If the functionality you are thinking of already exists across multiple
packages an alternative to creating a new package would be to create
a task view as in:
http://cran.r-project.org/src/contrib/Views/
as explained in the ctv package and the article in R News 5/1.
On 7/7/05, Jose Claudio
-
发件人: Gabor Grothendieck [mailto:[EMAIL PROTECTED]
发送时间: 2005年6月6日 10:21
收件人: Ivy_Li
抄送: r-help@stat.math.ethz.ch
主题: Re: [R] fail in adding library in new version.
On 6/5/05, Ivy_Li [EMAIL PROTECTED] wrote:
Hello everybody,
Could I consult you a question?
I always use
On 7/7/05, Uwe Ligges [EMAIL PROTECTED] wrote:
Gabor Grothendieck wrote:
On 7/7/05, Uwe Ligges [EMAIL PROTECTED] wrote:
Ivy_Li wrote:
Dear all,
I have done every step as the previous mail.
1. unpack tools.zip into c:\cygwin
2. install Active perl in c:\Perl
3. install
it for
review/critique. The 'max.pow' constant can be explicitly adjusted or
can be calculated automatically based upon input year ranges.
Best regards,
Marc Schwartz
On Wed, 2005-07-06 at 17:31 -0400, Gabor Grothendieck wrote:
Not sure if I am missing something essential here
On 7/7/05, Briggs, Meredith M [EMAIL PROTECTED] wrote:
This is what to start with:
Data Frame A BC D
c1 4 y 5
c3 6 d 7
c1 5 t 6
Now sort on A then C
This is what to
is wrong?
Thanks a lot!
BG
Ivy_Li
-原始邮件-
发件人: Gabor Grothendieck [mailto:[EMAIL PROTECTED]
发送时间: 2005年7月7日 20:57
收件人: Uwe Ligges
抄送: Ivy_Li; r-help@stat.math.ethz.ch
主题: Re: 答复: 答复: [R] fail in adding library in new version.
On 7/7/05, Uwe Ligges [EMAIL PROTECTED] wrote
There is also an even larger source of examples at:
http://cran.r-project.org/src/contrib/Descriptions/
although the built caveat mentioned below applies here as well.
On 7/7/05, Gabor Grothendieck [EMAIL PROTECTED] wrote:
You cannot use an empty DESCRIPTION file.
To get more info
To be fair none of Introduction to R, ?plot nor the reference card
really cover this without substantial digging.
# test data
x - 1:10
y - x*x
plot(x[x 5], y[x 5])
# or
plot(y ~ x, subset = x 5)
# We can have combine conditions like this:
plot(y ~ x, subset = x 5 y 50)
# also if
On 7/8/05, yyan liu [EMAIL PROTECTED] wrote:
Hi:
I have two time series y(t) and x(t). I want to
regress Y on X. Because Y is a time series and may
have autocorrelation such as AR(p), so it is not
efficient to use OLS directly. The model I am trying
to fit is like
Here are some possibilities:
- head(iris) will show the first few rows of the data frame
- edit(iris) will put up a spreadsheet with the data frame in it that
you can scroll
- In JGR (a GUI front end for R) you can use the object browser (ctrl-B)
- If the object is a file rather than a data frame
Check out:
http://tolstoy.newcastle.edu.au/R/help/04/06/1430.html
http://tolstoy.newcastle.edu.au/R/help/04/06/1406.html
On 7/8/05, Jeffrey Horner [EMAIL PROTECTED] wrote:
Is this possible?
For instance, I have a function that returns a vector length 3. In one
statement I'd like to assign
trim in package gdata will trim spaces off the beginning and end.
On 7/8/05, Ling Jin [EMAIL PROTECTED] wrote:
Hi all,
I have two data frames to merge by a column containing the site names
(as characters). However, somehow, one of the site names of one data
frame have fixed length, say 8,
On 7/8/05, Bret Collier [EMAIL PROTECTED] wrote:
R-Users,
Hopefully someone can shed some light on these questions as I had
little luck searching the archives (although I probably missed something
in my search due to the search phrase). I estimated multinomial
probabilities for some count
)
curve(dnorm(x, 2.84, 1.57), min(xrange), max(xrange), add = TRUE)
On 7/8/05, Gabor Grothendieck [EMAIL PROTECTED] wrote:
On 7/8/05, Bret Collier [EMAIL PROTECTED] wrote:
R-Users,
Hopefully someone can shed some light on these questions as I had
little luck searching the archives (although I
On 7/9/05, Spencer Graves [EMAIL PROTECTED] wrote:
Lindsey's
packages are not available for all platforms and so are not available on
CRAN.
Is it true that all CRAN packages in the main repository are available on
all platforms?
(There is at least an other-software area:
On 7/9/05, Jose Claudio Faria [EMAIL PROTECTED] wrote:
Dear R users,
The solution is probably simple but I need someone to point me to it.
How can I to generate a matrix from a numeric sequence of 1:10 like 'A' or 'B'
below:
A)
||
| 1 2 3 4 5 |
On 7/10/05, Yzhar Toren [EMAIL PROTECTED] wrote:
Hi ,
I want to be able to filter out results using a string. I'm running an
automated script that reads a list of filters I get from an external
source and applys them to my data frame consecutively.
For example I want to get :
I think you could simplify this by replacing everything after the
nObjects = nrow(mds) line with just these two statements.
f - function(a,b) mapply(function(a,b)
(mds[a,] - mds[b,])%*%InvS%*%(mds[a,] - mds[b,]), a,b)
D2 - outer(seq(nObjects), seq(nObjects), f)
This also eliminates
(nObjects), f)
}
#
# test
#
D2M3 = D2Mah3(iris[,1:4], iris[,5])
On 7/10/05, Gabor Grothendieck [EMAIL PROTECTED] wrote:
I think you could simplify this by replacing everything after the
nObjects = nrow(mds) line with just these two statements.
f - function(a,b) mapply(function(a,b)
(mds
(iris[,1:4], iris[,5])
print(D2M2)
Gabor Grothendieck wrote:
I think you could simplify this by replacing everything after the
nObjects = nrow(mds) line with just these two statements.
f - function(a,b) mapply(function(a,b)
(mds[a,] - mds[b,])%*%InvS%*%(mds[a,] - mds[b,]), a,b
On 7/11/05, Duncan Murdoch [EMAIL PROTECTED] wrote:
On 7/11/2005 3:21 PM, Sundar Dorai-Raj wrote:
Hi, all,
I just recently upgraded my computer though I'm using the same OS (XP).
But now I'm having difficulty building packages and I cannot seem to
solve the problem. I'm using R-2.1.1pat
On 7/12/05, Tan Hui Hui Jenny [EMAIL PROTECTED] wrote:
Couple of questions:
1. How can I obtain the frequency tables for a histogram chart?
2. Is there a short cut to obtain the frequency polygons directly without
having to generate the frequency table and doing a line plot?
res - hist(x)
On 7/12/05, Robin Hankin [EMAIL PROTECTED] wrote:
Hi
I want to write a little function that takes a vector of arbitrary
length n and returns a matrix of size n+1 by n+1.
I can't easily describe it, but the following function that works for
n=3 should convey what I'm trying to do:
f -
On 7/12/05, Luc Vereecken [EMAIL PROTECTED] wrote:
Hi list,
For my research, I started using R as a statistics engine, driven by
perl scripts that manage my data and computational jobs. I recently
upgraded my cluster to Suse 9.2, and obviously wanted to upgrade R to
it's latest version,
On 7/12/05, Sheri Conner Gausepohl [EMAIL PROTECTED] wrote:
Good day:
I am trying to use
readcsvIts(nwr_data_qc.txt,informat=its.format(%Y%m%d%h%M
%Y),header=TRUE,sep=,skip=0,row.names=NULL,as.is=TRUE,dec=.)
to read in a file (nwr_data_qc.txt) that looks like this:
Time Y
On 7/12/05, Gabor Grothendieck [EMAIL PROTECTED] wrote:
On 7/12/05, Sheri Conner Gausepohl [EMAIL PROTECTED] wrote:
Good day:
I am trying to use
readcsvIts(nwr_data_qc.txt,informat=its.format(%Y%m%d%h%M
%Y),header=TRUE,sep=,skip=0,row.names=NULL,as.is=TRUE,dec=.)
to read in a file
-
发件人: Gabor Grothendieck [mailto:[EMAIL PROTECTED]
发送时间: 2005年7月7日 20:57
收件人: Uwe Ligges
抄送: Ivy_Li; r-help@stat.math.ethz.ch
主题: Re: 答复: 答复: [R] fail in adding library in new version.
On 7/7/05, Uwe Ligges [EMAIL PROTECTED] wrote:
Gabor Grothendieck wrote:
On 7/7/05, Uwe
On 7/12/05, klebyn [EMAIL PROTECTED] wrote:
Hello,
How to use the function plot to produce graphs as Matlab?
example in Matlab:
a = [1,2,5,3,6,8,1,7];
b = [1,7,2,9,2,3,4,5];
plot(a,'b')
hold
plot(b,'r')
How to make the same in R-package ?
I am trying something thus:
a -
'D:/PROGRA~1/R/rw2011/library/example'
I don't know why it can not find the hhc file.
Please tell me which step is wrong.
Thank you for helping me!
^_^
-原始邮件-
发件人: Gabor Grothendieck [mailto:[EMAIL PROTECTED]
发送时间: 2005年7月13日 9:32
收件人: Ivy_Li
抄送: Duncan Murdoch; r-help
On 7/13/05, Soren Wilkening [EMAIL PROTECTED] wrote:
Dear all
the regular XML package does not work correctly with the R 2.0.1 windows
version.
Can anybody indicate a suitable alternative ?
I need to dynamically read, parse and process a HTML table in R that is
available at a certain url.
On 7/13/05, Young Cho [EMAIL PROTECTED] wrote:
Hi,
I have a column of a dataframe which has time stamps
like:
eh$t[1]
[1] 06/05/2005 01:15:25
and was wondering how to convert it to chron variable.
Thanks a lot.
Try this:
# test data frame eh containing a factor variable t
eh
You could use the nlines= argument to scan to read in a
portion at a time.
On 7/13/05, Weiwei Shi [EMAIL PROTECTED] wrote:
add:
I used
trn-matrix(scan('train1.dat', sep='|', na.string='.'), nrow=273529,
ncol=195)
it is done.
so it seems that I just have no patience to wait for half
On 7/13/05, Luis Tercero [EMAIL PROTECTED] wrote:
Dear R-help community,
would any of you have a (preferably simple) example of a
presentation-quality .png plot, i.e. one that looks like the .eps plots
generated by R? I am working with R 2.0.1 in WindowsXP and am having
similar problems
[I had some email problems and am sending this again. Sorry
if you get it twice.]
You could use the nlines= argument to scan to read in a
portion at a time.
On 7/13/05, Weiwei Shi [EMAIL PROTECTED] wrote:
add:
I used
trn-matrix(scan('train1.dat', sep='|', na.string='.'),
[I had some emails problems so I am sending this again. Sorry
if you get it twice.]
On 7/13/05, Gabor Grothendieck [EMAIL PROTECTED] wrote:
On 7/13/05, Young Cho [EMAIL PROTECTED] wrote:
Hi,
I have a column of a dataframe which has time stamps
like:
eh$t[1]
[1] 06/05/2005
[I had some email problems so I am sending this again.
Sorry if you get this twice.]
On 7/13/05, Gabor Grothendieck [EMAIL PROTECTED] wrote:
On 7/13/05, Luis Tercero
[EMAIL PROTECTED] wrote:
Dear R-help community,
would any of you have a (preferably simple) example
by passing around
matrix(). Since I could not find data.frame() with nrow or ncol
arguments. so i have to use matrix first and then as.data.frame to
convert it.
is there any other (better) way?
weiwei
On 7/13/05, Gabor Grothendieck [EMAIL PROTECTED] wrote:
You could use the nlines= argument
to
convert it.
is there any other (better) way?
weiwei
On 7/13/05, Gabor Grothendieck [EMAIL PROTECTED] wrote:
You could use the nlines= argument to scan to read in a
portion at a time.
On 7/13/05, Weiwei Shi [EMAIL PROTECTED] wrote:
add:
I used
trn-matrix
On 7/13/05, Ruben Roa [EMAIL PROTECTED] wrote:
Hi:
Where is the iris data set actually
located in the R 2.1.0 folder (under W XP)?
Is it a text file or it is a binary file?
Ruben
Uwe has already explained how to get it in text
form; however, if you are curious about its original
format in R
:25)
month.day.year(.Last.value)
$month
[1] 6 6
$day
[1] 5 7
$year
[1] 2005 2005
On 7/14/05, Sean O'Riordain [EMAIL PROTECTED] wrote:
are those dates in m/d/y or d/m/y ?
?chron and watch out for
format = c(dates = d/m/y, times = h:m:s)
On 13/07/05, Gabor Grothendieck [EMAIL PROTECTED
See ?sunflowerplot for a graphic indication of
the number of replications at each point.
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
1. Try using more spaces so your code is easier to read.
2. Use data.frame to define your data frame (since the method
in your post creates data frames of factors rather than
the desired classes).
3. Given the appropriate function, f, a single 'by' statement rbind'ed
together, as shown, will
], site_id = x[1,2], visit_no = x[1,3],
mean = mean(x[,6]), sd = sd(x[,6]), length = length(x[,6]))
do.call(rbind, by(fakesub, fakesub[,1:3], f))
On 7/14/05, Gabor Grothendieck [EMAIL PROTECTED] wrote:
1. Try using more spaces so your code is easier to read.
2. Use data.frame to define
The start list should only contain parameters, not x. Also
your function appears to have multiple errors including
reference to temp (presumably intended as tmp?)
and b(x-m) which presumably should be b*(x-m).
On 7/14/05, Yimeng Lu [EMAIL PROTECTED] wrote:
Sorry that I specified the x as
I am not sure how generally this works but I was able to get it to switch
back and forth between two languages within a single R
session like this:
Sys.getenv(LANGUAGE)
LANGUAGE
q() # note English prompt; c means continue rather than exiting
Save workspace image? [y/n/c]: c
On 7/16/05, Jeff Newmiller [EMAIL PROTECTED] wrote:
I have a rather basic background in statistics, and am looking for
assistance in solving what I expect is a common type of problem.
I have measurements of physical processes, and mathematical models of
those processes that I want to feed
On 7/17/05, Kerry Bush [EMAIL PROTECTED] wrote:
Dear R-helpers,
In my data set, I have a time variable 'RecordTime'
whose class property is 'times'. When I list my data
set, I see the values of RecordTime is like 10:20:30
in a 'h:m:s' format. Suppose I want to choose all the
data after 10
On 7/17/05, Rashmi Mathur [EMAIL PROTECTED] wrote:
Hello,
How would one index vectors and matrices starting from 0 (or some other
value other than the default of 1) in R?
Check out the Oarray package and also the list archives where threads
on Oarray mention other approaches as well.
On 7/19/05, Dirk Enzmann [EMAIL PROTECTED] wrote:
Although I tried to find an answer in the manuals and archives, I cannot
solve this (please excuse that my English and/or R programming skills
are not good enough to state my problem more clearly):
I want to write a function with an
I think its likely that you are using different versions of chron.
I noticed that version 2.2-33 of chron had the statement:
tms - dts - trunc(dts)
but version 2.2-35 seems to have replaced it with:
tms - dts - floor(dts)
and that seems to be causing the problem.
As a workaround:
On 7/19/05, [EMAIL PROTECTED] [EMAIL PROTECTED] wrote:
Dear R-helpers,
I am trying to estimate a model that I am proposing, which consists of putting
an extra hidden layer in the Markov switching models. In the simplest case the
S(t) - Markov states - and w(t) - the extra hidden variables -
On 7/19/05, Gabor Grothendieck [EMAIL PROTECTED] wrote:
I think its likely that you are using different versions of chron.
I noticed that version 2.2-33 of chron had the statement:
tms - dts - trunc(dts)
but version 2.2-35 seems to have replaced it with:
tms - dts - floor(dts
in the references.
R News 4/1 Help Desk has some examples of date manipulations
in Date, chron and POSIXct in the table at the end of the article.
On 7/19/05, Gabor Grothendieck [EMAIL PROTECTED] wrote:
On 7/19/05, Gabor Grothendieck [EMAIL PROTECTED] wrote:
I think its likely that you
Is there an R function to kill a process? I found one in package
fork but it is specific to UNIX and I want something that also
works on Windows. The XP console command, taskkill,
will do it so I can easily get the effect but it won't work
on other Windows systems, even 2000 and NT. I found a
Here is an example where R is the client and Excel is the server
so that R is issuing commands to Excel. This example uses the
RDCOMClient package from www.omegahat.org:
library(RDCOMClient)
xl - COMCreate(Excel.Application) # starts up Excel
xl[[Visible]] - TRUE
See ?goodfit in package vcd.
On 7/20/05, Thomas Isenbarger [EMAIL PROTECTED] wrote:
I haven't been an R lister for a bit, but I hope to enlist someone's
help here. I think this is a simple question, so I hope the answer
is not much trouble. Can you please respond directly to this email
Check out sum.exact in the caTools package.
On 7/20/05, Vincent Goulet [EMAIL PROTECTED] wrote:
We obtained some disturbing results from convolve() (inaccuracies and negative
probabilities). We'll try to make the context clear in as few lines as
possible...
Our function panjer() (code
R expert, I have built my R library
successfully.
Especially thanks: Duncan Murdoch
Gabor Grothendieck
Henrik Bengtsson
Uwe Ligges
You are welcome.
The following is intended for the records in the archive in order to
protect
An article like that would be really great.
On 7/21/05, Uwe Ligges [EMAIL PROTECTED] wrote:
Gabor Grothendieck wrote:
I think you have been using R too long. Something like
this is very much needed. There are two problems:
1. the process itself is too complex (need to get rid
On 7/21/05, Duncan Murdoch [EMAIL PROTECTED] wrote:
On 7/21/2005 9:43 AM, Gabor Grothendieck wrote:
I think you have been using R too long. Something like
this is very much needed. There are two problems:
1. the process itself is too complex (need to get rid of perl,
integrate
Use bquote instead of expression, e.g.
trees.lm - lm(Volume ~ Girth, trees)
trees.sm - summary(trees.lm)
trees.co - round(trees.sm$coefficients,2)
trees.rsq - round(trees.sm$r.squared,2)
plot(Volume ~ Girth, trees)
text(10,60, bquote(Intercept : .(trees.co[1,1])%+-%.(trees.co[1,2])), pos = 4)
On 22 Jul 2005 00:01:18 +0200, Peter Dalgaard [EMAIL PROTECTED] wrote:
Duncan Murdoch [EMAIL PROTECTED] writes:
On 7/21/2005 9:43 AM, Gabor Grothendieck wrote:
I think you have been using R too long. Something like
this is very much needed. There are two problems:
1. the process
There have already been some good solutions but here are three
others just to see a range of approaches:
sub(^[^-]*-, , A) # remove everything up to first minus
sub(Prefix-, , A) # simplified version if prefix known
substring(A, 8) # simplification if prefix always 7 chars including minus
On
Try as.expression(bquote(...whatever...))
On 7/22/05, Dan Bolser [EMAIL PROTECTED] wrote:
On Thu, 21 Jul 2005, Marc Schwartz (via MN) wrote:
[Note: the initial posts have been re-arranged to attempt to maintain
the flow from top to bottom]
Dan Bolser writes:
I would like to
On 7/22/05, Dan Bolser [EMAIL PROTECTED] wrote:
On Fri, 22 Jul 2005, Gabor Grothendieck wrote:
Try as.expression(bquote(...whatever...))
Sob, wimper, etc.
my.slope.1 - 3.22
my.slope.2 - 0.13
my.inter.1 - -10.66
my.inter.2 - 1.96
my.Rsqua.1 - 0.97
text(2,5,
paste
On 7/22/05, Thomas Lumley [EMAIL PROTECTED] wrote:
On Fri, 22 Jul 2005, Dan Bolser wrote:
On Fri, 22 Jul 2005, Gabor Grothendieck wrote:
Try as.expression(bquote(...whatever...))
Sob, wimper, etc.
a-7
plot(1)
legend(topleft,legend=do.call(expression
- list(
Intercept:, bquote(.(my.inter.1)%+-%.(my.inter.2)),
Slope:, bquote(.(my.slope.1)%+-%.(my.slope.2))
)
text(2, c(4,4,4.25,4.25), sapply(L, as.expression), pos = c(2,4,2,4))
On 7/22/05, Gabor Grothendieck [EMAIL PROTECTED] wrote:
On 7/22/05, Thomas Lumley [EMAIL PROTECTED] wrote:
On Fri
2005, Gabor Grothendieck wrote:
I think legend accepts a list argument directly so that could be
simplified to just:
a-7
plot(1)
L - list(bquote(alpha==.(a)),bquote(alpha^2+1==.(a^2+1)))
legend(topleft,legend=L)
Except that it wouldn't then work: the mathematical stuff comes
If one modifies legend by adding a vfont=c(serif, plain) argument
to the call to text (which is within the function text2 that is defined
within legend) then one can do this:
my.slope.1 -3.22
my.slope.2 - 0.13
my.inter.1 - -10.66
my.inter.2 - 1.96
my.Rsqua -0.97
plot(1:5)
tt -
=' dosn't work. Setting this to
anything (including the default) seems to surpress the legend without
error. But hey!
Thanks again,
HTH,
Marc Schwartz
On Fri, 2005-07-22 at 14:01 -0400, Gabor Grothendieck wrote:
You are right. One would have to use do.call as you did
the same time range and have the same
frequency. With
RSiteSearch(multiple series plot)
i found this post by Gabor Grothendieck:
http://finzi.psych.upenn.edu/R/Rhelp02a/archive/42281.html
Exactly what i need except for one detail. I want one series
to be made of points and the other by a line
hhc.exe is the Microsoft help compiler. You have to download that
and then put hhc.exe somewhere in your path. The Windows
console command
path
will give you the pathnames in your current path, any of which
you could put it in.
On 7/24/05, Jordi [EMAIL PROTECTED] wrote:
Dear R users,
On 7/24/05, Prof Brian Ripley [EMAIL PROTECTED] wrote:
On Sun, 24 Jul 2005, Jordi wrote:
I am having problems building R packages in Windows xp. I have followed the
instructions from Peter E. Rossi in Documentation - Other, except for the
Better to follow the accurate official
Check out:
?arima
Also:
http://cran.r-project.org/doc/contrib/Ricci-refcard-ts.pdf
http://cran.r-project.org/src/contrib/Views/
Depending on what you need the dyn package, not mentioned in
the above, may also be useful.
On 7/25/05, Paolo Bulla [EMAIL PROTECTED] wrote:
Hallo to everyone,
Numbers, not in characters strings do not come out bold:
plot(1:5, type = n)
text(x=3,y=3, quote(bold(paste(a==a ~~ 0.5 == 0.5
On 7/25/05, Wladimir Eremeev [EMAIL PROTECTED] wrote:
Dear Thomas,
TL In case 1 you have the string 0.5, in case 2 you have the number 0.5.
TLtext(x=2,y=2,
On 30 Jul 2005 09:16:26 +0200, Peter Dalgaard [EMAIL PROTECTED] wrote:
Gabor Grothendieck [EMAIL PROTECTED] writes:
Numbers, not in characters strings do not come out bold:
plot(1:5, type = n)
text(x=3,y=3, quote(bold(paste(a==a ~~ 0.5 == 0.5
(what's the paste() for?)
I had
You could set the source attribute like this:
R f - function(x) x+1
R # displays the word hidden instead of showing the source
R attr(f, source) - hidden
R f
hidden
R f(10) # still works as a function properly
[1] 11
Of course, someone knowledgable could change the source
attribute back but
Another way to do it is:
sub([.].*, .41, x)
This says to replace the first dot and everything after by .41. When . appears
in a character class, i.e. [.], then you don't need backslashes. Also
you don't need backslashes in the second argument.
On 7/30/05, Uwe Ligges [EMAIL PROTECTED]
On 7/30/05, Marco Blanchette [EMAIL PROTECTED] wrote:
I am fairly new to R and I am writing a script that would take a file, as an
input, and generates a bunch of graphs out of it. My first task is to be
sure that the file is of the right type by looking if there is a valid
barcode in it as in
Another approach is the Bell Labs graphviz system. See
http://www.graphviz.com
For an example of using it from R, see the dot.proto function
in the 'proto' package. dot.proto generates dot language output
to draw a graphviz graph of the objects in any R program written
using 'proto'.
Note that if the only difference is the addition of ... to the formal arguments
then you can just do this once in your session before using farimaSim:
formals(farimaSim) - c(formals(farimaSim), alist(... = ))
Now farimaSim will have ... as an argument. e.g.
formals(farimaSim) -
On 8/1/05, Haibo Huang [EMAIL PROTECTED] wrote:
Hi, when I used:
Dist=read.csv(test.csv,header=TRUE)
to read data from CSV file. For some cells, R
mistakenly put in as NA, while most of the cells still
Its not likely that there are errors in this software so
its probably not a mistake but
Check out the quantreg package.
On 8/1/05, Chunyu Yang {msbbb062} [EMAIL PROTECTED] wrote:
Dear R users,
I wonder if there are some functions or packages in R that can perform
regression under absolute error loss. I have searched the full manual of
R, but can not find it. I really
Assuming, as in your post:
set.seed(123)
mychron - chron(sort(runif(10, 0, 10)))
breaks - quantile(mychron)
# is one of these adequate?
cut(mychron, breaks)
cut(unclass(mychron), unclass(breaks), lab = FALSE)
On 8/2/05, Sebastian Luque [EMAIL PROTECTED] wrote:
Hello,
I've encountered
Try this. The regular expression says to match
- anything
- followed by a double underscore
- followed by one or more digits
- followed by an underscore
- followed by anything.
The digits have been parenthesized so that they can be referred to in
the backreference \\1.Also use the R
Note that we can omit the second argument to substitute as
in this case since they will be given by the default.
On 8/3/05, Sundar Dorai-Raj [EMAIL PROTECTED] wrote:
Eric Archer wrote:
List gurus,
I'm trying to code a Gompertz growth curve function as part of a larger
project and
Check out:
http://finzi.psych.upenn.edu/R/Rhelp02a/archive/18289.html
On 8/4/05, nwew [EMAIL PROTECTED] wrote:
Dear R-helpers,
The function optim implements algorithms that I would like to use.
I have function implemented in R, which given the parameters of which
minimization is to
On 8/4/05, Jose Claudio Faria [EMAIL PROTECTED] wrote:
Hi all,
I would like to suggest that all R functions/etc like:
codes-deprecated
grid-internal
ns-alt
ns-dblcolon
ns-hooks
ns-internals
ns-lowlev
ns-reflect.Rd
tools-internal
ts-defunct
utils-deprecated
On 8/4/05, Gabor Grothendieck [EMAIL PROTECTED] wrote:
On 8/4/05, Jose Claudio Faria [EMAIL PROTECTED] wrote:
Hi all,
I would like to suggest that all R functions/etc like:
codes-deprecated
grid-internal
ns-alt
ns-dblcolon
ns-hooks
ns-internals
ns-lowlev
ns
On 8/4/05, Matt Crawford [EMAIL PROTECTED] wrote:
I understand that in R, for loops are not used as often as other
languages, and am trying to learn how to avoid them. I am wondering
if there is a more efficient way to write a certain piece of code,
which right now I can only envision as a
On 8/5/05, Knut Krueger [EMAIL PROTECTED] wrote:
Gabor Grothendieck schrieb:
On 7/13/05, Luis Tercero [EMAIL PROTECTED] wrote:
Dear R-help community,
would any of you have a (preferably simple) example of a
presentation-quality .png plot, i.e. one that looks like the .eps plots
On 8/5/05, Gabor Grothendieck [EMAIL PROTECTED] wrote:
On 8/5/05, Knut Krueger [EMAIL PROTECTED] wrote:
Gabor Grothendieck schrieb:
On 7/13/05, Luis Tercero [EMAIL PROTECTED] wrote:
Dear R-help community,
would any of you have a (preferably simple) example
On 8/8/05, Clark Allan [EMAIL PROTECTED] wrote:
hi all
are we able to combine column vectors of different lengths such that the
result appears in matrix form?
e.g.
a=1
b=1:3
d=1:4
then
z=CBIND(a,b,d)
1 1 1
2 2
3 3
4
i stil want the following!
z[,1]=1
On 8/8/05, Gabor Grothendieck [EMAIL PROTECTED] wrote:
On 8/8/05, Clark Allan [EMAIL PROTECTED] wrote:
hi all
are we able to combine column vectors of different lengths such that the
result appears in matrix form?
e.g.
a=1
b=1:3
d=1:4
then
z=CBIND(a,b,d)
1 1 1
On 8/8/05, Krishna [EMAIL PROTECTED] wrote:
Hi Everyone
May I request for a small help while performing the regression analysis.
I would like to know is there any possibility of conducting the
regression for different data subsets (in the same data file),
classified on the basis of
On 8/8/05, Peter Yang [EMAIL PROTECTED] wrote:
Hi,
I would like to get the coefficient of polynomial expansion. For example,
(1+ x)^2 = 1 + 2x + x^2, and the coefficients are 1, 2 and 1.
(1 + x + x^2)^3 = 1 + 3*x + 6*x^2 + 7*x^3 + 6*x^4 + 3*x^5 + x^6, and
the coefficients are 1, 3, 6, 7,
Small point but since:
- the paste function will convert its arguments to character
- as.Date will give you the format requested anyways
- minus is the logical separator here
we could modify that to:
as.Date(paste(d, 15, sep = -))
On 8/10/05, bogdan romocea [EMAIL PROTECTED] wrote:
Note that even if you decide that this distinction is applicable,
you may still wish to run a linear model prior to
nls to get the starting values.
On 8/10/05, Dimitris Rizopoulos [EMAIL PROTECTED] wrote:
I think here it's important to consider how the errors term come into
the model. If y =
On 8/10/05, Prof Brian Ripley [EMAIL PROTECTED] wrote:
On Wed, 10 Aug 2005 [EMAIL PROTECTED] wrote:
Thompson's Manual to Accompany Agresti's book refers to a package named
repeated. It's not on CRAN from what I can see. I have seen rpm's for
it. Where is the best place to download this
David, Please correct me if I am wrong but I think svm partially works
with dyn although I don't remember what the specific limitations were.
Its possible that what works already is enough for Amir. For example,
library(e1071)
library(dyn)
set.seed(1)
y - ts(rnorm(100))
y.svm - dyn$svm(y ~
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