Re: [Vo]:1/f squared gamma distribution from Rossi-like

In reply to Nigel Dyer's message of Sat, 10 Mar 2018 16:02:01 +: Hi, Absorption would be energy dependent, but depends on the path taken. If the source were highly localized, then the path between source and detector would be the same for all photons. Would that yield one of the 1/f factors

Re: [Vo]:1/f squared gamma distribution from Rossi-like

Read this "A radio interview with Sergio Focardi, the father of “Ni-H Cold-Fusion". https://22passi.blogspot.com/2011/04/sergio-focardi-father-of-ni-h-cold.html So contrary to what Jones & Brian write, Ross's reactors worked from the early days. They both did lots of experiments and Foracdi

Re: [Vo]:1/f squared gamma distribution from Rossi-like

Ultra dense hydrogen (UDH) may not be a primary source for muon production. The Surface Plasmon Polariton may be the primary source of proton annihilation. The UDH by be a helpful host that provides a secondary support structure for the viability and maintenance of the SPPs. The SPP can use other

RE: [Vo]:1/f squared gamma distribution from Rossi-like

It is worth repeating that in Holmlid’s article cited by Axil, we find several problems with his claim of copious muon production (aside from the massive transfer of energy which becomes undetectable). Holmlid: “The muons formed do not decay appreciably within the flight distances used here.

Re: [Vo]:1/f squared gamma distribution from Rossi-like

I think there is every possibility that what is measured is a secondary, Bremstallung like effect. One other factor is that whatever is being measured is outside the alumina and steel container of the active ingredients of the glow stick.  If the gamma was generated from the 'active

Re: [Vo]:1/f squared gamma distribution from Rossi-like

You made me go bact to the source article http://journals.plos.org/plosone/article?id=10.1371/journal.pone.0169895 Abstract: " Large signals of charged light mesons are observed in the laser-induced particle flux from ultra-dense hydrogen H(0) layers. The mesons are formed in such layers on

Re: [Vo]:1/f squared gamma distribution from Rossi-like

Neutral particle flux probably won't create substantial electromagnetic noise and certainly no gamma. Best case is that it would occasionally knock off some electrons that would excite the characteristic x-ray emission of their host atom. They will excite acoustic noise that would quickly be

Re: [Vo]:1/f squared gamma distribution from Rossi-like

Pity you can't have an accident and stumble over something useful yourself. -Original Message- From: JonesBeene <jone...@pacbell.net> To: vortex-l <vortex-l@eskimo.com> Sent: Sat, Mar 10, 2018 6:04 pm Subject: RE: [Vo]:1/f squared gamma distribution fro

Re: [Vo]:1/f squared gamma distribution from Rossi-like

According to Holmlid, there is a high flux of neutral atomic fragments that receive a ton of kinetic energy from the primary reaction(nucleon particle decay). These fragments would dissipate their kinetic energy through particle collision cascades. That particle collision cascade would produce the

Re: [Vo]:1/f squared gamma distribution from Rossi-like

Keep in mind that as large massive charged particles (200x that of an electron), muons would not penetrate materials very well. For a given energy, they are moving much slower than electrons. Also, because they are so heavy, they will stop slowly, and hence, not create much bremsstrahlung

RE: [Vo]:1/f squared gamma distribution from Rossi-like

As was obvious from the start, your so-called evidence sucks… From: Adrian Ashfield As you won't believe anything short of working reactors on the market, I see no point in continuing this discussion. Rossi has stated he is not going to show anything more of the QX until they are in

Re: [Vo]:1/f squared gamma distribution from Rossi-like

2018 4:34 pm Subject: RE: [Vo]:1/f squared gamma distribution from Rossi-like Wait a minute – Adrian says he has independent evidence of a factory. This seems at first blush to be  irrational if not silly… but heck --  let’s hear or see this evidence ! Hopefully it will not come from Rossi or one

Re: [Vo]:1/f squared gamma distribution from Rossi-like

- From: JonesBeene <jone...@pacbell.net> To: vortex-l <vortex-l@eskimo.com> Sent: Sat, Mar 10, 2018 4:34 pm Subject: RE: [Vo]:1/f squared gamma distribution from Rossi-like Wait a minute – Adrian says he has independent evidence of a factory. This seems at first blush to be

RE: [Vo]:1/f squared gamma distribution from Rossi-like

hfi...@verizon.net> Sent: Saturday, March 10, 2018 3:04 PM To: vortex-l@eskimo.com Subject: Re: [Vo]:1/f squared gamma distribution from Rossi-like   I know that you and Brian can't resist bad mouthing Rossi, but there are signs that he has a commercial product with the QX.  I have some independent ev

Re: [Vo]:1/f squared gamma distribution from Rossi-like

I think there is a real possibility that some detectors are not detecting what we thought they were detecting.  I had not considered that possibility in this case, but I will keep that in mind. On 10/03/2018 20:11, JonesBeene wrote: BTW - Wouldn’t it be a hoot if muons showed up on a

Re: [Vo]:1/f squared gamma distribution from Rossi-like

Quantum 1/f noise https://en.wikipedia.org/wiki/Quantum_1/f_noise The *conventional Q1/fE* represents 1/f fluctuations caused by bremsstrahlung, decoherence and interference in the scattering of charged particles off one another, in tunneling or in any other process in solid state physics and in

Re: [Vo]:1/f squared gamma distribution from Rossi-like

There is no factory and less obvious, there is no Santa Claus either. From: Adrian Ashfield <a.ashfi...@verizon.net> Sent: Saturday, March 10, 2018 3:04 PM To: vortex-l@eskimo.com Subject: Re: [Vo]:1/f squared gamma distribution from Rossi-like I know th

Re: [Vo]:1/f squared gamma distribution from Rossi-like

Conversely, The muons may just be 1/f noise. From: JonesBeene <jone...@pacbell.net> Sent: Saturday, March 10, 2018 3:11 PM To: vortex-l@eskimo.com Subject: RE: [Vo]:1/f squared gamma distribution from Rossi-like BTW - Wouldn’t it be a hoot if muons sho

RE: [Vo]:1/f squared gamma distribution from Rossi-like

BTW - Wouldn’t it be a hoot if muons showed up on a particular detector as 1/f^2 noise ?? Nigel, Since you noticed the fit initially, were you looking for it based on phenomena from another field ? I see from Alan’s posting that the context is no mystery – except to someone who was not

Re: [Vo]:1/f squared gamma distribution from Rossi-like

anywhere near what he claims it is truly insulting to suggest he "stumbled" upon it. -Original Message- From: JonesBeene <jone...@pacbell.net> To: vortex-l <vortex-l@eskimo.com> Sent: Sat, Mar 10, 2018 12:58 pm Subject: RE: [Vo]:1/f squared gamma distri

RE: [Vo]:1/f squared gamma distribution from Rossi-like

There is plenty of excellent work from other researchers (other than Rossi) on this site. If we accept the reality of LENR we cannot reject Rossi solely because he is a dishonest scam artist. There is even the possibility that Rossi could stumble onto something valid at this juncture (2018)

Re: [Vo]:1/f squared gamma distribution from Rossi-like

rtex-l@eskimo.com Subject: Re: [Vo]:1/f squared gamma distribution from Rossi-like It has the characteristics of bremsstrahlung radiation, likely from stopping of beta emission within the reactor. On Sat, Mar 10, 2018 at 8:24 AM, Nigel Dyer <l...@thedyers.org.uk<mailto:l...@thedyers.org.uk>

Re: [Vo]:1/f squared gamma distribution from Rossi-like

In the calibrated trace, which you may not be seeing, it is not 1/f^2 exactly. Also, there will be absorption and scattering in going through the reactor that will affect the shape of the curve. On Sat, Mar 10, 2018 at 9:28 AM, JonesBeene wrote: > OK – but the context of

Re: [Vo]:1/f squared gamma distribution from Rossi-like

This was discussed in depth here, and on the QuantumHeat blog. Bob Higgins commented at that time: The way the signal behaved, it was strong in Spectrum-07, weak in Spectrum-08, missing in Spectrum-09, and tiny in Spectrum-10. It did not exist in Spectrum-06 at all. If it were a hot

RE: [Vo]:1/f squared gamma distribution from Rossi-like

OK – but the context of what is being graphed is not clear --- Is Trace 7 real or calculated? Maybe Trace 7 has been manipulated to show a desired fit. From: Nigel Dyer It is like both like a Maxwellian distribution and Bremstrahlung, but neither of these give a 1/f^2 distribtion. If you

Re: [Vo]:1/f squared gamma distribution from Rossi-like

It is like both like a Maxwellian distribution and Bremstrahlung, but neither of these give a 1/f^2 distribtion. If you overlay a 1/f^2 line over the red dots the fit is perfect, indeed it is so good that it almost looks as if that is how it was generated. On 10/03/2018 15:46, JonesBeene

RE: [Vo]:1/f squared gamma distribution from Rossi-like

Looks quasi-Maxwellian to me. Where is the inverse peak? From: Nigel Dyer I have been looking at the graph titled "After the MASSIVE broad band 'turn on' pulse, the excess heat mode is between 0 and 100KeV"  at

Re: [Vo]:1/f squared gamma distribution from Rossi-like

It has the characteristics of bremsstrahlung radiation, likely from stopping of beta emission within the reactor. On Sat, Mar 10, 2018 at 8:24 AM, Nigel Dyer wrote: > I have been looking at the graph titled > "After the MASSIVE broad band 'turn on' pulse, the excess heat

[Vo]:1/f squared gamma distribution from Rossi-like

I have been looking at the graph titled "After the MASSIVE broad band 'turn on' pulse, the excess heat mode is between 0 and 100KeV"  at http://www.quantumheat.org/index.php/en/home/mfmp-blog/519-the-cookbook-is-in-the-signal which shows the steady state gamma radiation from the Parkhomov-like