Trafim Vanishek wrote:
Dear all,
Does anybody know the probable reason why = gives false when it should give
true?
These two variables are of the same type, and everything works in the cycle
but then it stops when they are equal.
this is the output result
Rk[47] = RB[21]
[1] FALSE
Rk[47]
Hi Trafim,
take a look at FAQ 7.31.
HTH
Stephan
Trafim Vanishek schrieb:
Dear all,
Does anybody know the probable reason why = gives false when it should give
true?
These two variables are of the same type, and everything works in the cycle
but then it stops when they are equal.
this is
I would like to create a data.frame with dynamic created headers. I will later
fill it with percentiles. My percentiles vector is:
percentiles = c(0.05, 0.10, 0.20, 0.30, 0.40, 0.50, 0.60, 0.70, 0.80, 0.90,
0.95, 1.00)
From this vector I would like to have headers like:
p5, p10, p20, ..., p95,
Hi Mattias,
Try this,
percentiles - c(0.05, 0.10, 0.20, 0.30, 0.40, 0.50, 0.60, 0.70, 0.80, 0.90,
0.95, 1.00)
test - data.frame(matrix(NA,0,12))
names(test) - paste(p,percentiles*100,sep=)
test
[1] p5 p10 p20 p30 p40 p50 p60 p70 p80 p90 p95 p100
Cheers, Hans
-Original
hello
could you give me a hint to convert data in factor type to numeric (float) ?
regards
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check the following:
http://cran.r-project.org/doc/FAQ/R-FAQ.html#How-do-I-convert-factors-to-numeric_003f
Best,
Dimitris
Ahmet Temiz wrote:
hello
could you give me a hint to convert data in factor type to numeric (float) ?
regards
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On 01/13/2010 10:47 AM, Ahmet Temiz wrote:
hello
could you give me a hint to convert data in factor type to numeric (float) ?
regards
--
Open WebMail Project (http://openwebmail.org)
you could try as.numeric but without more details it is difficult to see
if this will work. How
Duncan Murdoch murd...@stats.uwo.ca 12/01/2010 18:07:46
I need to get the p values for a table with 15000 entries of t
values.
...
Put the t values into a vector, then use pt() in an appropriate way
... and don't forget any necessary correction for multiple comparisons;
see
?p.adjust
It did take me a good night's sleep to understand it. I was stuck with
the exact same question but I see now how the remaining balls are
shared among all 8 urns (therefore cases with 11, 12, 13, ... 17 balls
are also dealt with).
Thanks again,
baptiste
2010/1/12 Rolf Turner
On 01/13/2010 02:46 PM, Rex C. Eastbourne wrote:
On Tue, Jan 12, 2010 at 5:26 PM, Rex C. Eastbournerex.eastbou...@gmail.com
wrote:
Let's say I have data in the following schema that describes the number of
purchases a company has received from each County in the US:
State |
Hi
r-help-boun...@r-project.org napsal dne 13.01.2010 01:36:31:
tmp - scan()
0 2 1 0 1 0 2 1 2 3 0 0 0 0 1 0 0 2 3 1
dat - matrix(tmp, byrow=T, ncol=4)
apply(dat, 2, function(x, min.val, max.val) {
tmp - table(x)/length(x)
res - rep(0, max.val - min.val + 1)
Thanks to all of you,
therefore if I got it well, I could also use the command
And, say, --max-mem-size=8G would work
from outside R, to further increase the memory even if the machine is
6giga. I had an idea of that before, but I was not so sure!
Many thanks again for all your advices.
Best
Readers,
For a data set 'x':
1 a
2 b
3 c
4 d
5 e
6 f
7 g
8 h
9 i
How to select multiple subscripts to plot? For example to plot values
1:3 and 9:10:
plot(x[1:3,1],x[,2])
and
plot(x[9:10,1],x[,2])
into one plot?
Yours,
rhelpatconference.jabber.org
r251
Hi,
Thanks a lot for your suggestions and the very detailed instructions, I needed
them...
Everything worked fine also in the full dataset, up until the last suggestion
(the box plots)
Here I also got an error message, but a different one from what you got. And no
output...
Here are the last
Hi
see ?points or ?lines which you would surely found out if you bother to
look at ?plot help page
Regards
Petr
r-help-boun...@r-project.org napsal dne 13.01.2010 13:36:57:
Readers,
For a data set 'x':
1 a
2 b
3 c
4 d
5 e
6 f
7 g
8 h
9 i
How to select multiple subscripts to
On 13/01/2010 7:36 AM, e-letter wrote:
Readers,
For a data set 'x':
1 a
2 b
3 c
4 d
5 e
6 f
7 g
8 h
9 i
How to select multiple subscripts to plot? For example to plot values
1:3 and 9:10:
plot(x[1:3,1],x[,2])
and
plot(x[9:10,1],x[,2])
into one plot?
Neither of those will work, because
Hi,
Can R do FMOLS(Fully Modified OLS) and DOLS(Dynamic OLS)?
I cannot find any useful thing in the present package.
Thanks in advance!
--
View this message in context:
http://n4.nabble.com/How-to-do-FMOLS-and-DOLS-tp1012976p1012976.html
Sent from the R help mailing list archive at
On 13/01/2010, Duncan Murdoch murd...@stats.uwo.ca wrote:
On 13/01/2010 7:36 AM, e-letter wrote:
Readers,
For a data set 'x':
1 a
2 b
3 c
4 d
5 e
6 f
7 g
8 h
9 i
How to select multiple subscripts to plot? For example to plot values
1:3 and 9:10:
plot(x[1:3,1],x[,2])
and
On 13/01/2010, e-letter inp...@gmail.com wrote:
On 13/01/2010, Duncan Murdoch murd...@stats.uwo.ca wrote:
On 13/01/2010 7:36 AM, e-letter wrote:
Readers,
For a data set 'x':
1 a
2 b
3 c
4 d
5 e
6 f
7 g
8 h
9 i
How to select multiple subscripts to plot? For example to plot values
Dear UseRs,
I did not have any answer to my previous message (Is there a way to define
manually columns width when using write.dbf function from the library
foreign ?), so I tried to modify write.dbf function to do what I want.
Here is my modified version :
write.dbfMODIF - function (dataframe,
---BeginMessage---
---End Message---
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained,
On 13/01/2010 8:09 AM, e-letter wrote:
On 13/01/2010, Duncan Murdoch murd...@stats.uwo.ca wrote:
On 13/01/2010 7:36 AM, e-letter wrote:
Readers,
For a data set 'x':
1 a
2 b
3 c
4 d
5 e
6 f
7 g
8 h
9 i
How to select multiple subscripts to plot? For example to plot values
1:3 and
To R-helpers,
Running
R version 2.10.0 (2009-10-26)
Linux ... 2.6.25.20-0.5-default #1 SMP 2009-08-14 01:48:11 +0200 x86_64
x86_64 x86_64 GNU/Linux
openSUSE 11.0 (X86-64)
and having difficulties reading a fifo from within R.
A short example that I find simply haning is shown as 'SHORT
Hi,
I'm trying to make a regression of the form :
formula - y ~ Asym_inf + Asym_sup * ( (1 / (1 + (n1 * (exp( (tmid1-x)
/ scal1) )^(1/n1) ) ) ) - (1 / (1 + (n2 * (exp( (tmid2-x) / scal2)
)^(1/n2) ) ) ) )
which is a sum of the generalized logistic model proposed by richards.
with data such
I have been having the same problem as poster Hodgess, below. It appears
that her question was never answered, so I would like to share a solution
with the community.
The problem is the (apparent?) inability to produce moving range process
behavior (a.k.a. control) charts with individuals data in
Dear R users,
I am running a R code which gives me 10 columns and
160 rows. I need to run the code for 100 times and each time I need to store
the results in a single file.
I do not know how can I store them in a single file without over writting
the results?
Thanks
Alex
You could try the brute force of nls2 package; however, note that you
have 8 parameters and only 16 points so you might look for a more
parsimonious model. Plotting it it seems somewhat gaussian in shape
so:
mod - nls(y ~ a * dnorm(x, b, c), start = c(a = mean(y)/dnorm(0, 0,
sd(x)), b = mean(x),
hello
is it wrong with this expression:
subset(dfpr2_r,(as.numeric(as.character(dfpr2_r$pr2))) 0.2 (dfpr2_r$landa
10))
it gives nothing
regards
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Yupp, FAQ 7.31 is definitely your friend here.
You might also want to take a look at these two very recent threads on
this help list:
Strange behaviour of as.integer()
http://tolstoy.newcastle.edu.au/R/e9/help/10/01/index.html#547
Newbie question on precision
A few packages have support for basic download from Yahoo Finance. If that's
what you are trying to achieve - you may want to try quantmod (getSymbols
function) or tseries (get.hist.quote function). If you want to do something not
supported yet - first take a look at their source code.
My question is how could I estimate those initial values so that the nls
fitting works.
You can't. Your parameters are almost certainly nonidentifiable (which is
what Gabor told you more gracefully).
Just because you believe in a complex (often mechanistic) nonlinear model
and have some data
I would suggest that first you look at the results of
(as.numeric(as.character(dfpr2_r$pr2))) 0.2 (dfpr2_r$landa 10)
by itself. Does it give all FALSE ?
Then look at each of the parts separately. What are the results of
(as.numeric(as.character(dfpr2_r$pr2))) 0.2
and
dfpr2_r$landa
On 13/01/2010 10:45 AM, Don MacQueen wrote:
I would suggest that first you look at the results of
(as.numeric(as.character(dfpr2_r$pr2))) 0.2 (dfpr2_r$landa 10)
by itself. Does it give all FALSE ?
I'd guess the problem is using instead of .
Duncan Murdoch
Then look at each of
On 1/12/2010 8:29 PM, Yi Du wrote:
Hi,
Is that okay to let R to read data set more than 1 rows and
use it to do some kernel density estimation? Thanks.
Yi
Why don't you just try it and see? Nothing bad will happen - the
absolute worst case scenario is that R will hang.
But I can tell
Actually, the data that I used are measurements of plant growth during
an entire year.It is usual to model the growth with logistic models.
I have already tried the simple logistic model (which works). But the
problem is that with this model the inflexion point occurs half-way up
or down the
You could put all of your results into a single list, then just save the list.
Or, functions like write.table and write have an append argument, set that to
true and the information will be appended to the file rather than overwriting
it.
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data
Collect the results in a list (one entry for each matrix) and then 'save'
the list. When you 'load' it back in, you can easily reference each element
for further processing.
On Wed, Jan 13, 2010 at 9:59 AM, Alex Roy alexroy2...@gmail.com wrote:
Dear R users,
I am
Hi there,
My question relates to getting information about R packages. In particular i
would like to be able to find from within R:
what are a packages dependencies
what are a packages reverse dependencies
does a package contain a dll
The reason i ask is:
The organisation that i work
S Devriese wrote:
On 01/13/2010 10:47 AM, Ahmet Temiz wrote:
hello
could you give me a hint to convert data in factor type to numeric (float) ?
regards
--
Open WebMail Project (http://openwebmail.org)
you could try as.numeric but without more details it is difficult to see
if this will
Hello List,
I have a data frame object (wa2) that I am exporting for use in
another statistics package. Using
library(foreign)
write.foreign(wa2, choose.files(), choose.files(), package='SPSS')
I noticed that there were several differences between the data sets as
seen within R (View(wa2)) and
Hello,
I am learning randomForest, now I want to boxplot mse and mtry using 20
5-fold cross-validation(using median value), but I have no a good method to
do it, except a not good method.
randomforest package itself did not contain cross-validating method, and
caret package contain cross
Hello
I am currently investing software code metrics for a variety of software
projects of a company to determine the worst parts of software products
according to specified quality characteristics.
As the gathering of metrics correlates with effort, I would like to find a
subset of the metrics
Hello,
I find a way to convert data in factor type to numeric :
data_numeric - as.numeric(as.character(data_factor)).
It's treaky but works.
Peter Ehlers a écrit :
S Devriese wrote:
On 01/13/2010 10:47 AM, Ahmet Temiz wrote:
hello
could you give me a hint to convert data in factor type to
R 2.9
Windows XP
I have a matrix, Data, which contains a factor Sex and a continuous variable
Age.
I want to get mean age by sex. I know I can do this with two statements,
mean(Data[Age,Data[,Sex]==Male) and
mean(Data[Age,Data[,Sex]==Female)
I know this can be done in a single command, but I
with(yourdataframe, tapply(age,sex,mean))
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of John Sorkin
Sent: Wednesday, January 13, 2010 12:11 PM
To: r-help@r-project.org
Subject: [R] Applying function to parts of a matrix based on
try this:
with(Data, tapply(Age, Sex, mean))
I hope it helps.
Best,
Dimitris
John Sorkin wrote:
R 2.9
Windows XP
I have a matrix, Data, which contains a factor Sex and a continuous variable
Age.
I want to get mean age by sex. I know I can do this with two statements,
On Wed, 2010-01-13 at 15:59 +0100, Alex Roy wrote:
Dear R users,
I am running a R code which gives me 10 columns and
160 rows. I need to run the code for 100 times and each time I need to store
the results in a single file.
I do not know how can I store them in a
Dear friends,
If I have a table like this, first row A B C D ... are different
levels of the variable, first column 0 1 2 4 ... are the levels of the
numbers, the numbers inside the table are the probabilities of the
number occuring.
A B C D...
0 0.20.30.1
WOW, your results give about half the variance of my best optim run (possibly
due to my suboptimal use of optim).
Can you describe a little what the algorithm is doing?
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111
If your matrix were a data.frame, it could work like this:
df - data.frame(age=1:100, sex=rep(1:2, 50))
with(df, by(age, sex, mean))
without the lapply, sapply etc. family.
h
At 18:16 13.01.2010, Doran, Harold wrote:
with(yourdataframe, tapply(age,sex,mean))
-Original Message-
From:
If the trials are not connected then I would consider melting the table
using melt() from the reshape package.
And then using lapply() with the function
random.function - function(my.prob, number.of.observations = 10)
{
sum(rbinom(number.of.observations, 1, my.prob))
}
in case the trials are
Hi,
I use a vector of data to draw the histogram, but it is different from the
graph by SAS. Can you check it for me please?
b is a column vector of 4332
hist(b,probability=T,breaks=30,col='lightblue',ylim=c(0,1))
rug(b)
When I used rug, I find the records are smaller than 4332. I don't know
On 01/13/2010 05:41 PM, Peter Ehlers wrote:
S Devriese wrote:
On 01/13/2010 10:47 AM, Ahmet Temiz wrote:
hello
could you give me a hint to convert data in factor type to numeric
(float) ?
regards
--
Open WebMail Project (http://openwebmail.org)
you could try as.numeric but
Hi,
On Wed, Jan 13, 2010 at 12:58 PM, Yi Du abraham...@gmail.com wrote:
Hi,
I use a vector of data to draw the histogram, but it is different from the
graph by SAS. Can you check it for me please?
How are we supposed to check something without data, pictures, etc?
What do you want checking,
The key idea is that you are building a matrix that contains the
solutions to smaller problems which are sub-problems of the big
problem. The first row of the matrix SSQ contains the solution for no
splits, ie SSQ[1,j] is just the sum of squares about the overall mean
for reading chapters1
Try this:
dat - data.frame(x=11:14, pa=1:4/10, pb=4:1/10)
f - function(numreps, data){
pmat - as.matrix(data[-1])
x - data[,1]
result - matrix(0, nrow=numreps, ncol=ncol(pmat))
colnames(result) - c(A, B)
for(i in seq_len(numreps)){
result[i,] - apply(pmat, 2, function(p) sample(x,
Hi, please read the posting guide. You are not likely to get an extensive
answer to your question from this list. Your question is a please
solve/explain my statistical problem for me question. There are two things
problematic with that. First, statistical, and second please solve for
me.
First,
In caret, see ?trainControl. Use returnResamp = all
Max
On Wed, Jan 13, 2010 at 9:47 AM, bbslover dlu...@yeah.net wrote:
Hello,
I am learning randomForest, now I want to boxplot mse and mtry using 20
5-fold cross-validation(using median value), but I have no a good method to
do it,
Hello,
I am searching for a method to calculate a normal distribution.
For example this equation is used to calculate the normal curve when the
mean and standard deviation are know.
p(x) = (1/σ*sqrt(2π)) x exp (- (x-μ)2/2σ2)
or
(Embedded image moved to file: pic27350.jpg)Normal Probability
The sp package provides class definitions for spatial data, and utilities
for spatial data handling and manipulation.
The release of sp version 0.9-56 introduces changes in the ways in which
Polygon, Polygons, and SpatialPolygons objects are created, moving from R
code to compiled C code.
On 14/01/2010, at 6:00 AM, Nathalie Yauschew-Raguenes wrote:
Hello,
I find a way to convert data in factor type to numeric :
data_numeric - as.numeric(as.character(data_factor)).
It's treaky but works.
Possibly even more ``treaky'' but more efficient is:
data_numeric -
Hello everybody out there using R,
I'm using R for the analysis of biological data and write the results
down using LaTeX, both on a notebook with linux installed.
I've already tried two options for the import of my data:
1. Import from a SQLite database
2. Import from individual csv files edited
Hi
I would like to understand how to extend the function (FUN) I am using in
rollapply below.
##
With the following simplified data, test1 yields parameters for a rolling
regression
data = data.frame(Xvar=c(70.67,70.54,69.87,69.51,70.69,72.66,72.65,73.36),
If I do
b - rnorm(4332)
hist(b,probability=T,breaks=30,col='lightblue',ylim=c(0,1))
rug(b)
The plot looks entirely reasonable.
As far as being different from SAS, perhaps SAS and R use different
breakpoints, that is, different boundaries between the histogram bars.
-Don
At 11:58
Thanks all, I fixed it.
On Wed, Jan 13, 2010 at 2:47 PM, Don MacQueen m...@llnl.gov wrote:
If I do
b - rnorm(4332)
hist(b,probability=T,breaks=30,col='lightblue',ylim=c(0,1))
rug(b)
The plot looks entirely reasonable.
As far as being different from SAS, perhaps SAS and R use
Hi All
I have a data frame in which there are 4 columns .
Column 1 : name
Column 2-4 : values
I would like to calculate mean/Standard error of values in column 2-4 and
store them in column 5,6 respectively.
I have done the following but doesn't seem to work
mean_N_SE -function(x)
{
name
Try the merge function
?merge
in1 = id trait1
110.2
211.1
39.7
610.2
78.9
10 9.7
11 10.2
in2 = id trait2
1 9.8
2 10.8
4 7.8
5 9.8
6 10.1
1210.2
1310.1
data1 = read.table(textConnection(in1), header=T)
data2 =
See:
http://tolstoy.newcastle.edu.au/R/help/04/03/1446.html
On Wed, Jan 13, 2010 at 3:45 PM, Pete B peter.breckn...@bp.com wrote:
Hi
I would like to understand how to extend the function (FUN) I am using in
rollapply below.
##
With the following
Look at the apply function
?apply
x = data.frame(x1=c(1,2,3,4,5),x2=c(2,4,6,8,10),x3=c(1,3,5,7,9))
x$x5=apply(x,1,mean)
x$x6=apply(x,1,sd)
print(x)
Abhishek Pratap wrote:
Hi All
I have a data frame in which there are 4 columns .
Column 1 : name
Column 2-4 : values
I would like
See the dep function defined here:
http://tolstoy.newcastle.edu.au/R/e6/help/09/03/7159.html
On Wed, Jan 13, 2010 at 11:39 AM, Colin Millar c.mil...@marlab.ac.uk wrote:
Hi there,
My question relates to getting information about R packages. In particular i
would like to be able to find from
hi, I have a question about merging two files.
For example, I have two files, the first file is like the following:
id trait1
110.2
211.1
39.7
610.2
78.9
10 9.7
11 10.2
The second file is like the following:
idtrait2
1 9.8
2 10.8
4 7.8
5 9.8
6
Hi all,
I have a vector of strings and need to count the number of times a string
appears in the vector.
eg:
[1] spp6 spp10 spp6 spp6 spp4 spp2 spp9 spp10 spp5 spp2 spp2 spp3
[13] spp4 spp3 spp6 spp10 spp6 spp4 spp9 spp3 spp6 spp1 spp10 spp8
[25] spp2 spp10 spp9 spp7
Thanks all for a very quick solution. It is actually good to know different
ways to do the same things. It expands my limited understanding of R :).
-A
On Wed, Jan 13, 2010 at 5:12 PM, Stephan Kolassa stephan.kola...@gmx.dewrote:
Hi,
does this do what you want?
d -
Jesse,
see ?table and try
table(stringVector)
Greg
On 1/13/10 2:12 PM, Jesse Sinclair wrote:
Hi all,
I have a vector of strings and need to count the number of times a string
appears in the vector.
eg:
[1] spp6 spp10 spp6 spp6 spp4 spp2 spp9 spp10 spp5 spp2 spp2 spp3
[13]
?table
On 14/01/2010, at 11:12 AM, Jesse Sinclair wrote:
Hi all,
I have a vector of strings and need to count the number of times a
string
appears in the vector.
eg:
[1] spp6 spp10 spp6 spp6 spp4 spp2 spp9 spp10 spp5 spp2
spp2 spp3
[13] spp4 spp3 spp6 spp10 spp6 spp4
You could look at read.csv.sql in sqldf (http://sqldf.googlecode.com) as well.
On Wed, Jan 13, 2010 at 2:00 PM, Juliet Jacobson julietjacob...@aim.com wrote:
Hello everybody out there using R,
I'm using R for the analysis of biological data and write the results
down using LaTeX, both on a
Hi Karean,
If your first object is called obj1 and the second called obj2, then:
merge(obj1, obj2, all.x=TRUE)
id trait1 trait2
1 1 10.29.8
2 2 11.1 10.8
3 39.7 NA
4 6 10.2 10.1
5 78.9 NA
6 109.7 NA
7 11 10.2 NA
Hope this helps,
Adrian
On
Did you consider to look at the help page for merge?
h
At 22:01 13.01.2010, karena wrote:
hi, I have a question about merging two files.
For example, I have two files, the first file is like the following:
id trait1
110.2
211.1
39.7
610.2
78.9
10 9.7
11 10.2
The
Hi Jesse,
If your vector is called aa, then how about:
table(aa)
aa
spp1 spp10 spp2 spp3 spp4 spp5 spp6 spp7 spp8 spp9
7 216 815 9 910 915
Hope this helps,
Adrian
On Thursday 14 January 2010, Jesse Sinclair wrote:
Hi all,
I have a vector
Hi,
does this do what you want?
d - cbind(d,apply(d[,c(2,3,4)],1,mean),apply(d[,c(2,3,4)],1,sd))
HTH,
Stephan
Abhishek Pratap schrieb:
Hi All
I have a data frame in which there are 4 columns .
Column 1 : name
Column 2-4 : values
I would like to calculate mean/Standard error of values
I have a file like this:
idn1n2 n3 n4 n5 n6
1 3 47 8 102
2 4 12 4 3 10
3 7 00 0 0 8
4 1010 0 2 3
5 1110 0 0 5
what I want to do is: only if n2=0 and n3=0
This is great all.
It works perfectly. Thank-you.
Cheers,
Jesse
On Wed, Jan 13, 2010 at 14:27, Adrian Dusa dusa.adr...@gmail.com wrote:
Hi Jesse,
If your vector is called aa, then how about:
table(aa)
aa
spp1 spp10 spp2 spp3 spp4 spp5 spp6 spp7 spp8 spp9
7 216
thank you very much!
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Greg - thanks for posting this interesting problem.
Albyn - thanks for posting a solution. Now, I have some questions: (1) is
the algorithm guaranteed to find a best solution? (2) can there be
multiple solutions (it seems like there can be more than 1 solution
depending on the data)?, and (3) is
Hi All,
I have substantially expanded the table that compares SAS and SPSS
add-on modules to somewhat equivalent R packages. This new version is
at:
http://r4stats.com/add-on-modules
and I would very much appreciate any feedback you might have on it.
The site http://r4stats.com is the
On Wed, Jan 13, 2010 at 11:53 PM, Muenchen, Robert A (Bob) muenc...@utk.edu
wrote:
Hi All,
I have substantially expanded the table that compares SAS and SPSS
add-on modules to somewhat equivalent R packages. This new version is
at:
http://r4stats.com/add-on-modules
and I would very much
yourdataframe = subset(yourdataframe, !(n2==0 n3==0 n4==0 n5==0))
From: karena dr.jz...@gmail.com
To:r-help@r-project.org
Date: 14/Jan/2010 12:24 p.m.
Subject: [R] a question about deleting rows
I have a file like this:
idn1n2 n3 n4 n5 n6
1 3 47 8 10
Try this:
x
id n1 n2 n3 n4 n5 n6
1 1 3 4 7 8 10 2
2 2 4 1 2 4 3 10
3 3 7 0 0 0 0 8
4 4 10 1 0 0 2 3
5 5 11 1 0 0 0 5
delete - with(x, n2 == 0 n3 == 0 n4 == 0 n5 == 0)
delete
[1] FALSE FALSE TRUE FALSE FALSE
x[!delete,]
id n1 n2 n3 n4 n5 n6
1 1 3 4 7
FYI, in bioinformatics, we use dynamic programming algorithms in similar
ways to solve similar problems of finding guaranteed-optimal partitions in
streams of data (usually DNA or protein sequence, but sometimes numerical
data from chip-arrays). These path optimization algorithms are often
called
From: b.rowling...@googlemail.com [mailto:b.rowling...@googlemail.com] On
Behalf Of Barry Rowlingson
Sent: Wednesday, January 13, 2010 7:03 PM
To: Muenchen, Robert A (Bob)
Cc: r-help@r-project.org
Subject: Re: [R] Updated comparison table for SAS-SPSS Add-ons and R Functions
Maybe the first
Hi everyone,
Would somebody please explain (or point me to a reference that explains)
the following error:
Error: object of type 'closure' is not subsettable
I was trying to use rep() to replicate a function:
example_function - function() { return(TRUE) }
rep(example_function, 3)
Error:
Dear Uwe and all,
First of all, I want to congratulate you for your dedication in providing
and maintaining R for 64bit operating systems. I tried the 64bit version of
R, under a windows server 2003 system. It seems to work properly, but am
concerned since I need to use the package fields, which
See ?rep where it says that the argument must be a vector. Try
rep(list(sin), 3)
On Wed, Jan 13, 2010 at 8:11 PM, Matthew Walker
matthew.walke...@ulaval.ca wrote:
Hi everyone,
Would somebody please explain (or point me to a reference that explains) the
following error:
Error: object of
Hi Aaron! It's always nice to see a former student doing well.
Thanks for the notes and references, too!
albyn
On Wed, Jan 13, 2010 at 07:29:57PM -0500, Aaron Mackey wrote:
FYI, in bioinformatics, we use dynamic programming algorithms in similar
ways to solve similar problems of finding
steve_fried...@nps.gov wrote:
I am searching for a method to calculate a normal distribution.
For example this equation is used to calculate the normal curve when the
mean and standard deviation are know.
p(x) = (1/σ*sqrt(2π)) x exp (- (x-μ)2/2σ2)
However, some of the literature I'm
Thanks you solved and share with us.
But, why don't you use the RMySQL, which connects to MySQL without the
need of ODBC?
Caveman
On Wed, Jan 13, 2010 at 1:48 AM, Marcus, Jeffrey
jeffrey.mar...@nuance.com wrote:
I think I figured this out. I should not have put the Driver name in
braces.
Hi,
I'm struggling to install RCurl for 32-bit linux and am hoping for
some suggestions.
I obtained RCurl_1.3-1.tar.gz from CRAN today, and am using a very
recent version of R:
R version 2.10.1 Patched (2010-01-12 r50970).
I'm not the sysadmin for this system (disclaimer: my sysadmin
Thank you very much! It works now perfectly. I even extended it to be
able to apply it to the whole dataset:
data-read.delim(mhc_data.txt, stringsAsFactors=FALSE)
lettermatch - function(a, b) {
tb - merge(as.data.frame(table(strsplit(a, ))),
as.data.frame(table(strsplit(b, ))), by=Var1)
thank Max.
you are so responsible, every time, you give me a lot of help. On my
learning road, you are my guide, though we do not know each other.
best wishes
kevin
å¨2010-01-14ï¼Max Kuhn [via R] ml-node+1013265-480375...@n4.nabble.com
åéï¼ -åå§é®ä»¶-
å件人:Max
I have the following code:
## to check correlation between the simulated uniform data
x2 - uni[,1] ; x2[1:10]
y2 - uni[,2] ; y2[1:10]
result2 - boot(cbind(x2,y2), f, 20)
# get 95% confidence interval
boot.ci(result2, type=bca)
cor.test(x2,y2, method=pearson, conf.level=0.95)
part of my data:
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