Geoffrey == Geoffrey Zhu [EMAIL PROTECTED]
on Tue, 26 Dec 2006 10:05:55 -0600 writes:
Geoffrey I meant x[i] - x[i-1] + y[i-1] and Y[i] - y[i-1] + x[i] below.
Geoffrey The mailing list software just keep adding 3D's. Sorry.
It's not the mailing list software - not per se at least.
Hi Everyone,
I am stuck with a simple problem. Suppose I have a vector x, and I want
to calculate y[i]=3Dx[i+1]-x[i], it is very easy. I just need to write
y-x[2:length(x)]-x[1:length(x)-1].
Now if I know y, and want to know the vector x defined by
x[i]=3Dx[i-1]+y[i-1] for all i, how can I do
x[i]=3Dx[i-1]+y[i-1] for all i, how can I do this without a loop?
It looks like
x - cumsum(y)
What does 3D mean?
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PROTECTED]
Sent: Tuesday, December 26, 2006 9:56 AM
To: Geoffrey Zhu; r-help@stat.math.ethz.ch
Subject: Re: [R] vectorizing an iterative process.
x[i]=3D3Dx[i-1]+y[i-1] for all i, how can I do this without a loop?
It looks like
x - cumsum(y)
What does 3D mean
x[i]=3Dx[i-1]+y[i-1] for all i, how can I do this without a loop?
It looks like
x - cumsum(y)
What does 3D mean?
The =3D is probably an encoding error - it should just be =.
In general to vectorise an iterative problem, you will need to solve
the recurrence relation
-help@stat.math.ethz.ch
Subject: Re: [R] vectorizing an iterative process.
Hi Richard,
3D is automatically generated by the mailing list software, probably
because I had ] followed by =3D3D without a space in the original post.
What I meant was to calculate x[i] =3D3D x[i-1] + y[i-1]
For example
-help@stat.math.ethz.ch
Subject: Re: [R] vectorizing an iterative process.
I meant x[i] - x[i-1] + y[i-1] and Y[i] - y[i-1] + x[i] below.
The mailing list software just keep adding 3D's. Sorry.
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of Geoffrey Zhu
Yes, this solves my problem. Thanks for your help.
-Original Message-
From: Christos Hatzis [mailto:[EMAIL PROTECTED]
Sent: Tuesday, December 26, 2006 10:58 AM
To: Geoffrey Zhu; r-help@stat.math.ethz.ch
Subject: RE: [R] vectorizing an iterative process.
In your case, the recurrence
. Heiberger [mailto:[EMAIL PROTECTED]
Sent: Tuesday, December 26, 2006 9:56 AM
To: Geoffrey Zhu; r-help@stat.math.ethz.ch
Subject: Re: [R] vectorizing an iterative process.
x[i]=3D3D3Dx[i-1]+y[i-1] for all i, how can I do this without a loop?
It looks like
x - cumsum(y)
What does 3D
