Hello!
Assuming I have a vector, such as
v - c(1,2,1,2,3,3,1)
This vector has three unique elements: 1, 2, and 3.
unique(v)
[1] 1 2 3
If I shuffle this vector of unique elements, I get something like this:
sample(unique(v))
[1] 3 2 1
In the vector v I started with, I would now like to
Hi i have to table with IDs in each one.
I want to make a join (as in sql) by the ID. Is any way to use the RODBC
package (or other) in local tables (not a access, mysql, sql, etc. ) and
made the join?
Thanks in advance
__
R-help@stat.math.ethz.ch
Dear all,
Not a problem that is very specific to R, but I think that it is not only of
interest to me... So I hope that someone finds the time to provide me with some
clues on this probably rather basic issue.
I'm performing an analysis of experimental data with a categorical response
Dear collegues.
I am using scan( ) to read from a table (a csv file).
I am wondering how to let the program know that the end of the file is
reached?
Your help will be highly appreciated!
Best Wishes
Yuchen Luo
[[alternative HTML version deleted]]
Hi, Im looking for information to implement the kimura method (kimura
Chikuni. 1987. Mixtures of empirical distributions: an interative
application of the age length key) for calculation of fisheries age-length
key.
If someone have a manuals, methodology or examples about it I will be really
On Tue, 28 Aug 2007, Jorge Cornejo Donoso wrote:
Hi i have to table with IDs in each one.
And what is a 'table'? If these are data frames, see ?merge. If they are
tables (which are arrays in R), then still use merge() if they can be
converted to data frames.
I want to make a join (as in
hi everyone:
I have a Dell Server that has a Xeon processor, and I would like to use the
best ATLAS posted in the R website. I find that R has ATLAS for core2duo and
P4. I am not sure which one of these two is best suited for Xeon processor, or
is that neither of these two is good and I should
Hmm,
Excel bashing always brings joy ... but then again, it's a user's community of
more than 100 million people, and if one is careful one can do quite a few
interesting things with excel, in particular if it can be extended by R (using
R(D)COM by T Baier and RExcel by E Neuwirth).
I need to compute weighted descriptive statistics (mean, median,
variance) for a vector of data disaggregated by a set of index
variables. The weights to be used are vector in the same data frame
and have to be disaggregated by the same index variables.
Package Hmisc has functions for computing
Hi i have to table with IDs in each one.
I want to make a join (as in sql) by the ID. Is any way to use the RODBC
package (or other) in local tables (not a access, mysql, sql, etc. ) and
made the join?
With RODBC it would be normal SQL, so
I guess with local tables you mean data frames?
then
try the following:
v - c(1, 2, 1, 2, 3, 3, 1)
x - c(3, 2, 1)
fv - factor(v, levels = x)
as.vector(unclass(fv))
I hope it helps.
Best,
Dimitris
Dimitris Rizopoulos
Ph.D. Student
Biostatistical Centre
School of Public Health
Catholic University of Leuven
Address: Kapucijnenvoer 35,
Jorge,
I'm assuming that you mean dataframes of matrices. Then you could use
merge to join both dataframes into a new one. See ?merge for more
detail.
HTH,
Thierry
ir. Thierry Onkelinx
Instituut voor natuur- en
Jorge Cornejo Donoso wrote:
Hi i have to table with IDs in each one.
I want to make a join (as in sql) by the ID. Is any way to use the RODBC
package (or other) in local tables (not a access, mysql, sql, etc. ) and
made the join?
I guess you are looking for ?merge
Uwe Ligges
Ron Crump wrote:
Hi,
I have a dataframe that contains pedigree information;
that is individual, sire and dam identities as separate
columns. It also has date of birth.
These identifiers are not numeric, or not sequential.
Obviously, an identifier can appear in one or two columns,
Leeds, Mark (IED) wrote:
I was reading a presentation of Professor Peng's and typed the
presentation code into R but I changed it to make plot.polygon a
separate function instread of defining the function in SetMethod itself
as he did. Is that the problem with the code below because
Hello,
sorry that I interfer, but I tried to do this
The SymTest matrix:
A B C D E F G
A 0.3 0.1 0.5 0.7 0.2 0.8 0.1
B 0.1 0.5 0.4 0.6 0.7 0.3 0.7
C 0.5 0.4 0.3 0.5 0.1 0.1 0.5
D 0.7 0.6 0.5 0.4 0.3 0.5 0.7
E 0.2 0.7 0.1 0.3 0.5 0.2 0.1
F 0.8 0.3 0.1 0.5 0.2 0.3 0.5
G 0.1 0.7
I assume that by local tables you mean data frames in R.
You can use the merge function in the base of R, as others have already
mentioned, or if you want to use SQL syntax you can use the sqldf
package. See example 4 on the sqldf home page:
http://sqldf.googlecode.com
On 8/28/07, Jorge
Hi Jorge
In fact I have been working with that method. I made a simple R function to
apply it, and I'm sending you the code below. If you have any questions about
it just send me a message.
Cheers
Alberto
On Tuesday 28 August 2007 8:44 pm, Jorge Cornejo Donoso wrote:
Hi, I�m looking for
Hi Mark,
as last comment you may also take a look at
?summary.lm
where you will notice, that R reports two different R squares depending
on the presence or absence of an intercept term. For comparison issues
you should ensure that you use the same mathematical object.
There was a thread about
Ron Crump wrote:
Hi,
I have a dataframe that contains pedigree information;
that is individual, sire and dam identities as separate
columns. It also has date of birth.
These identifiers are not numeric, or not sequential.
Obviously, an identifier can appear in one or two columns,
Chris wrote:
Typically, people in the R community are not used to the spreadsheet
paradigm and need some time to be able to take advantage of
automatic recalculation, (...)
Do you know what's in my wish list?
I wish spreadsheets and computer languages had gone one
step further.
I mean,
Hi R users,
Is there a function in R, which does some calculation only for the month
end in a daily data?... In other words, is there a command in R,
equivalent to last. function in SAS?
BR, Shubha
[[alternative HTML version deleted]]
Hi,
Perhaps if object is of the type 'ts', the command 'end' can usefully.
--
Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40 S 49° 16' 22 O
On 29/08/2007, Shubha Vishwanath Karanth [EMAIL PROTECTED] wrote:
Hi R users,
Is there a function in R, which does some calculation only for
--- Rolf Turner [EMAIL PROTECTED] wrote:
On 28/08/2007, at 7:16 PM, J Dougherty wrote:
snip
PS, I quit using Excel for most important work
after it returned a
negative
variance on some data I was collecting descriptive
statistics on.
Those of you who have not seen it
But my dataset is a data frame
BR, Shubha
From: Henrique Dallazuanna [mailto:[EMAIL PROTECTED]
Sent: Wednesday, August 29, 2007 5:12 PM
To: Shubha Vishwanath Karanth
Cc: r-help@stat.math.ethz.ch
Subject: Re: [R] Month end calculations
Hi,
Perhaps if
I have run into some surprising behaviour when plotting data in a 3x2
grid:
random parts of the data on my graphs aren't rendered. Not on screen,
not on file,
and not when I send the plot to a printer. I don't get any error
messages either.
When I do the individual plots (not in a grid) they
Then, you can try:
For example:
head(df)
datevalue
1 1990-01-01 4.716572
2 1990-02-01 3.418355
3 1990-03-01 1.982209
4 1990-04-01 3.974942
5 1990-05-01 6.624222
6 1990-06-01 5.729092
max(as.Date(df$date))
or if you interest is in the month only:
max(format.Date(as.Date(df$date),
Hello, I would like to plot a histogram with title Return, and I would like
the font for the title to be Bold and the size to be 8( as in Excel).
I tried the following code, but it does not make any change. Could anyone
give me some advice?
hist (preturn, seq(-0.05,0.05,0.005),freq = FALSE,
Vikas Rawal wrote:
I need to compute weighted descriptive statistics (mean, median,
variance) for a vector of data disaggregated by a set of index
variables. The weights to be used are vector in the same data frame
and have to be disaggregated by the same index variables.
Package Hmisc has
Take a look at Mathematica or Maple. This is the kind of thing you do
with these languages.
Best,
Philippe Grosjean
Alberto Monteiro wrote:
Chris wrote:
Typically, people in the R community are not used to the spreadsheet
paradigm and need some time to be able to take advantage of
Hi,
I keep on trying to write some small scripts in order to learn R but even
with basic scripts I have problems ...
I start with the name of a file which is in fact the time the file has been
generated (I cannot change the format). Then I convert namefile with
strptime. The problem occurs when
Hi Yuchen,
I'm not sure my message will help you but who knows (I'm a newbie : I
discovered R one month ago).
To load data file, I use
donnees-read.table(datafile.dat, quote=\, sep=;, dec=,, skip=18)
and I don't need to tell when to stop. R knows it.
Good luck,
Ptit Bleu.
Yuchen Luo wrote:
Try chron:
library(chron)
namefile - 070707050642.dat#day-month-year-hour-minute-second.dat
x - chron(substr(namefile, 1, 6), substr(namefile, 7, 12),
+ format = c(dmy, hms), out.format = c(m/d/y, h:m:s))
c(x, x)
[1] (07/07/07 05:06:42) (07/07/07 05:06:42)
See R News 4/1 Help Desk
On Tue, 28 Aug 2007, hui xie wrote:
hi everyone:
I have a Dell Server that has a Xeon processor, and I would like to use
the best ATLAS posted in the R website. I find that R has ATLAS for
core2duo and P4. I am not sure which one of these two is best suited for
Xeon processor, or is that
Thanks Gabor !
It works.
Just one more thing : is there a possibility to remove ( and ) before I
copy the data to a MySQL database.
Again thank you for the tip.
Ptit Bleu.
Gabor Grothendieck wrote:
Try chron:
library(chron)
namefile - 070707050642.dat
To get a confidence interval on lambda, you need to have measures of
variability in the elements of the transition matrix. If you have that, you can
use a parametric bootstrap to get approximate confidence intervals. I have done
this, and it seems to work. Alternatively, you could calculate a
Simon Blomberg s.blomberg1 at uq.edu.au writes:
To get a confidence interval on lambda, you need to have measures of
variability in the elements of the
transition matrix. If you have that, you can use a parametric bootstrap to get
approximate confidence
intervals. I have done this, and it
Birgit Lemcke [EMAIL PROTECTED] writes:
Hello,
sorry that I interfer, but I tried to do this
The SymTest matrix:
A B C D E F G
A 0.3 0.1 0.5 0.7 0.2 0.8 0.1
B 0.1 0.5 0.4 0.6 0.7 0.3 0.7
C 0.5 0.4 0.3 0.5 0.1 0.1 0.5
D 0.7 0.6 0.5 0.4 0.3 0.5 0.7
E 0.2 0.7 0.1 0.3 0.5
In french, I wouls say Chapeau bas. In english, no idea. So I just say
Thanks again.
Ptit Bleu (reading chron reference manual :-).
Try
fmt - function(x) with(month.day.year(x),
sprintf(%02d/%02d/%02d %02d:%02d:%02d, month, day, year,
hours(x), minutes(x),
[EMAIL PROTECTED] wrote:
...
Here are a few additional comments related to the representation issue in
.csv files:
What is said about the .csv files with respect to rounding also holds for the
windows clipboard but not for the office clipboard. If you format data in an
excel range,
Try
fmt - function(x) with(month.day.year(x),
sprintf(%02d/%02d/%02d %02d:%02d:%02d, month, day, year,
hours(x), minutes(x), seconds(x)))
fmt(x)
On 8/29/07, Ptit_Bleu [EMAIL PROTECTED] wrote:
Thanks Gabor !
It works.
Just one more thing : is there a possibility to
This is a continuation from a previous posting of mine:
The following algorithm below is what I want to accomplish:
Z(xk) = Average(Yi, i belongs to Ik), where Ik contains all i such that for
each j, |Xi,j - xkj│≤ 2. Here, j = 1, 2 and i corresponds to the elements
in each X and/or xk
data
x1
Prof Brian Ripley wrote:
On Tue, 28 Aug 2007, hui xie wrote:
hi everyone:
I have a Dell Server that has a Xeon processor, and I would like to use
the best ATLAS posted in the R website. I find that R has ATLAS for
core2duo and P4. I am not sure which one of these two is best suited for
livia wrote:
Hello, I would like to plot a histogram with title Return, and I would like
the font for the title to be Bold and the size to be 8( as in Excel).
I tried the following code, but it does not make any change. Could anyone
give me some advice?
See ?par.
Uwe Ligges
hist
Your examples are not reproducible. Hence hard to tell what goes wrong.
There never was an R version 1.51.
Please use a current version of R and read the pposoting guide.
Uwe Ligges
Lindveld, Charles wrote:
I have run into some surprising behaviour when plotting data in a 3x2
grid:
random
This is my understanding of what is happening.
1. Standardize all the x variables to have mean 0 and variance 1 (possibly y as
well).
2. Compute the unconstrained least squares regression.
3. Sum the abs values of the b's.
That sum is the scaling factor. A bound of 1 means the sum above (and
Thanks very much for all your advice. To be clear, my OS is window XP. I bought
this server last year. It's Dell Precision PWS690. THe processor is Xeon(TM)
CPU 3GHZ, 2G RAM. I am not sure how to check more details of processor on my
computer. But I went to Dell website and from what I can
hui xie wrote:
Thanks very much for all your advice. To be clear, my OS is window
XP. I bought this server last year. It's Dell Precision PWS690. THe
processor is Xeon(TM) CPU 3GHZ, 2G RAM. I am not sure how to check
more details of processor on my computer. But I went to Dell website
and
[Alberto Monteiro]
Maybe I'll write a letter to Santa Claus [there are people
who write to congressman; they must have more faith than me].
:-) :-)
I wish a language where I can write
a = b + 10
and then when I write
a = 20
the language automatically assigns b = 10.
METAFONT does
Dear All,
How to cite the PDF user's guide for the LIMMA package?
This is not about how to cite the LIMMA package.
Roger
Roger L. Vallejo, Ph.D.
Computational Biologist Geneticist
U.S. Department of Agriculture, ARS
National Center for Cool Cold Water Aquaculture
11861 Leetown Road
I have a cox.obj named obj,
obj - coxph( Surv(time, status) ~ group, surv.data)
now I want to retrieve the p-value from obj, so that I can run this hundreds
of times and plot out the distribution of the p-value. could anyone tell me
how to get p-value from obj?
thanks,
--
View this message in
Dear John,
In the link that you provide, I do not see an example on referencing the
LIMMA package. Perhaps I am not being clear on my question. Again, I am
publishing a paper (Genetics journal) and I would like to reference the
User's Guide for the Limma Package which is this PDF document:
limma:
This depends on what style manual you , your
publisher, or your institution uses. One common syle
(APA ) recommends this:
http://library.osu.edu/sites/guides/apagd.php#sid
--- Vallejo, Roger [EMAIL PROTECTED]
wrote:
Dear All,
How to cite the PDF user's guide for the LIMMA
package?
This
str() is your friend. It tells you about the structure of any R object, from
which you can usually glean what you need to know to get what you want. It
is often useful to use it on summary(object) rather than on the object, as
the summary method for an (S3) classed object often contains what
I tried obj$p, obj$pvalue, but they both returned null~~
clearsky wrote:
I have a cox.obj named obj,
obj - coxph( Surv(time, status) ~ group, surv.data)
now I want to retrieve the p-value from obj, so that I can run this
hundreds of times and plot out the distribution of the p-value.
See the source code of function:
survival:::print.coxph
--
Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40 S 49° 16' 22 O
On 29/08/2007, clearsky [EMAIL PROTECTED] wrote:
I tried obj$p, obj$pvalue, but they both returned null~~
clearsky wrote:
I have a cox.obj named obj,
Except for the ability to perform circular recalculation, I believe that the
closest programming analogy to a spreadsheet is a functional programming
language. Check out Haskell (or LISP or Erlang) to do what you describe.
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL
Dear All,
I am trying to see if there is a package that will allow ALR within GEE for
R. I have found V J Carey of Harvard's page, but it seems out of data.
Does anyone know of such a package?
Sincerely
Russell Barbour Ph.D.
Co-Director for Statistical Analysis
Yale Center for
Thanks, Bert . It is a lot help!
gunter.berton wrote:
str() is your friend. It tells you about the structure of any R object,
from
which you can usually glean what you need to know to get what you want. It
is often useful to use it on summary(object) rather than on the object, as
the
Folks,
I wonder if anything could be said about the distribution of a random variate
x, where
x = N(0,1)/N(0,1)
Obviously x is pathological because it could be 0/0. If we exclude this point,
so the set is {x/(0/0)}, does x have a well defined distribution? or does it
exist a distribution
The subject says it all really: I've tried hitting control-C (multiple
times), but that doesn't seem to be a reliable way to interrupt a long
calculation. What is the right way to interrupt a calculation that has
been proceeding for several minutes and shows no sign of finishing
soon?
Hello,
sum(data.frame(),na.rm=TRUE) still throws an Error, is this really the
intended behavior?
sum(data.frame())
Error in FUN(X[[1L]], ...) : only defined on a data frame with all
numeric or complex variables
sum(data.frame(),na.rm=TRUE)
Error in FUN(X[[1L]], ...) : only defined on a data
Dear R community,
I have two questions concerning barplots that I struggle to resolve:
1) How can I break (interrupt) the x-axis (e.g.: have it display values from
-100 to -90 and 90 to 100 only)?
2) I overlay two horizontal barplots: one with negative values only and one
with positive
On Wed, Aug 29, 2007 at 10:39:17AM -0700, Horace Tso wrote:
Folks,
I wonder if anything could be said about the distribution of a random variate
x, where
x = N(0,1)/N(0,1)
Obviously x is pathological because it could be 0/0. If we exclude this
point, so the set is {x/(0/0)}, does x
On 29-Aug-07 17:39:17, Horace Tso wrote:
Folks,
I wonder if anything could be said about the distribution of a random
variate x, where
x = N(0,1)/N(0,1)
Obviously x is pathological because it could be 0/0. If we exclude this
point, so the set is {x/(0/0)}, does x have a well defined
On Wed, 29 Aug 2007, Horace Tso wrote:
Folks,
I wonder if anything could be said about the distribution of a random variate
x, where
x = N(0,1)/N(0,1)
Instead of asking this off topic question here try googling
'gaussian ratio'
Obviously x is pathological because it could be
On 29/08/2007, D. R. Evans [EMAIL PROTECTED] wrote:
The subject says it all really: I've tried hitting control-C (multiple
times), but that doesn't seem to be a reliable way to interrupt a long
calculation. What is the right way to interrupt a calculation that has
been proceeding for several
Excel bashing can be fun but also can be dangerous because
you are makeing your life harder than necessary.
Statisticians meanwhile know that the numerics of statistical
computation can be quite bad, therefore one should not use them.
But using our (we = Thomas Baier + Erich Neuwirth) RExcel addin
Thank you Ted, Daniel, and Charles. I thought Cauchy distribution has to do
with resonance. Didn't know this nice extension.
H.
Ted Harding [EMAIL PROTECTED] 8/29/2007 11:02 AM
On 29-Aug-07 17:39:17, Horace Tso wrote:
Folks,
I wonder if anything could be said about the distribution of a
Erich:
This is not a comment either for or against the use of Excel. I only wish to
point out that AFAICS, Hadley Wickham's reshape package offers all the pivot
table functionality and more.
If I am wrong about this, please let me and everyone else know.
Bert Gunter
Genentech Nonclinical
You would still need the interactive GUI to get to the point where its
at all comparable to Excel. Using rpad you could construct such
an interface although its a bit of work. Here is an example using
rpad and reshape:
http://www.rpad.org/Rpad/DataExplorer.Rpad
On 8/29/07, Bert Gunter [EMAIL
Erich Neuwirth said:
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of Erich Neuwirth
Sent: Wednesday, August 29, 2007 12:43 PM
To: r-help
Subject: Re: [R] Excel
Excel bashing can be fun but also can be dangerous because
you are makeing your
On 30/08/2007, at 8:49 AM, Greg Snow wrote:
Erich Neuwirth said:
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of Erich Neuwirth
Sent: Wednesday, August 29, 2007 12:43 PM
To: r-help
Subject: Re: [R] Excel
Excel bashing can be fun but also can be
Hi everyone,
I am quite new to R.
my command is
t.test(c(1:5,7:11), y=c(1:10),alternative = c(two.sided), paired = TRUE)
The output is
Paired t-test
data: c(1:5, 7:11) and c(1:10)
t = 3, df = 9, p-value = 0.01496
alternative hypothesis: true difference in means is not equal to 0
95
You need to save the output in order to do something with it (the
default if you don't save the output is to call the print method, so
what you are seeing is the results of calling print.htest on the return
value from t.test).
Save the output by doing something like:
out - t.test(c(1:5,7:11),
On 30/08/2007, at 8:53 AM, kurt Zhao wrote:
Hi everyone,
I am quite new to R.
my command is
t.test(c(1:5,7:11), y=c(1:10),alternative = c(two.sided), paired
= TRUE)
The output is
Paired t-test
data: c(1:5, 7:11) and c(1:10)
t = 3, df = 9, p-value = 0.01496
alternative
Rusers,
I am trying to append multiple .csv files of different dimensions (but
# of columns are the same for all .csv files). I do have .csv files
whose names are CA1.csv ~ CA100.csv. CA means california and 1 means
the first file. So what I have been doing (after googling how to append
by
On 30/08/2007, at 9:41 AM, [EMAIL PROTECTED] wrote:
Rusers,
I am trying to append multiple .csv files of different dimensions (but
# of columns are the same for all .csv files). I do have .csv files
whose names are CA1.csv ~ CA100.csv. CA means california and 1 means
the first file. So
On 8/29/07, D. R. Evans [EMAIL PROTECTED] wrote:
The subject says it all really: I've tried hitting control-C (multiple
times), but that doesn't seem to be a reliable way to interrupt a long
calculation. What is the right way to interrupt a calculation that has
been proceeding for several
Greg Snow wrote:
Or do you trust all of your clients to know to use R(D)COM as well as
how to install and use it?
Do you trust your clients to be fluent enough in R to use it?
For most of my clients, that is not true.
For this kind of users, the following strategy works.
They have their
Please look again at the help files for summarize and wtd.mean which
show how to do this.
This is from the summarize help file:
FUN: a function of a single vector argument, used to create the
statistical summaries for 'summarize'. 'FUN' may compute any
number of
In the help file for summarize
in the examples section search for the following line
# Get stratified weighted means
Vikas Rawal wrote:
Please look again at the help files for summarize and wtd.mean which
show how to do this.
--
Erich Neuwirth, University of Vienna
Faculty of Computer
Rolf Turner wrote:
On 30/08/2007, at 8:49 AM, Greg Snow wrote:
Erich Neuwirth said:
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of Erich Neuwirth
Sent: Wednesday, August 29, 2007 12:43 PM
To: r-help
Subject: Re: [R] Excel
Excel bashing can be
I'm puzzled by a phenomenon that I have just encountered, and was
hoping that someone
out there might be able to give me some insight. It's not an R
problem as such, but .
well, there are R aspects.
I have a rather messy data set, with a response, a fixed effect, and
3 random effects:
Dear list,
I have a series of data points which I want to approximate with exactly two
linear functions. I would like to choose the intervals so that the total
deviation from my fitted lines is minimal. How do I best do this?
Thanks!
Kamila
The information transmitted in this electronic
I think that one big problem of Excel regarding readability of the
calculation done is its non linear nature: mixing data and calculation
on a 2D grid could look nice at first sight, but indeed, it turns into a
nightmare to understand all the calculations actually done.
On the counterpart,
On Wed, 29 Aug 2007, Naxerova, Kamila wrote:
Dear list,
I have a series of data points which I want to approximate with exactly two
linear functions. I would like to choose the intervals so that the total
deviation from my fitted lines is minimal. How do I best do this?
From the information
On 30/08/2007, at 12:45 PM, Naxerova, Kamila wrote:
Dear list,
I have a series of data points which I want to approximate with
exactly two
linear functions. I would like to choose the intervals so that the
total
deviation from my fitted lines is minimal. How do I best do this?
hello,
I would like ot post questions to this list
so i am sending my email
Thanks
Luke Neraas
[[alternative HTML version deleted]]
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the
Hello,
I have two data frames, X and Y, with two columns each and different numbers
of rows.
# creation of data frame X
Loc1.alleles - c(1,5,6,7,8)
Loc1.Freq- c(0.35, 0.15, 0.05, 0.10, 0.35)
Loc1 - cbind( Loc1.alleles,Loc1.Freq)
X- data.frame(Loc1)
#creation
matrix(Y[,2]%o%X[,2],ncol=1)
On Wednesday 29 August 2007 03:21 pm, Luke Neraas wrote:
Hello,
I have two data frames, X and Y, with two columns each and different numbers
of rows.
# creation of data frame X
Loc1.alleles - c(1,5,6,7,8)
Loc1.Freq- c(0.35, 0.15, 0.05,
Below is one way to do this:
Loc1.alleles - c(1,5,6,7,8)
Loc1.Freq- c(0.35, 0.15, 0.05, 0.10, 0.35)
Loc1 - cbind( Loc1.alleles,Loc1.Freq)
X- data.frame(Loc1)
Loc2.alleles - c(1,4,6,8)
Loc2.Freq - c(0.35, 0.35, 0.10, 0.20)
Loc2 -
This question is related to the filehash package only.
I would like to use the filehash package because of it's ability to deal
with large amounts of data. I've set up a filehash database on a network
drive and populated it with several GB of data. Somehow, I must have
corrupted the files
[I've cc'ed this to the list because I think that it may be of value to
other useRs, at least for archiving purposes.]
Sorry, I did that work a long time ago in XLispStat (before I switched
to R). The delta method and the bootstrap method for standard errors for
eigenvalues are described in
Hi Shubha,
By using the tautology that the end of a month is immediately followed
by the first of a month, the following returns a TRUE when the date is
the last day of a month
IsMonthEnd - format(MyDates + 1, %d) == 01
where MyDates is a vector, or column in a data frame, typed as Date
(eg
Description of what I am trying to do:
I am using the xyplot code below to plot the variable “MeanBxg” against the
variable “PercentVarExplained” for all 9 possible combinations of variables
“bdg” and “bdx”. Within each of these 9 scenarios I am plotting a separate
line for each of up to 9
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