serie)
Yes and no. Of course that it can be plotted but the original problem was
Error in axis(side, at
See function VARselect() in package vars which computes AIC and BC for
each lag
function ar() also computed VAR models with automatic selection of lags
Mat
First of all, I was not aware of the RSiteSearch function. Cool. Thanks
for that.
That having been said, I could not find anything
I have a matrix with data that runs from 1/1/06 00:01:00-1/31/08 23:46:00.
I have read in the data with this
fmt.chron - function(x) {
chron(sub( .*, , x), gsub(.* (.*), \\1:00, x))
}
x - read.zoo(file.choose(), sep=,, header=T, FUN=fmt.chron)
plotted with this
plot(x[,(seq(3, by=9,
Hi
Is it from chron package? As I do not have it available now I can not try
it but the problem is not in plotting itself but in custom x axis
labeling when there are missing date on either end of a series.
You have several options
Define fake time values for yet nonexisting data.
Do your
Dear all,
sorry for this very basic question, but I did not find any good example yet.
I would like to set up a variable that can be recall later to substitute a
part of a file name.
As example:
var_filename = as.name(aaa)
jpeg(var_filename.jpg)
plot()
dev.off()
It would be very useful in
Like for instance that the xlim is small enough where the plot is showing
the day instead of the year (I believe). Now that I have figured this out
(I think). I would like to know if there is a way to tell plot.zoo how to
print the date ranges easily. When I did the example in my previous email
Try this:
sprintf(%s.jpg, var_filename)
On Wed, Jul 2, 2008 at 10:31 AM, Laura Poggio [EMAIL PROTECTED]
wrote:
Dear all,
sorry for this very basic question, but I did not find any good example
yet.
I would like to set up a variable that can be recall later to substitute a
part of a file
While trying to train randomForest with my dataset, I am ending up with the
following error
Error in randomForest.default(datatrain, classtrain) :
length of response must be the same as predictors
My data looks like:
A,B,C,D,Class
1,2,1,2,cl1
1,2,1,2,cl1
3,2,1,2,cl2
3,2,1,2,cl2
3,2,1,2,cl2
Thank you, it looks like that was the problem
Emma
Emma,
It looks like there is at least one location that has been sampled at
least twice in some year. A co-worker of me got similar errors. After
checking his data carefully he found a duplicate row. Removing the
duplicate row solved his
Thank you perfect! it worked also with the GDAL option.
Laura
2008/7/2 Richard Pearson [EMAIL PROTECTED]:
Laura
Does jpeg(paste(var_filename, jpg, sep=.)) do what you want?
Regards
Richard
Laura Poggio wrote:
Dear all,
sorry for this very basic question, but I did not find any good
Hello,
Is there a function in the survival package that will allow me to test a subset
of independent variables for joint significance? I am thinking along the lines
of a Wald, likelihood ratio, or F-test. I am using the survreg procedure to
estimate my parameters. Thank you.
Geoff
I think the covariance between dummy variables or between dummy variables and
intercept should always be zero. meaning: no sigularity problem??
rlearner309 wrote:
This is actually more like a Statistics problem:
I have a dataset with two dummy variables controlling three levels. The
?plot.zoo and the zoo faq vignette have examples of custom axes.
In the case of chron, the axes are done by chron:::axis.times in
the chron package.
On Wed, Jul 2, 2008 at 9:32 AM, stephen sefick [EMAIL PROTECTED] wrote:
Like for instance that the xlim is small enough where the plot is showing
one other thing- should I read the data in with the argument FUN=as.chron
? if this is the case how do I tell chron that the data is not in
-mm-dd HH:MM:SS but in the format m/d/y HH:MM:SS ?
thanks
stephen
On Wed, Jul 2, 2008 at 9:32 AM, stephen sefick [EMAIL PROTECTED] wrote:
Like for
Hi,
I want to export an table using the write.table and i want is this format:
(this table was exported in s-plus)
Q01
row.names Num Percmeabstdev min P5 P10 P25
P50 P75
P90 P95 max
A 10237 47.88 183.48 38.84 86.98 126.52
Hi,
I have a data frame with strings that have two letters and four numbers. When I
store a whole row as a new vector and try to remove the preceding letters using
the gsub command, it returns characters of single numbers that have no relation
to the numbers in each string. I also noticed that
R 2.7.1 windows xp and version of zoo upgraded with new installation of R
2.7.1 yesterday from CA1 mirror
window.zoo is not there?
On Wed, Jul 2, 2008 at 10:00 AM, Gabor Grothendieck [EMAIL PROTECTED]
wrote:
?plot.zoo and the zoo faq vignette have examples of custom axes.
In the case of chron,
Seems to be there:
library(zoo)
methods(window)
[1] window.default* window.ts* window.zoo*
Non-visible functions are asterisked
packageDescription(zoo)$Version
[1] 1.5-2
On Wed, Jul 2, 2008 at 10:08 AM, stephen sefick [EMAIL PROTECTED] wrote:
R 2.7.1 windows xp and version of zoo
Same with 1.5-3
methods(window)
[1] window.default* window.ts* window.zoo*
Non-visible functions are asterisked
packageDescription(zoo)$Version
[1] 1.5-3
R.version.string
[1] R version 2.7.1 RC (2008-06-16 r45949)
On Wed, Jul 2, 2008 at 10:31 AM, Gabor Grothendieck
[EMAIL PROTECTED]
Dear Nina,
Is this what you want?
x=c(MT2342,MT0982,MT2874)
substr(x,3,nchar(x))
HTH,
Jorge
On Wed, Jul 2, 2008 at 10:24 AM, [EMAIL PROTECTED] wrote:
Hi,
I have a data frame with strings that have two letters and four numbers.
When I
store a whole row as a new vector and try to remove
On Wed, 2 Jul 2008, rlearner309 wrote:
I think the covariance between dummy variables or between dummy variables and
intercept should always be zero. meaning: no sigularity problem??
No. You can easily check that this is not true using the cov() function.
Indicator variables for mutually
sorry, I am still trying to figure R out. window worked just fine with
chron, but when I use
d - locator()
as.chron(d)
it returns results that are not consistent with the plot do I need to put in
the format argument. I am still trying to figure out these date time
classes.
On Wed, Jul 2,
With that format you will need a custom function based on chron and sub
as you were doing at the beginning.
On Wed, Jul 2, 2008 at 9:53 AM, stephen sefick [EMAIL PROTECTED] wrote:
one other thing- should I read the data in with the argument FUN=as.chron
? if this is the case how do I tell
On 02.07.2008, at 15:31, Laura Poggio wrote:
Dear all,
sorry for this very basic question, but I did not find any good
example yet.
I would like to set up a variable that can be recall later to
substitute a
part of a file name.
As example:
var_filename = as.name(aaa)
Hi all!
Do you know if there is any R function/package that can be used to
estimate tobit models with panel data (e.g. with random individual
effects)?
In economics, a tobit model is a model with a dependent variable that is
left-censored at zero. Hence, it is a special case of a survival
Hi all:
I'm trying to plot two time series created in Rmetrics and label the
x-axis with dates. I tried the following:
dates - as.Date(seriesPositions(x.agg))
r - as.Date(range(dates))
ts.plot([EMAIL PROTECTED],c(1,5)],gpars=list(ylab=Volume,
lty=c(1:2),xaxt=n,main=Plot of
I can't tell what you are doing from that description. See last line to
every message to r-help.
It should be possible to copy your code and just paste it into a running
R session and see the problem If there is interaction give detailed
descriptions.
On Wed, Jul 2, 2008 at 10:42 AM, stephen
Hey Gang,
Here is the situation. First of all I am a newbie, in the arena of R, so
please bare with me. I am trying to make a plot with a series of plot lines
that uses logs on the x axis, and when I plot it I am having a few odd
things go on that I do not know how to correct.
1. the tick
commandArgs may do what you want.
Best,
luke
On Tue, 1 Jul 2008, Erin Hodgess wrote:
Dear R People:
I have used
./R --no-save -q -f e.in stuff.out
with great success on SUSE10.1 with R-2.7.1.
My question is, please: is there a way to pass in a variable to the
e.in file? I'm fairly sure
Hello -
I'm trying to use Hmisc's latex function to produce a postscript file of
a data.frame, using the longtable = TRUE option. When I run, for example,
## sample R code
dvips(latex(data.frame(a = rnorm(100), b = rnorm(100)),
longtable = TRUE), file = test.ps)
latex runs
Hi everybody,
I have a simple regression summary created by summary.lm and I wonder
how i can export it to another file format which can be used on the web.
.pdf would be possible, a html table would be nicer than your momma on
your birthday.
any suggestions ?
thx so much in advance
hi
I want to compare two list by its names and get the values of that list.
can anybody let me know the syntax of comparing the list by their names
using a for loop
c.genes- list()
for(i in 1:100)
c.genes[[1]]- geneset(which(geneset == tobecampared[i]))
}
here geneset is a list and also
For those attending useR! 2008 next month, something to look forward to:
http://www.gnome-look.org/content/show.php/show.php?content=84455
:-)
Cheers,
Marc Schwartz
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
Seems to work fine for me:
x - c(MT2342,MT0982,MT2874)
gsub([^0-9], , x)
[1] 2342 0982 2874
You might have 'factors' so you should use as.character to convert to
character strings:
gsub('[^0-9]','',as.character(PthwyGenes))
On Wed, Jul 2, 2008 at 10:24 AM, [EMAIL PROTECTED] wrote:
All,
I can't seem to get auto.key to work properly in an xyplot that is employing
panel.text. Specifically, I often change the default grouping colors then
use auto.key accordingly, but for some reason the same functionality isn't
working for this different type of plot. Any help much
library(Hmisc) has latex and html functions to convert the output into
latex (then to pdf, if you wish), and into html. A useful link for this
is http://biostat.mc.vanderbilt.edu/twiki/bin/view/Main/SweaveConvert
Bunny, lautloscrew.com wrote:
Hi everybody,
I have a simple regression summary
Erik Iverson wrote:
Hello -
I'm trying to use Hmisc's latex function to produce a postscript file of
a data.frame, using the longtable = TRUE option. When I run, for example,
## sample R code
dvips(latex(data.frame(a = rnorm(100), b = rnorm(100)),
longtable = TRUE), file =
Not likely the factor issue:
x - factor(c(MT2342,MT0982,MT2874))
x
[1] MT2342 MT0982 MT2874
Levels: MT0982 MT2342 MT2874
gsub([^0-9], , x)
[1] 2342 0982 2874
gsub() and friends coerce to character internally already:
gsub
function (pattern, replacement, x, ignore.case = FALSE,
Hi,
i have this glm:
shuttle.glm.test -
glm(cbind(r,m-r)~temperature,family=binomial,data=shuttle)
and when i try to find a probability of var r (with temperature=31 and
pressure=200):
predict(shuttle.glm.test,data.frame(temperatura=31,pressure=200),type=response,se=T)
i have this error:
have you tried package(zoo) it works very well and should do what you want
On Wed, Jul 2, 2008 at 10:54 AM, Kerpel, John [EMAIL PROTECTED]
wrote:
Hi all:
I'm trying to plot two time series created in Rmetrics and label the
x-axis with dates. I tried the following:
dates -
On Wed, 2 Jul 2008, Ben Tupper wrote:
On Jul 2, 2008, at 6:53 AM, Philip James Smith wrote:
Hi R people:
I have huge files with as many as 5000 columns. I'd really like to read
only certain columns of those files. I know column names I want to read.
I looked at the documentation of
Stephen:
That works great - thanks! I have to admit it gets a little frustrating
having to switch back and forth between packages because of
cross-package incompatibility, but hey, more functionality = good.
Best,
john
From: stephen sefick
Dear All:
I have the following data:
0 100
0.5 79.9605
0.75 84.7098
1.5 72.1793
2.5 97.4924
4.5
Dear R users,
I have some data sets and I'd want to test if they are genarated under
different probability functions. That is, some of them by gamma
distribution, exponential one etc.
Could anybody propose me any test (or procedure) to see that.
I search something similar to the normality tests.
Hey Gang,
Here is the situation. First of all I am a newbie, in the arena of R,
so please bare with me. I am trying to make a plot with a series of
plot lines that uses logs on the x axis, and when I plot it I am
having a few odd things go on that I do not know how to correct.
1. the tick
Incompatability? zoo can work with any date/time class that supports
certain methods and such methods have specifically been written
for fCalendar's timeDate class. In fact there is a section in
vignette(zoo) on the timeDate class.
Also we can readily convert between fSeries' timeSeries class
Marc Schwartz [EMAIL PROTECTED] [Wed, Jul 02, 2008 at 06:22:40PM CEST]:
For those attending useR! 2008 next month, something to look forward to:
http://www.gnome-look.org/content/show.php/show.php?content=84455
THIS is a sunset over Dortmund:
http://www.23hq.com/mBusolt/photo/2230816
Deep
How can I export an ftable object in the same format that appears in R
command window?
For testing that i was using this example that is in help of this function.
## Start with a contingency table.
ftable(Titanic, row.vars = 1:3)
ftable(Titanic, row.vars = 1:2, col.vars = Survived)
On Wed, 2 Jul 2008, [EMAIL PROTECTED] wrote:
Dear R Users,
I am attempting to use the strucchange package but get an error which is
difficult to decipher.
I get the following error with breakpoints:
bp-breakpoints(regr[,1]~regr[,2]+regr[,3])
Error in my.RSS.table[as.character(i), 3:4] -
on 07/02/2008 02:37 PM Johannes Huesing wrote:
Marc Schwartz [EMAIL PROTECTED] [Wed, Jul 02, 2008 at 06:22:40PM CEST]:
For those attending useR! 2008 next month, something to look forward to:
http://www.gnome-look.org/content/show.php/show.php?content=84455
THIS is a sunset over Dortmund:
Check out gap.plot in the plotrix package.
On Wed, Jul 2, 2008 at 2:49 PM, Zheng Lu [EMAIL PROTECTED] wrote:
Dear All:
I have the following data:
0 100
0.5 79.9605
0.75 84.7098
See ?write.ftable
On Wed, Jul 2, 2008 at 4:56 PM, Leandro Marino [EMAIL PROTECTED]
wrote:
How can I export an ftable object in the same format that appears in R
command window?
For testing that i was using this example that is in help of this function.
## Start with a contingency
I tried the following myself and I almost have something to work with. But I
still need a little input.
#Plots a filled contour
# Can someone help me in increasing the resolution as my data range is 0-11?
Also I need to put the row and column names on the axes.
x - 1:nrow(data)
y -
Dear R-helper,
I wonder if anyone can help me. I am trying to convert a dataset to a
format recognizable by a software onboard a research vessel but I am
having problems with some steps.
I have a data frame as follows:
Conc Lat LonDepth
Point 56.25-5.65
Hi there,
I am using JRClient to build logistic regression model in the
following manner :
Rconnection c = new Rconnection();
c.eval(KSN-read.table(\/Users/amine/Documents/Research/
Tools/R/D2R1.txt\,header=T,sep=\,\));
c.eval(result - glm(Nausea ~ Kaletra*Sustiva,
Hi there,
I am using JRClient to build logistic regression model in the
following manner :
Rconnection c = new Rconnection();
c.eval(KSN-read.table(\/Users/amine/Documents/Research/
Tools/R/D2R1.txt\,header=T,sep=\,\));
c.eval(result - glm(Nausea ~ Kaletra*Sustiva,
Dear All,
I'd like to use Weka functions that are not implemented (do not have
interface) in RWeka, like the Remove function and others in the
future!
The .java() functionality is for that purpose but I haven't seen any
example with Weka functions. Could anyone give me hand in how to do
it? For
folks,
is there a clever way to compute the sum of the product of two vectors such
that the common indices are not multiplied together?
i.e. if i have vectors X, Y, how can i compute
Sum (X[i] * Y[j])
i != j
where i != j
also, what if i wanted
Sum (X[i] * Y[j] * R[i, j])
i != j
Hello ,
I am having some difficulty reading a CSV file of unequal record length
in R . The data has 26 columns and do not have header and is generated
from a R syntax -
write.table(schat,schat.csv, sep=,, col.names=FALSE, append = TRUE)
Hi,
you can try the 'mixdist' package which allows fitting of multiple
(superposed) distributions to your vector of data.
The package is available on http://www.math.mcmaster.ca/peter/mix/mix.html
Unfortunately this package doesn't support combination of normal with
gamma etc..., but it
Thank you for your time to help. I don't think I was completely clear, I
want to keep the axis ticks and labels (which I now see is what R calls
the values like Jan, Feb, Mar) but want to suppress the label titles.
So a generic plot(thisZoo) would produce a plot whose X axis is the dates,
tick
Hi,
I'm programming in R and below is a summary of a generalized linear model:
** ***
Call:
glm(formula = offspring ~ degdays, family = quasi(link = log, variance =
mu), data = fecundity)
Deviance Residuals:
Min 1Q Median 3Q Max
-0.76674 -0.29117
Murali
I don't know about 'clever', but does this do what you want?
v1 - 1:3
v2 - 4:6
sum(matrix(rep(v1, length(v1)), nrow=length(v1))%*%v2)-sum(v1*v2)
Peter Alspach
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of Murali Menon
Sent: Thursday, 3
Try something about like this:
v1 %o% v2 - diag(v1*v2)
On Wed, Jul 2, 2008 at 1:30 PM, Murali Menon [EMAIL PROTECTED] wrote:
folks,
is there a clever way to compute the sum of the product of two vectors such
that the common indices are not multiplied together?
i.e. if i have vectors X,
My special thanks to Chunhao Tu for the suggestions about testing significance
of two locations.
I used logistic models to describe relationships between Y and X at two
locations (A B). And within each location, I have four groups
(N,E,S,W)representing directions. So the test data can be
On 7/2/08, Karin Lagesen [EMAIL PROTECTED] wrote:
I have a data matrix like this:
data[1:10,]
aaname grp cluster count
1 Ala All Singleton 432
2 Arg All Singleton 1239
3 Asn All Singleton 396
4 Asp All Singleton 152
5 Cys All Singleton 206
6
Hi Murali,
Just an idea, probably not the best :
x-1:4
y-1:6
z-matrix(1:(length(x)*length(y)),nrow=length(x))
I - matrix(1,nrow=length(x),ncol=length(y))
I[row(I)==col(I)] - 0
sum (outer (x, y, '*') * I)
sum (outer (x, y, '*') * z * I)
Hope this helps,
Nael
On Wed, Jul 2, 2008 at 6:30
Viswanathan Shankar wrote:
Hello ,
I am having some difficulty reading a CSV file of unequal record
length in R . The data has 26 columns and do not have header and is
generated from a R syntax -
write.table(schat,schat.csv, sep=,, col.names=FALSE, append = TRUE)
on 07/02/2008 02:10 PM R_Learner wrote:
raw - read.csv(file=filename, head=TRUE,sep=,)
I've read in a csv file, and I'm looking to access a column whose name is
held in a string.
For example, I want to access raw$one or raw$two, but this will depending on
the string. Let's say that the string
I'm sorry:
sum(v1 %o% v2 - diag(v1*v2))
On Wed, Jul 2, 2008 at 6:03 PM, Henrique Dallazuanna [EMAIL PROTECTED]
wrote:
Try something about like this:
v1 %o% v2 - diag(v1*v2)
On Wed, Jul 2, 2008 at 1:30 PM, Murali Menon [EMAIL PROTECTED] wrote:
folks,
is there a clever way to compute
Hello List,
Is there a faster way to set values in one data.frame equal to NA
conditional on the corresponding value in another data.frame? Currently
I am using:
b[is.na(a)] - NA
where 'a' and 'b' are data.frames of equal size/dimensions, and 'a'
contains NAs but 'b' does not. This is
1 - 100 of 130 matches
Mail list logo
