On Sun, 3 Apr 2011, Jeroen Ooms wrote:
Is there a way in R (in Linux) to detect the type of a file without invoking
a shell? E.g to do this:
system(file density.plot)
density.plot: PDF document, version 1.4
but without using system()? I tried file() and file.info(), but both do
display the
Hello I read on the Rmetrics webpage that all the development packages could
be intalled using the following command
source(RmetricsTools.R)
install.RmetricsDev([Rmetrics package to be installed]
I would like to know where I could get this RmetricsTools.R . I suppose it
might be somewhere
jose romero-3 wrote:
For one thing, i am using google docs to host the R object file and google
docs has secure https URL's, which apparently cannot be handled by R's
url(). So my questions are these:
Try ?getURL in the RCurl package
Dieter
--
View this message in context:
Hi,
I'm new to R and trying to some simple analysis. I have a data set with
about 88000 transactions and i want to perform a simple support count
analysis of an itemset which is say not a complete transaction but a subset
of a transaction.
say
{A,B,D} is a transaction and i want to find
On 04/03/2011 09:38 PM, jouba wrote:
Daer all, I have a question concerning longitudinal data: When we
have a longitudinal data and we have to do sem analysis there is in
the package lavaan some functions,options in this package that help
to do this or we can treat these data like non
Hello
I have a model with several hundred Y variables, and also several 1000 X
variables. The model is linear lm(Y ~ X). My questions are:
1.- how to avoid writing all Xs variables? is list() the right function?
2.- about the multiple Ys with dependence among some of them, how to
incorporate
Dear All,
Thank you to all of you for your fast reply. I will run the test and
subscribe to the R-sig-db list.
Cheers,
Henri
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
LFP == Luis Felipe Parra felipe.pa...@quantil.com.co
on Mon, 4 Apr 2011 14:32:32 +0800 writes:
LFP Hello I read on the Rmetrics webpage that all the
LFP development packages could be intalled using the
LFP following command
LFP source(RmetricsTools.R)
LFP
On 04/03/2011 10:02 PM, shahab wrote:
Hi,
I am using color2D.matplot (...) function of plotrix package. I used
a matrix of size around 20*20
However, apparently it failed to visualize the matrix and gave the
following exception, which I don't have any idea about possible source
of this error.
Dear list,
I searched the libraries but could not find means to compute the
svd of a coupled field. Is it possible in R
Thanks
nuncio
--
Nuncio.M
Research Scientist
National Center for Antarctic and Ocean research
Head land Sada
Vasco da Gamma
Goa-403804
[[alternative HTML
On Apr 4, 2011, at 01:10 , Timothy Spier wrote:
I've been searching for an answer to this for a while but no joy. I have a
simple 2-way ANOVA with an interaction. I'd like to determine the power of
this test for each factor (factor A, factor B, and the A*B interaction). How
can I do
Thanks juan, I got that, but what I have two matrices A and B, How can an
svd be performed on the two together. Is it correct to get the covariance
matrix and then perform the svd on the covariance matrix. If that is the
case I have another doubt. I understand the covariance of A and B is
Hello,
You can do that like in the example included in the function step()
lm1 - lm(Fertility ~ ., data = swiss)
But my advise is that prior to doing that, you should check this old
thread in this list:
http://tolstoy.newcastle.edu.au/R/e4/help/08/02/2842.html
Regards,
Carlos Ortega
On Mon, Apr 04, 2011 at 01:11:37AM -0500, psombe wrote:
Hi,
I'm new to R and trying to some simple analysis. I have a data set with
about 88000 transactions and i want to perform a simple support count
analysis of an itemset which is say not a complete transaction but a subset
of a
Hi all
Just as Pierre pointed out, i used rgeos instead of gpclib (the licence is
less restrictive even though i'm still students). A since the last release
the rgeos package seems to work well.
I'm really disapointed by the fact that some packages (e.g adehabitatMA
which is great thank's M.
Dear list,
Hi,
I am trying to get the second derivative of a logistic formula, in R summary
the model is given as :
###
$nls
Nonlinear regression model
model: data ~ logistic(time, A, mu, lambda, addpar)
data: parent.frame()
A mu lambda
0.53243 0.03741 6.94296
###
but I know
Dear R users,
I need to add 0 in front of a series of numbers, e.g. 1-001, 19-019,
Is there a fast way of doing that?
Many thanks
yan
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
Have a look at
?formatC
On Mon, Apr 4, 2011 at 11:35 AM, Yan Jiao y.j...@ucl.ac.uk wrote:
Dear R users,
I need to add 0 in front of a series of numbers, e.g. 1-001, 19-019,
Is there a fast way of doing that?
Many thanks
yan
[[alternative HTML version deleted]]
On Fri, 2011-04-01 at 11:52 +0530, nuncio m wrote:
HI all,
I am trying to compute the EOF of a matrix using prcomp but unable to get
the expansion co-efficients.
is it possible using prcomp or are there any other methods
thanks
nuncio
*sigh*
RSiteSearch(EOF)
It is at times like this
Dear Ben,
you answerd to Nancy Shackelford about Clarks 2Dt function.
Since the thread ended just after your reply,
I would like to ask, if you have an idea how to use this function in R
I defined it the following way:
function(x , p, u) {
(p/(pi*u))*(1+(x^2/u))^(p+1)
}
and would like to fit
Dear Sir/Madam,
I am stuck with a nagging problem in using R for SVM regression. My data has 5
dimensions and 400 observations. The independent variables are :
Peb, Ksub, Sub, and Xtt.
The dependent variable is: Rexp.
I tried using the svm.tune function to tune the hyper parameters: gamma,
Dear Sir,
I am stuck with a nagging problem in using R for SVM regression. My data has 5
dimensions and 400 observations. The independent variables are :
Peb, Ksub, Sub, and Xtt.
The dependent variable is: Rexp.
I tried using the svm.tune function as well as _tune(svm.), to tune the
hyper
Hello,
I am having a problem to control ticklabs in scatterplot3d. When I am using
it for small data then it is working fine. But with my big data all the
labels are misplaced (one upon another).
For example see the code below (I have just modified the scatterplot3d
example to show my problem ).
Dear Yan,
apart from formatC, you can also use sprintf, which works almost
exactly like the C sprintf function. To convert an integer x to a
string with 5 leading 0s, you do:
sprintf( %05d, x )
Best regards,
j.
On Mon, Apr 4, 2011 at 12:35 PM, Yan Jiao y.j...@ucl.ac.uk wrote:
Dear R users,
Dear expeRts,
I recently asked for a real centered title (see, e.g.,
http://tolstoy.newcastle.edu.au/R/e13/help/11/01/0135.html).
A nice solution (from Deepayan Sarkar) is to use xlab.top instead of main:
library(lattice)
trellis.device(pdf)
print(xyplot(0 ~ 0, xlab.top = This title is now
Hi all,
I have a local server insalled on my system and have to start that from
within my R function.
here is how I start it:
cmd-sh start-server.sh
system(cmd, wait=FALSE)
My function has to start the server and proceed with further steps. The
server starts but the further steps of the
Thank you Ahmadou,
I got an error when I change fill to colour:
p + geom_point(aes(size = ACE, colour = ACE)) + theme_bw() +
+ scale_size(to = c(3, 15), name = Número de especies, breaks = c(10,
40, 70, 100, 130, 160, 190, 220, 250)) +
+ scale_colour_gradientn(name = 'Número de especies',
Hello
Lets say as an example I have a dataframe with the following attributes:
rownum(1:405), colnum(1:287), year(2000:2009), daily(rownum x colnum x year)
and foragePotential (0:1, by 0.01). The data is actually stored in a netcdf
file and I'm trying to provide a conceptual version of the
I appreciate that this is OT, but I'd be grateful for pointers to examples of
where
Sweave has been used for web-based applications. In particular, examples of
where reports/analyses are produced automatically through submission of data
to a web-sever. I am mostly interested in situations
Hi R helpers... I am having troubles because of the discrepancy
between the dendrogram plotted from hclust and what is wrote in the
hc2Newick file. I've got a matrix C:
hc - hclust(dist(C))
plot(hc)
with the:
write(hc2Newick(hc),file='test.newick')
both things draw completely different
and time to upgrade R
I'm still fighting to find out how to upgrade stuff on Ubuntu. After
a
repository update the newest available version was still 2.10.1.
I'll figure it out, sooner or later :)
That's simple. Just add
$deb http://my.favorite.cran.mirror/bin/linux/ubuntu
On Mon, Apr 4, 2011 at 8:30 AM, Steve Friedman skfgla...@gmail.com wrote:
Hello
Lets say as an example I have a dataframe with the following attributes:
rownum(1:405), colnum(1:287), year(2000:2009), daily(rownum x colnum x year)
and foragePotential (0:1, by 0.01). The data is actually
On Sun, Apr 3, 2011 at 8:29 PM, Cleber N. Borges kle...@yahoo.com.brwrote:
hello all
I am trying to learn how to use the RGtk2 package...
so, my first problem is: I don't get the right way for populate my
gtkListStore object!
any help is welcome... because I am trying several day to mount
I've written about a bunch of Web R interfaces here:
*
http://www.r-statistics.com/2010/04/jeroen-oomss-ggplot2-web-interface-a-new-version-released-v0-2/
*
http://www.r-statistics.com/2010/04/r-node-a-web-front-end-to-r-with-protovis/
(And some other posts here:
I retrieve for a few hundred times a group of time series (10-15 ts
with 1 values each), on every group I do some calculation, graphs
etc. I wonder if there is a faster method than what presented below to
get an appropriate timeseries object.
Making a query with RODBC for every group I get a
Hi R-experts
I have many text files to read and combined them into one into R that are
output from other programs. My textfile have unbalanced number of rows for
example:
;this is example
; r help
Var1 Var2 Var3 Var4 Var5
0 0.05 0.0112
1
I am trying to make a barplot with a broken axis using gap.barplot (in the
indispensable plotrix package). This works well when the data is a vector:
twogrp-c(rnorm(10)+4,rnorm(10)+20)
gap.barplot(twogrp,gap=c(8,16),xlab=Index,ytics=c(3,6,17,20),ylab=Group
values,main=Barplot with gap)
But
?read.table
Then look at the 'fill' 'flush' parameters; this may do the trick
On Mon, Apr 4, 2011 at 9:32 AM, Ram H. Sharma sharma.ra...@gmail.com wrote:
Hi R-experts
I have many text files to read and combined them into one into R that are
output from other programs. My textfile have
Hello,
I am trying to find out if R can do the following:
I have a mixture of normals say f = 0.2*Normal(2, 5) + 0.8*Normal(3,2)
How do I find the difference in the densities at any particular point of f
and at Normal(2,5)?
--
Thanks,
Jim.
[[alternative HTML version deleted]]
try this:
x - read.table(textConnection(;this is example
+ ; r help
+ Var1 Var2 Var3 Var4 Var5
+ 0 0.05 0.0112
+ 1 0.04 0.0618A
+ 2 0.05 0.0814
+ 3 0.01 0.0615 B
+ 4
Hi Dan,
On Mon, Apr 4, 2011 at 7:49 AM, Den Alpin den.al...@gmail.com wrote:
I retrieve for a few hundred times a group of time series (10-15 ts
with 1 values each), on every group I do some calculation, graphs
etc. I wonder if there is a faster method than what presented below to
get an
On Mon, Apr 4, 2011 at 8:49 AM, Den Alpin den.al...@gmail.com wrote:
I retrieve for a few hundred times a group of time series (10-15 ts
with 1 values each), on every group I do some calculation, graphs
etc. I wonder if there is a faster method than what presented below to
get an
Is something like this what you're looking for?
R library(nor1mix)
R nmix2 - norMix(c(2, 3), sig2=c(25, 4), w=c(.2, .8))
R dnorMix(1, nmix2) - dnorm(1, 2, 5)
[1] 0.03422146
Andy
-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of
Hi,
On Mon, Apr 4, 2011 at 5:15 AM, Sadaf Zaidi s.zaidi...@amu.ac.in wrote:
Dear Sir/Madam,
I am stuck with a nagging problem in using R for SVM regression. My data has 5
dimensions and 400 observations. The independent variables are :
Peb, Ksub, Sub, and Xtt.
The dependent variable is:
On 2011-04-04 06:39, Andrew D. Steen wrote:
I am trying to make a barplot with a broken axis using gap.barplot (in the
indispensable plotrix package). This works well when the data is a vector:
twogrp-c(rnorm(10)+4,rnorm(10)+20)
Hi I have very simple issue as I am still new to the group of R
I have basically
vector of names for which i want to create mutliple combinations and then
place them in different vectors. In some other language I can just place a
third dimension to separate list (or matrix) but i do not know
bialozyt at biologie.uni-marburg.de writes:
Dear Ben,
you answerd to Nancy Shackelford about Clarks 2Dt function.
Since the thread ended just after your reply,
I would like to ask, if you have an idea how to use this function in R
Dear Ronald,
I got started on your problem, but I
Try this:
lapply(2:3, FUN = combn, x = string, paste, collapse = '')
On Mon, Apr 4, 2011 at 11:24 AM, michalseneca michalsen...@gmail.com wrote:
Hi I have very simple issue as I am still new to the group of R
I have basically
vector of names for which i want to create mutliple combinations
On Apr 4, 2011, at 7:39 AM, Marius Hofert wrote:
Dear expeRts,
I recently asked for a real centered title (see, e.g., http://tolstoy.newcastle.edu.au/R/e13/help/11/01/0135.html)
.
A nice solution (from Deepayan Sarkar) is to use xlab.top instead
of main:
library(lattice)
Hello,
Using the dse package I have estimated a VAR model using estVARXls().
I can perform forecasts using forecast() with no problems, but when I
try to use simulate() with the same model, I get the following error:
Error in diag(Cov, p) :
'nrow' or 'ncol' cannot be specified when 'x' is a
Hi Paul,
I am using R v. 2.12.2, and the dse package with build 2.12.2.
I have attached some sample data to this email, and the R code I use
to create the model and then forecast with it.
Thanks,
Alison
On Mon, Apr 4, 2011 at 11:02 AM, Paul Gilbert
pgilb...@bank-banque-canada.ca wrote:
Could
I did some tests on Your and Gabor solutions, below my findings:
- Your solution is fast as my solution in xts (below) but MUCH MORE
READABLE, in particular I think your test should take into account xts
creation from the data.frame (see below);
- Gabor's solution with read.zoo is fast as xts but
On Apr 4, 2011, at 6:35 AM, kitty wrote:
Dear list,
Hi,
I am trying to get the second derivative of a logistic formula, in R
summary
the model is given as :
###
$nls
Nonlinear regression model
model: data ~ logistic(time, A, mu, lambda, addpar)
data: parent.frame()
A mu lambda
Juraj17 wrote:
Do I have to write my own, or it exists yet? How name has it, or how can I
use it.
Try the R-function search. It return the function you are looking for as the
first match.
Dieter
--
View this message in context:
On Mon, Apr 4, 2011 at 11:20 AM, Den Alpin den.al...@gmail.com wrote:
I did some tests on Your and Gabor solutions, below my findings:
- Your solution is fast as my solution in xts (below) but MUCH MORE
READABLE, in particular I think your test should take into account xts
creation from the
Bert Jacobs-2 wrote:
I would like to replace the last tree characters of the values of a
certain
column in a dataframe.
Besides the mentioned standard method: I found the subset of string
operations in Hadley Wickhams stringr package helpful. They have a much more
consistent interface
True - gapped stacked bar plots make no sense at all. I'm working my way up
to a gapped bar plot with series next to each other (and error bars!), what
you'd get if you put a gap in the y-axis of
twogrp2-array(twogrp, dim=c(2,5))
barplot(twogrp2, beside=TRUE)
I'm guessing I can do this if I
Hi R Group
Thanks for some suggestions.
I have finally figured it out..
The following script called from within R Session does what i want..(to
attach files called test1.pdf and Document-1.pdf into the file test2.pdf and
then save the new file with attachments as test3.pdf at the given path)
Dear R community members
I did find a good way to merge my 200 text data files in to a single data
file with one column added will show indicator for that file.
filelist = list.files(pattern = K*cd.txt) # the file names are K1cd.txt
.to K200cd.txt
data_list
Dear all,
I have an n x n matrix of p-values. The matrix is symmetrical, as it
describes the each against each p values of correlation
coefficients.
How can I best correct the p values of the matrix? Notably, the total
number of the tests performed is n(n-1)/2, since I do not test the
Hi
Thanks ,however I would need something different still...
I would need to return a vector so if as to choose
cc[[3]] [2] would return vector/list as in terms of c(b,d,e)
Thanks
--
View this message in context:
Hi all,
I would like to multithread that script, to detect structure from multilocus
genetic data :
library(Geneland)
geno = read.table(cot966gen_test.txt) #the file is show after
MCMC(geno.dip.codom = geno, varnpop=T, npopmax=20, spatial = F, nit=10,
thinnin=100, path.mcmc=./)
1. This is not an R question, AFAICS.
2. Sounds like a research topic. I don't think there's a meaningful
simple answer. I suspect it strongly depends on the model and context.
-- Bert
On Mon, Apr 4, 2011 at 8:02 AM, January Weiner
january.wei...@mpiib-berlin.mpg.de wrote:
Dear all,
I have
You can use simulation:
1. decide what you think your data will look like
2. decide how you plan to analyze your data
3. write a function that simulates a dataset (common arguments include sample
size(s) and effect sizes) then analyzes the data in your planned manner and
returns the p-value(s)
On Apr 4, 2011, at 17:02 , January Weiner wrote:
Dear all,
I have an n x n matrix of p-values. The matrix is symmetrical, as it
describes the each against each p values of correlation
coefficients.
How can I best correct the p values of the matrix? Notably, the total
number of the
There are also the multcomp and multcompView packages that might
provide something of interest in this regard. multcomp has a
companion book, Multiple Comparisons Using R (Bretz, Hothorn,
Westfall, 2010, CRC Press), which I believe provides an excellent
overview of the state of the art
On 04.04.2011 12:35, Yan Jiao wrote:
Dear R users,
I need to add 0 in front of a series of numbers, e.g. 1-001, 19-019,
Is there a fast way of doing that?
formatC(c(1, 19), flag=0, width=3)
Uwe Ligges
Many thanks
yan
[[alternative HTML version deleted]]
How about
as.matrix(p.adjust(as.dist(pmat)))
Benno
On 4.Apr.2011, at 17:02, January Weiner wrote:
Dear all,
I have an n x n matrix of p-values. The matrix is symmetrical, as it
describes the each against each p values of correlation
coefficients.
How can I best correct the p
On 04.04.2011 16:41, Umesh Rosyara wrote:
Dear R community members
I did find a good way to merge my 200 text data files in to a single data
file with one column added will show indicator for that file.
filelist = list.files(pattern = K*cd.txt)
I doubt you meant K*cd.txt but
Hi Mauricio,
A Windows binary is now available on CRAN:
http://dirk.eddelbuettel.com/blog/2011/04/04/#rquantlib_0.3.7
Best,
--
Joshua Ulrich | FOSS Trading: www.fosstrading.com
On Tue, Mar 29, 2011 at 10:38 AM, Mauricio Romero
mauricio.rom...@quantil.com.co wrote:
Dear R users,
I have
Dear David,
I intended to use another x-label. But your suggestion brings me to the idea of
just using a two-line xlab, so s.th. like
print(xyplot(0 ~ 0, xlab.top = This title is now 'centered' for the human's
eye, xlab = but subtitles are _now_ centered\nbla, scales = list(alternating
=
Use exprs on the output from RMA (or another method you like)
library(affy)
myData -ReadAffy()
myRMA - rma(myData)
e = exprs(myRMA)
Also, check out the Bioconductor mailing list where
Bioconductor-related topics are discussed.
On Fri, Apr 1, 2011 at 9:54 AM, Landes, Ezekiel
Hi,
i am new in this forum.
I hope someone can help me or correct me, if this is the false subforum to
write this.
I have to choose the best arima model from different possibilities of a
timeseries. I know the AIC; BIC and similar. But now i would like to check
the value called r-squared or
There are, however, the multcomp and multcompView packages that
might provide something of interest in this regard. multcomp has a
companion book, Multiple Comparisons Using R (Bretz, Hothorn,
Westfall, 2010, CRC Press), which I believe provides an excellent
overview of the state of
Dear Uwe and R community members
Thank you Uwe for the help.
I have still a question remaining, I am trying to find answer from long
time.
While exporting my data, I have some characters mixed into it. I want to
define any characters as na.string? Is it possible to do so?
Thanks;
Umesh
On Apr 4, 2011, at 12:45 PM, Marius Hofert wrote:
Dear David,
I intended to use another x-label. But your suggestion brings me to
the idea of just using a two-line xlab, so s.th. like
print(xyplot(0 ~ 0, xlab.top = This title is now 'centered' for the
human's eye, xlab = but subtitles are
Hello!
I have my data frame mydata (below) and data frame reference -
that contains all the dates I would like to be present in the final
data frame.
I am trying to merge them so that the the result data frame contains
all 8 dates in both subgroups (i.e., Group1 should have 8 rows and
Group2 too).
On Apr 4, 2011, at 12:37 PM, Umesh Rosyara wrote:
Dear Uwe and R community members
Thank you Uwe for the help.
I have still a question remaining, I am trying to find answer from
long
time.
While exporting my data, I have some characters mixed into it. I
want to
define any characters
To clarify just in case, here is the result I am trying to get:
mydate group values
12/29/2008 Group1 0.453466522
1/5/2009Group1 NA
1/12/2009 Group1 0.416548943
1/19/2009 Group1 2.066275155
1/26/2009 Group1 2.037729638
2/2/2009Group1 -0.598040483
Dear David,
do you know how to get plotmath-like symbols in both rows?
I tried s.th. like:
lab - expression(paste(alpha==1, , , beta==2, sep=))
xlab - substitute(expression( atop(lab==lab., bold(foo)) ), list(lab.=lab))
xyplot(0 ~ 0, xlab = xlab)
Cheers,
Marius
On 2011-04-04, at 18:59 , David
On Apr 4, 2011, at 1:27 PM, Marius Hofert wrote:
Dear David,
do you know how to get plotmath-like symbols in both rows?
I tried s.th. like:
lab - expression(paste(alpha==1, , , beta==2, sep=))
xlab - substitute(expression( atop(lab==lab., bold(foo)) ),
list(lab.=lab))
xyplot(0 ~ 0, xlab =
On 2011-04-04 10:27, Marius Hofert wrote:
Dear David,
do you know how to get plotmath-like symbols in both rows?
I tried s.th. like:
lab- expression(paste(alpha==1, , , beta==2, sep=))
xlab- substitute(expression( atop(lab==lab., bold(foo)) ), list(lab.=lab))
xyplot(0 ~ 0, xlab = xlab)
Maybe:
xyplot(0 ~ 0, xlab =
bquote(expression(atop(alpha==.(x)*,~beta==.(y), bold(foo) )) ))
On Mon, Apr 4, 2011 at 2:58 PM, David Winsemius dwinsem...@comcast.net wrote:
On Apr 4, 2011, at 1:27 PM, Marius Hofert wrote:
Dear David,
do you know how to get plotmath-like symbols in both rows?
Dear Community,
I am new to R and have a question concerning the causality () test in
the vars package. I need to test whether, say, the variable y Granger
causes the variable x, given z as a control variable.
I estimated the VAR model as follows: model-VAR(cbind(x,y,z),p=2)
Then I did the
Dear all,
many thanks, that helped a lot!
Cheers,
Marius
On 2011-04-04, at 19:58 , David Winsemius wrote:
On Apr 4, 2011, at 1:27 PM, Marius Hofert wrote:
Dear David,
do you know how to get plotmath-like symbols in both rows?
I tried s.th. like:
lab - expression(paste(alpha==1, ,
Dear All,
I have a large data frame with 10 rows and 82 columns. I want to apply the
same function to all of the columns with a single command. e.g. zl - lm
(snp$a_109909 ~ snp$lat) will fit a linear model to the values in lat and
a_109909. What I want to do is fit linear models for the values
Thanks you for your response
For lavaan package can i have more information about this example you have
applied in the section 7
the meanings of The variables (c1,c2,c3,c4, i ,s ,x1,x2)
I think i have need more information to learn more about how able to apply
growth model in my data
On Mon, Apr 4, 2011 at 1:09 PM, Dimitri Liakhovitski
dimitri.liakhovit...@gmail.com wrote:
Hello!
I have my data frame mydata (below) and data frame reference -
that contains all the dates I would like to be present in the final
data frame.
I am trying to merge them so that the the result
Try this:
merge(mydata, cbind(reference, group = rep(unique(mydata$group), each
= nrow(reference))), all = TRUE)
On Mon, Apr 4, 2011 at 2:24 PM, Dimitri Liakhovitski
dimitri.liakhovit...@gmail.com wrote:
To clarify just in case, here is the result I am trying to get:
mydate group values
Hi:
Here's an alternative using ldply() from the plyr package. The idea is to
read the data frames into a list, name them accordingly and then call
ldply().
# Read in the test data frames (you want to use list.files() instead to
input the data per Uwe's guidelines)
df1 -
Hi:
Here's a small example:
df - data.frame(y1 = rnorm(10), y2 = rnorm(10), y3 = rnorm(10), lat =
rnorm(10))
m - lm(cbind(y1, y2, y3) ~ lat, data = df)
summary(m)
snip...provides summaries for each response
The LHS of the model formula needs to be a matrix. In your case, something
like
m -
On Mon, Apr 4, 2011 at 3:40 PM, Mark Novak mnov...@ucsc.edu wrote:
Thank you very much Gabor! It looks like that's gonna work wonderfully. I
didn't even know 'ave' existed.
For others out there: I only needed to add a comma: dat[,c(Site,
Plot, Sp)]
Actually, if dd is a data frame dd[,
-Original Message-
From: stephen sefick [mailto:ssef...@gmail.com]
Sent: April-03-11 5:35 PM
To: Steven McKinney
Cc: R help
Subject: Re: [R] Linear Model with curve fitting parameter?
Steven:
You are exactly right sorry I was confused.
Thank you very much Gabor! It looks like that's gonna work
wonderfully. I didn't even know 'ave' existed.
For others out there: I only needed to add a comma: dat[,c(Site,
Plot, Sp)]
Small follow up Q: Is there any reason to use 'aggregate' vs. 'ave' in
general?
-mark
On 4/3/11
Is there a generic binary search routine in a standard library which
a) works for character vectors
b) runs in O(log(N)) time?
I'm aware of findInterval(x,vec), but it is restricted to numeric vectors.
I'm also aware of various hashing solutions (e.g. new.env(hash=TRUE) and
fastmatch),
Thank you Dennis for the solution. It is a step ahead..However I need to
read all 200 files as dataframes one-by-one. Can we automate this process.
I used the following step to read all file at once however the data_list
ended as list.
filelist = list.files(pattern = K*cd.txt) # the file
Thanks!
I must confess I am just a beginner, but I followed your suggestion and did
'm - lm(as.matrix(snp[, -1]) ~ lat, data = snp) ' and it worked perfectly.
I would like to understand what is being done here. as.matrix I understand
makes my data frame be a matrix, but I don't understand the
-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of Stavros Macrakis
Sent: Monday, April 04, 2011 1:15 PM
To: r-help
Subject: [R] General binary search?
Is there a generic binary search routine in a standard library which
Thanks, I had recently seen reference to caTools but had forgotten about it.
Much appreciated.
friedman.st...@gmail.com
517-648-6290
-Original message-
From: Gabor Grothendieck ggrothendi...@gmail.com
To: Steve Friedman skfgla...@gmail.com
Cc: r-help@r-project.org
Sent: Mon, Apr 4,
This has to do with using pipe() and grep and read.csv()
I have a .csv file that I grep using pipe() and read.csv() as follows:
read.csv(pipe('grep foo bar.csv'))
However, is there a way to have this command run when for example,
there is no foo text in the bar.csv file? I get an error message
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