for your time and suggestion.
On 4/26/07, Duncan Murdoch [EMAIL PROTECTED] wrote:
On 4/26/2007 5:21 PM, xpRt.wannabe wrote:
I made a few slight modifications to the original model in an effort
to see the inner workings of the code:
deductible - 1
coverage.limit - 2
insurance.threshold
Dear List,
Below is a simple, standard loss model that takes into account the
terms of an insurance policy:
deductible - 15
coverage.limit - 75
insurance.threshold - deductible + coverage.limit
tmpf - function() {
loss - rlnorm(rpois(1, 3), 2, 5)
sum(ifelse(loss insurance.threshold, loss -
(accept payout, ifelse(loss insurance.threshold, loss -
coverage.limit, pmin(loss, deductible)), 0))
}
net - replicate(100, tmpf())
On 4/26/07, Duncan Murdoch [EMAIL PROTECTED] wrote:
On 4/26/2007 12:48 PM, xpRt.wannabe wrote:
Dear List,
Below is a simple, standard loss model
.
Any further suggestions would be greatly appreciated.
On 4/26/07, Duncan Murdoch [EMAIL PROTECTED] wrote:
On 4/26/2007 2:31 PM, xpRt.wannabe wrote:
Just to be sure, is what I have below the right intepretation of your
suggestion:
Yes, that's what I suggested.
Duncan Murdoch
deductible
])
sub4.m[unlist(lapply(sub4.m, function(x) length(x) 0))]
[[1]]
[1] 5
Patrick Burns
[EMAIL PROTECTED]
+44 (0)20 8525 0696
http://www.burns-stat.com
(home of S Poetry and A Guide for the Unwilling S User)
xpRt.wannabe wrote:
Yet another question:
Let's say I do the following
Dear List,
The following code produces a list, which is what I what:
set.seed(123)
tmpf - function() {
x - rpois(rpois(1,4),2)
}
n - 3
m - replicate(n,tmpf())
m
[[1]]
[1] 3 2 4
[[2]]
[1] 0 2 4 2 2 5 2
[[3]]
[1] 2 0 4 1 0
Now I need something that would to extract iteratively (or as many
] 2 0 4 1 0
lapply(m, function(x)x[x2])
[[1]]
[1] 3 4
[[2]]
[1] 4 5
[[3]]
[1] 4
On 8/25/06, xpRt.wannabe [EMAIL PROTECTED] wrote:
Dear List,
The following code produces a list, which is what I what:
set.seed(123)
tmpf - function() {
x - rpois(rpois(1,4),2)
}
n - 3
[[3]]
[1] 2 0 4 1 0
lapply(m, function(x)x[x2])
[[1]]
[1] 3 4
[[2]]
[1] 4 5
[[3]]
[1] 4
On 8/25/06, xpRt.wannabe [EMAIL PROTECTED] wrote:
Dear List,
The following code produces a list, which is what I what:
set.seed(123)
tmpf - function() {
x
Dear List,
I am trying to fit Truncated Lognormal to a data set that is
'truncated' from above a certain value, say, 0.01. Below is what I
was able to come up with. I would appreciate it if you could review
and make any necessary changes.
# This is modified off the code for 'dtnorm' of
- rnorm(rpois(1,5))
sum(ifelse(x90,x-75,pmin(x,15)))
}
replicate(10,replicate(8,tmpf()))
On 6/2/06, Uwe Ligges [EMAIL PROTECTED] wrote:
xpRt.wannabe wrote:
Dear List:
I have the follow code:
y - replicate(10,replicate(8,sum(rnorm(rpois(1,5)
Now I need to apply the following
Dear List:
I have the follow code:
y - replicate(10,replicate(8,sum(rnorm(rpois(1,5)
Now I need to apply the following condition to _every_ randomly generated
Normal number in the code above:
x - max(0,x-15) + max(0,x-90), where x represents the individual Normal
numbers.
In other words,
Dear List,
I have some S-PLUS script files (.ssc). Does there exist an R
function/command that can read such files? I simply want to view the
code and practice in R to help me learn the subject matter.
Any help would be greatly appreciated.
platform i386-pc-mingw32
arch i386
os
Is there a way to show also the intermediate tick marks without the
values?
Example:
plot(cars)
What would one do to show the tick marks in, say, gray color at the
increment of 1 without showing the actual values in-between the default
x
values: 5, 10, 15, 20, 25?
platform i386-pc-mingw32
arch
Dear List,
A follow-up question related to bpplot() of the Hmisc package: How does
one
color the box , or the middle half of the data, of a box-percentile
plot?
bpplot(... , col=lightgray) apparently does not work, though
boxplot(...
, col=lightgray) works.
With much appreciation,
platform
Dear List,
I have a two-part question related to bpplot(), a box-percentile plot
function in the Hmisc package.
Take the example given in the Help for bpplot(), for instance.
(1) How does one set but not draw the y-axis? What I did was,
bpplot(... , yaxt=n), but that apparently does not work
Dear List,
I am using R to learn bootstrapping concepts. Not to be oblivious to
the
contributed packages of boot and bootstrap, I have opted to do the
following as a way to hone my R skills.
One example I am trying to work through is the following:
x - 1:20
Observed - sample(x,20)
Resamples -
Dear List,
I have the following code that does what I want:
x - replicate(5,replicate(10,sum(rnorm(rpois(1,10)
How might one change it such that the maximum value generated by
rnorm(rpois(1,10)) can be retrieved for later use?
__
,replicate(10 ... )
In the end, I expect to get 10 x 5 max values.
In that context, how might the code be changed?
On 8/11/05, jim holtman [EMAIL PROTECTED] wrote:
temp - rnorm(rpois(1,10))
x - replicate(5,replicate(10,sum(temp)))
temp - max(temp)
On 8/11/05, xpRt.wannabe [EMAIL PROTECTED
Ted and List,
In your code that produced 'mx', you dropped sum() from my original
code though. As a result, the 10 x 5 max's are of the same value.
Unfortunately, that's not what I need.
On 8/11/05, ecatchpole [EMAIL PROTECTED] wrote:
On 12/08/05 05:55, xpRt.wannabe wrote,:
Dear List
/08/05 12:17, xpRt.wannabe wrote,:
Ted and List,
In your code that produced 'mx', you dropped sum() from my original
code though. As a result, the 10 x 5 max's are of the same value.
Unfortunately, that's not what I need.
On 8/11/05, ecatchpole [EMAIL PROTECTED] wrote:
On 12/08/05
Thank you! That was helpful.
Another thing I learned was that I would need to do set.seed(99) not
once but twice in this context.
On 8/11/05, ecatchpole [EMAIL PROTECTED] wrote:
On 12/08/05 13:27, xpRt.wannabe wrote,:
Ted and List,
What I need is I need to know what max of rnorm(rpois
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