On Feb 17, 2015, at 3:58 AM, Knut Hansen wrote:
Dear list,
I have a vector:
my.vector - c(A, B, C, D, E, F, G)
and two other:
vec1 - c(p, q, r, s, t)
vec2 - c(x, y, z)
I want to substitute elements b and e in my.vector with vectors vec1 and
vec2 respectively so that the result
Hi,
Here is an implementation.
my.vector
[1] A B C D E F G
vec1
[1] p q r s t
vec2
[1] x y z
final - as.character(unlist(sapply(my.vector,function(x)
if(x==B){vec1}else{if(x==E){vec2}else{x}})))
final
[1] A p q r s t C D x y z F G
--
View this message in context:
Hi,
It appears that you used left double quotation marks and right double
quotation marks in your vector for characters. The first lst assignment is
copied from your post and indicates issues. I retyped with doulbe quotation
mark and went through fine with the second lst assignment. Unicode
On Feb 17, 2015, at 10:46 AM, Joule Madinga jmadi...@yahoo.fr wrote:
Hi,I'm new to R.I would like to make a barplot of parasite infection
prevalence (with 95% confidence interval) by age group.I have 4 parasite
species and 5 age-groups and the example by Marc Schwartz (barplot2) fits
very
Pam,
Please let me know what you discover. I just started looking at a similar
problem. I understand
that a Kalman filter can sometimes be applied to this problem,
but at this time I don't know how to accomplish this.
John
John David Sorkin M.D., Ph.D.
Professor of Medicine
Chief,
Has somebody implemented Bayesian Networks in R ?
--
Best regards... 8^)
“*A mente que se abre a novas ideias jamais voltará *
*a seu tamanho original*” *Albert Einstein*
_
Prof. Elias César Araújo de Carvalho
CV:
On 02/17/2015 02:10 PM, Erich Neuwirth wrote:
AFAIK dplyr imports magrtittr.
So dplyr ses %% from migrittr, it does not have its own version.
But it has its own man page so who knows?
H.
On Feb 17, 2015, at 22:19, Ben Bolker bbol...@gmail.com wrote:
David Barron dnbarron at gmail.com
I have a list object in R with dataframe names as:
pav_DJF_histo.csvpav_DJF_rcp26_2040s.csv
pav_DJF_rcp26_2080s.csv
pav_DJF_rcp45_2040s.csvpav_DJF_rcp45_2080s.csv
pav_DJF_rcp85_2040s.csv pav_DJF_rcp85_2080s.csv
pav_JJA_histo.csv
pav_JJA_rcp26_2040s.csv pav_JJA_rcp26_2080s.csv
I am trying to generalize a working piece of code for a single parameter to a
multiple parameter problem. Reproducible code is below. The parameters to be
estimated are a, b, and c. The estimation problem is such that there is one set
of a, b, c parameters for each column of the data. Hence, in
On Tue, Feb 17, 2015 at 6:02 PM, Hervé Pagès hpa...@fredhutch.org wrote:
On 02/17/2015 02:10 PM, Erich Neuwirth wrote:
AFAIK dplyr imports magrtittr.
So dplyr ses %% from migrittr, it does not have its own version.
But it has its own man page so who knows?
If you import and re-export a
Hi,
Here I use the data.frame b as an example to show how it can be
accomplished. The sixth column of b has values 6 through 996 by an
increment of 10. The statement
sapply(b[,6],function(x)if(x==6){0}else{if(x==996){2}else{1}}) assigns 0 to
6, 2 to 996 and 1 to the rest in column 6. In your
Hi list,
I am running the following R code, the answer should be zero. But R gives
a very small negative number, what should I do?
##R code
library(numDeriv)
h_x - function(x){
a = x[1]
b = x[2]
c = x[3]
d = x[4]
(a^2 + c^2 + d^2) * (b^2 + c^2 + d^2)
}
x1 = 10
x2 = 1
x3 = 0
x4
Tena koe Elias
Googling 'Bayesian Networks in R' brings up several packages, so the answer
appears to be 'Yes'. Whether any of them are relevant to you is another
question.
HTH
Peter Alspach
-Original Message-
From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of
Hi,
Just learned another way to calculate sd for a frequency distribution
matrix:
p - matrix(c(10,3,20,4,30,5),ncol=2,byrow=TRUE)
p
[,1] [,2]
[1,] 103
[2,] 204
[3,] 305
rep(p[,1],p[,2])
[1] 10 10 10 20 20 20 20 30 30 30 30 30
sd(rep(p[,1],p[,2]))
[1] 8.348471
--
On 18-02-2015, at 05:02, BRC brc@gmail.com wrote:
I am developing a r package faisalconjoint, when i run R CMD check
--as-cran faisalconjoint, got the following notes.
* using log directory
'D:/r-test-packages/faisalconjoint/faisalconjoint.Rcheck'
* using R version 3.1.2
On 02/17/2015 08:03 PM, Hadley Wickham wrote:
On Tue, Feb 17, 2015 at 6:02 PM, Hervé Pagès hpa...@fredhutch.org wrote:
On 02/17/2015 02:10 PM, Erich Neuwirth wrote:
AFAIK dplyr imports magrtittr.
So dplyr ses %% from migrittr, it does not have its own version.
But it has its own man page so
I am developing a r package faisalconjoint, when i run R CMD check
--as-cran faisalconjoint, got the following notes.
* using log directory
'D:/r-test-packages/faisalconjoint/faisalconjoint.Rcheck'
* using R version 3.1.2 (2014-10-31)
* using platform: i386-w64-mingw32 (32-bit)
* using session
I had never thought of violins. It might be interesting. However , I still
think there maybe some use out of the 4-panel approach.
What does your vioilin code look like?
Using Denis' code
gg- ggplot(dat1, aes(x = condition, y = t, color = gender, linetype =
direction)) +
In the course of slicing-and-dicing some data, I had occasion to create a list
like this:
list(
subset(my_dataframe, GR1==XX1),
subset(my_dataframe, GR1==XX2),
subset(my_dataframe, GR1==YY),
subset(my_dataframe, GR1 %in% c(XX1, XX2)),
subset(my_dataframe, GR2==Remission),
Comment inline
On 17/02/2015 12:40, Angela Smith wrote:
Hi R user,
I'm new to R so
my problem is probably pretty simple but I'm stuck:
my data is consist of 2 variables: co2, temp and one
treatment (l_group). The sample size is different among the treatments. so
that, I wanted to make
Dear list,
I have a vector:
my.vector - c(A, B, C, D, E, F, G)
and two other:
vec1 - c(p, q, r, s, t)
vec2 - c(x, y, z)
I want to substitute elements b and e in my.vector with vectors vec1 and
vec2 respectively so that the result becomes the vector:
c(A, p, q, r , s , t, C , D, x, y, z, F, G)
Hi R user,
I'm new to R so
my problem is probably pretty simple but I'm stuck:
my data is consist of 2 variables: co2, temp and one
treatment (l_group). The sample size is different among the treatments. so
that, I wanted to make equal sample size among three groups (A,B and C) of the
Hi all,
I am starting an image processing project. Through the project, I am going
to be needing tools/techniques such as SIFT, HOG,
bag-of-visual-words/features etc...
It seems than OpenCv has most of these features. I have found r-opencv here
https://www.openhub.net/p/r-opencv , but from this
Thank you David and Thierry, your answers helped a lot!
Kind regards,
RK.
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https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
Thanks for your comments. I hard disk meltdown has slowed me down somewhat,
but I am now back online.
I have reposted to the ME-list, and requested SAS output from my colleagues.
I will update the thread again as soon I know more.
Thanks,
Andreas
--
View this message in context:
Dear Constanze,
the error message gives you a hint, where the problem might be. The
first error massage says that you have NAs in your index variables
Unit and Week. You can check that with the is.na() function. The
second error message (r.squared) tells you to specify the model, that is
on
Hi,
I like the aggregate version. Here is an implementation with sapply and
apply:
data
X2 gbm_tcga lusc_tcga ucec_tcga_pub
1 gbm_tcga 1.0 0.14053719 -0.102847164
2 gbm_tcga 1.0 0.04413434 0.013568055
3 gbm_tcga 1.0
Inline.
-- Bert
Bert Gunter
Genentech Nonclinical Biostatistics
(650) 467-7374
Data is not information. Information is not knowledge. And knowledge
is certainly not wisdom.
Clifford Stoll
On Tue, Feb 17, 2015 at 1:33 AM, Chris Campbell
ccampb...@mango-solutions.com wrote:
# Assuming you
Hi,
I need help with a for loop and printing data. I want to loop through a
few years and print the data from each year stacked on top of each other.
For example,
for (i in 2000:2003){
#script for downloading each year
Data = readLines(sprintf('file/%4i,i))
}
It only prints out the data from
Hello,
Where can I find info about the operator %%?
Never used it but when I search for it I gives no result.
Thanks,
André
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PLEASE do
I am relatively new to R and I would appreciate some advice on how to include
both discrete and continuous predictor variables in a stepwise backward log
likelihood ration logistic regression. I have a model that includes 3
continuous predictor variables (soilmois, grasscov, and ranvar) and one
On Feb 17, 2015, at 6:51 AM, Javier Rodriguez Zaurin wrote:
Hi all,
I am starting an image processing project. Through the project, I am going
to be needing tools/techniques such as SIFT, HOG,
bag-of-visual-words/features etc...
It seems than OpenCv has most of these features. I have
On 17/02/2015 2:41 PM, André de Boer wrote:
Hello,
Where can I find info about the operator %%?
Never used it but when I search for it I gives no result.
That is a user-defined binary operator. You need to look in the sources
that used it to find how it was defined. (See section 10.2 of
It's in the magrittr package.
David
On 17 February 2015 at 19:41, André de Boer rnie...@gmail.com wrote:
Hello,
Where can I find info about the operator %%?
Never used it but when I search for it I gives no result.
Thanks,
André
__
Dear David and Michael,
Thank you so much for the code. It helped me to understand in making a loop and
perform the analysis. I am really obliged with your help.
cheers,
AS
=
From: dcarl...@tamu.edu
To: i...@aghmed.fsnet.co.uk; angela.smith2...@hotmail.com;
r-help@r-project.org
Hello, I am sure you have solved this problem, but I just experienced this
same problem. I was able to fix this by closing my current R session and
then reopening a new one. So, close your current R session and then open a
new one and then you should be able to cut,copy,paste, etc :)
I am running
The code is the same as the last one I showed, except I used geom_violin()
instead.
pp - ggplot(dat1, aes(x = condition, y = t, color = gender, linetype =
direction)) +
geom_violin() +
facet_wrap(~ location) +
scale_color_manual(values = c(blue, darkorange))+
theme_bw()+
Great! Thanks, Aravind.
On Monday, February 16, 2015 10:50 PM, Aravind Jayaraman
aravindjayaramana...@gmail.com wrote:
Hi,
I think you need not split the data.frame to get the desired result.
You can work with your list lst4 itself.
#Convert the vectors in the list to data.frames.
On 17/02/2015 11:19 AM, John Posner wrote:
In the course of slicing-and-dicing some data, I had occasion to create a list
like this:
list(
subset(my_dataframe, GR1==XX1),
subset(my_dataframe, GR1==XX2),
subset(my_dataframe, GR1==YY),
subset(my_dataframe, GR1 %in% c(XX1,
Expanding a bit on Michael's answer, you don't need the sampling package for
this, just the sample.int() function to draw a random set of integers that you
will use to extract rows from each of your groups. The write a function that
returns what you want, the regression slopes from each group
Great! many thanks, Chris and Bert.
On Tuesday, February 17, 2015 8:29 AM, Bert Gunter
gunter.ber...@gene.com wrote:
Inline.
-- Bert
Bert Gunter
Genentech Nonclinical Biostatistics
(650) 467-7374
Data is not information. Information is not knowledge. And knowledge
is certainly not
On 17-02-2015, at 12:58, Knut Hansen knut.han...@uit.no wrote:
Dear list,
I have a vector:
my.vector - c(A, B, C, D, E, F, G)
and two other:
vec1 - c(p, q, r, s, t)
vec2 - c(x, y, z)
I want to substitute elements b and e in my.vector with vectors vec1 and
vec2 respectively so
What is 'large'? have you tried 'View'?
Jim Holtman
Data Munger Guru
What is the problem that you are trying to solve?
Tell me what you want to do, not how you want to do it.
On Tue, Feb 17, 2015 at 4:52 AM, carol white via R-help
r-help@r-project.org wrote:
what is the best function to
Dear All
temp matrix describes correlated genes by disease. Can I include which
genes are common between diseases in chord diagram?
temp
X1 X2Disease1Disease2Disease3
1 Gene1 Disease1 1. -0.31428571 0.25714286
2 Gene2 Disease1 1. 0.42857143
Hi,I'm new to R.I would like to make a barplot of parasite infection prevalence
(with 95% confidence interval) by age group.I have 4 parasite species and 5
age-groups and the example by Marc Schwartz (barplot2) fits very well to my
data.However, I would like to plot my own 95%CI (as calculated
David Barron dnbarron at gmail.com writes:
It's in the magrittr package.
David
It also exists in dplyr.
(I would guess that it's imported/exported from magrittr.)
Although I think the documentation in magrittr is a little better.
__
Thanks JS
I think aggregate function is better.
Karim
Le 17 févr. 2015 08:33, JS Huang js.hu...@protective.com a écrit :
Hi,
I hope that someone can provide a better way to implement it. This is my
implementation.
data
X2 gbm_tcga lusc_tcga ucec_tcga_pub
1
Dear R users,
I want to announce an update of the package phia, version 0.2-0, now
on CRAN:
http://cran.r-project.org/web/packages/phia/
phia (Post-Hoc Interaction Analysis) is aimed at the analysis of the
expected values and other terms of in linear, generalized, and mixed
linear models, on the
AFAIK dplyr imports magrtittr.
So dplyr ses %% from migrittr, it does not have its own version.
On Feb 17, 2015, at 22:19, Ben Bolker bbol...@gmail.com wrote:
David Barron dnbarron at gmail.com writes:
It's in the magrittr package.
David
It also exists in dplyr.
(I would
Hello!
I have a longitudinal dataset of radiation exposures of an occupational
cohort. A percentage of the exposure values are missing and I would like to
multiply impute the missing values (it is one option of several we are
comparing). The data are recorded in long format (one row for each
Alexandra,
According to the documentation (?readLines), readLines returns a character
vector with one line from the file being read in each element of the vector.
You can put the character vector from each file (as represented by a year
designation in your example) in a separate list element.
Alexandra,
According to the documentation (?readLines), readLines returns a character
vector with one line from the file being read in each element of the vector.
You can put the character vector from each file (as represented by a year
designation in your example) in a separate list element.
Hello,
Try the following.
Data - lapply(sprintf('file/%4i', 2000:2003), readLines)
This will give you a list with 4 elements, each of which is the contents
of each file.
Hope this helps,
Rui Barradas
Em 17-02-2015 18:15, Alexandra Catena escreveu:
Hi,
I need help with a for loop and
# Assuming you want to create many data frames, you can use
# assign to create new objects.
newDFNames - unique(means$source)
newDFNames
# [1] iris1.csv iris2.csv
for (nm in newDFNames) {
assign(x
what is the best function to view large tables or data frames, scrolling
down-up, left-right?
Thanks
c.
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Hi,
I am using hash-values to cache certain results in R. This caching
also depends on the hash-value of the function that is being cached
(calculated using the digest package). I noticed that computations
that should already be cached are recomputed when switching from an
interactive session to
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