Hello Troy.
A tiny question (without answering your question), why did you choose to do
it this way instead of using
?step
or
?stepAIC
?
Best,
Tal
Contact
Details:---
Contact me: tal.gal...@gmail.com | 972-52-7275845
Read
Hello all,
When building a CART model (specifically classification tree) using rpart,
it is sometimes interesting to know what is the importance of the various
variables introduced to the model.
Thus, my question is: *What common measures exists for ranking/measuring
variable importance of
On Sun, Jan 23, 2011 at 07:29:16PM -0800, eric wrote:
Is there a way to vectorize this loop or a smarter way to do it ?
y
[1] 0.003990746 -0.037664639 0.005397999 0.010415496 0.003500676
[6] 0.001691775 0.008170774 0.011961998 -0.016879531 0.007284486
[11] -0.015083581
On Sun, Jan 23, 2011 at 11:13:11PM +0100, Marc Jekel wrote:
Hello R Fans,
Another question for the community that really frightened me today. The
following logical comparison produces a false as output:
t = sum((c(.7,.69,.68,.67,.66)-.5)*c(1,1,-1,-1,1))
tt =
On 22.01.2011 00:16, Horace Tso wrote:
I follow Alan Lenarcic's very helpful tutorial on building R package for Windows
(XP), which could be found in
Hello I have one function that creates polynomials (i.e legendre.polynomials) I
want to use this one to create polynomials for variable x and variable y.
legendre.polynomials(2)
[[1]]
1
[[2]]
x
[[3]]
-0.5 + 1.5*x^2
the ideal would be to receive the same output but for another variable (eg.
Hi,
If you have the formula stored in a string, you could also use
as.formula in your call to lm, like this:
form - x ~ y + z
lm(as.formula(form))
HTH,
Ivan
Le 1/23/2011 21:38, Joshua Wiley a écrit :
Hi Paul,
You need to pass the formula object, not a string. If you have a
function that
On 23.01.2011 21:47, Kamina Chororoka wrote:
Hi,
I am a student at the University of Twente ( ITC).
I am using the R packages for my data analysis, but for the last few weeks now
, I have been getting the error message when trying to work on variograms or
krigging.
Error : .onLoad failed
Hi
Would anyone have any pointers on how to slice up a large zoo table. I
have the following structure: -
str(ZOO_OBJ)
zoo [1:632, 1:83] 30.4 30.4 30.4 30.4 30.3 ...
- attr(*, dimnames)=List of 2
..$ : NULL
..$ : chr [1:83] COL1 COL2 COL3 COL4 ...
- attr(*, index)= POSIXct[1:632],
Please do read the posting guide: what OS, what version of R, what
graphics device
At a guess this was Mac OS X (and this was the wrong list) and you
need to repair your Mac OS fonts. There are threads on R-sig-mac about
that every couple of months, including this month.
On Sun, 23 Jan
Dear Jarrod,
recently you suggested that to overcome overdispersion in a binomial
distribution by fitting a observation-level random effect.
I was wondering if this method has been described anywhere so I can put a
reference in my report.
Thanks a lot,
Greetings David Jansen
Hi Thierry +
On Jan 23, 2011, at 19:32 , MM wrote:
The $ notation, such as accountants$statef,
shouldn't it be
The $ notation, such as accountants$home,
instead?
Yes... (Not strictly incorrect, but confusing when we have
accountants - data.frame(home=statef,
I've solved my own problem using ZOO_OBJ[,COL2, COL5]. The trick
was preceding the list of names with a comma as described in the
standard ts document.
On Mon, Jan 24, 2011 at 9:51 AM, Blair Sutton blai...@gmail.com wrote:
Hi
Would anyone have any pointers on how to slice up a large zoo table.
On Mon, Jan 24, 2011 at 4:51 AM, Blair Sutton blai...@gmail.com wrote:
Hi
Would anyone have any pointers on how to slice up a large zoo table. I
have the following structure: -
str(ZOO_OBJ)
zoo [1:632, 1:83] 30.4 30.4 30.4 30.4 30.3 ...
- attr(*, dimnames)=List of 2
..$ : NULL
..$
My previous post had a typo. So as not to confuse future readers of
the list it should have read ZOO_OBJ[,cbind(COL2, COL5)].
Thanks Gabor.
On Mon, Jan 24, 2011 at 10:54 AM, Blair Sutton blai...@gmail.com wrote:
I've solved my own problem using ZOO_OBJ[,COL2, COL5]. The trick
was preceding
Isn't necessary a formula, but a class that could be coerced to that class:
x - rnorm(100)
y - rnorm(100)
z - rnorm(100)
lm(x ~ y + z)
On Sun, Jan 23, 2011 at 2:46 PM, Paul Evans p.evan...@yahoo.com wrote:
Hi,
I had a function that looked like:
diff - lm(x ~ y + z)
How can I pass the
On Sun, 2011-01-23 at 10:56 -0800, torbjore wrote:
I think you guys make it more difficult than it has to be. Estimating
probability of success with a loglog-link is equivalent to estimating
probability of failure with a cloglog-link, so all you have to do is to
change the response variable
On 2011-01-23 19:28, Deb Midya wrote:
Hi R-Users,
Thanks in advance.
I am using R-2.12.0 on Windows XP.
I am trying to produce an n X m matrix from text data stored in different
files. Where n = number of words (say w1, w2, …, wn). M is the number of
documents (say d1, d2, …, dm)
A. Using
Tal Galili tal.galili at gmail.com writes:
Hello Troy.
A tiny question (without answering your question), why did you choose to do
it this way instead of using
?step
or
?stepAIC
?
[snip snip]
My questions are:
Should I be using var.test to run the F-test to decide which
I would appreciate any information about how to carry out a hierarchical
cluster analysis with cluster of subjects. I need to find cluster of
subjects that share many variables. I know that fcp package have a lot of
options to carry out the regular hierarchical cluster analysis (cluster of
Quoting Frank H: These relationships rarely occur in nature... I
agree; I have seen cutpoint relationships only a handful of times in 25
years of medical work.
A better approach is to look at the data using a smoothing spline:
options(na.action=na.exclude)
fit -
I think this is a problem with quotes.
If you look good, you see:
seiz.df - sqlFetch(chnl, 'source.MAIN')
... 'source.main': table not found on channel
You asked MAIN, but your db can't find main.
If you use seiz.df - sqlFetch(chnl, '\source\.\MAIN\') , you problem
should be gone.
Bart
--
Hello,
I have a problem writing a raster with the raster package.
I have the raster object mask which has the following geoinformation:
R output
mask
class : RasterLayer
filename:
E:/Daten/FE/HyMAP/Luxembourg_2010/Kehlen_Useldange/mosaik/LUX_LC_noOverlap_mask
nrow: 5198
Dear all,
I have a question about the output of linear mixed model fitted in R
using nlme package. In particular, what are the t-values that are given
in an output, how are they calculated and based on what test? I guess it
cannot be a simple Student t-test, otherwise how can the simple Student
Hi all,
I am using the example on page 737 of The R Book by Michael J Crawley,
to plot factor loadings against each other (in a multivariate analysis).
However the following line code
plot(loadings(model)[,1],loadings(model)[,2],pch=16,xlab=Factor 1,
ylab=Factor 2)
throws an
does the arima/arima0 function use the state space form of the model
equation even when fitting with the CSS-method?
regards
Christoph
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
Hi All
I was using the DFA() in the fractal package to examine a set of time
series data.
And I was not sure what the H estimate meant from the summary table.
is it the alpha of the power law equation?
__
R-help@r-project.org mailing list
I have a problem using augPred from the nlme package on a data set with NAs.
Consider this example, modified from the augPred help page:
library(nlme)
Orthodont[100,]$age=NA Insert NA somewhere in the data set
fm1 - lme(Orthodont, random = ~1,na.action=na.exclude) Can still fit
Hi everyone,
Does anyone know if there is a package to run Latent Transitional
Analysis using R?
Regards!
--
Sebastián Daza
sebastian.d...@gmail.com
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read
What is the meaning of offset?
As in glm() an offset is a variable on the right hand side of the
equation that is a fixed part of the predictor. When doing linear
regression, or rpart with continuous Y, there is no need for an offset;
adding +offset(x3) on the right hand side of the equation
Dear Alex,
I have read your question about post-hoc test:
Let's assume that according to Anova(lm(y~a*b, data=d)) the a:b interaction is
significant, and I would like to know if there are specific combinations of a
and b levels that differ from the control group. Are there any caveats against
Dear all
I simulate a panel data:
n - 10
t - 5
nt - n*t
pData - data.frame(id = rep(paste(JohnDoe, 1:n, sep = .), each =
t),time = rep(1981:1985, n))
rho -0.99#simulate alphai corelated with the xi
print(rho)
alphai - rnorm(n,mean=0,sd=1)#alphai simulation
x- as.matrix(rnorm(nt,1))#xi
I have a problem with expressions. I am trying to create a title where
the parameter of interest is displayed as a Greek character. Which
parameter is being considered is stored in a character variable.
As an example, if I have
param - alpha
and then do
plot(0, 0, main =
--- included message
Thus, my question is: *What common measures exists for ranking/measuring
variable importance of participating variables in a CART model? And how
can
this be computed using R (for example, when using the rpart package)*
---end
Consider the following printout from
Hi Terry,
I've actually already written such a function (based on an old similar
question I once asked on this list), which I attached bellow to this e-mail.
But I have a few problems with my function:
1) I wasn't sure how to include the surrogate variable importance level
into the function
This is a nice tutorial on doing this:
http://www.r-tutor.com/gpu-computing/clustering/hierarchical-cluster-analysis
http://www.r-tutor.com/gpu-computing/clustering/hierarchical-cluster-analysis
Contact
Details:---
Contact me:
Check out caret::varImp.rpart(). It's described in the original CART
book.
Andy
From: Tal Galili
Hello all,
When building a CART model (specifically classification tree)
using rpart,
it is sometimes interesting to know what is the importance of
the various
variables introduced to
On Tue, 25 Jan 2011, David Scott wrote:
I have a problem with expressions. I am trying to create a title where the
parameter of interest is displayed as a Greek character. Which parameter is
being considered is stored in a character variable.
As an example, if I have
param - alpha
param -
On Sun, 2011-01-23 at 17:37 -0600, Stuart Luppescu wrote:
[snip] Thanks to Ben and Dennis for their help, but right after I sent
the original message, I figured out how to solve my problem. I noticed
that boxplot() contains the at= argument. To get the box locations, I
used a line like this:
Thanks. Exactly what I wanted.
As usual, I played around with all sorts of things to try and get the
expression right, but never thought of as.name.
David Scott
On 25/01/2011 4:32 a.m., Charles C. Berry wrote:
On Tue, 25 Jan 2011, David Scott wrote:
I have a problem with expressions. I am
Kostenko, Olga O.Kostenko at nioo.knaw.nl writes:
I have a question about the output of linear mixed model fitted in R
using nlme package. In particular, what are the t-values that are given
in an output, how are they calculated and based on what test? I guess it
cannot be a simple Student
hi
I am seeing a strange behavior I can't understand... doing:
source(/tmp/RFile.r,echo=TRUE)
Error in rep.int(c(prompt.echo, continue.echo), c(leading, length(dep) - :
invalid 'times' value
traceback()
3: rep.int(c(prompt.echo, continue.echo), c(leading, length(dep) -
leading))
2:
Dear all,
I want to draw a graph that contains the scatterplot matrix in the lower panel
and coefficients in the upper panel. I used and adapted the example for the
function pairs but cannot figure out how to get no values and ticks in the
upper panel (the values should only be in the lower
On Mon, Jan 24, 2011 at 12:07 PM, Matthieu Stigler
matthieu.stig...@gmail.com wrote:
hi
I am seeing a strange behavior I can't understand... doing:
source(/tmp/RFile.r,echo=TRUE)
Error in rep.int(c(prompt.echo, continue.echo), c(leading, length(dep) - :
invalid 'times' value
traceback()
Le 24. 01. 11 18:22, Gabor Grothendieck a écrit :
On Mon, Jan 24, 2011 at 12:07 PM, Matthieu Stigler
matthieu.stig...@gmail.com wrote:
hi
I am seeing a strange behavior I can't understand... doing:
source(/tmp/RFile.r,echo=TRUE)
Error in rep.int(c(prompt.echo, continue.echo), c(leading,
FWIW, I think it fair to say that modern statistical practice
generally views stepwise regression as a bad idea, especially in the
hands of non-experts lke yourself. The procedures you describe are
dangerous: they have an uncomfortably high chance of choosing the
wrong variables and leading to
It sounds like you have some invalid expressions. Dump out the values
of 'leading' and 'length(dep) - leading'. Learn some simple debugging
techniques. One is to set
options(error=utils::recover)
so that on the error you can use the browser to examine what the values are.
On Mon, Jan 24,
ok, thanks Jim
The problem comes from length(dep)leading, so we get negative number...
length(dep)
[1] 183
c(leading, length(dep) - leading)
[1] 516 -333
But 183 seems to be the right number:
$ wc -l /tmp/RFile.r
183 /tmp/RFile.r
So now need to understand what is this dep, and why it has a
On Mon, Jan 24, 2011 at 12:29 PM, Matthieu Stigler
matthieu.stig...@gmail.com wrote:
Le 24. 01. 11 18:22, Gabor Grothendieck a écrit :
On Mon, Jan 24, 2011 at 12:07 PM, Matthieu Stigler
matthieu.stig...@gmail.com wrote:
hi
I am seeing a strange behavior I can't understand... doing:
Is it possible to generate a density plot comparing several (6 or 7) groups
of data and have the x-axis in date format (e.g.: %d%b, 10Mar)?
When I try to input the data in date format I get an error saying this
function only allows 1-d data.
Thank you,
Claudia
[[alternative HTML version
Hello :)
I wanted to right an expression to check when x and y have the same sign
and I wrote the following:
if ((x0 y0) || (x0 y0))
which looks pretty ugly to me.
Can you please suggest me a better way for that?
Regards
Alex
__
Do 'str(dep)' to see what dep is and where it comes from. If you have
the 'options' set as I suggested, you can do this examination when the
error occurs.
On Mon, Jan 24, 2011 at 12:41 PM, Matthieu Stigler
matthieu.stig...@gmail.com wrote:
ok, thanks Jim
The problem comes from
Try this:
!diff(sign(c(x, y)))
On Mon, Jan 24, 2011 at 4:18 PM, Alaios ala...@yahoo.com wrote:
Hello :)
I wanted to right an expression to check when x and y have the same sign
and I wrote the following:
if ((x0 y0) || (x0 y0))
which looks pretty ugly to me.
Can you please suggest
On Monday, January 24, 2011 07:18:03 pm Alaios wrote:
Hello :)
I wanted to right an expression to check when x and y have the same sign
and I wrote the following:
if ((x0 y0) || (x0 y0))
which looks pretty ugly to me.
Can you please suggest me a better way for that?
Regards
I have installed the latest relaimpo library ( form their website with the 8
functions)
When running pvmd as a type in c=type(pmvd) in calc.relimp
I get the error message ...could not find function pmvdcalc
(this is in R version 2.12.1)
Can anyone help?
Paul
Prof P Rheeder
School of Health
Does anyone know what I am doing wrong?
Could be a lot or could be a little, but we have to guess, because you
haven't given us the important information. That you are following Crawley
is of little or no interest. We need to know what _you_ did.
What is model and what's in it?
##
str(model)
splm package is a r implemention of spatial panel data models.
and the loglik paremeter is most important infomation for splm methods.
but i found the loglik always been null ,it's craze to get right estimation
in splm with null loglik.
Any one knows the splm package and can get the right
How many records can the R recursive partitioning software handle?
We are analyzing 5,000,000 medical records looking at 100 risk factors for
the outcome of interest
Richard H. White, MD
Hibbard E. Williams Endowed Professor of Medicine
Chief, Division of General Medicine
DIrector,
Hi,
I am trying to construct a svmpoly model using the caret package (please
see code below). Using the same data, without changing any setting, I am
just changing the seed value. Sometimes it constructs the model
successfully, and sometimes I get an “Error in indexes[[j]] : subscript out
of
Dear List,
I am having trouble setting the transparency of a ribbon in ggplot2 and was
wondering if anybody had any suggestions
so far i have a plot exactly as i want it and i want to add a ribbon connecting
the ymax and ymin, whci i do with the following command
m10 +
Greetings,
I would like to calculate tolerancelimits for a series of predicted values
from nonlinear regression models. I've been using the tolerance package
but the self-starting functions are not in the derivitive tables. When I
spellout the functions and supply starting values I repeatedly
Hi
I'm using the Limma package to analyze microarray data from a 2x2 factorial
loop design.
u --- t
ll
ll
v --- v.t
The samples hybridized to my arrays are: u/t, t/v.t, v.t/t, v.t/v, v/u, and
u/v.
My design matrix is:
v t v.t
v 1 0 0
t 0 1 0
Dear R-users,
This is a loop which is part of a bigger script. I managed to isolate the
error in this loop and simplified it to the bare minimum and made it
self-contained.
a-c(2,3,4,5,5,5,6,6,6,7)
for(n in 1:10)
{
print(paste(n: ,n))
z1-a[n]
#make a list container
ldata-list()
t=1
put
options(error=utils::recover)
in the script and when the error occurs use the browser to examine the
values to see where the error is.
On Mon, Jan 24, 2011 at 12:44 PM, Neeti nikkiha...@gmail.com wrote:
Hi,
I am trying to construct a svmpoly model using the caret package (please
see
I currently set the Bioconductor repository in my .Rprofile using this
code (which needs editing for every version number change of
Bioconductor):
# Choose repositories
repos - structure(c(CRAN=http://streaming.stat.iastate.edu/CRAN;,
Put a space after the # in the line
#line 516
to avoid the problem. A similar problem also
appears in parse().
parse(text=#line 102\nlog(pi)\n)
Error in `Encoding-`(`*tmp*`, value = character(0)) :
'value' must be of positive length
parse(text=# line 102\nlog(pi)\n)
Roy,
I have no idea what you're actually trying to do here, but
it looks like there would be a more natural R'ish way if
you're concerned about grouping consecutive elements of 'a'.
At any rate, within your while loop, you're incrementing n by
1, and eventually n will be 10, which will be
On 01/24/2011 10:45 AM, Kevin Wright wrote:
I currently set the Bioconductor repository in my .Rprofile using this
code (which needs editing for every version number change of
Bioconductor):
# Choose repositories
repos - structure(c(CRAN=http://streaming.stat.iastate.edu/CRAN;,
Exactly what do you want to do with the data? It is 5M rows with 100
columns of data? Do you want to read it all in at once? If so, and
if they are numeric, you will need 4GB to hold one copy, and be
running on a 64-bit version of R. If you want to do any processing
with everything in memory,
On 11-01-24 12:07 PM, Matthieu Stigler wrote:
hi
I am seeing a strange behavior I can't understand... doing:
source(/tmp/RFile.r,echo=TRUE)
Error in rep.int(c(prompt.echo, continue.echo), c(leading, length(dep) - :
invalid 'times' value
traceback()
3: rep.int(c(prompt.echo,
Hi again,
I have checked the same code (see below) using MATLAB. It produces the
same error (i.e., equal numbers are evaluated as unequal). Do I miss
something?
Thanks for help!
Marc
Marc Jekel schrieb:
Hello R Fans,
Another question for the community that really frightened me today.
Of course, before posting my question, I did RTFM and RTFcode and
RTFmailinglists. The key word in my question was simpler. I
rejected copying a modified version of the repositories file to my
home directory since it has changed numerous times with addition of
R-forge etc.
Here is another
if (x*y0) {...}
On Mon, Jan 24, 2011 at 1:27 PM, Rainer Schuermann
rainer.schuerm...@gmx.net wrote:
On Monday, January 24, 2011 07:18:03 pm Alaios wrote:
Hello :)
I wanted to right an expression to check when x and y have the same sign
and I wrote the following:
if ((x0 y0) || (x0 y0))
It is easier than that. Use
http://www.bioconductor.org/packages/release/bioc
or
http://www.bioconductor.org/packages/devel/bioc
/Henrik
On Mon, Jan 24, 2011 at 10:56 AM, Martin Morgan mtmor...@fhcrc.org wrote:
On 01/24/2011 10:45 AM, Kevin Wright wrote:
I currently set the Bioconductor
Marc
You have been given the answer already and a solution. See the R FAQ 7.31. As
you have discovered this issue is not specific to R. In order to eliminate
this problem entirely, you will need a computer system with infinite
precision.
Dan
Daniel J. Nordlund
Washington State Department
kognDisso wrote:
Hi again,
I have checked the same code (see below) using MATLAB. It produces the
same error (i.e., equal numbers are evaluated as unequal). Do I miss
something?
1. It is NOT an error
2. The numbers are NOT equal
3. Please read FAQ 7.31.
3. Do
t - tt
and you will
On 1/24/2011 7:44 AM, Sam wrote:
Dear List,
I am having trouble setting the transparency of a ribbon in ggplot2
and was wondering if anybody had any suggestions
so far i have a plot exactly as i want it and i want to add a ribbon
connecting the ymax and ymin, whci i do with the following
Now that is _simple_. Thanks.
Kevin
On Mon, Jan 24, 2011 at 1:49 PM, Kevin Wright kw.s...@gmail.com wrote:
Of course, before posting my question, I did RTFM and RTFcode and
RTFmailinglists. The key word in my question was simpler. I
rejected copying a modified version of the repositories
Sebastian,
There is a number of packages that fit hidden (or latent) Markov models
which are in most regards identical to latent transition analysis.
Best, Ingmar
2011/1/24 Sebastián Daza sebastian.d...@gmail.com
Hi everyone,
Does anyone know if there is a package to run Latent Transitional
Dear list,
Please consider the following call of sort
sort(c(a,f))
[1] a f
sort(c(f,a))
[1] a f
sort(c(aa,ff))
[1] ff aa
sort(c(ff,aa))
[1] ff aa
The last two results look strange to me. Is that a bug???
The result seems to come from calls to order:
order(c(a,f))
[1] 1 2
order(c(f,a))
Hi
Well this is the output of str(dep) on a small example:
str(dep)
chr [1:8] ### ...
Browse[1] dep
[1] ###
[2] ### chunk number 1:
[3] ###
[4] #line
Hello everyone,
I am doing the hypothesis test and I need the score vector of each iteration
in glm (family=binomial); how could I do it. I tried trace option but it
gives me just AIC of each iteration nothing more.
thanks;
[[alternative HTML version deleted]]
On Mon, Jan 24, 2011 at 07:16:58PM +0100, Roy Mathew wrote:
Dear R-users,
This is a loop which is part of a bigger script. I managed to isolate the
error in this loop and simplified it to the bare minimum and made it
self-contained.
a-c(2,3,4,5,5,5,6,6,6,7)
for(n in 1:10)
{
indeed this makes the trick! quite strange... is this a known bug/issue?
thanks!
Matthieu
Le 24. 01. 11 19:48, William Dunlap a écrit :
Put a space after the # in the line
#line 516
to avoid the problem. A similar problem also
appears in parse().
parse(text=#line 102\nlog(pi)\n)
Le 24. 01. 11 20:43, Duncan Murdoch a écrit :
On 11-01-24 12:07 PM, Matthieu Stigler wrote:
hi
I am seeing a strange behavior I can't understand... doing:
source(/tmp/RFile.r,echo=TRUE)
Error in rep.int(c(prompt.echo, continue.echo), c(leading,
length(dep) - :
invalid 'times' value
-Original Message-
From: mat [mailto:matthieu.stig...@gmail.com]
Sent: Monday, January 24, 2011 2:09 PM
To: William Dunlap
Cc: jim holtman; r-help@r-project.org; murdoch.dun...@gmail.com
Subject: Re: [R] error with source(): invalid 'times' value
indeed this makes the trick!
On Mon, 24 Jan 2011, Søren Højsgaard wrote:
Dear list,
Please consider the following call of sort
sort(c(a,f))
[1] a f
sort(c(f,a))
[1] a f
sort(c(aa,ff))
[1] ff aa
sort(c(ff,aa))
[1] ff aa
The last two results look strange to me. Is that a bug???
It seems that you and your OS
Hi Andy,
Thank you for your response.
I've already came by this function but also noticed that the help file
states that:
This method does *not* currently provide classspecific measures of
importance when the *response is a factor*.
Which is the case I need to deal with.
Any suggestions as to
Roy Mathew wrote:
Thanks for the reply Erik, As you mentioned, grouping consecutive
elements of 'a' was my idea.
I am unaware of any R'ish way to do it. It would be nice if someone in
the community knows this.
Is this the idea you're trying to execute? It uses ?rle and ?mapply.
a -
I am using the function permutations from the package *gregmisc*. However, I
am also making use of the package *e1071*, which also contains a function
called permutations. I want to use the function permutations from the *
gregmisc* package, however, the other package is masking this function.
On Mon, Jan 24, 2011 at 2:47 PM, Yanika Borg akina...@gmail.com wrote:
I am using the function permutations from the package *gregmisc*. However, I
am also making use of the package *e1071*, which also contains a function
called permutations. I want to use the function permutations from the *
Hello Andy and other R-help readers,
I've just realized that your function *does* answer my needs at full.
(That's what happens when reading something late at night I guess...)
Thanks again Andy for your help!
Best,
Tal
Contact
I make plenty of scatterplots, especially using scatterplot.matrix from
library(car). One thing I don't know how to do is determine which points
are plotted last. Sometimes I plot a large number of points for multiple
groups represented by different colors.
I would like to guarantee that
On 11-01-24 5:09 PM, mat wrote:
Le 24. 01. 11 20:43, Duncan Murdoch a écrit :
On 11-01-24 12:07 PM, Matthieu Stigler wrote:
hi
I am seeing a strange behavior I can't understand... doing:
source(/tmp/RFile.r,echo=TRUE)
Error in rep.int(c(prompt.echo, continue.echo), c(leading,
length(dep)
On Jan 24, 2011, at 6:49 PM, Mike Miller wrote:
I make plenty of scatterplots, especially using scatterplot.matrix
from library(car). One thing I don't know how to do is determine
which points are plotted last. Sometimes I plot a large number of
points for multiple groups represented by
On Mon, 24 Jan 2011, David Winsemius wrote:
On Jan 24, 2011, at 6:49 PM, Mike Miller wrote:
I make plenty of scatterplots, especially using scatterplot.matrix from
library(car). One thing I don't know how to do is determine which
points are plotted last. Sometimes I plot a large number of
On 2011-01-24 16:39, Mike Miller wrote:
On Mon, 24 Jan 2011, David Winsemius wrote:
On Jan 24, 2011, at 6:49 PM, Mike Miller wrote:
I make plenty of scatterplots, especially using scatterplot.matrix from
library(car). One thing I don't know how to do is determine which
points are plotted
We should really have an R package rating site, comments, reviews or
such, like folks do for apps or movie reviews. Does anyone know of a
site trying to do this. If i remember correctly a few R user
conferences ago this was talked about but not sure if anything was ever
implemented.
http://crantastic.org/
On 01/24/2011 09:08 PM, zubin wrote:
We should really have an R package rating site, comments, reviews or
such, like folks do for apps or movie reviews. Does anyone know of a
site trying to do this. If i remember correctly a few R user
conferences ago this was talked
Thanks for the reply Erik, As you mentioned, grouping consecutive elements
of 'a' was my idea.
I am unaware of any R'ish way to do it. It would be nice if someone in the
community knows this.
The error resulting in the NA was pretty easy to fix, and my loop works, but
the results are still wrong
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