better if I just use the order from the form. It seems
a shame that the servlet API discards the data. (At least that is
what I gathered from the previous thread.)
Thank You,
Bob Byron
- Original Message -
From: Sean Tiley [EMAIL PROTECTED]
Problem is that the form fields
was able to successfully
forward inside my own site though. But I do need to forward to a different
site. Is there any way for me to do this?
I am in http://websiteone.com/someservlet; and want to forward back to
http://anotherwebsite.com/somepage.html;.
Thank You,
Bob Byron
Thank you Craig!
Of course I just sent out a renewed plea for help. Murphy's
Law. I checked for email, sent out my new plea, and
then received your email.
I will be utilizing this technique. Thanks for the info.
Bob Byron
- Original Message -
From: Craig R. McClanahan [EMAIL
Does the resource need to be mapped in the web.xml file?
Bob
- Original Message -
From: Craig R. McClanahan [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Wednesday, October 03, 2001 11:28 AM
Subject: Re: Open a file?
On Tue, 2 Oct 2001, Bob Byron wrote:
Date: Tue, 2 Oct 2001
Does the resource need to be defined in the web.xml file?
If so, how?
Thank You,
Bob
- Original Message -
From: Bob Byron [EMAIL PROTECTED]
To: [EMAIL PROTECTED]; [EMAIL PROTECTED]
Sent: Wednesday, October 03, 2001 12:11 PM
Subject: Re: Open a file?
Thank you Craig!
Of course I
Tomcat 4.0, I created my library using the Tomcat 4.0 common directory
jar files
including crimson. Any ideas?
Thank You,
Bob Byron
I am receiving the following error:
org.xml.sax.SAXException: System property org.xml.sax.driver not specified
was compiling against JAXP. Under
Tomcat 4.0, I created my library using the common jar files
including crimson. Any ideas?
Thank You,
Bob Byron
I am receiving the following error:
org.xml.sax.SAXException: System property org.xml.sax.driver not specified
to the webapp
that it is running under? I hope I have phrased the question
sufficiently for you to understand what I need to do. I need
a different reference point, one that uses the webapp itself
as a base.
Thank You,
Bob Byron
();
SAXParser saxParser = saxParserFactory.newSAXParser();
XMLReader xr = saxParser.getXMLReader();
And it worked!
Bob Byron
- Original Message -
From: Bob Byron [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Tuesday, October 02, 2001 5:57 PM
Subject: Tomcat 4.0 and XML - deployment problems
