Dear list,
I am needing to extract the estimate of overdispersion (deviance / residual
degrees of freedom or c-hat) from multiple model objects - so they can then be
used to compare the extent of overdispersion among alternative models as well
as calculate qausi-AIC values. I have been
On 9/11/2006 3:57 PM, Michael Prager wrote:
R 2.3.1 on Windows XP Professional.
I am writing some scripts to generate examples. The Rgui menu
item File, Save to File is helpful. Is there perhaps an
equivalent R function that can be incorporated into a script?
I think sink() is the closest
On 11-Sep-06 Gregor Gorjanc wrote:
Thank you. Your solution is usable but unfortunatelly not portable to
Windows. I would like to use this test in package check, which can
include also windows OS.
Now that I think about it (should have done that earlier),
you can use the value of
On Mon, 11 Sep 2006, John Kornak wrote:
Thanks to Professor Ripley and Sarah Goslee for their helpful responses
which have progressed my installation of rimage a little further.
Installing fftw2 instead of fftw3 of course solves the problem and I
apologize for initially missing that
Prof Brian Ripley ripley at stats.ox.ac.uk writes:
...
Check out tests/internet.R. nsl() checks if you can resolve host names,
which has worked well enough there.
Thank you prof. Ripley for this pointer. I am posting here the relevant part if
someone does not look at SVN. I would just like to
Aldo Crossa aldo.crossa at wright.edu writes:
Hi,
I've been trying to recreate plots of that follow a cubic form.
[snip]
I've noticed that in R all curves are pixelated, regardless of howmany
points I use. Is there anything I can do to smoothen these graphs so
that they are no longer
in line
Douglas Bates wrote:
On 9/11/06, Thomas Wutzler [EMAIL PROTECTED] wrote:
Hello,
How do I specify the formula and random effects without a startup object
? I thought it would be a mixture of nls and lme.
after trying very hard, I ask for help on using nlme.
Can someone hint me
On Tue, 12 Sep 2006, Alexander Nervedi wrote:
Hi
I am having trouble with dotcharts, and I keep getting the error message:
Error in Summary.data.frame(..., na.rm = na.rm) :
only defined on a data frame with all numeric or complex variables
I am sure there is a really simple
Thanks,
that works but what are the coordinates of at in the y-direction? On
which y-position mtext plots?
Christian
Jeff Bricker schrieb:
?mtext, also ?barplot since barplot returns midpoints of the bars.
also ?rep for setting up a vector of repeating values.
something like this:
Christian Oswald wrote:
Thanks,
that works but what are the coordinates of at in the y-direction? On
which y-position mtext plots?
Please read ?mtext which tells you to use argument line.
Uwe Ligges
Christian
Jeff Bricker schrieb:
?mtext, also ?barplot since barplot returns
Christos Hatzis christos at nuverabio.com writes:
Try this:
old.colnames - colnames(my.439.vars.df)
old.colnames[old.colnames==fksm] - new.name.a
old.colnames[old.colnames==klmk] - new.name.b
For a newcomer, it will be useful to have a function like this in the base R:
that can take a
Hello!
So, my problem is following. I have bird offspring growth data and I'd
like to model individual growth curves (aim is to study asymptotes and
inflection points) with nlme according to Pinheiro Bates 2000: first using
nlsList to generate individual curves and then nlme to study the
... or use lattice and splom() instead. If the successive graphs bear some
relationship to each other, this might produce a more useful display, too.
-- Bert Gunter
Genentech Non-Clinical Statistics
South San Francisco, CA
The business of the statistician is to catalyze the scientific learning
Jason Barnhart jasoncbarnhart at msn.com writes:
These posts may be helpful.
http://tolstoy.newcastle.edu.au/R/help/05/06/5776.html
https://stat.ethz.ch/pipermail/r-help/2002-May/021145.html
Using scan directly may also work for you rather than read.fwf.
Also, there are posts regarding
summary(modeltest)@sigma
Toby Gardner wrote:
Dear list,
I am needing to extract the estimate of overdispersion (deviance / residual
degrees of freedom or c-hat) from multiple model objects - so they can then
be used to compare the extent of overdispersion among alternative models as
Hi
I hope this isn't off topics, but I have always found when I stepAIC() some
glm I get an improvement in accuracy and kappa, but I have just done a case
where I got a marginal deterioration. Is this possible, or should I be
going through my figures carefully to see if I have messed up?
You can extract it from a summary.lmer object, which has a slot names
sigma that contains this scale parameter. For example,
sum.modeltest - summary(modeltest)
[EMAIL PROTECTED]
On 11/09/06, Toby Gardner [EMAIL PROTECTED] wrote:
Dear list,
I am needing to extract the estimate of
On Tue, 12 Sep 2006, stephenc wrote:
Hi
I hope this isn't off topics, but I have always found when I stepAIC() some
glm I get an improvement in accuracy and kappa, but I have just done a case
where I got a marginal deterioration. Is this possible, or should I be
going through my
Thanks to Professor Ripley and Sarah Goslee for their helpful responses
which have progressed my installation of rimage a little further.
Installing fftw2 instead of fftw3 of course solves the problem and I
apologize for initially missing that requirement in the rimage
documentation.
My
Dear R-users,
I have some problems with the geweke.diag-Function of the coda-package. I
try to obtain the Geweke-diagnostic by using the following, simple code:
library(coda)
input.geweke = as.mcmc(input.matrix)#input.matrix is a
25.000 x 35 matrix with the 25.000 saved draws
Hello Pekka,
there may be a way around it. However, you should provide commented,
minimal, self-contained, reproducible code so we can see what you are
trying to do. We need to see exactly what you are telling R, and what
nlme is telling you.
Cheers
Andrew
On Tue, Sep 12, 2006 at 09:49:28AM
PS, the equivalent for a glm is:
sum.modeltest - summary(modeltest)
sum.modeltest$dispersion
Hope this helps.
On 11/09/06, Toby Gardner [EMAIL PROTECTED] wrote:
Dear list,
I am needing to extract the estimate of overdispersion (deviance / residual
degrees of freedom or c-hat) from
On Sep 12, 2006, at 2:47 AM, Anupam Tyagi wrote:
Jason Barnhart jasoncbarnhart at msn.com writes:
These posts may be helpful.
http://tolstoy.newcastle.edu.au/R/help/05/06/5776.html
https://stat.ethz.ch/pipermail/r-help/2002-May/021145.html
Using scan directly may also work for you rather
Michael Kubovy wrote:
Please consider saving your data in a way that will make it easier to
read into R. No program can read every dataset.
going back to the original post, there seems to be a couple of hanging
questions:
None of these seem to read non-coniguous variables from columns; or
Dear All
Is there some way of exporting R plots to epslatex, i.e., to a file
with the eps file and another one with the LaTeX commands
(representing the text in the plots), likewise Gnuplot does? If so,
could you please indicate it to me?
Thanks in advance,
Paul
I did an eps/ps file with e.g.:
postscript(c:/Temp/test.eps, width = 8.0, height = 6.0, horizontal =
FALSE, onefile = FALSE, paper = special)
curve(x^2)
dev.off()
but I am not sure what you mean with the second file with the latex
commands.
Paul Smith schrieb:
Dear All
Is there some way of
On Tue, 12 Sep 2006, Paul Smith wrote:
Is there some way of exporting R plots to epslatex, i.e., to a file
with the eps file and another one with the LaTeX commands
(representing the text in the plots), likewise Gnuplot does? If so,
could you please indicate it to me?
R has an xfig driver,
I could use some help understanding how nls parses the formula argument
to a model.frame and estimates the model. I am trying to utilize the
functionality of the nls formula argument to modify garchFit() to handle
other variables in the mean equation besides just an arma(u,v)
specification.
Hello everyone !
I am trying to write a short program to estimate semivariogram
parameters. But I keep running into a problem when using the nls
function.
Could you please shed some light. I have put a sample of one of the
codes and ran a short example so you see what I mean.
-
Hi
Well. I use R quite extensively for a quite a long time without
knowing perl, cut, awk etc. Do you think I shall learn it?
I agree with Barry Rowlingson that best way how to get a correct
answer is to present all relevant information. Seems to me that
read.table, read.fwf are obvious
Hello everyone !
I am trying to write a short program to estimate semivariogram
parameters. But I keep running into a problem when using the nls
function.
Could you please shed some light. I have put a sample of one of the
codes and ran a short example so you see what I mean.
-
Hi
On 12 Sep 2006 at 6:44, Anupam Tyagi wrote:
To: r-help@stat.math.ethz.ch
From: Anupam Tyagi [EMAIL PROTECTED]
Date sent: Tue, 12 Sep 2006 06:44:03 + (UTC)
Subject:Re: [R] rename cols
Christos Hatzis christos at
I don't know, this seems pretty simple and intuitive (to me)
# Create a sample data set with 439 variables
tmp - data.frame(matrix(c(rnorm(4390)), ncol=439))
colnames(tmp)-paste(col, 1:439, sep = )
# rename a certain variable in that dataset
names(tmp)[(which(names(tmp)=='col1'))]-'NewName'
For a newcomer who wants to rename variable fksm and klmk in a dataframe
of
with 439 variables there is not easy and intuitive solution. That person has
to
spend a lot of time listing columns and counting columns or doing string
searches or using brackets within brackets within brackets to
I'm using the 'cloud' function in the 'lattice' package to produce
multi-panel 3D scatter plots. The range of the values used vary much
between each panel (especially on the z axis), so I wish the axis limits
to be calculated based on the (conditional) data.
Here's a minimal example:
Hi
There is even an Excel like possibility for renaming columns.
try
newDF-edit(oldDF)
you can go through columns and after clicking on header you can
change column name.
Petr
On 12 Sep 2006 at 8:31, hadley wickham wrote:
Date sent: Tue, 12 Sep 2006 08:31:43 -0400
From:
Hi,
I have a problem with aggregate.
x - aggregate(t1,list(t2,t3,t4), mean)
z-x[,3]
I want z to be a vector but it is a factor.
I've tried to use as.vector(z,mode=numeric) but then the numbers get
scrambeled.
Any help is appriciated
/anders
__
On 9/12/06, Prof Brian Ripley [EMAIL PROTECTED] wrote:
Is there some way of exporting R plots to epslatex, i.e., to a file
with the eps file and another one with the LaTeX commands
(representing the text in the plots), likewise Gnuplot does? If so,
could you please indicate it to me?
R
Hello,
I can't find a package which calculates Kendall's tau-c. There is the
package Kendall, but it only calcuates Kendall's tau-b.
Here is the example from
ttp://www2.chass.ncsu.edu/garson/pa765/assocordinal.htm.
cityriots - data.frame(citysize=c(1,1,2,2,3,3),
riotsize=c(1,2,1,2,1,2),
Hi
all culumns which are used for discrimination (in your case 3) are
factor. If you want to change them to numeric you has to use
as.numeric(as.character(x[,3]))
I believe it is in FAQ.
HTH
Petr
Please use sensible subject.
On 12 Sep 2006 at 14:49, Anders Eklund wrote:
Date sent:
From the FAQ:
7.10 How do I convert factors to numeric?
It may happen that when reading numeric data into R (usually, when
reading in a file), they come in as factors. If f is such a factor
object, you can use
as.numeric(as.character(f))
to get the numbers back. More efficient, but harder
Gabor Grothendieck wrote:
Here is a variation for Windows. The second line returns TRUE or FALSE
and may need to be varied if the output of ping is not the same on your
system as on mine:
ping - system(ping www.google.com, intern = TRUE)
as.numeric(strsplit(grep(Received, ping, value =
On Tue, 2006-09-12 at 15:02 +0200, Knut Wenzig wrote:
Hello,
I can't find a package which calculates Kendall's tau-c. There is the
package Kendall, but it only calcuates Kendall's tau-b.
Here is the example from
ttp://www2.chass.ncsu.edu/garson/pa765/assocordinal.htm.
cityriots -
Dear R gurus,
I have XY data giving the locations of tree seedlings that were
surveyed during a 210 meter belt transect. This belt transect was
taken by stretching a line across the field, then measuring all
seedlings within 1 meter on either side of the line. The end result
was XY
On 9/12/2006 9:27 AM, Michael Prager wrote:
Duncan Murdoch wrote:
On 9/11/2006 3:57 PM, Michael Prager wrote:
R 2.3.1 on Windows XP Professional.
I am writing some scripts to generate examples. The Rgui menu
item File, Save to File is helpful. Is there perhaps an
equivalent R
Assuming you only use the X direction to split the data into 10 m cells.
table(list(Species, round(X, digits = -1)))
This will generate a table with the number of seedlings per species in
each 10 m cell. Divide this by the area of each cell and you get the
densities.
Cheers,
Thierry
On 9/11/06, Manuel Morales [EMAIL PROTECTED] wrote:
On Mon, 2006-09-11 at 11:43 -0500, Douglas Bates wrote:
On 9/10/06, Andrew Robinson [EMAIL PROTECTED] wrote:
On Thu, Sep 07, 2006 at 07:59:58AM -0500, Douglas Bates wrote:
I would be happy to re-institute p-values for fixed effects
Thanks again to both Sarah Goslee and Professor Ripley.
Installing the libjpeg-devel package was the key.
John
Sarah Goslee wrote:
Well, there are two possible problems.
One, you don't have the file.
Two, it isn't where it's supposed to be.
Did you install it from the rpm?
If so, did
All,
When I take a subset of a factor the reduced factor still maintains all
the original levels of the factor when say forming the key in a plot.
The data is correct, but the variable still remembers the original
levels. See below for reproducible code. Does anyone know how to fix
this?
Just add the following to your code
new.fact = fact[1:6, drop=T]
new.fact
[1] A A A B B B
Levels: A B
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of
Afshartous, David
Sent: Tuesday, September 12, 2006 11:23 AM
To: r-help@stat.math.ethz.ch
Try
new.fact = fact[1:6, drop=TRUE]
On 12/09/06, Afshartous, David [EMAIL PROTECTED] wrote:
All,
When I take a subset of a factor the reduced factor still maintains all
the original levels of the factor when say forming the key in a plot.
The data is correct, but the variable still
You have at least two choices:
R factor(fact[1:6])
[1] A A A B B B
Levels: A B
R fact[1:6, drop=TRUE]
[1] A A A B B B
Levels: A B
HTH,
Andy
From: Afshartous, David
All,
When I take a subset of a factor the reduced factor still
maintains all
the original levels of the factor when say
On 9/12/06, Afshartous, David [EMAIL PROTECTED] wrote:
All,
When I take a subset of a factor the reduced factor still maintains all
the original levels of the factor when say forming the key in a plot.
The data is correct, but the variable still remembers the original
levels. See below for
I think you want 'fact[1:6, drop = TRUE]'
-roger
Afshartous, David wrote:
All,
When I take a subset of a factor the reduced factor still maintains all
the original levels of the factor when say forming the key in a plot.
The data is correct, but the variable still remembers the original
factor(new.fact) will do the trick. But that will recode the levels and
that might be something you don't want.
fact = as.factor(c(rep(A, 3),rep(B, 3), rep(C, 3)))
new.fact = fact[1:6]
new.fact
[1] A A A B B B
Levels: A B C
factor(new.fact)
[1] A A A B B B
Levels: A B
Cheers,
Thierry
Also, it is probably easier to use gl() than coerce your data into a
factor
fact - gl(3, 3, label = c(A, B, C))
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of Liaw, Andy
Sent: Tuesday, September 12, 2006 11:32 AM
To: Afshartous, David;
Duncan Murdoch wrote:
On 9/11/2006 3:57 PM, Michael Prager wrote:
R 2.3.1 on Windows XP Professional.
I am writing some scripts to generate examples. The Rgui menu
item File, Save to File is helpful. Is there perhaps an
equivalent R function that can be incorporated into a script?
check ?[.factor, you need:
fact[1:6, drop = TRUE]
Best,
Dimitris
Dimitris Rizopoulos
Ph.D. Student
Biostatistical Centre
School of Public Health
Catholic University of Leuven
Address: Kapucijnenvoer 35, Leuven, Belgium
Tel: +32/(0)16/336899
Fax: +32/(0)16/337015
Web:
On Mon, 11 Sep 2006, Gregor Gorjanc wrote:
Prof Brian Ripley ripley at stats.ox.ac.uk writes:
...
Check out tests/internet.R. nsl() checks if you can resolve host names,
which has worked well enough there.
Thank you prof. Ripley for this pointer. I am posting here the relevant part
thanks to all for the quick replies!
if the factor is part of a dataframe, I can apply the subsetting
to the entire dataframe, and then use drop=True to the factor
separately and then put it back into the new dataframe (code below). is there
a way
to do this in a single step?
dat
Afshartous, David [EMAIL PROTECTED] writes:
All,
When I take a subset of a factor the reduced factor still maintains all
the original levels of the factor when say forming the key in a plot.
The data is correct, but the variable still remembers the original
levels. See below for
Dear List,
how can I coerce a matrix like this
[,1] [,2] [,3] [,4] [,5] [,6]
[1,] 0 1 1 0 0 0
[2,] 1 0 1 0 0 0
[3,] 1 1 0 0 0 0
[4,] 0 0 0 0 1 0
[5,] 0 0 0 1 0 0
[6,] 0 0 0 0 0 0
to be filled with numbers?
this is the result of replacing some character (v,
Hello, has anyone tried doing this?
Local System:
NX client (windows version)
Remote System:
Linux Fedora Core 5, running on 64 bit Intel
R 2.3.1
The plots display weird in the sense that the y-labels don't show, i.e.
they appear as solid black rectangles rather than numbers. I know the
Hi,
I use R in remote access on a Debian server.
I need X11() to create graphical things so I use xvfb-run (Virtual X server
environnement) R to allowing X11() capabilities to R.
An other technique is to connect in shh -X to execute my R script.
With the connection ssh -X, my R script is well
Hello:
I'm trying to find some reading material about .a files. I'm attempting to
build a package which accesses many C routines via .Call, and its been
suggested that I need a lib_C_code.a file inside the C directory. What
does such a file do? Where can I read somthing about it?
I've tried
Yes. I do this periodically:
dat.new - dat[1:6, ]
dat.new[] - lapply(dat.new, function(x)
if(is.factor(x)) factor(x) else x)
HTH,
--sundar
Afshartous, David said the following on 9/12/2006 11:00 AM:
thanks to all for the quick replies!
if the factor is part of a
On Tue, 2006-09-12 at 18:42 +0200, Simone Gabbriellini wrote:
Dear List,
how can I coerce a matrix like this
[,1] [,2] [,3] [,4] [,5] [,6]
[1,] 0 1 1 0 0 0
[2,] 1 0 1 0 0 0
[3,] 1 1 0 0 0 0
[4,] 0 0 0 0 1 0
[5,] 0 0 0 1 0 0
[6,] 0 0 0 0 0 0
to be
if only 2 letters:
(z==v)*1
else:
lapply(z, function(x) as.numeric(as.character(factor(x,levels=
c(d,v,w),labels=c(0,1,2)
---
Jacques VESLOT
CNRS UMR 8090
I.B.L (2ème étage)
1 rue du Professeur Calmette
B.P. 245
59019 Lille
Hi, is there anyone knows how to install R-2.3.1 on Mac OS X 10.3.9(panther)?
Thanks a lot!
Lei
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
Marc,
wpw, great, what a lot of solutions!!!
thank you very much,
simone
Il giorno 12/set/06, alle ore 19:21, Marc Schwartz (via MN) ha scritto:
On Tue, 2006-09-12 at 18:42 +0200, Simone Gabbriellini wrote:
Dear List,
how can I coerce a matrix like this
[,1] [,2] [,3] [,4] [,5]
Thank you so much!!
ej
On 9/11/06, Tony Plate [EMAIL PROTECTED] wrote:
The following works for data frames and matrices (you didn't say which
you were working with).
x - data.frame(V1=1:3,V2=4:6)
x
V1 V2
1 1 4
2 2 5
3 3 6
colnames(x) - c(Apple, Orange)
x
Apple Orange
A quick question, please!
How do you extract a certain value of vector?
i.e. x = c(2,5,3,6,21,3,6,24, )
How do you get the 1st one (which is 2); the 5th one (which is 21); etc?
thx much,
ej
[[alternative HTML version deleted]]
__
It's a known problem. Run the X11 device with the arguments stated,
as it says
On Tue, 12 Sep 2006, Gael Even wrote:
Hi,
I use R in remote access on a Debian server.
I need X11() to create graphical things so I use xvfb-run (Virtual X server
environnement) R to allowing X11()
I'm not quite sure what you mean. To get the first item in a vector you use
x[1]
[1] 2
x[5]
[1] 21
Is that what you want?
On 12/09/06, Ethan Johnsons [EMAIL PROTECTED] wrote:
A quick question, please!
How do you extract a certain value of vector?
i.e. x = c(2,5,3,6,21,3,6,24, )
On 9/12/06, Ethan Johnsons [EMAIL PROTECTED] wrote:
A quick question, please!
How do you extract a certain value of vector?
i.e. x = c(2,5,3,6,21,3,6,24, )
How do you get the 1st one (which is 2); the 5th one (which is 21); etc?
Simple, Ethan:
x[1], x[5], ...
Paul
Prof Brian Ripley [EMAIL PROTECTED] writes:
It's a known problem. Run the X11 device with the arguments stated,
as it says
Alternatively, try playing with the pixel depth of xvfb. I think this
mainly happens with 8-bit displays.
On Tue, 12 Sep 2006, Gael Even wrote:
Hi,
I
Hi All,
I tried RSiteSearch('truncated distribution') , and found a lot of threads on
'fitting truncated normal distribution'. No doubt they are all helpful in
fitting the distribution based on the data of known original mean and sd.
But my question is a bit different. What I know is the mean
Prof Brian Ripley wrote:
On Mon, 11 Sep 2006, Gregor Gorjanc wrote:
Prof Brian Ripley ripley at stats.ox.ac.uk writes:
...
Check out tests/internet.R. nsl() checks if you can resolve host names,
which has worked well enough there.
Thank you prof. Ripley for this pointer. I am posting here
[This is a follow-up to the recent discussion on R-help]
Hi all,
I can reproduce both problems on gentoo (2006.0 profile),
but not on OpenSuSE-10.1.
bash cat rgl.postscript.r
library(rgl)
example(spheres3d)
rgl.postscript(spheres.eps, fmt=eps)
R source(rgl.postscript.r)
X Error of failed
I have the following code that I am trying to execute using the whole
object approach and get rid of the for loop. I have looked at the
manual and seached the database for examples or similar questions with
no luck. The following example works without any problems.
for (j in 1:186)
{
You want:
anova(my.glm)
On 12-Sep-06, at 4:00 AM, [EMAIL PROTECTED] wrote:
Suppose we have a data.frame where variables are categorical and
the response is
categorical eg:
my.df=NULL
for(i in LETTERS[1:3]){my.df[[i]]=sample(letters, size=10)}
my.df=data.frame(my.df)
Is there any way to put an argument into an object name. For example,
say I have 5 objects, model1, model2, model3, model4 and model5.
I would like to make a vector of the r.squares from each model by code
such as this:
rsq - summary(model1)$r.squared
for(i in 2:5){
rsq - c(rsq,
I am experiencing some problems with the windows graphics device
and bitmaps. (Everything is done in R 2.3.1 on Windows XP)
As an example, I will use
windows(3,2)
plot(1:10)
It is not a pretty or meaningful graph, but it demonstrates the problem.
savePlot(file=test,type=bmp)
creates a bitmap
Hi Ken,
Not quite the way you're thinking about it, but yes, there is,
and it is very useful. See ?get for more information, but here's
the basics:
for(i in 2:5) {
thismodel - get(paste(model, i, sep=))
rsq - c(rsq, summary(thismodel)$r.squared)
}
Also see ?assign for the opposite effect.
Ken,
I have a similar example in my blog:
http://statcompute.spaces.live.com/blog/cns!39C8032DBD1321B7!229.entry
On 9/12/06, Pierce, Ken [EMAIL PROTECTED] wrote:
Is there any way to put an argument into an object name. For example,
say I have 5 objects, model1, model2, model3, model4 and
you need something like the following,
fit.lis - list(model1, model2, model3, model4, model5)
# or if you have many models
fit.lis - lapply(paste(model, 1:5, sep = ), get)
sapply(fit.lis, function(x) summary(x)$r.squared)
I hope it helps.
Best,
Dimitris
Dimitris Rizopoulos
Ph.D. Student
Thanks to all who showed me to the get() function. That works like a
charm.
Ken
From: David Barron [mailto:[EMAIL PROTECTED]
Sent: Tuesday, September 12, 2006 1:24 PM
To: Pierce, Ken; r-help
Subject: Re: [R] variables in object names
The trick is to use the
The trick is to use the function get():
vns - paste(model,1:4,sep=)
x - rnorm(10)
model1 - lm(rnorm(10) ~ x)
model2 - lm(rnorm(10) ~ x)
model3 - lm(rnorm(10) ~ x)
model4 - lm(rnorm(10) ~ x)
r.sq - summary(model1)$r.square
for (i in 2:4) r.sq - c(r.sq,summary(get(vns[i]))$r.square)
On
Hi!
I got error when I did make check:
running code in 'reg-tests-1.R' .../bin/sh: line 1: 9538 Segmentation
fault LC_ALL=C SRCDIR=. R_DEFAULT_PACKAGES= ../bin/R --vanilla
reg-tests-1.R reg-tests-1.Rout 21
make[3]: *** [reg-tests-1.Rout] Error 1
make[3]: Leaving directory
Hello,
I'd like to group the lines of a matrix so that:
A 1.0 200
A 3.0 800
A 2.0 200
B 0.5 20
B 0.9 50
C 5.0 70
Would give:
A 2.0 400
B 0.7 35
C 5.0 70
So all lines corresponding to a letter (level), become a single line
where all the values of each column are averaged.
I've done that with a
Emmanuel Levy said the following on 9/12/2006 3:50 PM:
Hello,
I'd like to group the lines of a matrix so that:
A 1.0 200
A 3.0 800
A 2.0 200
B 0.5 20
B 0.9 50
C 5.0 70
Would give:
A 2.0 400
B 0.7 35
C 5.0 70
So all lines corresponding to a letter (level), become a single line
you are looking for the outer product
?outer
a - 1:6
cc - matrix(1:6, 3, 2)
e - matrix(0, 6,3)
for (j in 1:3) e[,j] - a*cc[j,2]
e
[,1] [,2] [,3]
[1,]456
[2,]8 10 12
[3,] 12 15 18
[4,] 16 20 24
[5,] 20 25 30
[6,] 24 30 36
a %o% cc[,2]
Dear listers,
I tried RSiteSearch('truncated distribution') , and found a lot of threads on
'fitting truncated normal distribution'. No doubt they are all helpful in
fitting the distribution based on the data of known original mean and sd.
But my question is a bit different. What I know is the
On Tue, September 12, 2006 7:34 am, Manuel Morales wrote:
On Mon, 2006-09-11 at 11:43 -0500, Douglas Bates wrote:
Having made that offer I think I will now withdraw it. Peter's
example has convinced me that this is the wrong thing to do.
I am encouraged by the fact that the results from
But my question is a bit different. What I know is the mean
and sd after truncation. If I assume the distribution is
normal, how I am gonna develope the original distribution
using this two parameters?
You can't, as they are plainly not sufficient (you need to know the amount
of
However, if you know the point(s) of truncation then you should be able to
work your way back. Look for the mean and variance of a truncated normal, it
will involve mu, sigma and c (point of truncation). You will need to solve
for mu and sigma from two equation. For example look at the wikipedia
On 9/12/06, Karl Ove Hufthammer [EMAIL PROTECTED] wrote:
I'm using the 'cloud' function in the 'lattice' package to produce
multi-panel 3D scatter plots. The range of the values used vary much
between each panel (especially on the z axis), so I wish the axis limits
to be calculated based on
On 9/12/06, Klaus Nordhausen [EMAIL PROTECTED] wrote:
Dear Deepayan,
thanks for your reply, the change of the aspect does however not solve my
problem with the space below the graph on the .eps
I attached the .eps (still with the old aspect) so that it is maybe clearer
what my
problem is.
Dear list,
I want to validate the coefficients computed from Firth bias reduction
ligistic regression using bootstrap resampling method. However, I got an
error message which I coule not decipher. Help is needed
Error in if (mx 1) delta - delta/mx : missing value where TRUE/FALSE
needed
I'm attempting to write a general function to implement Faraway's
bootstrapping algorithm for mixed models with lmer, but have run into
a curious problem. I'm comparing two models
model.1-lmer(Response ~ Treatment + (1|Trial), data=exp.data,
method=ML)
model.2-lmer(Response ~ 1 +
1 - 100 of 109 matches
Mail list logo
