dear all
i am trying to perform t-test (t.test) in R
here i am putting the commands and answer i got
t.test(Ht_cm[from_treeline=='above'][type=='SD'],Ht_cm[from_treeline=='below'][type=='SD'])
Welch Two Sample t-test
data: Ht_cm[from_treeline == above][type == SD] and
2009/10/25 Uwe Ligges lig...@statistik.tu-dortmund.de
Rainer M Krug wrote:
Hi
I am using Ubuntu Hardy, and I installing many packages from source. I am
keeping my R packages fairly up to date.
My question is: is there a way, of keeping the source packages, so that
when
I am installing
Readers,
I have a data set as follows:
1,1
2,2
3,3
4,4
5,3
6,2
7,-10
8,-9
9,-3
10,2
11,3
12,4
13,5
14,4
15,3
16,2
17,1
I entered this data set using the command 'read.csv'. I want to
exclude values fewer than zero in column 2 so then I tried the
following command:
ms.com wrote:
dear all
i am trying to perform t-test (t.test) in R
here i am putting the commands and answer i got
t.test(Ht_cm[from_treeline=='above'][type=='SD'],Ht_cm[from_treeline=='below'][type=='SD'])
Welch Two Sample t-test
data: Ht_cm[from_treeline == above][type == SD] and
Try this:
boxplot.stats(x[x[,2]0,2],do.conf=FALSE)
HTH,
Stephan
e-letter schrieb:
Readers,
I have a data set as follows:
1,1
2,2
3,3
4,4
5,3
6,2
7,-10
8,-9
9,-3
10,2
11,3
12,4
13,5
14,4
15,3
16,2
17,1
I entered this data set using the command 'read.csv'. I want to
exclude values fewer than
Hi
data(gasoline)
str(gasoline)
'data.frame': 60 obs. of 2 variables:
$ octane: num 85.3 85.2 88.5 83.4 87.9 ...
$ NIR : AsIs [1:60, 1:401] -0.050193 -0.044227 -0.046867 -0.046705
-0.050859 ...
..- attr(*, dimnames)=List of 2
.. ..$ : chr 1 2 3 4 ...
.. ..$ : chr 900 nm 902 nm
Hi
not sure that i understand what you want but maybe something like this can
help you
df-data.frame(x=1:10, y=5*(1:10)+3+rnorm(10))
plot(df)
abline(fit-lm(y~x, data=df))
matlines(predict(fit, interval=confidence))
segments(df$x, df$y, df$x, df$y-resid(fit))
Regards
Petr
Thank you everyone for all the responses.
Clint you are correct in assuming that the problem deals with sensors in a
lab setup which can be assumed to be isolated from outside temperature
changes. And, I am only dealing with temperature so the other parameters are
not important.
There will be
I am using eclipse and jboss server.I am successful in calling R from java
using Rserve.
Now i want to solve lpp (linear programming). For this i require rglpk
package
how to write the java program to include the rglpk package or to solve the
lpp.
this is the small program which i tried
Dear list,
I have been searching for a week to fit a simple linear model to my data. I
have looked into the previous posts but I haven't found anything relevant to
my problem. I guess it is something simple...I just cannot see it.
I have the following data frame, named data, which is a subset of
I'm not familiar with microarray data, so I hope I'm not off base here.
Data frames are structured so that variables appear in the columns and
cases in the rows. From your formula it looks like you're trying to
fit a model using rows as variables and columns as cases. There is
probably a way to
Hi
r-help-boun...@r-project.org napsal dne 26.10.2009 10:48:51:
Dear list,
I have been searching for a week to fit a simple linear model to my
data. I
have looked into the previous posts but I haven't found anything
relevant to
my problem. I guess it is something simple...I just cannot
Thank you all for your replies. I have tried transposing my data and before
but I did not mention it because I was getting the same error. In the
present case though it worked because I put
lm1=lm(*norm~*.,data=t(data))
instead of
lm1=lm(*fm1*, data=t(data))
where *fm1=norm~cols...*
I actually
Hi all,
Is there a function in R that handle nonparametric model for survival
analysis (Cox or Weibull)?
Thanks a lot
Val
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
When I run sentDetect in the openNLP package I receive a Java heap space
exception. How can I increase the heap space?
I am running the 64-bit Leopard version of R 2.9.2 and R.app on a Mac with
OS X 10.5.8.
Thanks,
Richard
--
View this message in context:
r-help-boun...@r-project.org napsal dne 26.10.2009 11:31:26:
Thank you all for your replies. I have tried transposing my data and
before
but I did not mention it because I was getting the same error. In the
present case though it worked because I put
lm1=lm(*norm~*.,data=t(data))
instead of
On Oct 25, 2009, at 1:20 PM, Tanya Cashorali wrote:
I'm trying to extract the points above and below a particular lsfit.
I can only get the residuals from the original fit though.
x = runif(100, 0, 10)
plot(x)
abline(lsfit(1:100, test))
Error in as.matrix(y) : object 'test' not found
I
On 10/26/09, Val valkr...@gmail.com wrote:
Is there a function in R that handle nonparametric model for survival
analysis (Cox or Weibull)?
http://www.rseek.org/?cx=010923144343702598753%3Aboaz1reyxd4q=survival+analysissa=Search+functions%2C+lists%2C+and+morecof=FORID%3A11
Liviu
Hi,
This is my first post in this page althougt i've been using R for several
months (by the way english is not my native language so sorry about the
grammar).
I have a problem with a xyplot on lattice, it's supossed to print different
lines for each river (Rio) conditioned by a chemical
My guess is (since no data was supplied) is that the data is not
sorted into date order. Can you provide a subset of the data that
exhibits the problem? It may just be a matter of sorting your
dataframe into date order before doing the plots.
On Mon, Oct 26, 2009 at 9:14 AM, marcos carvajalino
On Oct 26, 2009, at 8:47 AM, Tanya Cashorali wrote:
Sorry here's working code, I wrote it from my iPhone before!
Gee, can I get the R.app that runs on an iPhone?
x = runif(100, 0, 10)
plot(x)
abline(lsfit(1:100, x))
abline(lsfit(1:100, x + sd(x)))
fit = lsfit(1:100, x + sd(x))
y =
Dear list,
I have the following text to parse (originating from readLines as some
lines have unequal size),
st = c(START text1 1 text2 2.3, whatever intermediate text, START
text1 23.4 text2 3.1415)
from which I'd like to extract the lines starting with START, and
group the subsequent fields in
Thanks a lot Jim!! i sorted them and BINGO!!
How about the sum issue? any ideas?
--
Marcos Antonio Carvajalino Fernández
Estudiante de Ingeniería Ambiental y Sanitaria
Universidad del Magdalena, Colombia
[[alternative HTML version deleted]]
Thanks a lot Jim!! i sorted them and BINGO!!
How about the sum issue? any ideas?
--
Marcos Antonio Carvajalino Fernández
Estudiante de Ingeniería Ambiental y Sanitaria
Universidad del Magdalena, Colombia
__
R-help@r-project.org mailing list
Hi,
I am new in statistics and i manage to make the linear model analysis but i
have some difficulties in explaining the results. Can someone help me
explain the output of my linear model analysis ? My data are with 2
variables habitat (e,s) and treatment (a,c,p) with multiple trials within.
You probably want to use something like aggregate or tapply to sum up
the required quantities. Impossible to give more precise answers
without the actual data and what the expected results might look like.
On Mon, Oct 26, 2009 at 9:36 AM, marcos carvajalino
maancafe...@gmail.com wrote:
Thanks a
Hi all,
I am new to R and learning the same. I would like to create a sparse matrix
from an existing file whose contents are in the format
rowIndex,columnIndex,value
for ex:
1,2,14
2,4,15
I would like to create a sparse matrix by taking the above as input.
However, I couldn't find an
Dear all
I am trying to learn R
I was trying to calculate standard deviation
here are the commands and outputs in R
sd(Ht_cm[type=='SD'])[1] 3.283605 sd(Ht_cm[from_treeline=='above'])[1]
16.83289 sd(Ht_cm[type=='SD'][from_treeline=='above'])[1] NA
the problem is that, i could not understand
Dear R users,
Im performing some GLMMs analysis with a negative binomial link.
I already performed such analysis some months ago with the lmer() function
but when I tried it today I encountered this problem:
*Erreur dans famType(glmFit$family) : unknown GLM family: Negative
Binomial*
Does
Assuming only START fields match pat:
## this one has more fields: how do I generalize the regular expression?
st2 = c(START text1 1 text2 2.3 text3 5, whatever intermediate text,
+ START text1 23.4 text2 3.1415 text3 6)
pat - [[:alnum:]]+ +([0-9.]+)
s - strapply(st2, pat, c, simplify =
Sorry here's working code, I wrote it from my iPhone before!
x = runif(100, 0, 10)
plot(x)
abline(lsfit(1:100, x))
abline(lsfit(1:100, x + sd(x)))
fit = lsfit(1:100, x + sd(x))
y = which(residuals(fit) 0)
points(y, x[y], col=red)
Notice the points that are red are all the ones above the first
Perfect, thanks!
baptiste
2009/10/26 Gabor Grothendieck ggrothendi...@gmail.com:
Assuming only START fields match pat:
## this one has more fields: how do I generalize the regular expression?
st2 = c(START text1 1 text2 2.3 text3 5, whatever intermediate text,
+ START text1 23.4 text2
On 26-Oct-09 09:44:55, ms.com wrote:
Dear all
I am trying to learn R
I was trying to calculate standard deviation
here are the commands and outputs in R
sd(Ht_cm[type=='SD'])[1] 3.283605
sd(Ht_cm[from_treeline=='above'])[1] 16.83289
sd(Ht_cm[type=='SD'][from_treeline=='above'])[1] NA
I am reading Section 5 and 6 of
http://cran.r-project.org/doc/contrib/Leisch-CreatingPackages.pdf
It seems that I have to do the following two steps in order to make an
R package. But when I am testing these package, these two steps will
run many times, which may take a lot of time. So when I
Hello,
I have done a robust two-way ANOVA with the WRS (Wilcox's Robust
Statistics) package. I was also interested in doing a planned
comparison among means, but my knowledge of statistics is quite
limited, and I don't know if a robust version for a planned
comparison of means exists. If it
On 10/26/2009 10:29 AM, Peng Yu wrote:
I am reading Section 5 and 6 of
http://cran.r-project.org/doc/contrib/Leisch-CreatingPackages.pdf
It seems that I have to do the following two steps in order to make an
R package. But when I am testing these package, these two steps will
run many times,
Peng Yu wrote:
I am reading Section 5 and 6 of
http://cran.r-project.org/doc/contrib/Leisch-CreatingPackages.pdf
It seems that I have to do the following two steps in order to make an
R package. But when I am testing these package, these two steps will
run many times, which may take a lot
What are the values of
length((Ht_cm[type=='SD'][from_treeline=='above'])[1])
I suspect the error is in the subsetting - the following seems more plausible:
Ht_cm[type=='SD' from_treeline=='above']
Hadley
--
http://had.co.nz/
__
On 10/26/2009 11:05 AM, hadley wickham wrote:
What are the values of
length((Ht_cm[type=='SD'][from_treeline=='above'])[1])
I suspect the error is in the subsetting - the following seems more plausible:
Ht_cm[type=='SD' from_treeline=='above']
But don't double that ampersand: use
I've rolled up R-2.10.0.tar.gz some hours ago. This is a development
release which contains a number of new features, notably a brand new
HTML based dynamic help system.
Also, a number of mostly minor bugs have been fixed. See the full list
of changes below.
You can get it from
Hi and sorry for the late reply. The Gdk library is part of the GTK+ bundle
(GTK+, Gdk and GdkPixbuf are distributed together and have synchronized
versions). So you'll just need GTK+ 2.12 or higher.
Michael
On Tue, Oct 20, 2009 at 8:16 AM, Ronggui Huang ronggui.hu...@gmail.comwrote:
Dear all,
(D'oh. Forgot to change the Subject: line...)
I've rolled up R-2.10.0.tar.gz some hours ago. This is a development
release which contains a number of new features, notably a brand new
HTML based dynamic help system.
Also, a number of mostly minor bugs have been fixed. See the full list
of
Dear MS,
please follow the posting guide and provide reproducible lines of code !
Like this I have no idea what's inside your Ht_cm object .
Maybe the problem is that your data might contain NAs, since the basic
formula doesn't allow missing values. In this case you have to specify
how the
On 26 October 2009 at 07:57, Martin Morgan wrote:
| Peng Yu wrote:
| I am reading Section 5 and 6 of
| http://cran.r-project.org/doc/contrib/Leisch-CreatingPackages.pdf
|
| It seems that I have to do the following two steps in order to make an
| R package. But when I am testing these
Aneeta,
My gorilla and mouse analogies were referring to the magnitude of
the disturbance and also to its time signature. Are you only
interested in the large disturbance which is abrupt (the gorilla)?
Or do you also want to be able to detect the more surreptitious
attack which may be quite
Dear all,
I am trying to use the crr function in the cmprsk package version 2.2 to
analyse 198 observations.I have receive the error in solve.default.
Can anyone give me some
insights into where the problem is?
Thanks
here is my script and in attached file my data.
cov=cbind(x1,x2)
Hexbin used to use base graphics, but has switched to grid. So you can either
learn how to augment the grid graph, use lattice and learn how to augent there.
Or you can get a fairly good base graphics approximation using the my.symbols
function in the TeachingDemos package, e.g.:
x -
All these have been really helpful. Once again I see that anything's possible
in R!
Thank you for the suggestion Bill, I think arranging the data in one data
frame is a good idea.
-Daniel
William Dunlap wrote:
-Original Message-
From: r-help-boun...@r-project.org
Thank you ,Petr
It is a good answer,clearly.
thanks!
Petr Pikal wrote:
Hi
data(gasoline)
str(gasoline)
'data.frame': 60 obs. of 2 variables:
$ octane: num 85.3 85.2 88.5 83.4 87.9 ...
$ NIR : AsIs [1:60, 1:401] -0.050193 -0.044227 -0.046867 -0.046705
-0.050859 ...
..-
Hello All!
I am trying to plot the frequency of species coocurrance.
If given a data set similar like this...(V1=species A, V2=species B,
V3=frequency of cooccurance)
data
V1 V2 V3
1 A B 0
2 A C 2
3 A D 5
4 B C 0
5 B D 1
6 C D 0
I'm having a little trouble building a package with a namespace. Suppose I have
two functions: g and f and I want to build the package foo. Suppose f is a
function that has an internal purpose and should not be visible to the user.
Additionally, I do not want to write a help (Rd) file for f.
Dear useRs,
I have the following plot:
pos - c(27/44, 11/32, 8/40, 4/42, 3/40, 4/40, 2/40)
tmin - c(15.8, 12.6, 10.5, 2.4, 5.2, 8.5, 7.9)
plot(tmin, pos)
I would like to fit an exponential curve to it.
How could I be able to do this?
Thanks in advance,
Rafael.
Hi,
Using the latest rms package I am able to make nice plots of model predictions
+/- desired confidence intervals like this:
# need this
library(rms)
# setup data
d - data.frame(x=rnorm(100), y=rnorm(100))
dd - datadist(d)
options(datadist='dd')
# fit model
l - ols(y ~ rcs(x), data=d)
#
Hi Rafael,
Here is a suggestion:
# Data
pos - c(27/44, 11/32, 8/40, 4/42, 3/40, 4/40, 2/40)
tmin - c(15.8, 12.6, 10.5, 2.4, 5.2, 8.5, 7.9)
d - data.frame(pos, tmin)
# Non-linear model
fit - nls(pos ~ a*tmin^b,
data = d,
start = list(a = .1, b = .1),
Manue wrote:
Dear R users,
Im performing some GLMMs analysis with a negative binomial link.
I already performed such analysis some months ago with the lmer() function
but when I tried it today I encountered this problem:
*Erreur dans famType(glmFit$family) : unknown GLM family:
Lanna Jin wrote:
Hello All!
I am trying to plot the frequency of species coocurrance.
If given a data set similar like this...(V1=species A, V2=species B,
V3=frequency of cooccurance)
data
V1 V2 V3
1 A B 0
2 A C 2
3 A D 5
4 B C 0
5 B D 1
6 C D 0
Dylan Beaudette wrote:
Hi,
Using the latest rms package I am able to make nice plots of model predictions
+/- desired confidence intervals like this:
# need this
library(rms)
# setup data
d - data.frame(x=rnorm(100), y=rnorm(100))
dd - datadist(d)
options(datadist='dd')
# fit model
l -
On 10/26/2009 1:43 PM, Doran, Harold wrote:
I'm having a little trouble building a package with a namespace. Suppose I have
two functions: g and f and I want to build the package foo. Suppose f is a
function that has an internal purpose and should not be visible to the user.
Additionally, I
On Mon, Oct 26, 2009 at 11:22 AM, Dirk Eddelbuettel e...@debian.org wrote:
On 26 October 2009 at 07:57, Martin Morgan wrote:
| Peng Yu wrote:
| I am reading Section 5 and 6 of
| http://cran.r-project.org/doc/contrib/Leisch-CreatingPackages.pdf
|
| It seems that I have to do the
I've never seen the / used in a formula like that. What does it do?
-Ista
On Mon, Oct 26, 2009 at 8:13 AM, john56 panath...@gmail.com wrote:
Hi,
I am new in statistics and i manage to make the linear model analysis but i
have some difficulties in explaining the results. Can someone help me
I thought that 'validity' defined in 'setClass' should be called in
'new'. Could somebody let me know why 'validity' is not called? How to
make it be called?
setClass(
+ Class='A',
+ representation=representation(
+ x='numeric'
+ ),
+ validity=function(object){
+
There are different way to make R classes. I know R.oo and S4. I'm
wondering which one is the current popular one. Which one is current
recommended when make new R packages? Thank you!
__
R-help@r-project.org mailing list
Peng Yu wrote:
I thought that 'validity' defined in 'setClass' should be called in
'new'. Could somebody let me know why 'validity' is not called? How to
make it be called?
setClass(
+ Class='A',
+ representation=representation(
+ x='numeric'
+ ),
+
Peng Yu wrote:
There are different way to make R classes. I know R.oo and S4. I'm
wondering which one is the current popular one. Which one is current
recommended when make new R packages? Thank you!
It depends on who the recommender is. S4 is part of the methods package
and therefore of R's
'?removeClass' shows that 'removeClass' is from package
'package:methods'. Is there a command which can show me all the
functions and the classed defined in a package such as
'package:methods'?
__
R-help@r-project.org mailing list
-Original Message-
From: Duncan Murdoch [mailto:murd...@stats.uwo.ca]
Sent: Monday, October 26, 2009 2:29 PM
To: Doran, Harold
Cc: r-help@r-project.org
Subject: Re: [R] Help with namespace
On 10/26/2009 1:43 PM, Doran, Harold wrote:
I'm having a little trouble building a
On 26 October 2009 at 13:29, Peng Yu wrote:
| On Mon, Oct 26, 2009 at 11:22 AM, Dirk Eddelbuettel e...@debian.org wrote:
|
| On 26 October 2009 at 07:57, Martin Morgan wrote:
| | Peng Yu wrote:
| | I am reading Section 5 and 6 of
| |
Perhaps subset the data first?
subset(x, x[,2] =0)
--- On Mon, 10/26/09, e-letter inp...@gmail.com wrote:
From: e-letter inp...@gmail.com
Subject: [R] exclude data for boxplot stats using mathematical operator
To: r-help@r-project.org
Received: Monday, October 26, 2009, 3:25 AM
Readers,
Peng Yu wrote:
'?removeClass' shows that 'removeClass' is from package
'package:methods'. Is there a command which can show me all the
functions and the classed defined in a package such as
'package:methods'?
getClasses(where=getNamespace('methods'))
showMethods(where=getNamespace('methods'))
Dirk Eddelbuettel wrote:
On 26 October 2009 at 13:29, Peng Yu wrote:
| On Mon, Oct 26, 2009 at 11:22 AM, Dirk Eddelbuettel e...@debian.org wrote:
|
| On 26 October 2009 at 07:57, Martin Morgan wrote:
| | Peng Yu wrote:
| | I am reading Section 5 and 6 of
| |
There are two basic class method dispatching mechanisms in R: S3 and
S4. These are not R.oo.
From a *design* point of view, S3 and S4 are rather similar, or more
precisely, you can do the same things in both if you're careful. From
an implementation point of view, they are different, and the
On Mon, Oct 26, 2009 at 1:49 PM, Martin Morgan mtmor...@fhcrc.org wrote:
Peng Yu wrote:
I thought that 'validity' defined in 'setClass' should be called in
'new'. Could somebody let me know why 'validity' is not called? How to
make it be called?
setClass(
+ Class='A',
+
S3 and S4 are part of the core of R so they would presumably be the
most used. S4 is an extension to S3 but adds strong typing and a
number of other features. R.oo and proto are packages on CRAN which
give access to different models of object oriented programming than S3
and S4. R.oo uses a more
I'm having some difficulty with graphing outputs of a GLM model I've
been working. I have count data for both my predictor (only 1) and
response variables, and I have pseudoreplication which I've modeled as
a random effect. The odTest() from pscl:: indicated that the negative
binomial distribution
Any news about this?
I sent reproducible data to author but no reply.
Thanks in advance,
Max
madmax1425 wrote:
Thanks! I just sent him an email. If anyone noticed any behavior change
with this function version 3.3.1 please report any finding.
Thanks in advance,
Max
Uwe Ligges-3
Hi,
I'd like to clarify my previous posting. See below - my updates are noted with
*s
Thanks,
Sarah Ordaz
ord...@upmc.edu
Hello,
I am a newbie to the lattice package in R, and I'm trying to make a plot using
the xyplot function. I have repeated measures data (2 conditions) for two
different
Peng Yu wrote:
On Mon, Oct 26, 2009 at 1:49 PM, Martin Morgan mtmor...@fhcrc.org wrote:
Peng Yu wrote:
I thought that 'validity' defined in 'setClass' should be called in
'new'. Could somebody let me know why 'validity' is not called? How to
make it be called?
setClass(
+ Class='A',
+
Hello,
I apologize for the post as I am certainly overlooking a simple
solution to my difficulties with getting a legend to print on a
survplot from the rms package.
I am plotting the following:
survplot(survest(fita), n.risk=T, conf='none', cex.n.risk=.85, dots=T,
col='gray10', lty=2)
Dear R People:
Suppose I have a data.frame, x.df, which has one column and 100 rows.
Sometimes I need to see it as 20 rows and 5 columns, sometimes I need
to see it as 10 rows with 10 columns.
Is there a quick way to make those transformations, please?
Thanks in advance,
Sincerely,
Erin
PS
I know that my question is like a very newbie question, but at the moment
I stacked with it and I need a quick solution. I need to make an overall
statistical overview of various datasets, the summary() and numSummary()
functions are fully sufficient. My question is, how can I export results
to a
Any suggestions?
quaildoc wrote:
Hello List,
I am fitting a logistic regression model for some presence/absence type
data. I have numerous covariates I am fitting to explain variation, and I
am using AIC to rank models. However, I would like to report how well my
best model (s) do at
Aric Gregson wrote:
Hello,
I apologize for the post as I am certainly overlooking a simple
solution to my difficulties with getting a legend to print on a
survplot from the rms package.
I am plotting the following:
survplot(survest(fita), n.risk=T, conf='none', cex.n.risk=.85, dots=T,
Hi everybody
When I try example of strptime
x - c(1jan1960, 2jan1960, 31mar1960, 30jul1960)
z - strptime(x, %d%b%Y)
The result is;
z
[1] NA NA NA NA
I have got the same result with complete form of month but not with numeric
form.
Any idea?
[[alternative HTML version deleted]]
Not able to replicate:
x - c(1jan1960, 2jan1960, 31mar1960, 30jul1960)
z - strptime(x, %d%b%Y)
z
[1] 1960-01-01 CST 1960-01-02 CST 1960-03-31 CST 1960-07-30 CDT
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
On Behalf Of guillaume chaumet
Hi
Second question in a day, i'm beginnning to feel incompetent...
This time i'm having a weird problem, i'm importing the next data base:
car-read.csv2(Historicos.csv)
'data.frame': 1818 obs. of 6 variables:
$ Dpto : Factor w/ 11 levels ANTIOQUIA,ATLÁNTICO,..: 2 2 2 2 2 1
1 1 1 5 ...
$
-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of guillaume chaumet
Sent: Monday, October 26, 2009 1:32 PM
To: r-help@r-project.org
Subject: [R] as.POSIXct month problem
Hi everybody
When I try example of strptime
x -
Hi Guillaume,
What is your sessionInfo() ? It works me:
x - c(1jan1960, 2jan1960, 31mar1960, 30jul1960)
z - strptime(x, %d%b%Y)
z
[1] 1960-01-01 1960-01-02 1960-03-31 1960-07-30
sessionInfo()
R version 2.9.2 RC (2009-08-23 r49375)
i386-pc-mingw32
locale:
LC_COLLATE=English_United
Thank you for your quick response
sessionInfo()
R version 2.9.2 (2009-08-24)
x86_64-pc-linux-gnu
locale:
Dear all,
I just tried to be fast for once, installed R 2.10 and also newly installed
all previously-installed packages. However, now all my help files are text
only, which is of course a pity with the new possibilities of links between
help pages. What can I do to re-activate chm-help?
On Mon, 26 Oct 2009 13:21:23 -0700
Frank E Harrell Jr f.harr...@vanderbilt.edu wrote:
Please send exact code for an example that fails. If possible,
generate the data using a simple simulation to make the example
reproducible.
endtime - c(251,753,753,791,732,1081,184,713,674,732,254,
That's work with
Sys.setlocale(LC_TIME,en_US.UTF-8)
Thank you
2009/10/26 Jorge Ivan Velez jorgeivanve...@gmail.com
Hi Guillaume,
What is your sessionInfo() ? It works me:
x - c(1jan1960, 2jan1960, 31mar1960, 30jul1960)
z - strptime(x, %d%b%Y)
z
[1] 1960-01-01 1960-01-02 1960-03-31
Hello
On 10/26/09, lanc...@fns.uniba.sk lanc...@fns.uniba.sk wrote:
nsu - numSummary(x[,c(a, b, c)], statistics=c(mean, sd,
quantiles), quantiles=c(0,.25,.5,.75,1))
write.csv(nsu, file = numsummary.csv)
I get the ERROR: cannot coerce class numSummary into a data.frame
message.
Try
Thanks Phil, exactly what i was looking for!!
2009/10/26 Phil Spector spec...@stat.berkeley.edu:
Marcos -
Either refer to
levels(factor(car4$Rio))
or
levels(car4$Rio[,drop=TRUE])
to show only the levels that are present in the variable.
- Phil
guillaume chaumet wrote:
Thank you for your quick response
sessionInfo()
R version 2.9.2 (2009-08-24)
x86_64-pc-linux-gnu
locale:
I realize now that the dynamic help is no longer implemented via chm
apparently. But nevertheless, the intention is certainly to be able to call
help WITH links from within R? What can I do to make that work instead of
the pure text files I get at the moment ? Could a proxy be in the way ?
I
Hello all,
I recently opened a backup .RData file which contained (three) time
variables created in the session I had a few months ago.
Upon inspecting those variables I suddenly realized they all got an extra
hour to them.
So a variable like:
morning - as.difftime(08:00:00)
That was defined a
I am on Ubuntu Karmic.
2009/10/26 Peter Dalgaard p.dalga...@biostat.ku.dk
guillaume chaumet wrote:
Thank you for your quick response
sessionInfo()
R version 2.9.2 (2009-08-24)
x86_64-pc-linux-gnu
locale:
Why not just unlist the data.frame and specify the number of rows in a matrix
each time you need look at a different layout, assuming I understand the
question.
Example
===
aa - data.frame(1:100)
bb - unlist(aa)
(cc - matrix(bb,
Aric Gregson wrote:
On Mon, 26 Oct 2009 13:21:23 -0700
Frank E Harrell Jr f.harr...@vanderbilt.edu wrote:
Please send exact code for an example that fails. If possible,
generate the data using a simple simulation to make the example
reproducible.
endtime -
On Mon, 26 Oct 2009 15:10:42 -0700
Frank E Harrell Jr f.harr...@vanderbilt.edu wrote:
survplot(survest(fit.example1), n.risk=T, conf='none',
cex.n.risk=.85, dots=T, col='gray10', lty=2)
The argument to survplot should be a cph or psm or survfit object (or
a survest result on a psm object).
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