)
xyplot(y ~ time|ID, data = dat, type = 'l')
xyplot(y ~ time, data = dat, group = ID, type = 'l')
library(ggplot2)
qplot(time, y, data = dat, facets = .~ID, geom = 'line')
qplot(time, y, data = dat, group = ID, color = ID, geom = 'line')
hth,
Kingsford Jones
On Mon, Aug 23, 2010 at 1:58 PM, Lei
- aggregate(formula = y ~ time, data = dat, FUN = mean)
mean.y - cbind(ID = as.factor('mean'), mean.y)
dat - rbind(dat, mean.y)
dat
library(ggplot2)
qplot(time, y, data=dat, group = ID, color = ID, geom = c('point', 'line'))
best,
Kingsford Jones
__
R-help@r
= 'a' (shorthand for panel.average()) that can be
used to good effect in xyplot(), but it creates 'holes' where missing
data reside, so taking care of the problem externally at the data
level is much cleaner.
HTH,
Dennis
best,
Kingsford Jones
__
R
is now my favorite interface to R under Windows.
Yesterday I used the document comparison tool for the first time
(Tools Differences) ...very nice.
Kingsford Jones
On Fri, Jul 23, 2010 at 10:55 AM, Bert Gunter gunter.ber...@gene.com wrote:
Google on tinn-r tutorial. However, I believe that you
to make the desired within R's plotting device rather than in latex try:
par(mfrow = c(3, 2))
and you'll probably want to adjust other mar, parameters as well (e.g.
mar, cex.lab, etc).
Or, take advantage of the flexibility offered by the graphics package
by studying ?layout
hth,
Kingsford
not an xtable solution, but R2HTML::HTML has an impressive list of
methods, including HTML.infl:
lm.SR - lm(sr ~ pop15 + pop75 + dpi + ddpi, data = LifeCycleSavings)
influencia - influence.measures(lm.SR)
library(R2HTML)
methods(HTML)
HTML(influencia, 'influencia.html')
and open the html file in
Can't give more specific advice without more information (see the
posting guide), but I suspect you want to use nlme::lme, specifying a
weights argument to adjust for the heterogeneity.
Kingsford
On Wed, Jul 21, 2010 at 11:10 PM, Kline, Keith A kkli...@gatech.edu wrote:
I have heterogeneous
On Thu, Jul 22, 2010 at 8:23 AM, Christopher David Desjardins
desja...@umn.edu wrote:
* Please cc me if you reply as I am a digest subscriber *
Hi,
I am wondering how I can run a multilevel survival model in R? Below is
some of my data.
head(bi0.test)
childid famid lifedxm sex
,
Kingsford Jones
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Christian Raschke
Sent: Tuesday, 20 July 2010 9:16 AM
To: r-help@r-project.org
Subject: [R] Indexing by logical vectors
Dear R-Listers,
My question concerns
model or using logit-transformed Accuracy (noting that
nothing can retrieve the 'theoretical effects' mentioned in (iv)
above, but that may not be of interest),
best,
Kingsford Jones
Very best regards,
John
--
View this message in context:
http://r.789695.n4.nabble.com/Help-with-Reshaping
see ?sp::overlay and section 5.2 of Applied Spatial Data Analysis with R
I see there is now also raster::overlay, but I can't claim experience
with that funciton (however my impression is that the raster package
is a powerful tool for working with potentially very large rasters in
R).
hth,
://comments.gmane.org/gmane.comp.lang.r.lme4.devel/3291
hope it helps,
Kingsford Jones
My working example is:
library(nlme)
library(lattice)
Ortho - Orthodont
Ortho$year - Ortho$age - 8 # make intercept = initial status
Ortho.mix1 - lme(distance ~ year * Sex, data=Ortho,
random = ~ 1
On Fri, Jul 2, 2010 at 8:16 AM, Hadley Wickham had...@rice.edu wrote:
?formula in R 2.9.2 says in para 2:
The %in% operator indicates that the terms on its left are nested
within those on the right. For example a + b %in% a expands to the
formula a + a:b.
Ooops, missed that. So b %in% a =
regarding notation of these formulas in lme
(package nlme)? The help files weren't exactly clear to me on this subject.
IMO Pinheiro and Bates' companion book to nlme is a prerequisite for
efficient use of their software.
hoping this helps,
Kingsford Jones
What confuses me most, is the use
objects within R. This was vastly facilitated by the use of str and
indexing tools ([, [[, $, @).
A mantra for R beginners might be In R we work with objects, and str
reveals their essence ;-)
Kingsford Jones
Rob
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help
,
TARSIER, ZORILLA, GENSTAT, and STORM, among others.
best,
Kingsford Jones
On Thu, Feb 18, 2010 at 9:05 PM, myrm...@earthlink.net wrote:
I am old enough to have lived through this particular transition.
Prior to the advent of SAS, trials were analyzed by in-house written
programs (usually
On Tue, Feb 2, 2010 at 10:25 AM, Peng Yu pengyu...@gmail.com wrote:
On Mon, Oct 19, 2009 at 12:53 PM, Kingsford Jones
kingsfordjo...@gmail.com wrote:
sum((x-mean(x))^2)/(n)
[1] 0.4894708
((n-1)/n) * var(x)
[1] 0.4894708
But this is not a built-in function in R to do so, right?
No because
at 5:25 PM, Peng Yu pengyu...@gmail.com wrote:
On Mon, Oct 19, 2009 at 12:53 PM, Kingsford Jones
kingsfordjo...@gmail.com wrote:
sum((x-mean(x))^2)/(n)
[1] 0.4894708
((n-1)/n) * var(x)
[1] 0.4894708
But this is not a built-in function in R to do so, right?
hth,
Kingsford
# ..$ : chr [1:3] Variance StdDev Corr
# - attr(*, title)= chr Subject = pdLogChol(1 + age)
(sigma2.age - as.numeric(vc[2, 1]))
# [1] 0.05126955
hth,
Kingsford Jones
On Mon, Nov 16, 2009 at 9:25 AM, Green, Gerwyn (greeng6)
g.gre...@lancaster.ac.uk wrote:
Dear all
Apologies in advance
By default orthogonal polynomial contrasts are used for ordered
factors. Drop the 'ordered = TRUE' and you will get treatment
contrasts.
hth,
Kingsford Jones
On Tue, Nov 3, 2009 at 8:52 AM, Jen-Chien Chang jcch...@andrew.cmu.edu wrote:
Hi,
I am wondering if there is a way to display the full
See the nlme library and accompanying book by Pinheiro and Bates. The
lme function is appropriate for linear mixed models with normal
errors, and the 'weights' argument provides flexible methods for
modeling error heterogeneity.
hth,
Kingsford
On Mon, Nov 2, 2009 at 12:10 PM, jinyan fan
Thank you for the response, Prof Ripley. Some comments below
On Fri, Oct 30, 2009 at 9:27 AM, Prof Brian Ripley
rip...@stats.ox.ac.uk wrote:
On Wed, 28 Oct 2009, Kingsford Jones wrote:
I thought I'd share this with the list since it appears to provide a
quick fix to some memory problems
On Wed, Oct 28, 2009 at 9:23 AM, Tom Gottfried tom.gottfr...@wzw.tum.de wrote:
?curve
regards,
Tom
and I was in the process of writing a curve example when I noticed Tom
sent this. Here it is:
set.seed(777)
x - runif(100, 0, 100)
y - 10*x + x^2 - .01*x^3 + rnorm(100, 0, 500)
fit - lm(y ~ x
this method *please* post a response.
best,
Kingsford Jones
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self
Within the plot.lars code, change the type argument to matplot from 'b' to 'l':
library(lars)
myplot.lars - edit(plot.lars)
#change type = 'b' to type = 'l' in the call to matplot
data(diabetes)
object - with(diabetes, lars(x,y))
myplot.lars(object, lty = 1, breaks = FALSE)
hth,
Kingsford
...which would complement the apropos fortune from John Fox:
library(fortunes)
fortune('dangerous')
If you give people a linear model function you give them something dangerous.
-- John Fox
useR! 2004, Vienna (May 2004)
On Tue, Oct 27, 2009 at 12:48 PM, Rolf Turner
Perhaps functional data analysis would be of interest. See, for
example, package fda.
Kingsford
On Fri, Oct 23, 2009 at 4:46 PM, Dylan Beaudette
debeaude...@ucdavis.edu wrote:
Hi,
I have fit a series of ols() models, by group, in this manner:
l - ols(y ~ rcs(x, 4))
... where the series
help(gnls, pack=nlme)
hth,
Kingsford Jones
On Thu, Oct 22, 2009 at 4:36 PM, Michael A. Gilchrist mi...@utk.edu wrote:
Hello,
I've been fitting a random effects model using nlme to some data, but I am
discovering that the variation in my random effect is very small. As a
result, I would
summary(f2)$corFixed['year.c', '(Intercept)']
# [1] 0
A possibility is that the data are not of the expected classes. What
does str(long) report?
hth,
Kingsford Jones
I am puzzled, as I thought centering the time variable should eliminate, or
at least strongly reduce, this correlation
Mixed models based on likelihood methods can often handle missing
observations within subjects, but they not do well with missing
individual elements in the design matrices (think unit nonresponse vs
item nonresponse in the survey world). Continuing with the example I
recently sent to you
of the between group variation for each of the levels
of the station factor, as well as for the N slope.
hth,
Kingsford Jones
Thank you a lot in advance for every suggestions you'll give me.
Enrico
[[alternative HTML version deleted]]
__
R
On Tue, Oct 20, 2009 at 5:09 AM, r-quantide r...@quantide.com wrote:
[snip]
. Is there any methods/functions to obtain the variance components
for the station factor too? (please, give me some references, at least.)
Pinheiro and Bates 2000 is (practically) a prerequisite for
intelligent
= 3, lty = 3)
legend('topleft', c('male', 'female'), lty = 2:3, col = 2:3)
For some fancier plots see the ggplot2 examples here:
http://had.co.nz/ggplot2/stat_smooth.html
hth,
Kingsford Jones
On Tue, Oct 20, 2009 at 1:20 PM, Marsha Melnyk mmel...@stevens.edu wrote:
I am trying to make
sum((x-mean(x))^2)/(n)
[1] 0.4894708
((n-1)/n) * var(x)
[1] 0.4894708
hth,
Kingsford
On Mon, Oct 19, 2009 at 9:30 AM, Peng Yu pengyu...@gmail.com wrote:
It seems that var() computes sample variance. It is straight forward
to compute population variance from sample variance. However, I feel
Peng,
It's generally useful to know the class of the object you are working
with, and the methods available for that class. This would have led
you to the 'loadings' help page.
class(pca_result$loadings)
[1] loadings
methods(class='loadings')
[1] print.loadings*
Non-visible functions are
during optimization.
hth,
Kingsford Jones
Thanks.
Mike
On Fri, 16 Oct 2009, Dieter Menne wrote:
Michael A. Gilchrist wrote:
-
nlme(Count ~ quad.PBMC.model(aL, aN, T0),
+ data = tissueData,
+ weights = varConstPower(form =~ Count
see
https://stat.ethz.ch/pipermail/r-sig-ecology/2008-May/000160.html
hth,
Kingsford
On Tue, Oct 13, 2009 at 6:00 AM, Anne-Katrin Link anne.l...@gmx.de wrote:
Normal 0 21 false false
false
MicrosoftInternetExplorer4
Dear R-helpers,
I
see ?curve
e.g.
qftn - function(x) 1 + 2*x - .1*x^2
curve(qftn, 0, 10)
hth,
Kingsford
On Mon, Oct 5, 2009 at 9:42 AM, Juliano van Melis jvme...@gmail.com wrote:
Good day for all,
I'm a beginner aRgonaut, thus I'm having a problem to plot a quadratic model
of regression in a plot.
First I
On Mon, Oct 5, 2009 at 8:52 AM, Umesh Srinivasan
umesh.sriniva...@gmail.com wrote:
Hi all,
[snip]
Fixed effects:
Estimate Std. Error z value Pr(|z|)
(Intercept) -138.8423 0.4704 -295.1 2e-16 ***
SpeciesCr -0.9977 0.6259 -1.6 0.11091
SpeciesDb -1.2140
that differ in their random
effects.
best,
Kingsford Jones
-- Bert
hth,
Kingsford
Many thanks for any help.
Cheers,
Umesh Srinivasan,
Bangalore, India
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
, using the SS resids you are once again back to a linear
transormation of the MSE estimate...
Kingsford
What do you / other R list members think?
Regards
On Thursday 03 September 2009 15:06:14 Kingsford Jones wrote:
There are many ways to measure prediction quality, and what you choose
On Mon, Sep 7, 2009 at 10:34 AM, Alain Zuurhighs...@highstat.com wrote:
rapton wrote:
Hello,
I am using R to analyze a large multilevel data set, using
lmer() to model my data, and using anova() to compare the fit of various
models. When I run two models, the output of each model is
for example...
x - y - seq(.1, 2, .1)
ftn - function(x, y) x - .25*x^2
z - outer(x, y, ftn)
persp(x, y, z, theta = 330, phi = 30)
hth,
Kingsford
On Sun, Sep 6, 2009 at 8:28 AM, Steve
Lianogloumailinglist.honey...@gmail.com wrote:
Hi,
On Sat, Sep 5, 2009 at 5:16 AM, gallon
On Mon, Sep 7, 2009 at 12:42 AM, Gundala Viswanathgunda...@gmail.com wrote:
How do people usually use the result of density function (e.g. dnorm)?
Especially when its value can be greater than 1.
What do they do with such density 1?
dnorm(2.02,2,.24)
[1] 1.656498
There are countless uses.
There are many ways to measure prediction quality, and what you choose
depends on the data and your goals. A common measure for a
quantitative response is mean squared error (i.e. 1/n * sum((observed
- predicted)^2)) which incorporates bias and variance. Common terms
for what you are looking for
Effects Monitor
Santa Monica Mountains National Recreation Area
401 W. Hillcrest Dr.
Thousand Oaks, CA 91360
805-370-2347
Kingsford Jones
kingsfordjo...@g
mail.com
Hi Ben,
Pinheiro and Bates 2000 is the real documentation for nlme. See the
Cell Culture Bioassay example starting on pg 163 for a demonstration
of fitting crossed random effects using pdIdent and pdBlocked objects.
hth,
Kingsford
On Tue, Sep 1, 2009 at 6:44 AM, bamselbenam...@gmail.com wrote:
off-diagonals.
hth,
Kingsford Jones
##More detailed information
##function calls:
sppl.i.xx = gls(all.all.rch~l10area+newx, data = gtemp, method=ML)
sppl.i.ex = gls(all.all.rch~l10area+newx, data = gtemp, method=ML,
correlation = corExp(c(20,.8), form=~x+y|area, nugget=TRUE
of Medicine
Johns Hopkins University
Ph. (410) 502-2619
email: rvarad...@jhmi.edu
- Original Message -
From: Kingsford Jones kingsfordjo...@gmail.com
Date: Friday, August 28, 2009 10:12 pm
Subject: Re: [R] how to generate a random correlation matrix with
restrictions
be MakeColName(...)
-- I was happy to see promotion of -. Reading code using '=' for
both object assignment and argument setting is a little like
fingernails on a blackboard...again and again and...
-- It's nice that people have made these guides available
Kingsford Jones
On Fri, Aug 28, 2009
R - matrix(runif(1), ncol=100)
hth,
Kingsford Jones
On Fri, Aug 28, 2009 at 7:26 PM, Ning Mapnin...@gmail.com wrote:
Hi,
How can I generate a random 100x100 correlation matrix, R={r_ij},
where about 10% of r_ij are greater than 0.9
Thanks in advance
at 7:36 PM, Kingsford
Joneskingsfordjo...@gmail.com wrote:
R - matrix(runif(1), ncol=100)
hth,
Kingsford Jones
On Fri, Aug 28, 2009 at 7:26 PM, Ning Mapnin...@gmail.com wrote:
Hi,
How can I generate a random 100x100 correlation matrix, R={r_ij},
where about 10% of r_ij are greater than
See the Bayesian Task View
http://cran.r-project.org/web/views/Bayesian.html
which will lead you to the arm and bayesm packages, among others.
hth,
Kingsford
On Tue, Jul 28, 2009 at 1:54 AM, nikolay12nikola...@gmail.com wrote:
Hello,
I need to implement a hierarchical model for Bayesian
a couple more options:
ls(package:glmnet)
[1] coef.glmnet glmnet jerr
nonzeroCoef plot.glmnet
[6] plotCoefpredict.elnet predict.glmnet
predict.lognet predict.multnet
[11] print.glmnet
# or
ls(pos = 2)
[1] coef.glmnet glmnet jerr
nonzeroCoef
(plotmath)
hth,
Kingsford Jones
On Sat, Jul 25, 2009 at 6:25 AM, Buckmaster,
Sarahs.buckmaster...@aberdeen.ac.uk wrote:
Hi everyone,
I have a question about calculating r-squared in R. I have tried searching
the archives and couldn't find what I was looking for - but apologies
() +
labs(x=Area, y=Povs)
pb1
hth,
Kingsford Jones
On Thu, Jul 23, 2009 at 5:13 PM, John Kanejrkrid...@yahoo.ca wrote:
I have just started using ggplot2 and I seem to be doing something stupid
in writing ggplot2 commands on more than one line.
In the example below the commands on one line
:
fit2 - aov(Value ~ Group + Error(SS), data = smallDS)
#or
library(nlme)
fit3 - lme(Value ~ Group, data = smallDS, random = ~1|SS)
As you might have suspected from the lmer t-value close to 0, the
associated p-value is about .5.
hth,
Kingsford Jones
My subjects are divided into two groups
,
Kingsford Jones
My subjects are divided into two groups (variable GROUP), individual
subjects are indicated by the variable SS, Value is the outcome measure,
each subject has Value measured three times.
I have used the following code:
fit1-lmer(Value~Group+(1|SS),data=smallDS)
print(fit1
is that code is much clearer if modeling and
plotting calls do not implicitly rely on a non-standard data
structure.
hth,
Kingsford Jones
On Tue, Jul 14, 2009 at 8:54 AM, FMHkagba2...@yahoo.com wrote:
Hi,
I have an original data frame with 8 columns of variables, which are stored
in 'data1
-models list.
hoping it helps,
Kingsford Jones
On Fri, Jul 10, 2009 at 9:27 AM, Djibril
Dayambadjibril.daya...@ess.slu.se wrote:
Hello,
I would appreciate if somebody could help me clear my mind about the below
issues.
I have a factorial experiment to study the effects of Grazing and Fire
thinks there are duplicates in
lonlat. Have you tried, for example, sum(duplicated(lonlat))? Or you
could add a small amount of random noise to one of the coordinates and
then see if Initialize will run...
hth,
Kingsford Jones
Thanks!
K.
__
R
Assuming you are referring to ESRI shapefiles, options can be found in
the following packages: maptools, rgdal, and shapefiles
See the Spatial Task View for more info:
http://cran.r-project.org/web/views/Spatial.html
hth,
Kingsford
On Tue, Jul 7, 2009 at 12:28 PM, Sunnysunshineab...@gmail.com
try
do.call(rbind, yourByList)
hth,
Kingsford Jones
On Wed, Jun 24, 2009 at 9:34 PM, Stephan Lindnerlindn...@umich.edu wrote:
Dear all,
I have a code where I subset a data frame to match entries within
levels of an factor (actually, the full script uses three difference
factors do do
see
?[
and notice the 'drop' argument.
So in your example try
dat[1, , drop=FALSE]
hth,
Kingsford
On Tue, Jun 23, 2009 at 1:13 AM, Bogasobogaso.christo...@gmail.com wrote:
Let say, I have following matrix :
dat - matrix(rnorm(40), 2, 20)
Now I want to partition this like this :
try:
dfr - data.frame(A=rnorm(50), B=runif(50),
X=factor(sample(c('L1','L2'),50,repl=TRUE)))
by(dfr[, 1:2], dfr$X, mean)
hth,
Kingsford Jones
On Tue, Jun 23, 2009 at 7:57 PM, R_help Helprhelp...@gmail.com wrote:
Hi,
To set a simple an clear picture of what I'd like to do, here
Task View
http://cran.r-project.org/web/views/Spatial.html
and an active spatial mailing list
https://www.stat.math.ethz.ch/mailman/listinfo/R-SIG-Geo/
hth,
Kingsford Jones
On Mon, Jun 22, 2009 at 1:01 PM, John
Lipkinsjohn.lipk...@googlemail.com wrote:
Hey,
A basic question. Is there anyone
try:
'x' %in% colnames(df)
hth,
Kingsford
On Mon, Jun 22, 2009 at 9:17 PM, R_help Helprhelp...@gmail.com wrote:
Hi,
I have a matrix or data.frame (df). When I would like to check if a column
named x exists, it becomes my habit to do the following:
if (length(which(colnames(df)==x))0)
Is
attr(,contrasts)$f2
[1] contr.treatment
hth,
Kingsford Jones
On Fri, Jun 19, 2009 at 10:13 PM, Sean Zhangseane...@gmail.com wrote:
Dear R helpers:
Sorry to bother for a basic question about model.matrix.
Basically, I want to apply the dummy coding rule in a dataframe with
complete
Hi Dajiang,
try
plot(1, main=expression(beta[1]))
and, more generally, see
?plotmath
or
demo(plotmath)
Kingsford Jones
On Sun, Jun 7, 2009 at 4:43 PM, Dajiang Jeff Liudajiang@gmail.com wrote:
Dear All,
I want to ask how to make latex symbol \beta_1 into the title of the page
position of the firefox
search bar so that on my windows box I can Ctrl-Tab to firefox, then
Ctrl-K to search R sites.
hth,
Kingsford Jones
On Wed, May 20, 2009 at 3:05 PM, Kynn Jones kyn...@gmail.com wrote:
Thank you all very much for the so many useful ideas and resources.
KJ
,
Kingsford Jones
On Thu, Apr 23, 2009 at 7:15 AM, calpeda mauro.bias...@calpeda.it wrote:
Hi all,
When you want to draw a surface with a mathematics program you need of two
vectors x and y and a matrix z. Then you plot the surface.
For example:
x=[1 2 3];
y=[5 6 7];
z=[1 2 3
4 5 6
7 8 9
The model has multiple levels of random effects, so you need to tell
qqnorm.lme which one you're interested in.
e.g.
qqnorm(m1, ~ranef(., level=1))
hth,
Kingsford Jones
On Thu, Apr 23, 2009 at 11:03 AM, Patrick Zimmerman patz...@gmail.com wrote:
Hello,
I am trying to do some plotting
. Also,
you may need to adjust the ylim and xlim arguments if the densities
from your two samples are dissimilar.
As for converting the histogram to a bar plot -- I think that's an
aberration best left in Excel...
hope it helps,
Kingsford Jones
On Wed, Apr 22, 2009 at 2:56 AM, Thomas Fröjd tfr
The attachment didn't come through, but try:
example(filled.countour)
#or
library(lattice)
example(levelplot)
hth,
Kingsford Jones
On Tue, Apr 21, 2009 at 9:46 PM, mau...@alice.it wrote:
I wonder whether it is possible in R to generate color-coded 3D plots, like
the attached example
,
Kingsford Jones
shadvlength - lapply(shadvector,nchar)
shadmaxind - which.max(shadvlength) ## Maximum element
shadmax - nchar(shadvector[shadmaxind])
shadmax
[1] 9
Many thanks for your help and suggestions.
Shad
[[alternative HTML version deleted
See ?lmer and notice model gm1 in the examples.
As with glm, a binomial lmer model can have the response specified as
a two-column matrix with the columns giving the numbers of successes
and failures.
hth,
Kingsford Jones
On Fri, Apr 10, 2009 at 2:48 PM, Sean Zhang seane...@gmail.com wrote
See 'mar' under ?par
e.g.,
x - y - -100:100
z - outer(x, y, function(x,y) sqrt(x^2 + y^2))
par(mar=c(0,0,0,0))
image(x,y,z)
hth,
Kingsford Jones
On Wed, Apr 8, 2009 at 9:07 PM, Bob Meglen bmeg...@comcast.net wrote:
I am using several scripts that employ various packages to process images
from Alcohol.Spray. There are many other
options for setting up the design matrix to test hypotheses of
interest, and for making adjustments for multiple testing.
Hope that helps,
Kingsford Jones
On Sun, Mar 29, 2009 at 11:01 AM, Dan Kelley kelley@gmail.com wrote:
I'm trying to follow along
Hi Dwight,
The answer likely depends on how you are fitting the model. Have a
look at the multcomp package and its vignettes to see if it can handle
the model class you are interested in.
hth,
Kingsford Jones
On Sun, Mar 29, 2009 at 11:11 AM, Krehbiel, Dwight
krehb...@bethelks.edu wrote
combinations of the coefficients to be tested to be 0.
Kingsford
On Sun, Mar 29, 2009 at 11:57 AM, Kingsford Jones
kingsfordjo...@gmail.com wrote:
Hi Dwight,
The answer likely depends on how you are fitting the model. Have a
look at the multcomp package and its vignettes to see if it can handle
]
Error in `[.default`((coef(summary(lm(t(returns2) ~ factors)))[50]), 1,
:
incorrect number of dimensions
Use of the 'str' function will reveal you are indexing a list element,
so try [[50]] rather than [50]
hth,
Kingsford Jones
above is:
diag(sqrt(getVarCov(fm1)))
(Intercept) age
2.3270339 0.2264276
Warning message:
In sqrt(getVarCov(fm1)) : NaNs produced
And to get the estimate of the error standard deviation:
fm1$sigma
[1] 1.31004
hth,
Kingsford Jones
Thanks,
Ben
,
Kingsford Jones
if that is any use to help explain where i'm going wrong, it
seems to run fine and feeds back just what you noted it would, but i still
get the error message as before - if you have any more suggestions i'd be
very greatful, i'm sure it is down to me missing something very simple
is
create my own palette, but i'm having limited success in trying to work out
how to do this.
Kingsford Jones wrote:
Try
#install.packages('RColorBrewer')
example(brewer.pal, pack='RColorBrewer')
hth,
Kingsford Jones
On Fri, Mar 13, 2009 at 3:20 AM, Ross Culloch ross.cull...@dur.ac.uk
For permutations a couple of options are 'permutations' in package
gtools, and 'urnsamples' in package prob
hth,
Kingsford Jones
On Fri, Mar 13, 2009 at 6:35 AM, Dale Steele dale.w.ste...@gmail.com wrote:
I'm doing a permutation test and need to efficiently generate all
distinct subsets
$color.names))
chr [1:4] tomato1 yellow1 green blue
hth,
Kingsford
Ross
Kingsford Jones wrote:
One option for creating your own palette is
#install.packages('epitools')
mycols - colors.plot(locator = TRUE)
then left-click on 15 colors of your liking and then right-click 'Stop
Also, see
# install.packages('sp')
example('spplot', package='sp')
Kingsford Jones
On Wed, Mar 11, 2009 at 9:38 AM, Greg Snow greg.s...@imail.org wrote:
Another possibility is the my.symbols function in the TeachingDemos package.
You can define a polygon of your arrow (or other symbol
or spatially correlated.
Kingsford Jones
On Mon, Mar 9, 2009 at 1:15 PM, Paul Gribble pgrib...@uwo.ca wrote:
After much research I've listed a couple of ways to do repeated measures
anova here:
http://gribblelab.org/2009/03/09/repeated-measures-anova-using-r/
including univariate
may be
difficualt, depending on the spatial layout of your study). I don't
know of a regression tool in R that allows for estimation of the
spatial correlation strructure at levels higher than than the
observations.
Kingsford Jones
On Mon, Mar 9, 2009 at 7:28 AM, John Poulsen jpoul...@zoo.ufl.edu
, and unfortunately the issues are
compounded by the sparseness of your data in the predictor space.
hth,
Kingsford Jones
On Mon, Mar 9, 2009 at 4:44 PM, Menelaos Stavrinides mens...@gmail.com wrote:
I am running an lme model with the main effects of four fixed variables (3
continuous and one categorical
())
plot(f1, distance~fitted(.)|Subject, abline=c(0,1))
intervals(f1)
hth,
Kingsford Jones
any other suggestion on dealing with this
problem is welcome.
Thanks,
--
View this message in context:
http://www.nabble.com/ANOVA-tp22353919p22353919.html
Sent from the R help mailing list archive
, ..., V100 try
dat - as.data.frame(replicate(100, rnorm(10)))
hth,
Kingsford Jones
Thanks~
[[alternative HTML version deleted]]
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R-help@r-project.org mailing list
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PLEASE do read the posting
Does cex.axis not work in that it reduces the size for both x and y
axes? If that's the case try calling plot with axes=FALSE, and then
add axes seperately with the axis function.
Kingsford Jones
On Wed, Mar 4, 2009 at 1:59 PM, Tiffany Vidal
tvi...@mercury.wh.whoi.edu wrote:
I am trying
see
https://stat.ethz.ch/pipermail/r-help/2008-January/151694.html
hth,
Kingsford Jones
On Wed, Mar 4, 2009 at 7:30 PM, Fuchs Ira irafu...@gmail.com wrote:
How can I print the definition of a function that is in the base package?
for example, if I type:
which.min
I get
function (x
Thanks.
On Mar 4, 2009, at 10:26 PM, Kingsford Jones wrote:
see
https://stat.ethz.ch/pipermail/r-help/2008-January/151694.html
hth,
Kingsford Jones
On Wed, Mar 4, 2009 at 7:30 PM, Fuchs Ira irafu...@gmail.com wrote:
How can I print the definition of a function that is in the base package
[1] 259
--
: H
: B
[1] 169
hth,
Kingsford Jones
On Wed, Mar 4, 2009 at 8:17 PM, Pele drdi...@yahoo.com wrote:
Hi R users,
I have an R object with the following attributes:
str(sales.bykey1)
'by' int [1:3, 1:2, 1
RSiteSearch('trpaths')
will lead you to potential solutions...
On Fri, Feb 27, 2009 at 7:18 PM, rkevinbur...@charter.net wrote:
I am running an R script with Tinn-R (2.2.0.1) and I get the error message
Error in source(.trPaths[4], echo = TRUE, max.deparse.length = 150) :
object .trPaths
Aslo note there are a number of packages with functions producing
Burnham and Anderson style AIC tables: pgirmess, bbmle,
dRedging(off-CRAN), PKtools, ...
On Wed, Feb 25, 2009 at 4:58 PM, Mark Drever mdre...@interchange.ubc.ca wrote:
hi folks,
I'm trying to build a table that contains
X11() on my Vista machine running 2.8.1 seems to work the same as
windows(). From the help page, the only difference I see is that
'X11' (and 'x11') have only width, height and pointsize arguments
('windows' has another 13).
Kingsford
On Wed, Feb 25, 2009 at 8:58 PM, Ted Harding
, sample(1:27, ncell(r), replace=1))
plot(r)
r[] - r[]==1
plot(r)
If you'd rather have the non-1 cells be NA, just replace 'r[]==1' with
'ifelse(r[]==1, 1, NA)'
hth,
Kingsford Jones
On Sat, Feb 21, 2009 at 8:46 AM, Michelle Greve
michelle_gr...@yahoo.com wrote:
I have a raster (which I called glc
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