On 03/11/2010 01:36 AM, t.wun...@stud.uni-heidelberg.de wrote:
Hello,
does anybody know which command to consider when I'm trying to plot a
stacked barplot with a legend at the most empty portion of the graphic?
I've searched for it, and somebody stated to use the labcurve-command,
but I don't
Hello everyone,
I have versions 2.7.2 and 2.10.1 installed on a machine that has no
access to internet.
In 2.7.2 I can use ? to get help on functions, which in 2.10.1 that
does not work, all I see is starting httpd help server...done and
then nothing.
Have I downloaded 2.10.1 incorrectly
Hi,
I think, the correct formula for beta should be
beta.hat=I(T(X)*X)*T(X)*y
and as far as I remember
beta.hat \sim N(beta,sigma^2*I(T(X)*X),
not I(T(X)*X)/sigma^2
Rnewb schrieb:
i am trying to duplicate R's computation of standard errors but having some
trouble. i loaded some data into R
Hi,
I think you do need an Internet connection to access the help files with
R2.10.
There might be some way to access them off-line, though I have no idea how.
Maybe someone here knows.
Ivan
Le 3/11/2010 09:42, Sergey Goriatchev a écrit :
Hello everyone,
I have versions 2.7.2 and 2.10.1
David,
That's useful to highlight my problem.
If instead of e=e we use a vector like GreenEyes:
GreenEyes=c(1,2,3,4)
niceplot(GreenEyes)
1 2 3 4
What I want is niceplot to print GreenEyes bot 1 2 3 4
I want this so I can use it in a legend without having to type in
GreenEyes...
On 10
That is quite helpful David
niceplot-function(...) {
parms=list(...)
for (x in parms) {
xname - paste(deparse(substitute(x), 500), collapse = \n)
cat(xname)
}
}
GreenEyes=c(1,2,3,4)
niceplot(GreenEyes)
c(1, 2, 3, 4)
BUT what I want is:
GreenEyes=c(1,2,3,4)
niceplot(GreenEyes)
I have some probems in merging the following datasets:
table1
Paese Continente
Italia EU
franciaEU
germania EU
stati uniti AM
canadaAM
table2
Continente
Hi
r-help-boun...@r-project.org napsal dne 11.03.2010 10:08:58:
Hi,
I think you do need an Internet connection to access the help files with
R2.10.
I presume the OP is working with Windows. I do not think Internet
connection is necessary. It is necessary to have some browser installed.
Hi,
What about merge(table1, table2)?
See ?merge for more details
Ivan
Le 3/11/2010 10:15, n.via...@libero.it a écrit :
I have some probems in merging the following datasets:
table1
Paese Continente
Italia EU
franciaEU
I have a matrix with a POSIXct as a numeric in the first column.
I would like to create a new matrix that is grouped by my chosed time
bars.
i.e. So I would like to group by hour or day or 5 days, and have all my
columns be summed or averaged or counted..
mydata:
V1,V2,V3
10:03:13,3.4,1002
On Wed, 10-Mar-2010 at 10:58PM -0800, chinna wrote:
|
| sample report data that i want to forecast
|
| quarter quarter_index Revenue
| 2007 Q1 1 $3,856,799
| 2007 Q2 2 $4,243,328
| 2007 Q3 3
Hi
r-help-boun...@r-project.org napsal dne 11.03.2010 09:34:06:
David,
That's useful to highlight my problem.
If instead of e=e we use a vector like GreenEyes:
GreenEyes=c(1,2,3,4)
niceplot(GreenEyes)
1 2 3 4
What I want is niceplot to print GreenEyes bot 1 2 3 4
I want
Shaoqiong Zhao wrote:
I am not sure if this is correct and also this can only solve one row. How
to get the whole 1000 rows of p and q?
You can try something like this:
library(nleqslv)
library(BB)
fn - function(x, s){
f - rep(NA, length(x))
f[1] - digamma(x[1]) -
Hi Peter konings,
Sorry man the forecasted values i have given wrong
once again see my question and please give me the answer.
sample report data that i want to forecast
quarter quarter_index Revenue
2007 Q1 1 $3,856,799
2007
Hi Patrick,
Sorry man the forecasted values i have given wrong
once again see my question and please give me the answer.
sample report data that i want to forecast
quarter quarter_index Revenue
2007 Q1 1 $3,856,799
2007 Q2
Is there a way to modify the dots-argument?
Let's consider I have a function that passes on its ... arguments to
another function.
For some reason I know, that some elements in ... will cause problems.
Can I modify the ... structure somehow, e.g. delete elements?
foo - function(...){
what about:
niceplot-function(...) {
arg.names - as.list (match.call () [-1])
for (a in seq_along (arg.names))
cat (as.character (as.expression (arg.names [[a]])), \n\n)
}
niceplot (greeneye, log (greeneye), 1:3)
note that this works also if there is no greeneye
Disclaimer: I don't know
Mark,
dots - list (...) gives you a list with the dots arguments
if innerFoo expects not a list but normal arguments, do.call is your friend:
do.call (innerFoo, dots)
HTH schönen Tag,
Claudia
Mark Heckmann wrote:
Is there a way to modify the dots-argument?
Let's consider I have a function
ManInMoon wrote:
That is quite helpful David
niceplot-function(...) {
parms=list(...)
for (x in parms) {
xname - paste(deparse(substitute(x), 500), collapse = \n)
cat(xname)
}
}
GreenEyes=c(1,2,3,4)
niceplot(GreenEyes)
c(1, 2, 3, 4)
BUT what I want is:
Ivan Calandra wrote:
Hi,
I think you do need an Internet connection to access the help files with
R2.10.
No, it's all local, but you do need a web browser if you want to view
the HTML help. If you don't want the HTML help, you can set the help
type to text using
Hi
r-help-boun...@r-project.org napsal dne 11.03.2010 11:51:19:
Hi Patrick,
Sorry man the forecasted values i have given wrong
once again see my question and please give me the answer.
sample report data that i want to forecast
quarter quarter_index Revenue
2007 Q1
Try this:
DF - read.csv(textConnection(V1,V2,V3
10:03:13,3.4,1002
10:03:14,5.6,1001
10:05:27,7.2,999
10:05:33,8.2,998), header = TRUE)
tDates - strptime(DF$V1, %H:%M:%S)
tDates[[2]] - floor(strptime(DF$V1, %H:%M:%S)[[2]] / 5) * 5
aggregate(DF[,c('V2', 'V3')],
list(format(tDates,
Is it possible to get hold of the name of a frame?
Tom
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R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal,
Greets to the list!
I am aware that this topic has been discussed several times. And I've
read quite some related posts [1]. Yet, can't seem to give a solution to
my problem.
I have 6 data frames consisting of 6 rows x 7 columns put together from
other data.frames.
Something like:
a b c d e
Hello all,
I have two matrices, pop and pop2, each the same number of rows and
columns that I want to compare for equality. I am concerned about
efficiency in this operation.
I've tried a few things without success so far. Doing something simple like:
if (pop==pop2) { cat('equal') } else {
Well, when I try to access help files (not all of them actually) without
internet connection, I don't get anything.
What is it related to then?
Le 3/11/2010 13:06, Duncan Murdoch a écrit :
Ivan Calandra wrote:
Hi,
I think you do need an Internet connection to access the help files
with
Hi,
I have a matrix with m rows and n column and a vector with n elements. I
want to divid each rows of the matrix by vector direcly.
could you please hint me?
Thank you
khazaei
__
R-help@r-project.org mailing list
On 11.03.2010 13:38, Ivan Calandra wrote:
Well, when I try to access help files (not all of them actually) without
internet connection, I don't get anything.
What is it related to then?
MAybe your browser tries to be too clever and goes to some kind of
offline mode. But it should not since
say 'mat' is your matrix and 'vec' is your vector, then try this:
mat / rep(vec, each = m)
I hope it helps.
Best,
Dimitris
On 3/11/2010 1:44 PM, khaz...@ceremade.dauphine.fr wrote:
Hi,
I have a matrix with m rows and n column and a vector with n elements. I
want to divid each rows of the
On Thu, Mar 11, 2010 at 12:30 PM, Tom Backer Johnsen
bac...@psych.uib.no wrote:
Is it possible to get hold of the name of a frame?
I can't see a direct way, but you could capture the output of print:
framename=function(frame){capture.output(print(frame))}
See ?sweep
On Thu, Mar 11, 2010 at 9:44 AM, khaz...@ceremade.dauphine.fr wrote:
Hi,
I have a matrix with m rows and n column and a vector with n elements. I
want to divid each rows of the matrix by vector direcly.
could you please hint me?
Thank you
khazaei
DF
V1 V2 V3
1 10:03:13 3.4 1002
2 10:03:14 5.6 1001
3 10:05:27 7.2 999
4 10:05:33 8.2 998
DF2 - t(sapply(split(DF[,-1], gsub('(.{5}).*', '\\1:00', DF$V1)), colSums))
data.frame(V1 = rownames(DF2), DF2)
V1 V2 V3
10:03:00 10:03:00 9.0 2003
10:05:00 10:05:00 15.4
Hmm. I need to do some pondering on that one. I do not really
understand it, at least not yet.
Tom
Barry Rowlingson wrote:
On Thu, Mar 11, 2010 at 12:30 PM, Tom Backer Johnsen
bac...@psych.uib.no wrote:
Is it possible to get hold of the name of a frame?
I can't see a direct way,
The question is what should I do then to be able to access all the help
files, even off-line?
That would really help me to know it.
Thanks
Ivan
Le 3/11/2010 13:46, Uwe Ligges a écrit :
On 11.03.2010 13:38, Ivan Calandra wrote:
Well, when I try to access help files (not all of them actually)
On 11/03/2010 7:38 AM, Ivan Calandra wrote:
Well, when I try to access help files (not all of them actually) without
internet connection, I don't get anything.
What is it related to then?
When I do that, things just work. Why is that?
Duncan Murdoch
Le 3/11/2010 13:06, Duncan Murdoch
Hi
This seems to be nice example why lists shall be used and not several data
frames scattered in environment.
put your data frames to list
lapply(list.of.data, function(x) names(x) - column_names)
Regards
Petr
r-help-boun...@r-project.org napsal dne 11.03.2010 13:33:33:
Greets to the
It is interesting because I've tried again with some functions and it
does work perfectly without Internet connection.
Actually, the problem might have been more related to some specific
functions (and hence help files) than to the fact I was working off-line.
But great, I don't have to worry
You can try this:
lapply(lapply(ls(pattern = 'DF[0-9]'), get),
'names-', c(SDev,PC1, PC2, PC3, PC4, PC5, PC6))
On Thu, Mar 11, 2010 at 9:33 AM, Nikos Alexandris
nikos.alexand...@felis.uni-freiburg.de wrote:
Greets to the list!
I am aware that this topic has been discussed several
It seems that the names of original data frames have not changed in
this way. I guess textConnection() could help, like this:
for (name in objects(pattern = df[0-9]))
eval(parse(textConnection(paste('names(', name, ') -
column_names'
On Thu, Mar 11, 2010 at 9:25 PM, Henrique Dallazuanna
Yes, just in the list.
If they want change the name in Environment GlobalEnv:
for(i in ls(pattern = DF[0-9]))
assign(i, `names-`(get(i), c(SDev,PC1, PC2, PC3,
PC4, PC5, PC6)), globalenv())
On Thu, Mar 11, 2010 at 10:39 AM, Linlin Yan yanlinli...@gmail.com wrote:
It seems that the names
Hi Samantha,
Did you check out the help for plclust? There's a labels argument that
is used to label the leaves of your dendrogram. By default, the rownames
of your dataframe are used.
Sarah
On Wed, Mar 10, 2010 at 9:01 PM, Samantha samantha.fra...@gmail.com wrote:
Hi,
I am clustering data
Guo-Hao Huang wrote:
Date: Thu, 11 Mar 2010 14:55:35 +0800
From: Guo-Hao Huang guohao.hu...@gmail.com
To: Norm Matloff matl...@cs.ucdavis.edu
Cc: r-help@r-project.org
Subject: Re: [R] ANNOUNCE--Rdsm package, a threads-like environment
for R
I am interested in Rdsm package, but I
Amazing! I haven't seen usage of calling `names-` like this before.
Thanks so much!
On Thu, Mar 11, 2010 at 9:50 PM, Henrique Dallazuanna www...@gmail.com wrote:
Yes, just in the list.
If they want change the name in Environment GlobalEnv:
for(i in ls(pattern = DF[0-9]))
assign(i,
Look at:
identical(pop, pop2) # if you want to do exact comparison
Or
all.equal(pop, pop2, tolerance=1.e-10) # if you want to allow for
some small noise
Ravi.
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of
In the following code:
y - 1
niceplot( x=y )
Do you want x, y, or 1?
1 is just the value, which you had already. If you want y then the
deparse(substitute()) approach gives that to you as others have said. But if
you want x, then you want to look at the names of the dots list, e.g.:
tmp
Duncan,
Thanks you - your deparse(substitute(...)) work - fantastic.
But, when I pass in multiple arguments: f(z[,1],z[,2])
I only show first argument, rest shows up as NULL
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Thank you
In the aggregate how does it know which column to group?
I know you give it tDates as the second argument, but it doesn't know that
is from DF - we could have put anything there I think...
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Sent
Hi Samantha,
You can check out the graph and source code on this page:
http://addictedtor.free.fr/graphiques/RGraphGallery.php?graph=79
best, Xian
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Sent from the R help
This does what I was hoping it would:
aggregate(tm[,-1],by=list(tm[,10]),FUN=mean)
but I don't know what tm[,-1] means (well - the -1 bit anyway.
Does it somehow means the whole matrix?
Please don't tell me to check the manual - I tried and failed dismally...
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of this release:
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Hi:
I want to add a constant to an existing col of the
data.frame. I have the following dataset:
structure(list(x = c(1, 1, 1, 1, 1), y = c(1, 1, 1, 1, 1)),
.Names = c(x,
y), row.names = c(NA, 5L), class = data.frame)
I want to add a
tDates assumes DF$V1, which is from DF object.
On Thu, Mar 11, 2010 at 11:13 AM, ManInMoon xmoon2...@googlemail.com wrote:
Thank you
In the aggregate how does it know which column to group?
I know you give it tDates as the second argument, but it doesn't know that
is from DF - we could
Please do check the Intro to R manual.
Hint: section 2.7.3
**
1.
*A vector of negative integral quantities*. Such an index vector
specifies the values to be *excluded* rather than included. Thus
y - x[-(1:5)]
gives y all but the first five elements of x.
On
-Mensaje original-
De: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] En
nombre de ManInMoon
Enviado el: jueves, 11 de marzo de 2010 12:22
Para: r-help@r-project.org
Asunto: [R] tm[,-1]
This does what I was hoping it would:
On 11.03.2010 12:22, ManInMoon wrote:
This does what I was hoping it would:
aggregate(tm[,-1],by=list(tm[,10]),FUN=mean)
but I don't know what tm[,-1] means (well - the -1 bit anyway.
Does it somehow means the whole matrix?
Please don't tell me to check the manual - I tried and failed
Try this:
sweep(DF, 2, 1:2, '+')
On Thu, Mar 11, 2010 at 9:20 AM, GULATI, BRIJESH (Global Markets FFO
NY) brijesh.gul...@baml.com wrote:
Hi:
I want to add a constant to an existing col of the
data.frame. I have the following dataset:
structure(list(x = c(1, 1,
I think (but I didn't follow what you're trying to do and what is what)
that it means the whole matrix (tm) except the first column (therefore
the - sign)
Ivan
Le 3/11/2010 12:22, ManInMoon a écrit :
This does what I was hoping it would:
aggregate(tm[,-1],by=list(tm[,10]),FUN=mean)
but I
One of my colleagues has a data set from a two-level nested design from
which we would like to estimate variance components. But we'd like some
idea of what the inevitable outliers are doing, so we were looking for
something in R that uses robust (eg Huber) treatment and returns robust
estimates
R starts its own mini web server which parses the raw text pages and serves
them as HTML. It does so using a particular randomly chosen port number on
127.0.0.1 (localhost). The port number is listed in the message 'if nothing
happens, you should open '
followed by a url to paste into your
On 10.03.2010 23:45, Raphael Aggio wrote:
Hi,
I developed a package that requires 5 other packages. I was wondering if
anyone knows how can I automatically download and install the required
packages during the installation of my new package. My idea is to make this
process easier to the final
On 10.03.2010 12:45, alison waller wrote:
Thanks Gabor,
As I said I would like to use gsubfn, but I am having problems
installing it, which I assume are due to some conflict with the current
tcltk package
Below is the error I got after issuing install.packages(gsubfn)
Any advice?
On 11.03.2010 15:58, S Ellison wrote:
R starts its own mini web server which parses the raw text pages
No, actually it uses the parsed form of the Rd files anmd renders them
in either html or other formats...
and serves them as HTML. It does so using a particular randomly chosen port
On 11/03/2010 7:25 AM, ManInMoon wrote:
Duncan,
Thanks you - your deparse(substitute(...)) work - fantastic.
But, when I pass in multiple arguments: f(z[,1],z[,2])
I only show first argument, rest shows up as NULL
Yes, that's because substitute has specific meanings for its two
On 10.03.2010 20:30, ManInMoon wrote:
I understand you can pass a variable number of arguments to a function that
is written to accept ...
I have searched for any documentation on how to write such a function -
could someone tell me where to look please
The manual An Introduction to R
Hi,
(answer below)
Le 3/11/2010 16:03, Uwe Ligges a écrit :
On 11.03.2010 15:58, S Ellison wrote:
R starts its own mini web server which parses the raw text pages
No, actually it uses the parsed form of the Rd files anmd renders them
in either html or other formats...
and serves them as
matrix(1:12,nrow=3)
# [,1] [,2] [,3] [,4]
# [1,]147 10
# [2,]258 11
# [3,]369 12
t(t(matrix(1:12,nrow=3))/c(2,3,4,5))
# [,1] [,2] [,3] [,4]
# [1,] 0.5 1.33 1.75 2.0
# [2,] 1.0 1.67 2.00 2.2
# [3,] 1.5
On Thu, 11 Mar 2010 03:22:27 -0800 (PST) ManInMoon xmoon2000
@googlemail.com wrote:
but I don't know what tm[,-1] means (well - the -1 bit anyway.
Does it somehow means the whole matrix?
No, it means everything except the first column.
Please don't tell me to check the manual - I tried
Helen:
It is good practice to reply not only to the responder to your post, but also
to the list in general. I don't know of any methods for non-parametric ability
estimation. The irt.ability function provides you with three options for
estimating ability: the maximum likelihood estimate
Hallo,
hope you can help me with this question:
I have calculated a function using f-smooth.spline(data) and
approxfun(f). Now I want to calculate the mean slope of the resulting
function.
Haven't found the right R command yet, maybe you can give me a hint.
Thanx, Antje
Also look at
?any
and
?all
Very handy functions.
Miguel
On Thu, Mar 11, 2010 at 12:37 PM, Esmail esmail...@gmail.com wrote:
Hello all,
I have two matrices, pop and pop2, each the same number of rows and
columns that I want to compare for equality. I am concerned about
efficiency in
Thanks! I think that will do the trick. I had not known of the match
function before. Always learn something new on this list.
--Chris
Christopher W. Ryan, MD
SUNY Upstate Medical University Clinical Campus at Binghamton
425 Robinson Street, Binghamton, NY 13904
cryanatbinghamtondotedu
If you
Hello,
http://tolstoy.newcastle.edu.au/R/help/04/07/0312.html#0313qlink1 Could
anybody tell me how to generate discrete Laplacian distribution?
I need to sample uma discretised Laplacian density like this:
J( g - g´) ~ exp (-lambda | g´ - g |) g in {0,
, gmax}
Thanks,
Dear R community,
I am a newbie to R and I am using lme() to analyzed a two way repeated
measures ANCOVA on some data I have gathered. In producing some
graphs based on the fixed effects I noticed that I get vary different
results depending on how I order my levels in my factor statement
Hi all,
I am trying to call a C function from R (version 2.10.1) on a windows machine.
The C code is in a .c file, I have pasted the code below although I'm very
confident that it does not contain any errors (it is not my code), but also,
the problem that I have occurs with every .c file that
I have a model that can be estimated in nls
mod.base -
deriv(~(Jan+a1*Feb+a2*Mar+a3*Apr+a4*May+a5*Jun+a6*Jul+a7*Aug+a8*Sep+a9*Oct+a10*Nov+a11*Dec)*(b2*relAge+b3*relAge^2),
c(a1,a2,a3,a4,a5,a6,a7,a8,a9,a10,a11,b2,b3),
Hi guys, here is a list of names that I have:
MyList:
myList-list(A, B,C,D)
myList
[[1]]
[1] A
[[2]]
[1] B
[[3]]
[1] C
[[4]]
[1] D
I want to turn this list into a matrix of 1 row and 4 columns with those
four components (A, B, C, D) so here is what I do:
myDataFrame - data.frame(myList)
I have never got it working with rcmd SHLIB. it is much easier to create a
shared library separately with the C compiler and then load it with dyn.load
the makefiles for SHLIB are quite big and going through them will give you a
headache, so just use the flag for a dll when you compile.
--
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On 11/03/2010 10:57 AM, denise xifaras wrote:
Hi all,
I am trying to call a C function from R (version 2.10.1) on a windows machine.
The C code is in a .c file, I have pasted the code below although I'm very
confident that it does not contain any errors (it is not my code), but also,
the
Hi,
Is this what you want?
matrix(unlist(myList),nr=1)
Miguel
On Thu, Mar 11, 2010 at 4:03 PM, anna lippelann...@hotmail.com wrote:
Hi guys, here is a list of names that I have:
MyList:
myList-list(A, B,C,D)
myList
[[1]]
[1] A
[[2]]
[1] B
[[3]]
[1] C
[[4]]
[1] D
I want to
Hi!
Try: myMatrix - as.matrix(myDataFrame)
Looking at ?data.matrix: Return the matrix obtained by converting all
the variables in a data frame to numeric mode.
You could also do directly: myMatrix - as.matrix(myList)
Though you might need to transpose (see ?t)
HTH,
Ivan
Le 3/11/2010
Yes, definitely! so unlist() turns the list components into a vector? What if
the component are vectors, matrices etc? Thank you Miguel!
-
Anna Lippel
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Sent from the R help
so I was getting ones because it converted the characters into numeric?
-
Anna Lippel
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Sent from the R help mailing list archive at Nabble.com.
I would say so; it would make sense.
Le 3/11/2010 17:16, anna a écrit :
so I was getting ones because it converted the characters into numeric?
-
Anna Lippel
--
Ivan CALANDRA
PhD Student
University of Hamburg
Biozentrum Grindel und Zoologisches Museum
Abt. Säugetiere
ok guys, thanks a lot!
-
Anna Lippel
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see for yourself - AFAIK it'll just concatenate eveverything which is
atomic into a vector, thus losing all the structure associated.
Miguel
On Thu, Mar 11, 2010 at 4:14 PM, anna lippelann...@hotmail.com wrote:
Yes, definitely! so unlist() turns the list components into a vector? What
if
I am interested in a model diagnostic for logistic regression which is normally
distributed (much like the residuals in linear regression with are ~
N(0,variance unknown).
My understanding is that most (all?) of the residuals returned by residuals.lrm
{design} either don't have a well defined
Hi,
What R libraries should I use to implement mixed effects models with continuous
time and discrete-time survival data? What if I have two crossed random
effects? I'd appreciate any help.
Regards,
Hakan Demirtas
[[alternative HTML version deleted]]
On Wed, Mar 10, 2010 at 07:48:45PM +, hadley wickham wrote:
Run that function hourly with plyr
output.hourly - dlply(df.i1,tshour,cor.dat)
Why not
output.hourly - ddply(df.i1,tshour,cor.dat)
Doh! Because I didn't read the docs properly and missed it.
Thanks, much nicer than
I'm writing a function that can take a data.frame as an argument. I'd
like to be able to obtain the name of the data.frame and print it out
within the function. My current function looks like this:
examineIt-function(x) {
print(nrow(x))
print(x[ceiling(runif(10)*nrow(x)),])
Try this:
foo - function(data)print(deparse(substitute(data)))
foo(DF)
On Thu, Mar 11, 2010 at 2:31 PM, Jason Baucom jason.bau...@ateb.com wrote:
I'm writing a function that can take a data.frame as an argument. I'd
like to be able to obtain the name of the data.frame and print it out
within
I have spent a few days trying to figure this from the reply out but am still
stuck!
I need the equation to reply to a request from a referee that was to: show
the specific estimating equation associated with the fitted line.
the model I am running is (I hope the data frame is not necessary as I
In R on Windows (ver 7) I have somehow set the preferences for the R
console window to be always on top. I'm sure at the time I did this it
seemed like a good idea, but in practice it is not. Unfortunately, I
cannot remember where the setting is changed, and thus it is stuck
this way. Does anyone
Hi all,
I re-installed R and tcltk. I find some of the documentation misleading
as it indicates that tcltk is included with R. And when you type
library() it shows tcltk, even though it hasn't been installed.
Anyways, I've decided to go with sprintf.
I am having errors with my query criteria.
Hello,
I recently had to reinstall R on my windows machine, because MASS
mysteriously vanished from my packages list. Before, when I used
help(), the files would load in a Windows help window. Now, the help
files load in my internet browser, which actually is problematic
because I always made use
Hello,
I recently had to reinstall R on my windows machine, because MASS
mysteriously vanished from my packages list. Before, when I used
help(), the files would load in a Windows help window. Now, the help
files load in my internet browser, which actually is problematic
because I always made use
Thank you Duncan,
the paths were first so that wasn't the problem, but when I changed to the
directory of the file and then typed rcmd SHLIB it did work, like you said.
Great news.
Best,
Denise
--- On Thu, 3/11/10, Duncan Murdoch murd...@stats.uwo.ca wrote:
From: Duncan Murdoch
Hi,
On Thu, Mar 11, 2010 at 3:46 AM, chinna durgache...@gmail.com wrote:
Hi Peter konings,
Sorry man the forecasted values i have given wrong
once again see my question and please give me the answer.
snip
This is the forecasted report that i get using the reporting tool
Jim Holtman's solution generates a data frame that can be easily indexed by
year:
setwd(/r-help/2010-03-10)
x - read.csv(restored.csv, as.is=TRUE)
require(reshape)
x.m - melt(x, id=c('Year', 'LocationID', 'SpeciesCode'),
measure='PlotFreq')
x.binary - cast(x.m, Year + LocationID ~ SpeciesCode,
On 11/03/2010 11:59 AM, Robert M. Flight wrote:
In R on Windows (ver 7) I have somehow set the preferences for the R
console window to be always on top. I'm sure at the time I did this it
seemed like a good idea, but in practice it is not. Unfortunately, I
cannot remember where the setting is
On 11/03/2010 12:21 PM, David Bapst wrote:
Hello,
I recently had to reinstall R on my windows machine, because MASS
mysteriously vanished from my packages list. Before, when I used
help(), the files would load in a Windows help window. Now, the help
files load in my internet browser, which
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