Hi,
I have a data set consisting of the x and y coordinate locations of 1600
points. I would like to generate a graph using the functions in igraph.
However the graph making functions in igraph requires the data to be in the
form of an adjacency matrix. I'd like some advice on how to convert my
How can I truncate the scientific value keeping two digits decimal.
For example from:
6.95428812397439e-35
into
6.95e-35
-E.W.
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
See the respective help files. The continuity correction only affects
the normal approximation in wilcox.test. With this small samples sizes,
the default evaluation is exact, so it doesn't change anything. In
contrast, kruskal.test is incapable to compute exact values but always
uses the
Juanita,
On Tue, Sep 8, 2009 at 8:02 AM, juanita choojuanitac...@gmail.com wrote:
Hi,
I have a data set consisting of the x and y coordinate locations of 1600
points. I would like to generate a graph using the functions in igraph.
However the graph making functions in igraph requires the
may be this can work
testfun-function(x) {
rval=
k-length(x)
for (i in 1: k) rval-paste(rval,x[i],sep=-)
rval
}
v1-paste(evalr,1:4,sep=)
eval-expand.grid(w=v1,x=v1,y=v1,z=v1)
n-dim(eval)[1]
results-rep(, n)
for (i in 1:n) {
row-unique(unlist(eval[i,]))
if (length(row)=3)
Hi John,
When Group is entered as a factor, and the factor has two levels, the
ANOVA table gives a p value for each level of the factor.
This does not (normally) happen so you are doing something strange.
## From your first posting on this subject
x=0.01345778543577
signif(x,3)
-
cuncta stricte discussurus
-
-Ursprüngliche Nachricht-
Von: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] Im
Auftrag von Gundala Viswanath
Gesendet: Tuesday, September 08,
On Mon, 2009-09-07 at 12:49 +0300, Rousi Heta wrote:
Hi,
I´m doing cca for a community data set in R and I have made a biplot
for my data. Otherwise everything seems to be allright but the biplot
is so messy I can´t read it well enough or publish it. I would like to
get the row numbers
Hello,
This is to announce the first release of the ant R package, which has
been pushed to CRAN yesterday, and should reach your mirror and your
platform soon.
The package provides an R-aware version of the famous build tool from
the apache project. http://ant.apache.org/
The package
scatterplot3d() in package scatterplot3d can do, probably also
plot3d() in rgl and others.
Uwe Ligges
oleg lugovoy wrote:
Hello,
Can anyone suggest a way to draw a plot similar to the example from Matlab
(
After further investigation it appears that the problem is specific to
my Vista PC. I am able to get the correct results using R 2.9.2 on a
Window XP 64bit machine. However i do not know why this does not work
on my Vista PC. The following was done after rebooting Vista.
From CMD.exe I ran the
OK, I get it now. Thank you very much!
Cheers,
Tom
On Tue, Sep 8, 2009 at 8:20 AM, Meyners,Michael,LAUSANNE,AppliedMathematics
michael.meyn...@rdls.nestle.com wrote:
See the respective help files. The continuity correction only affects
the normal approximation in wilcox.test. With this
Dear All,
I'm looking for a way on computing the derivative of first and second order of
a smoothing curve produced by a nonprametric regression. For instance, if we
run the R script below, a smooth nonparametric regression curve is produced.
provide.data(trawl)
Zone92 - (Year == 0 Zone ==
Dear All,
I have some data which were stored in few matrices with different orders. Let
have three different matrices a, b and c, which have the same number of column
but different number of row.
a - matrix(1, nrow = 5, ncol = 1)
b - matrix(2, nrow = 10, ncol = 1)
c - matrix(3, nrow = 15,
Martin Morgan mtmor...@fhcrc.org
on Tue, 01 Sep 2009 09:07:05 -0700 writes:
spencerg wrote:
Bryan Hanson wrote:
Looks like the discussion is no longer about R Style, but S3 vs S4?
yes nice topic rename!
To that end, I asked more or less the same question a
Sorry if this is too OT, but there is a particular relevance to
postings to R-help.
Of recent times, I have received several postings via R-help (and some
other mailing-lists) in which the _ character is inserted where,
presumably, a space, , was intended. An example (received this
morning) is
have you tried rbind?
On Tue, Sep 8, 2009 at 11:16 AM, FMHkagba2...@yahoo.com wrote:
Dear All,
I have some data which were stored in few matrices with different orders.
Let have three different matrices a, b and c, which have the same number of
column but different number of row.
a -
Hi,
Thanks for the hint! Of course, you are correct.
Here is a link with some background for others with tired heads:
http://luna.cas.usf.edu/~mbrannic/files/regression/Logistic.html
On Sep 4, 1:15 pm, ONKELINX, Thierry thierry.onkel...@inbo.be
wrote:
You could use a glm with the binomial
Hi,
sorry for the simple question. I am usually able to change the font for PDF
graphics with pdf.options(family=Times)
However, I have found no way yet to get an emf file with a times font. I also
tried a detour by using pstoedit to convert a pdf with the desired font to an
emf but even there
Do you have 'times' in a format suitable for EMF? If so you can
select it for win.metafile() as for any other windows() device. You
would need a TrueType version, and I suspect you do under the name
'Times New Roman'. See ?windowsFonts: my memory is that
family=serif gives you that font.
Hello ALL!
I have a problem to plot factor (lets say gender) as a line, or at least
both line and point, from ols model:
ols1 - ols(Y ~ gender, data=dat, x=T, y=T)
plot(ols1, gender=NA, xlab=gender, ylab=Y,
ylim=c(5,30), conf.int=FALSE)
If I convert gender into discrete numeric predictor, and
On 08-Sep-09 10:40:18, Duncan Murdoch wrote:
On 08/09/2009 6:09 AM, (Ted Harding) wrote:
Sorry if this is too OT, but there is a particular relevance to
postings to R-help.
Of recent times, I have received several postings via R-help (and some
other mailing-lists) in which the _ character
Gavin Simpson gavin.simpson at ucl.ac.uk writes:
On Mon, 2009-09-07 at 12:49 +0300, Rousi Heta wrote:
Hi,
I´m doing cca for a community data set in R and I have made a biplot
for my data. Otherwise everything seems to be allright but the biplot
is so messy I can´t read it well
I have a text file similar to this (separated by spaces):
x - DF12 This is an example 1 This
DF12 This is an 1232 This is
DF14 This is 12334 This is an
DF15 This 23 This is an example
and I know the field lengths of each variable (there is 5 variables in
this data set), which are:
varlength -
On Tue, Sep 8, 2009 at 12:53 PM, Lauri Nikkinenlauri.nikki...@iki.fi wrote:
I have a text file similar to this (separated by spaces):
x - DF12 This is an example 1 This
DF12 This is an 1232 This is
DF14 This is 12334 This is an
DF15 This 23 This is an example
and I know the field lengths
On 9/8/2009 7:53 AM, Lauri Nikkinen wrote:
I have a text file similar to this (separated by spaces):
x - DF12 This is an example 1 This
DF12 This is an 1232 This is
DF14 This is 12334 This is an
DF15 This 23 This is an example
and I know the field lengths of each variable (there is 5
Thanks, I tried it but I got
varlength - c(2, 2, 18, 5, 18)
read.fwf(c:temppi.txt, widths=varlength)
V1 V2 V3V4 V5
1 DF 12 This is an exampl e 1 T his
2 DF 12 This is an 1232 T his is
3 DF 14 This is 12334 Thi s is an
4 DF 15 This 23 This is a n exa mple
Can you post how you would like it.
On Tue, Sep 8, 2009 at 8:07 AM, Lauri Nikkinenlauri.nikki...@iki.fi wrote:
Thanks, I tried it but I got
varlength - c(2, 2, 18, 5, 18)
read.fwf(c:temppi.txt, widths=varlength)
V1 V2 V3 V4 V5
1 DF 12 This is an exampl e 1 T his
2
Yes, but what actually i want to have is an array that might store these
different matrices.
- Original Message
From: Schalk Heunis schalk.heu...@enerweb.co.za
To: FMH kagba2...@yahoo.com
Cc: r-help@r-project.org
Sent: Tuesday, September 8, 2009 11:16:29 AM
Subject: Re: [R] Data in
On 9/8/2009 8:07 AM, Lauri Nikkinen wrote:
Thanks, I tried it but I got
varlength - c(2, 2, 18, 5, 18)
read.fwf(c:temppi.txt, widths=varlength)
V1 V2 V3V4 V5
1 DF 12 This is an exampl e 1 T his
2 DF 12 This is an 1232 T his is
3 DF 14 This is 12334 Thi s is
Dear all,
I need to test for the existence of an index on a table. This cannot be done
with sqlPrimaryKeys as it is not a primary key. Therefore I select directly
from the systemtable of SQL-Server 2000 named sysindexes. This works well with
RODBC Version 1.2-5 but not with version 1.3-0.
Here
On 08/09/2009 6:09 AM, (Ted Harding) wrote:
Sorry if this is too OT, but there is a particular relevance to
postings to R-help.
Of recent times, I have received several postings via R-help (and some
other mailing-lists) in which the _ character is inserted where,
presumably, a space, , was
Sure, here you go
structure(list(V1 = structure(c(1L, 1L, 1L, 1L), .Label = DF, class
= factor),
V2 = c(12L, 12L, 14L, 15L), V3 = structure(c(4L, 3L, 2L,
1L), .Label = c(This, This is, This is an, This is an example
), class = factor), V4 = c(1L, 1232L, 12334L, 23L), V5 =
I don't think you described your problem precisely.
You implied that you wanted the field lengths to be
(2,2,18,5,18) -- which is what you got with read.fwf --
but it looks like what you meant is something more like:
field 1: first two characters
field 2: characters 3-4
field 3: all
On Sep 8, 2009, at 12:39 AM, Steven Kang wrote:
Dear R users,
Suppose I have a data set with inconsistent names for a field.
I desire to make these to consistent names.
i.e
University of New Jersey, New Jersey Uni, New Jersey
University (3
different inconsistent names) to The University
This data is from database and the maximum length of a field is
defined. I mean that every column has a maximum length and I want to
use this maximum length as a separator. So if one cell in that
column is shorter than the maximum, cell should be padded with white
spaces or something like that.
Dear R saviors,
kindly address to this problem, I would really appreciate any takers. I am
trying to resolve this issue of IMR in clustered (multilevel)
cross-sectional panel data for more than two months now,.
The characteristics of my dataset are as follows:
- some 900 000 individuals
-
This bears no relationship to what you were first asking. It look
like you want to split the leading 4 characters into two groups of two
and then split the remaining data into three parts based on numerics
in the middle. Is this correct?
On Tue, Sep 8, 2009 at 8:15 AM, Lauri
On 9/8/2009 8:21 AM, Lauri Nikkinen wrote:
This data is from database and the maximum length of a field is
defined. I mean that every column has a maximum length and I want to
use this maximum length as a separator. So if one cell in that
column is shorter than the maximum, cell should be padded
On Tue, Sep 08, 2009 at 02:53:11PM +0300, Lauri Nikkinen wrote:
I have a text file similar to this (separated by spaces):
x - DF12 This is an example 1 This
DF12 This is an 1232 This is
DF14 This is 12334 This is an
DF15 This 23 This is an example
and I know the field lengths of each
Kevin,
I did the same installation a week or two ago. The same downloading
process occurred, but not so many iterations. I don't know if it was
normal or not , but the system seems to work very well.
Steve
Steve Friedman Ph. D.
Spatial Statistical Analyst
Everglades and Dry Tortugas National
Dear all,
I have collected the standardize regression coefficients of
Ridge and PLS.
As theory says that Ridge and PLS can retain the grouping property. How can
I see such grouping properties in a data sets i.e group of correlated
variables will get similar coefficients. But how
Petar Milin wrote:
Hello ALL!
I have a problem to plot factor (lets say gender) as a line, or at least
both line and point, from ols model:
ols1 - ols(Y ~ gender, data=dat, x=T, y=T)
plot(ols1, gender=NA, xlab=gender, ylab=Y,
ylim=c(5,30), conf.int=FALSE)
If I convert gender into discrete
Thanks for the suggestion, but I don't have an access to this
database, I just got this messy file.
-L
2009/9/8 Duncan Murdoch murd...@stats.uwo.ca:
On 9/8/2009 8:21 AM, Lauri Nikkinen wrote:
This data is from database and the maximum length of a field is
defined. I mean that every column
Hi
what about reading each line by readLine and then split it to desired
portions?
x-paste(letters, collapse=)
substring(x, c(1,3,5),c(2,4,15))
Regards
Petr
r-help-boun...@r-project.org napsal dne 08.09.2009 14:21:53:
This data is from database and the maximum length of a field is
On Tue, Sep 08, 2009 at 03:21:53PM +0300, Lauri Nikkinen wrote:
This data is from database and the maximum length of a field is
defined. I mean that every column has a maximum length and I want to
use this maximum length as a separator. So if one cell in that
column is shorter than the
Thanks Petr, I tried something like this
con - file(C:temppi.txt, r, blocking = FALSE)
g - readLines(con)
close(con)
sta - c(1, 3, 5, 19)
sto - c(2, 4, 18, 100)
do.call(rbind, lapply(g, function(x) substring(x, sta, sto)))
[,1] [,2] [,3] [,4]
[1,] DF 12 This is an ex
UPDATE:
I'm not sure why, but on my Windows XP 64bit machine, I ran the same
code again and this time it is not working even though it worked
previously. This has been done using the Rgui --vanilla command.
x - c(Weekly sales figures to 30 August 2008 published 5 September,
Weekly sales
Hi Yan,
Before I try to answer your question: please send R questions to the r-
help mailing list (cc'd here). You will likely get your answer more
quickly (since I'm not the only one looking at it) and it might help
other people who get stuck on a similar situation by finding the
answer
On 08-Sep-09 12:21:53, Lauri Nikkinen wrote:
This data is from database and the maximum length of a field is
defined. I mean that every column has a maximum length and I want to
use this maximum length as a separator. So if one cell in that
column is shorter than the maximum, cell should be
Hi
I deal with long vectors almost all of whose elements are zero.
Typically, the length will be ~5e7 with ~100 nonzero elements.
I want to deal with these objects using a sort of sparse
vector.
The problem is that I want to be able to 'add' two such
vectors.
Toy problem follows. Suppose I
Hi Steve
I am facing a little problem in predict function which is I think mismatch of
dimension. Infacted area is covered by ***.
svm = function()
{
library(RODBC) # load RODBC library for database access
channel = odbcConnect(demo_dsn, sa, 1234) # connecting to the database
Hi,
On Sep 8, 2009, at 9:09 AM, Abbas R. Ali wrote:
Hi Steve
I am facing a little problem in predict function which is I think
mismatch of dimension. Infacted area is covered by ***.
svm = function()
{
library(RODBC) # load RODBC library for database access
channel =
This is to announce a new package rms on CRAN. rms goes along with my
book Regression Modeling Strategies. The home page for rms is
http://biostat.mc.vanderbilt.edu/rms, or go directly to
http://biostat.mc.vanderbilt.edu/Rrms for information just about the
software.
rms is a re-write of
one simple way could be:
sparse.vec - function (..., fun = sum) {
lis - list(...)
values - unlist(lapply(lis, [[, value))
inds - factor(unlist(lapply(lis, [[, index)))
out - tapply(values, inds, FUN = fun)
list(index = as.numeric(levels(inds)), values = out)
}
a - list(index
I have to start by saying that I am new to R, so I might miss something crucial
here. It seems to me that the results of friedman.test and ks.test are wrong.
Now, obviously, the first thing which crossed my mind was it can't be, this is
a package used by so many, someone should have observed,
Hi,
On Sep 8, 2009, at 9:06 AM, Robin Hankin wrote:
Hi
I deal with long vectors almost all of whose elements are zero.
Typically, the length will be ~5e7 with ~100 nonzero elements.
I want to deal with these objects using a sort of sparse
vector.
Would using sparse matrices (from the
Gavin Simpson gavin.simpson at ucl.ac.uk writes:
On Fri, 2009-09-04 at 17:15 +0200, Kim Vanselow wrote:
Dear all,
I would like to calculate a cca (package vegan) with species and
environmental data. One of these environmental variables is
cos(EXPOSURE).
The problem: for flat releves
Robin == Robin Hankin rk...@cam.ac.uk
on Tue, 08 Sep 2009 14:58:49 +0100 writes:
Robin Hi guys
Robin thanks for this, it works fine, but I'm not sure the Matrix package
does
Robin what I want:
a = sparseMatrix(i=c(20, 30, 10), j=rep(1, 3), x=c(2.2, 3.3,
4.4))
Not sure what you mean by 'store', but you can use a list:
a - matrix(1, nrow = 5, ncol = 1)
b - matrix(2, nrow = 10, ncol = 1)
c - matrix(3, nrow = 15, ncol = 1)
myList - list(a, b, c)
str(myList)
List of 3
$ : num [1:5, 1] 1 1 1 1 1
$ : num [1:10, 1] 2 2 2 2 2 2 2 2 2 2
$ : num [1:15,
Dear useRs,
I want to plot the following barplot with lines instead of bars. Is there a way?
data - data.frame(cbind(k = 0:3, fk = c(11, 20,7,2), f0k = c(13.72, 17.64,
7.56, 1.08), fkest = c(11.85, 17.78, 8.89, 1.48)))
d - t(data[,2:4])
barplot(d, beside=TRUE)
Regards,
Rafael.
dear Dan,
As far as I know, the strucchange package can be helpful for you..
On the other hand, if your regression function is continuous at the
unknown break points to be estimated, you could try the segmented package.
Hope this helps you,
vito
Daniel Brewer ha scritto:
Hello,
I would
Hi,
On Sep 8, 2009, at 9:56 AM, Abbas R. Ali wrote:
my dimentions of trining set dim(trainingset) = 7 x 96 and dim
(validation) = 3 x 96
other thing if i want to predicit trainingset accuracy it is also
giviing me same error. Now its no issue of dimentions from my side.
1. Please keep
Hi,
On Sep 8, 2009, at 9:28 AM, Abbas R. Ali wrote:
by using predict(model.ksvm, validationset, ...) I am facing
following error:
Error: '...' used in an incorrect context
No. I didn't mean to explicitly use ..., sorry.
Actually, I had a two line fix here, but I'm looking back at your
Here is a solutions using ggplot2 and reshape
library(reshape)
library(ggplot2)
data - data.frame(k = 0:3, fk = c(11, 20,7,2), f0k = c(13.72, 17.64, 7.56,
1.08), fkest = c(11.85, 17.78, 8.89, 1.48))
Molten - melt(data, id.vars = k)
ggplot(Molten, aes(x = k, y = value, colour = variable)) +
Pharmacokinetic and pharmacodynamic modeling and simulation
By Dr. Jan Freijer
September 24, 2009
Amsterdam, The Netherlands
http://www.can.nl/events/details.php?id=57
This course is aimed at users of R or S-PLUS in the bio-pharmaceutical
sciences who would like to use R for
library(Matrix)
a = sparseMatrix(i=c(20, 30, 1), j=rep(1, 3), x=c(2.2, 3.3,
4.4))
b = sparseMatrix(i=c(3, 30), j=rep(1, 2), x=c(0.1, 0.1), dims=dim(a))
theSum = a+b
summary(theSum)
hth,
b
On Sep 8, 2009, at 10:19 AM, Henrique Dallazuanna wrote:
Try this:
abMerge - merge(a, b, by
On 08-Sep-09 13:06:28, Robin Hankin wrote:
Hi
I deal with long vectors almost all of whose elements are zero.
Typically, the length will be ~5e7 with ~100 nonzero elements.
I want to deal with these objects using a sort of sparse
vector.
The problem is that I want to be able to 'add' two
On Tue, Sep 8, 2009 at 1:52 PM, Lauri Nikkinenlauri.nikki...@iki.fi wrote:
But this is not the solution I was looking for. Thanks.
I think the only way you'll get the solution you are looking for is
if you can let us have a copy of the original input file, or at least
the first few lines - and
Thanks to Justin, Baptiste, and Sebed for your answers.
The solutions work well. I have been putting them to good use today: the
code now works wonderfully and I learnt some useful tricks!
thanks, Peter
-Original Message-
From: justin bem [justin_...@yahoo.fr]
Sent: 9/8/2009 9:06:23
Alex,
It's mainly speculation, as I cannot check the Excel add-in nor Vassar, but
I'll give it a try.
For the Friedman-test: Results of R coincide with those reported by Hollander
Wolfe, which I'd take as a point in favor of R. In any case, my guess is that
ties are handled differently
Win7, R-2.9.1
Dear list,
I have a large (nxm) matrix which is the output of an analysis. Since it
is so large, I would like to use output formatting to make it easier to
find particular values and patterns in the matrix. In particular, I want
to print the matrix as follows:
- cells with a
Hi list,
I have a data frame with a Date column and a Price column - for example:
Date Price
01/01/2009 5.45
01/03/2009 6.53
01/04/2009 7.55
01/06/2009 6.76
01/08/2009 4.12
01/18/2009 5.87
...
As you can see, there are days for which I don't have any data.
Dear All,
Has anyone tried to use this plug-in? Since I am running R-2.9.1 it will not
even let me install it. Further, since I am running Windows I cannot use the R
provided R-2.7.0 Linux installation file from the archive (tried to install it
through cygwin and it was a mess). Suggestions?
Hello,
I would like to test some data to see whether it has the shape of a step
function (i.e. y1 up until x_th and then y2 where x_th is the
threshold). The threshold x_th is unknown and the x values can only
take discrete values (0,1,2,3,4).
An example would be:
data-
Thanks a lot, Mohamed.
Kind regards,
Ezhil
--- On Mon, 9/7/09, Mohamed Lajnef mohamed.laj...@inserm.fr wrote:
From: Mohamed Lajnef mohamed.laj...@inserm.fr
Subject: Re: [R] Averaging rows if a condition is true.
To: A Ezhil ezhi...@yahoo.com
Cc: r-help@r-project.org
Date: Monday,
Ok, I think that I have to give up and try to get this data separated
by some char. It seem pretty much impossible to separate those fields.
Thanks for your help and efforts.
-L
2009/9/8 Lauri Nikkinen lauri.nikki...@iki.fi:
This is the file (see the attachment) that represents the problem I'm
Hi
Actually there is no more trouble with R 2.9.2 version. I was using 2.5.0 and
really needed to update!
Thanks anyway
Edwige
De : William Dunlap wdun...@tibco.com
Envoyé le : Mardi, 8 Septembre 2009, 18h12mn 59s
Objet : RE: [R] R-crash when loading
Hello, I have the following makefile. The problem is that the bibliography
doesn t work. Any help would be appreciated! I really don t don t what to
do..:-(
# The sources of the report (tex, Rnw and other files (e.g. bib, idx))
TEX_CMPS = Report problem
RNW_CMPS = prop1 prop2 ExeExps
OTHER =
Dear useRs,
I have a complicated function to be optimized with optim(), and whose
parameters are passed to another function within its evaluation. This
function allows for the parameters to enter as arguments to various
probability distribution functions.
However, I am violating some scoping
Lauri,
Having looked at your example file, and examined its byte-by-byte
content, it is a plain ASCII file which gives exactly the same layout
as you originally posted. This, along with the field-width information
you originally supplied, is not sufficient to determine a
unique dcomposition into
Consider the following simple example using R-2.9.0 and 'perm' 2.9.1:
require('perm')
p- c(15,21,26,32,39,45,52,60,70,82)
g- c('y','n','y','y', rep('n',6)) #Patients ranked 1,3,4 receive treatment
permTS(p ~ g, alternative = 'two.sided', method='exact.ce') #find
p-value by complete
On Sep 8, 2009, at 12:00 PM, Lauri Nikkinen wrote:
Ok, I think that I have to give up and try to get this data separated
by some char. It seem pretty much impossible to separate those fields.
Thanks for your help and efforts.
The solution that Henrique offered seems to be a complete one:
This is the file (see the attachment) that represents the problem I'm
facing with the original file. I'm looking for some generic way to
solve this problem. Thank you for your time.
-L
2009/9/8 Barry Rowlingson b.rowling...@lancaster.ac.uk:
On Tue, Sep 8, 2009 at 1:52 PM, Lauri
I'm sorry, but I think I was misunderstood. What I need is something like
this:
http://img525.imageshack.us/img525/2818/imagemyu.jpg
Lines instead of bars
Thanks!
Rafael.
ONKELINX, Thierry wrote:
Here is a solutions using ggplot2 and reshape
library(reshape)
library(ggplot2)
data -
swertie v_coudrain at voila.fr writes:
Hello, I performed a Mantel test and plotted communitiy similarities. I
would like to add a least square line. I thought about using abline taking
as slope the r-statistic of the Mantel test and calculating the y-intercept
analytically. Is this method
On 08-Sep-09 16:17:00, David Winsemius wrote:
On Sep 8, 2009, at 12:00 PM, Lauri Nikkinen wrote:
Ok, I think that I have to give up and try to get this data separated
by some char. It seem pretty much impossible to separate those fields.
Thanks for your help and efforts.
The solution that
Hi there,
Does anyone know a method to calculate the number of different patterns
in a given data frame. The variables are of polytomous type and not
binary (for the latter i found a package called countpattern which
unfortunately only functions for binary variables).
V1 V2 V3
0 3 1
Hi there,
I have the following problem:
I have a package called polLCA which has the following syntax:
poLCA(formula, data)
and needs the following formula definition:
formula - cbind(V1,V2,V3,...)
So far so good.
What I tried now was the following:
#Get data with the read.table fuction
SOLVED.
Thanks to a reply off-list it appears that the 'space' in published
11 is actually some kind of multibyte character. If I physically
delete the 'space' and replace it by using the spacebar on my
keyboard, then strsplit() behaves as expected.
I had got the text from a hyperlink and copy
Dear R users,
Something is strange in summary and IQR. Suppose, I have a data set and I
would like to find the Q1, Q2, Q3 and IQR.
x-c(2,4,11,12,13,15,31,31,37,47)
summary(x)
Min. 1st Qu. MedianMean 3rd Qu.Max.
2.00 11.25 14.00 20.30 31.00 47.00
IQR(x)
[1] 19.75
Hello,
I am trying to map a factor variable within a data frame to a new variable
whose entries are derived from the content of the original variable and there
are fewer factors in the new variable. That is, I'm trying to set up a
surjection.
After first thinking that this would be a common
okay fixed it by putting c in quote marks.
1Rnwb wrote:
Hello, I am using B as a vector to store all the t.tests. since i am a
newbie to both R and statistics I am not sure if B is the list. Also I
see c used in the do.call formula and do not know what it is being used
for. I used
It's all simply a matter of definitions, and there are many who disagree. See
?quantile , specifically the type argument. Since IQR does not appear to
have a type argument, you could easily write your own versions of these that do
what SAS does (assuming that is your goal).
With x defined
What's the difference between a line and a thin bar?
Hadley
On Tue, Sep 8, 2009 at 12:17 PM, rafamoralrafa_moral2...@yahoo.com.br wrote:
I'm sorry, but I think I was misunderstood. What I need is something like
this:
http://img525.imageshack.us/img525/2818/imagemyu.jpg
Lines instead of
Hi,
I am using ada to predict a data set with 36 variables
ada(x~.,data=train,iter=Iter,
control=rpart.control(maxdepth=4,cp=-1,minsplit=0,xval=0))
can any one tell me in in laymans terms
maxdepth- how do you set this, how do you change this to improve
predictions success
cp- same question
Well, yeah, Henrique's solutions works fine with this data. Thanks for
that, although this is not so generic solutions which I was looking
after. As I originally posted, I was looking for solution which uses
the field-width information, as Ted pointed out. But as I already
mentioned, it seems that
Vishal vishalps at gmail.com writes:
Jari, thanks for the quick answer.
sqrt(eigen(cov.trob(mydataforellipse)$cov)$values)
what will this return?
For my data, I get:
sqrt(eigen(cov.trob(r)$cov)$values)
[1] 1.857733e-05 4.953181e-06
Is this Left hand value the major or the
Dear Jürgen,
If x is your data, here are two suggestions:
# Suggestion 1
length(unique( apply(x, 1, paste, sep=, collapse=) ) )
# [1] 2
# Suggestion 2
res - as.data.frame( xtabs( ~. , as.data.frame( x ) ) )
dim(res[res$Freq 0,])[1]
# [1] 2
HTH,
Jorge
2009/9/8 Biedermann, Jürgen
try this:
DF - data.frame(V1 = c(0,1,1), V2 = c(3,2,2), V2 = c(1,0,0))
DF
nrow(unique(DF))
I hope it helps.
Best,
Dimitris
Biedermann, Jürgen wrote:
Hi there,
Does anyone know a method to calculate the number of different patterns
in a given data frame. The variables are of polytomous
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