Try this:
with(subset(data, x 0), summary(y + z))
On 5/18/07, Vadim Ogranovich [EMAIL PROTECTED] wrote:
Hi,
When using evalq to evaluate expressions within a say data.frame context I
often wish there was a 'subset' argument, much like in lm() or any ather
advanced regression model. I
: Gabor Grothendieck [EMAIL PROTECTED]
To: Vadim Ogranovich [EMAIL PROTECTED]
Cc: r-help@stat.math.ethz.ch
Sent: Friday, May 18, 2007 9:19:49 AM (GMT-0600) America/Chicago
Subject: Re: [R] subset arg in (modified) evalq
Try this:
with(subset(data, x 0), summary(y + z))
On 5/18/07, Vadim
this to the columns I actually need.
Thanks,
Vadim
- Original Message -
From: Gabor Grothendieck [EMAIL PROTECTED]
To: Vadim Ogranovich [EMAIL PROTECTED]
Cc: r-help@stat.math.ethz.ch
Sent: Friday, May 18, 2007 9:19:49 AM (GMT-0600) America/Chicago
Subject: Re: [R] subset arg
, May 18, 2007 9:53:26 AM ( GMT-0600 ) America/Chicago
Subject: Re: [R] subset arg in (modified) evalq
I would check your performance assumption with an actual test before
concluding such but at any rate subset does have a select argument. See
?subset
On 5/18/07, Vadim Ogranovich vogranovich
]
To: Vadim Ogranovich [EMAIL PROTECTED]
Cc: r-help@stat.math.ethz.ch
Sent: Friday, May 18, 2007 9:53:26 AM (GMT-0600) America/Chicago
Subject: Re: [R] subset arg in (modified) evalq
I would check your performance assumption with an actual test before
concluding such but at any rate subset does have
