On Tue, Feb 01, 2011 at 08:30:22PM -0500, Bryan Hanson wrote:
[Sorry, resending with a proper subject line!]
Hi Guru's...
I have a set of points that may lie along any of the x, y and z axes
in a Cartesian coordinate system. I am hoping that a function exists
which will determine if
On Tue, 1 Feb 2011, Joel wrote:
Hi
I wondering if its possible to make a hidden environment for a package, so
the user cant see whats in it but the diffrent functions inside the package
can use the variables in the environment.
Up to a point:
1) See the manual about the concept of a name
Hello
I am trying to find a way to find the max value, for only a subset of a
dataframe, depending on how the data is grouped for example,
How would I find the maxmium responce, for all the GPR119a condition below:
I've tried tapply
tapply(GPR119data$responce, GPR119data$GPR119a, max)
Error
Hi R users
I have these two vectors:
Row - sample(1:25, 10)
Col - sample(1:25, 10)
Is there a way to combine them into a list, whose first component is a
vector containing the first element of Row and the first element of Col,
the second component is a vector containing the second
Hi all,
I have commited a new release of my package and waited for more than one
day. After that install.packages(tests,repos=http://r-forge.r-projet.org;)
still returns package 'tests' is not available. I have done the local
build check and the package seems ok. Also have mofified the Title in
I know it's a common error and there is a lot of help available but still
can't resolve the issue:
all i am trying to do is to read a csv file from my folder and this is what
i get:
Error in scan(file, what, nmax, sep, dec, quote, skip, nlines, na.strings,
:
scan() expected 'a real', got
Hello everyone,
I have a data set like this:
head( fish_transect)
ID_TRANSECT ID_PROJECT DE_ZONE DE_LOCALITY DE_SECTOR MES
1 42 MB TarragonaCreixell Control I 9
2 42 MB TarragonaCreixell Control I 9
3 42 MB Tarragona
I have a 32000 x 14 matrix (M) where entry (x, y) corresponds to
person x at a discrete time y. I then have a matrix (M2) of 6 x 2
where each entry is a an event by a person that is in the above 32000
and at a time that is in the range of the discrete time points above.
I want to populate the
Hi Frank,
I believe that glmnet scales variables by their standard deviations.
This would not be appropriate for categorical predictors.
That's an excellent point, which many are likely to forget (including me)
since one is using a model matrix. The default argument is to standardize
inputs,
Hi,
I have the code for the density plot
j - 8
plot(density(diff_in_sample[,1]), main = list.files()[j])
for(i in 1:25){
lines(density(diff_in_sample[,i]))
}
This gives me an error
Error in density.default(diff_in_sample[, i]) :
'x' contains missing values
I am not quite sure what to do.
On Tue, 1 Feb 2011 14:20:51 +0900
Gundala Viswanath gunda...@gmail.com wrote:
I have a R script that contain these lines for plotting:
plot(foo,lwd=2,lty=3,col=red, main=);
plot(bar,lwd=2,lty=3,col=blue);
legend(0.6,0.6,c('Default','Probabilistic'),
col=c('red','blue'),lwd=3);
But it
Hi
I'm having some trouble with getting RMySQL installed on my Ubuntu system.
As the apt-get install version of R is 2.10.x I've reinstalled 2.12 the old
fashion way by ./conf and make.
But now when I shall install RMySQL I get
Configuration error:
could not find the MySQL installation
We don't need a loop!
require(Rmpfr)
factorial(mpfr(1:500,3800))
2011/2/2 Waclaw Kusnierczyk w...@idi.ntnu.no
library(bc)
factorial = function(n) bc(sprintf('
define factorial(n) {
if (n 2) return (1)
f = 2
i = 2
while (i n) f *= ++i
return (f)
Hi,
Try this:
mapply(FUN=c, Row, Col, SIMPLIFY=FALSE)
HTH,
Ivan
Le 2/2/2011 08:55, Lorenzo Cattarino a écrit :
Hi R users
I have these two vectors:
Row- sample(1:25, 10)
Col- sample(1:25, 10)
Is there a way to combine them into a list, whose first component is a
vector containing
Hi,
Not sure what you want to do, but take a look at ?duplicated, ?unique,
and maybe ?aggregate; it might be what you're looking for.
HTH,
Ivan
Le 2/2/2011 10:13, Lucia Rueda a écrit :
Hello everyone,
I have a data set like this:
head( fish_transect)
ID_TRANSECT ID_PROJECT DE_ZONE
On Wed, 2 Feb 2011, Joel wrote:
Hi
I'm having some trouble with getting RMySQL installed on my Ubuntu system.
As the apt-get install version of R is 2.10.x I've reinstalled 2.12 the old
fashion way by ./conf and make.
But now when I shall install RMySQL I get
Configuration error:
could
Hi
r-help-boun...@r-project.org napsal dne 31.01.2011 15:51:16:
snip
Hi
thanks. I am not sure if I have understood 100% but at least I know now
that
there's a diference.
About this:
lapsales
Store Prod qtd
5 Aveiro Lapiseira 3
8 Coimbra Lapiseira 1
On Wed, Feb 02, 2011 at 09:35:28AM +0200, Leendert Punt wrote:
I have a 32000 x 14 matrix (M) where entry (x, y) corresponds to
person x at a discrete time y. I then have a matrix (M2) of 6 x 2
where each entry is a an event by a person that is in the above 32000
and at a time that is in
Hi
r-help-boun...@r-project.org napsal dne 01.02.2011 07:02:50:
Hi AD,
You might try the following:
# data
a - c(2,3,5)
b - c(8,7) # you got this wrong ;)
# option 1
foo - function(x) as.numeric(paste(x, sep = , collapse = ))
# examples
foo(a)
# [1] 235
foo(b)
# [1] 87
On Wed, Feb 02, 2011 at 01:13:11AM -0800, Lucia Rueda wrote:
Hello everyone,
I have a data set like this:
head( fish_transect)
ID_TRANSECT ID_PROJECT DE_ZONE DE_LOCALITY DE_SECTOR MES
1 42 MB TarragonaCreixell Control I 9
2 42 MB Tarragona
Can somebody tell me that, if I do some arithmetic calculation over 2
matrices then how the column names and row names are preserved? It seems
that, for multiplication, column names and row names of the 2nd matrix are
preserved and for additional, there seems not having any explicit rule:
Hi
r-help-boun...@r-project.org napsal dne 02.02.2011 11:14:18:
Hi
r-help-boun...@r-project.org napsal dne 31.01.2011 15:51:16:
snip
Hi
thanks. I am not sure if I have understood 100% but at least I know
now
that
there's a diference.
About this:
Thank you for the suggestion and it is exactly as you said only one
observation in each cluster. I know I can avoid this anyway and I am just
out of curiosity of the error.
I am writing a special algorithm to cluster some datasets with different
numbers of observations. For some particular
Hi
r-help-boun...@r-project.org napsal dne 01.02.2011 10:20:48:
Good morning,
I have an excel spreadsheet with similarities among objects. The format
of
the file is the following:
1st row: empty cell,object-1-name,object-name-2,...,object-N
2nd row: object-name-1,0,s1,2,s1,3,...,s1,N
Dear Rers,
I have a function to barplot() a matrix, eg
myfun - function(x, ...) { barplot(x , ... )}
(The real function is more complicated, it does things to the matrix first.)
So I can do:
m1 - matrix(1:20,4)
myfun(m1)
myfun(m1, main=My title)
I'd like to be able to add the number of
without a reproducible sample, it is hard to tell, but I will give it a shot.
Maybe it's possible to merge your M with M2: merge(M, M2)
If you only want to count times, you can use seq_along(x) in a by function
eg:
dat - data.frame(person=rep(c(1,2,3), each=5), time=rnorm(15))
by(dat$person,
Hi Ivan,
Thanks for your reply. This is what I want to do:
Imagine my dataset looks like this:
Species N Size
Coris julis 1 8
Coris julis 3 10
D.vulgaris 2 12
I have 1 C.julis of 8 cm, 3 C. julis of 10 cm and 2 D.vulgaris of 12 cm. I
want 1 row for each
Hi,
I'm pulling in data for the past 30 days or so. I'm going to slice
each day into 5 minute time intervals, and I want to find the average
value across all days for the given slice of time. That is, I want to
know what the average value at 8:00 was for the 30 day period, the
average value at
Dear R-help,
I am doing clustering via finite mixture model. Please suggest some packages in
R to find clusters via finite mixture model with continuous variables. And
also I wish to verify the distributional properties of the mixture
distributions
by fitting the model with lognormal, gamma,
Try this:
transform(fish[rep(seq(nrow(fish)), fish$N),], N = 1)
On Wed, Feb 2, 2011 at 8:58 AM, Lucia Rueda lucia.ru...@ba.ieo.es wrote:
Hi Ivan,
Thanks for your reply. This is what I want to do:
Imagine my dataset looks like this:
Species N Size
Coris julis 1 8
Coris
Exactly!! Thanks a lot Petr. It worked!
Thansk to you as well Ivan!
--
View this message in context:
http://r.789695.n4.nabble.com/reshape-data-adding-rows-to-dataframe-tp3253640p3253793.html
Sent from the R help mailing list archive at Nabble.com.
Dear R Helpers,
I would like to report on an error in the ff package here.
The ff package is an R package which enables us to store large data on disk
systematically and have fast access to the database.
I used the package in Linux as a guest OS of VirtualBox, and executed the
following
Is there any reason to expect a problem ?
i'm running this script on the cluster down the hall:
module load R/2.11.0
R
library(multicore)
fxx-function(ll) runif(1)
mclapply(1:10,fxx)
i get:
Error in fork() : Unable to fork.
less /proc/cpuinfo
yields:
processor : 0
vendor_id :
On Tue, Feb 01, 2011 at 12:51:18PM -0800, Kiogou Lydie wrote:
PLEASE HELP
I actually want to do the following:
a[j] = (1/(j!))*?? (i-1-d), j = 500, ?? means product i = 1 to
j
??
Yet, j! will stop at 170 and ?? (i-1-d) at 172; so, a[j] will
not exceed 170.
I would like to
Hello,
How to convert x into y?
x
[1] 15, 23, 2, 21, 11, 5
y
[,1] [,2]
[1,] 15 23
[2,] 232
[3,]221
[4,] 21 11
[5,] 115
Thanks a lot!
Romildo
[[alternative HTML version deleted]]
__
R-help@r-project.org
Try this:
embed(scan(textConnection(x), sep = ,), 2)
On Wed, Feb 2, 2011 at 10:12 AM, Romildo Martins
romildo.mart...@gmail.comwrote:
Hello,
How to convert x into y?
x
[1] 15, 23, 2, 21, 11, 5
y
[,1] [,2]
[1,] 15 23
[2,] 232
[3,]221
[4,] 21 11
[5,]
'Strange' to have no response on this. Can a knowledgeable Danish
writer please confirm that this is how the OSes are supposed to handle
Danish collation?
On Mon, 24 Jan 2011, Prof Brian Ripley wrote:
On Mon, 24 Jan 2011, Søren Højsgaard wrote:
Dear list,
Please consider the following
This is clearly a problem occuring in the C code of the ff package.
Please report to the package maintainer, Cced here (with the 'at a
minimum' information requested in the posting guide, most importantly
the Linux architecture and the versions involved).
FWIW it works for me on
Not sure if I qualify as being knowledgeable, but...
You write
I recall that 'aa' used to sort at the end of the alphabet in Danish
telephone books, so it seems the sort used on Windows thinks so too. See
?Comparison for some further details. What I don't understand is that
someone
Hi everyone,
Following this post:
http://r.789695.n4.nabble.com/currency-conversion-function-tt906056.html#a906061
I was trying to run the code:
foo - function(from, to, date){
url -
http://www.oanda.com/convert/classic?script=..%2Fconvert%2Fclassiclanguage=envalue=1
params -
It is clear that you have letters in the data you are trying to
process; that is the cause of the erro. What was the 'scan' statement
you were using? Were you expecting all numerics in the string? The
error message is consistent with your input.
On Wed, Feb 2, 2011 at 2:07 AM, gked
On Wed, 2 Feb 2011, Søren Højsgaard wrote:
Not sure if I qualify as being knowledgeable, but...
You write
I recall that 'aa' used to sort at the end of the alphabet in Danish
telephone books, so it seems the sort used on Windows thinks so too. See
?Comparison for some further details. What
Ramya ramya.victory at gmail.com writes:
I have the code for the density plot
j - 8
plot(density(diff_in_sample[,1]), main = list.files()[j])
for(i in 1:25){
lines(density(diff_in_sample[,i]))
}
This gives me an error
Error in density.default(diff_in_sample[, i]) :
'x' contains
Thanks Petr, the sign function will be of help. I was not aware of
it. Bryan
On Feb 2, 2011, at 3:21 AM, Petr Savicky wrote:
On Tue, Feb 01, 2011 at 08:30:22PM -0500, Bryan Hanson wrote:
[Sorry, resending with a proper subject line!]
Hi Guru's...
I have a set of points that may lie
Dear Prof. Brian Ripley,
Thank you for your kind advice. I have to report to you that I attempted to
save the ff file at a shared directory between guest OS (Linux) and host OS
(Windows 7).
I tried to change the working directory as an unshared folder, and then I
tried the same commands. In
I have a matrix with a lot of values inside..
when I execute the folowing command
matrix2=subset(martix, condition.)
it works...
but after the previous command I execute another subset
matrix3=subset(martix2, condition2.)
and appears the following error:
(subscript) logical
Hi all,
I have a grid of points at regular intervals (taken from a raster).
I want to create a listw matrix which opperates like this
1 1 1
1 1 1
1 1 1
and also like this
1 1 1 1 1
1 1 1 1 1
1 1 1 1 1
1 1 1 1 1
1 1 1 1 1
and so on
I want it to work with
Thanks Henrique!
It solves the problem of having the column N with unreal number of
individuals since N=1
with Petr's example:
expand - transform(dat[rep(1:nrow(dat), times=dat$N), ] ,N=1)
rownames(expand) - NULL
expand
expand
animal N
1 a 1
2 a 1
3 b 1
4 c 1
5 c 1
Hi all,
Does anyone know a way to change the significant stars in mtable (package
memisc)? The default is
Signif. codes: 0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1,
however I need it to be
Signif. codes: 0 '***' 0.01 '**' 0.05 '*' 0.1 ' ' 1
Kind regards,
Erich
[[alternative
Hi all.
This is perhaps more a statistics question but I'm hoping someone can
help me.
I have a group of patients for whom I'm looking at beat to beat RR
interval changes.
I have plotted the difference between one beat length and the next
against the difference between the previous beat length
Hi all,
I've got an R script that loads the following libraries
library(rJava)
library(RWeka)
library(tm)
At some when I try to run the tm tokenizer as
MyTokenizer - function(x) NGramTokenizer(x, Weka_control(min = 1, max = 4))
ECONOMIST_TDM -
Hello,
I am trying to calculate the autocovariance matrix for any general
farima(p,d,q) with
p,q 1. Could anyone give an idea how to implement in R or if there
is any package for this?
thank you beforehand.
Jose.
__
R-help@r-project.org mailing list
Take a look on symnum function:
symnum(runif(30), cutpoints = c(0, 0.01, 0.05, 0.1, 1), symbols = c(***,
**, *, ))
On Wed, Feb 2, 2011 at 11:25 AM, Striessnig, Erich
erich.striess...@wu.ac.at wrote:
Hi all,
Does anyone know a way to change the significant stars in mtable (package
memisc)?
On Feb 2, 2011, at 3:48 AM, Asan Ramzan wrote:
Hello
I am trying to find a way to find the max value, for only a subset
of a
dataframe, depending on how the data is grouped for example,
How would I find the maxmium responce, for all the GPR119a condition
below:
I've tried tapply
hello
I have recently started using the LOCFIT package, together with Clive
Loader's book. I need to implement some method for automatic (plug-in)
bandwidth selection in a multivariate kernel regression. From the book, and
the LOCFIT documentation, it is not clear whether this is possible. As
There are quite a few packages that work with finite mixtures, as
evidenced by the descriptions here:
http://cran.r-project.org/web/packages/index.html
These might be useful:
http://cran.r-project.org/web/packages/flexmix/index.html
http://cran.r-project.org/web/packages/mclust/index.html
On Jan 31, 2011, at 3:44 AM, ADias wrote:
David Winsemius wrote:
On Jan 30, 2011, at 5:27 PM, ADias wrote:
dados-
data
.frame
(Store
=
c
(Setubal
,lx
,Aveiro
,Coimbra
,Aveiro,Evora,Aveiro,Coimbra,Setubal),Prod=c(Bloco
Desenho,Bloco
Desenho
,Tinteiro
,Régua
,Lapiseira
,Regua
Dear list members,
I recall seeing a convenience function for applying multiple functions to
one object (i.e., almost the opposite of 'mapply’) somewhere.
Example: If the function was named ’fun’ the output of
fun(3.14, mode, typeof, class)
would be identical to the output of
Hi Karl,
same to me. Much of the times when coding I think, 'damn it, I have seen
that before, but where...'
... and so the following is from scratch, not from memory.
fun-function(x,...){
mthd-list(...)
lapply(mthd,function(m) do.call(m,list(x)))
}
fun(3.14, mode, typeof, class)
there is no
Hello Again...
I know that R has plenty of functions for drawing splines between two
points in 2d, and plenty of ways to fit a spline curve among various
points in 2d or 3d (I think), but, is there a function which can be
used to draw a simple spline curve between any two points in 3d
On Feb 2, 2011, at 8:22 AM, Ben Bolker wrote:
Ramya ramya.victory at gmail.com writes:
I have the code for the density plot
j - 8
plot(density(diff_in_sample[,1]), main = list.files()[j])
for(i in 1:25){
lines(density(diff_in_sample[,i]))
}
This gives me an error
Error in
R-help,
I'm using the update command for a multiple regression model and it is
just not working:
update(model1, . ~ . temp:wind:rad,data=ozone.pollution)
Error: unexpected input in model2-update(model1, . ~ .
summary(model1)
Call:
lm(formula = ozone ~ temp * wind * rad + I(rad^2) +
Excellent!! thanks for all!
misil
2011/2/1 mbedward [via R]
ml-node+3253006-114577237-210...@n4.nabble.comml-node%2b3253006-114577237-210...@n4.nabble.com
Another search term is geometric mean regression.
For simple models you can try the lmodel2 package.
Michael
On 2 February 2011
Hi
I have this function and this matrix:
function(x,y) x+y/x
m-matrix(c(1,2,4,2,10,8),3,2)
m
[,1] [,2]
[1,]12
[2,]2 10
[3,]48
each row represent a point (x,y) in a chart and I want via my fucntion to
calculate the image in order to get this results:
for point
Hi all,
I have multiple datasets of time series data taken from GPS collars. The
collars are supposed to take a fix every hour on the half hour, i.e., 0:30,
1:30, 2:30...23:30, (because it sometimes takes longer for the collars to
acquire a location the minute of these locations vary from
Hello all I would like to ask your help use mapply.
I have a function called findCell that takes two arguments(x,sr)
where x is a vector of size two (e.g x-c(2,3) and sr is a matrix.
I would like to call many times the findCell function (thus I need mapply) for
different x inputs but always for
Hi
I'm trying to predict using a model I fitted with SVM.
I constructed the model (called Svm) using a training set, and now I want to
use a test set (called BankTest) for prediction.
The response variable is in the first column of BankTest.
SvmPred = predict(Svm, BankTest[,-1],
On Feb 2, 2011, at 9:12 AM, ADias wrote:
Hi
I have this function and this matrix:
function(x,y) x+y/x
m-matrix(c(1,2,4,2,10,8),3,2)
m
[,1] [,2]
[1,]12
[2,]2 10
[3,]48
each row represent a point (x,y) in a chart and I want via my
fucntion to
calculate the
Hi,
On Wed, Feb 2, 2011 at 9:56 AM, Brian ctto...@hotmail.com wrote:
Hi
I'm trying to predict using a model I fitted with SVM.
I constructed the model (called Svm) using a training set, and now I want to
use a test set (called BankTest) for prediction.
The response variable is in the
Hi
r-help-boun...@r-project.org napsal dne 02.02.2011 16:05:21:
On Feb 2, 2011, at 9:12 AM, ADias wrote:
Hi
I have this function and this matrix:
function(x,y) x+y/x
m-matrix(c(1,2,4,2,10,8),3,2)
m
[,1] [,2]
[1,]12
[2,]2 10
[3,]48
there is no need for 'apply' here, because R can handle vectors.
ord-m[,1]+m[,2]/m[,1]
Am 02.02.2011 15:12, schrieb ADias:
Hi
I have this function and this matrix:
function(x,y) x+y/x
m-matrix(c(1,2,4,2,10,8),3,2)
m
[,1] [,2]
[1,]12
[2,]2 10
[3,]48
Hi everyone,
Does anyone know how to get black and white theme (grey scale,, I
would say) graphs using lattice or ggplot2, as it is shown in this
webpage: http://lmdvr.r-forge.r-project.org/figures/figures.html?
I am using Sweave, and I cannot get that color configuration.
I have added the
Hi Luis,
Well, when I copied your code I discovered that
On Wed, Feb 2, 2011 at 9:42 AM, Luis Ridao luri...@gmail.com wrote:
R-help,
I'm using the update command for a multiple regression model and it is
just not working:
update(model1, . ~ . – temp:wind:rad,data=ozone.pollution)
On 2/2/11 3:59 AM, Łukasz Ręcławowicz wrote:
We don't need a loop!
require(Rmpfr)
factorial(mpfr(1:500,3800))
This is very good! I get an unexpected warning, though:
Warning message:
In if (mpfr.is.integer(x)) round(r) else r :
the condition has length 1 and only the first element will
Well, if you're using pdf, you could set the gray option there, e.g.,
pdf.options(colormodel=gray)
Or you could just use a gray theme. In ggplot2 use
+ theme_gray()
Not sure in lattice, but I think it also has a themeing system.
Best,
Ista
2011/2/2 Sebastián Daza sebastian.d...@gmail.com:
Hi
Is it possible to cross the cell boundaries set by layout using base graphics?
I.e. I want to draw e.g. a line from one layout cell to another.
Is there a way to do that?
layout(matrix(c(1,2), byrow=TRUE, ncol=2))
plot.new()
text(0,0,paste(rep(a, 200), collapse=), xpd=T)
layout.show(2)
I would
Hi,
maybe you rethink your calculations. Just for curiosity, what's the purpose?
First of all, using
prod(1:j-1-.25) #and
prod(1:j)
instead of a loop is much more efficent.
If you need all values for a[1] up to a[j] you can use cumprod
But this doesn't get you rid of numeric overflow
but
Hi:
Using df as your data frame,
max(subset(df, condition == 'GPR119a', select = responce))
[1] 0.6451204
You asked this question yesterday with several correct responses. What was
wrong with them?
Dennis
On Wed, Feb 2, 2011 at 12:48 AM, Asan Ramzan asanram...@yahoo.com wrote:
Hello
I am
Hi Anyi,
That's not currently possible. You could use the rollmean function in
the development version of the zoo package (on R-forge) to calculate
the simple moving average as you described.
I would like to add this as an option to TTR functions, but it is not
high on my priority list. I
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
On Behalf Of Bryan Hanson
Sent: Wednesday, February 02, 2011 5:23 AM
To: Petr Savicky
Cc: r-help@r-project.org
Subject: Re: [R] Function to locate points in 3d octants or points on
twoaxes
What's farima? functional arima or fractional arima? If the former,
the fda package includes a function cor.fd for correlation matrix
from functional data object(s). If the latter, I suggest you use sos
as follows:
library(sos)
(fr - findFn('fractional arima'))
findFn searches a
Thanks Dan for pointing that out. My question really arose from the
need to draw splines between arbitrary 3d pairs of points, so I posted
a new question to the list addressing that more specifically. While
the issue of 3d splines must have been dealt with in graphics/
animation oriented
To solve it, a little more data would help. At least provide exactly
the statements you are using and an 'str' of the objects; e.g.,
str(matrix2)
str(condition2)
error message might indicate that the length of condition2 is larger
than the subset of matrix2 that you want.
On Wed, Feb 2, 2011
Hi,
On Wed, Feb 2, 2011 at 8:30 AM, alcesgabbo alcesga...@hotmail.com wrote:
I have a matrix with a lot of values inside..
when I execute the folowing command
matrix2=subset(martix, condition.)
it works...
but after the previous command I execute another subset
On Feb 2, 2011, at 10:26 AM, Sebastián Daza wrote:
Hi everyone,
Does anyone know how to get black and white theme (grey scale,, I
would say) graphs using lattice or ggplot2, as it is shown in this
webpage: http://lmdvr.r-forge.r-project.org/figures/figures.html?
I am using Sweave, and I
Hi all,
I have commited a new release of my package and waited for more than
one day. After that
install.packages(tests,repos=http://r-forge.r-projet.org;) still
returns package 'tests' is not available. I have done the local
build check and the package seems ok. Also have mofified the Title
in
Thanks for the reply.
When I run this:
head(SvmPred)
3570 2361 5406 2041 3440 4123
NNYYYY
Levels: N Y
--
View this message in context:
http://r.789695.n4.nabble.com/SVM-Prediction-and-Plot-tp3254421p3254570.html
Sent from the R help mailing list archive at
I have a data set covering a large number of cities with values for
characteristics such as land area, population, and employment. The problem I
have is that some cities lack observations for some of the characteristics and
I'd like a quick way to determine which cities have missing data. For
Hello to R people
Does anybody know to calculate exact logistic regression in R?
Does such option exist anywhere?
Surprisingly, could not find it using search engine. It is hard to
believe, however, that such useful function is not implemented in R yet?
Could you help, please
Thank you
Denis
I'm wondering about the behavior of the merge function when using factors as by
variables. I know that when you combine two factors using c() the results can
be odd, as in:
c(factor(1:5),factor(6:10))
which prints: [1] 1 2 3 4 5 1 2 3 4 5
I presume this is because factors are actually stored
Hi,
I have several data sets which are all approximately within the same values
as each other (both X and Y) and all of these data sets more or less overlap
each other when plotted on the same graph. However, although each data set
varies between approximately the same range, there are vastly
On Feb 2, 2011, at 12:28 PM, Bryan Hanson wrote:
Thanks Dan for pointing that out. My question really arose from the
need to draw splines between arbitrary 3d pairs of points, so I
posted a new question to the list addressing that more
specifically. While the issue of 3d splines must
H Roark wrote:
I'm wondering about the behavior of the merge function when using factors as by
variables. I know that when you combine two factors using c() the results can
be odd, as in:
c(factor(1:5),factor(6:10))
which prints: [1] 1 2 3 4 5 1 2 3 4 5
I presume this is because factors
H Roark wrote:
I have a data set covering a large number of cities with values for
characteristics such as land area, population, and employment. The problem I
have is that some cities lack observations for some of the characteristics and
I'd like a quick way to determine which cities have
Hi,
On Wed, Feb 2, 2011 at 10:35 AM, Brian ctto...@hotmail.com wrote:
Thanks for the reply.
When I run this:
head(SvmPred)
3570 2361 5406 2041 3440 4123
N N Y Y Y Y
Levels: N Y
Hmmm ... I think we'll need more info.
It looks like it should be working. By your output,
Try this:
subset(as.data.frame(xtabs( ~ city + var, df)), !Freq)
On Wed, Feb 2, 2011 at 1:49 PM, H Roark hrbuil...@hotmail.com wrote:
I have a data set covering a large number of cities with values for
characteristics such as land area, population, and employment. The problem I
have is
On 2011-02-02 08:44, mattnixon wrote:
Hi,
I have several data sets which are all approximately within the same values
as each other (both X and Y) and all of these data sets more or less overlap
each other when plotted on the same graph. However, although each data set
varies between
Hello, thank you all for your patience and time
I am essentially trying to get disorganised data into long form for linear
modelling.
I have 2 dataframes rec and book
Each row in book needs to be pasted onto the end of several of the rows of
rec according to two variables in the row: MRN and
It is not clear from your message whether these data represent
functions or such. Could you perhaps bring up an example?
I'm guessing each data set contains evaluation points and function
values at those points, and that you would like to plot these
functions and the mean function all on the same
Hard to know exactly without seeing the structrure of rec and book,
but I would start with ?merge
Best,
Ista
On Wed, Feb 2, 2011 at 2:06 PM, dunner ross.du...@tcd.ie wrote:
Hello, thank you all for your patience and time
I am essentially trying to get disorganised data into long form for
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