On Dec 6, 2008, at 1:24 PM, [EMAIL PROTECTED] wrote:
In reply to Horace Heffner's message of Fri, 5 Dec 2008 13:50:32
-0900:
Hi,
[snip]
As I understand ordinary QM, the electron spatial distribution in
an ordinary
Hydrogen atom is such that the electron spends much of it's time in
the
In reply to Horace Heffner's message of Fri, 5 Dec 2008 13:50:32 -0900:
Hi,
[snip]
As I understand ordinary QM, the electron spatial distribution in an ordinary
Hydrogen atom is such that the electron spends much of it's time in the
neighborhood of the nucleus anyway, and the chance that it will
On Dec 5, 2008, at 9:40 AM, OrionWorks wrote:
From Horace,
...
Under the inflation fusion model I would in fact expect that most
of the
13C is in fact CH, because the heat released and total gamma
energy can
not account for the actual fusion of so much 13C. Further, the C
+p reaction
On Dec 4, 2008, at 10:17 AM, Jed Rothwell wrote:
I wrote:
Here is a hypothetical situation to ponder. Suppose Mizuno uses
conventional nuclear theory as a working model for his experiments.
Suppose this 'works' in the sense that he makes progress toward
better control of the excess heat
On Dec 4, 2008, at 1:49 PM, Jones Beene wrote:
I have talked to two experts who suspect that the putative 13C+
could be molecular 12CH (whether or not the H there is a hydrino -
it does not matter).
[snip]
Jones
Say, it may be that CH gas is being momentarily created in the
process.
Jones sez:
...
Wouldn't it be curious - since there is some excess energy appearing in
3-space, if the effective interest rate or more like ROI - from borrowing
at the cosmic bank (ZPE branch) happened to be .73% ... i.e. 1/137 g
This is what happens when one watches too many Lost episodes.
On Dec 5, 2008, at 7:31 AM, Jones Beene wrote:
Horace Heffner writes,
Say, it may be that CH gas is being momentarily created in the
process. In any case, in CH or in other hydrocarbon forms, if the
H is periodically in the deflated state then stimulation by
polarized laser will
From Horace,
...
Under the inflation fusion model I would in fact expect that most of the
13C is in fact CH, because the heat released and total gamma energy can
not account for the actual fusion of so much 13C. Further, the C+p reaction
is weak, and thus should have a very small cross
In reply to Horace Heffner's message of Fri, 5 Dec 2008 03:28:53 -0900:
Hi,
[snip]
Of special interest are the possibilities indicated by:
He+ + e- He + 24.59 eV
C++ + e- C+ + 24.38 eV
Mo++ + e- Mo+ + 27.13 eV
which are close to the 27.21 eV energy Mills prescribes.
The third
In reply to Horace Heffner's message of Fri, 5 Dec 2008 03:49:22 -0900:
Hi,
[snip]
Say, it may be that CH gas is being momentarily created in the
process.
[snip]
CH is a radical, and would not likely have a long life. Consequently it is far
more likely that the experiment itself, at most,
Jones Beene wrote:
Well, I am still of the opinion that the mass difference between CH and
13C should have been noticed by the authors in the spectrometry, since
it so very critical to their conclusion, and so obvious as an
alternative ... should I say alternative to the near-miraculous
Robin van Spaandonk wrote:
Don't forget that the analysis was outsourced. IOW the product of the reaction
(presumably a black solid resembling soot) was sent offsite to be analyzed,
implying a likely time between production and analysis of days at
least. Far too
long for a radical to continue
In reply to Horace Heffner's message of Fri, 5 Dec 2008 08:42:53 -0900:
Hi,
[snip]
I think it is entirely possible that, except for trace amounts, *all*
the 13C is actually CH.
I agree. One would need to determine the resolving power of the actual MS used,
as it may not have been adequate to
Robin van Spaandonk wrote:
Mizuno is a physicist (I believe) . . .
Good heavens no! He is an electrochemist. A protégé of John O'M Bockris.
In my experience, physicists and electrochemists
do not see eye to eye. You might say they are in different camps.
- Jed
On Dec 5, 2008, at 11:55 AM, [EMAIL PROTECTED] wrote:
In reply to Horace Heffner's message of Fri, 5 Dec 2008 03:49:22
-0900:
Hi,
[snip]
Say, it may be that CH gas is being momentarily created in the
process.
[snip]
CH is a radical, and would not likely have a long life.
What makes you
In reply to Jed Rothwell's message of Fri, 05 Dec 2008 16:40:45 -0500:
Hi,
[snip]
Robin van Spaandonk wrote:
Mizuno is a physicist (I believe) . . .
Good heavens no! He is an electrochemist. A protégé of John O'M Bockris.
In my experience, physicists and electrochemists
do not see eye to eye.
I would like to clear up a little confusion. A mass spectrometer only
measures the mass/charge ratio of ions. These ions are made by
bombarding the gas with electrons. This causes the molecules in the
gas to ionize and to decompose. One of the decomposition products of
most organic
In reply to Horace Heffner's message of Fri, 5 Dec 2008 12:44:40 -0900:
Hi,
[snip]
On Dec 5, 2008, at 11:55 AM, [EMAIL PROTECTED] wrote:
In reply to Horace Heffner's message of Fri, 5 Dec 2008 03:49:22
-0900:
Hi,
[snip]
Say, it may be that CH gas is being momentarily created in the
In reply to Edmund Storms's message of Fri, 5 Dec 2008 14:49:37 -0700:
Hi,
[snip]
I would like to clear up a little confusion. A mass spectrometer only
measures the mass/charge ratio of ions. These ions are made by
bombarding the gas with electrons.
Some MS use positive ions (e.g. Ar+).
Edmund Storms wrote:
I would like to clear up a little confusion. A mass spectrometer
only measures the mass/charge ratio of ions. These ions are made by
bombarding the gas with electrons.
Ah. So they are only transient, appearing during the measurement
itself. I was wondering.
These
In reply to Stephen A. Lawrence's message of Fri, 05 Dec 2008 16:06:57 -0500:
Hi,
[snip]
Jones Beene wrote:
Well, I am still of the opinion that the mass difference between CH and
13C should have been noticed by the authors in the spectrometry, since
it so very critical to their conclusion,
]:Mizuno depends upon conventional chemical theory
I would like to clear up a little confusion. A mass spectrometer only
measures the mass/charge ratio of ions. These ions are made by
bombarding the gas with electrons. This causes the molecules in the
gas to ionize and to decompose. One
On Dec 5, 2008, at 3:04 PM, [EMAIL PROTECTED] wrote:
In reply to Edmund Storms's message of Fri, 5 Dec 2008 14:49:37
-0700:
Hi,
[snip]
I would like to clear up a little confusion. A mass spectrometer only
measures the mass/charge ratio of ions. These ions are made by
bombarding the gas
PROTECTED]
Sent: Friday, December 5, 2008 1:49:37 PM
Subject: Re: [Vo]:Mizuno depends upon conventional chemical theory
I would like to clear up a little confusion. A mass spectrometer only
measures the mass/charge ratio of ions. These ions are made by
bombarding the gas with electrons. This causes
Ed,
In any case, the evidence has a lot of holes.
YUP ... otherwise we would probably see some kind of secrecy order and the
immediate removal of this from public dissemination.
Would you not agree - that from the mainstream perspective: the conversion of
half a sample of 12C to 13C is ...
I wrote:
Here is a hypothetical situation to ponder. Suppose Mizuno uses
conventional nuclear theory as a working model for his experiments.
Suppose this 'works' in the sense that he makes progress toward
better control of the excess heat and higher power levels. . . .
In real life Mizuno
In reply to Jed Rothwell's message of Thu, 04 Dec 2008 14:17:09 -0500:
Hi,
[snip]
I do not mean, for example, that you should suggest a spectroanalysis
that would confirm these are hydrinos. I do not see how that
knowledge would do Mizuno much good.
[snip]
Knowing what's going on in your
Robin van Spaandonk wrote:
I do not mean, for example, that you should suggest a spectroanalysis
that would confirm these are hydrinos. I do not see how that
knowledge would do Mizuno much good.
Knowing what's going on in your experiment narrows down the parameter space,
allowing productive
Jones Beene wrote:
I have talked to two experts who suspect that the putative 13C+
could be molecular 12CH (whether or not the H there is a hydrino -
it does not matter).
Did Mizuno retain enough of the residue to have a sample
re-analyzed, perhaps independently - with this single goal of
In reply to Jed Rothwell's message of Thu, 04 Dec 2008 18:05:42 -0500:
Hi,
[snip]
Jones Beene wrote:
I have talked to two experts who suspect that the putative 13C+
could be molecular 12CH (whether or not the H there is a hydrino -
it does not matter).
Did Mizuno retain enough of the residue
In reply to Jed Rothwell's message of Thu, 04 Dec 2008 17:32:08 -0500:
Hi,
[snip]
Well, what are the suggestions? Can they be made without a
spectroanalysis or other extra steps? If so, let us make these suggestions now.
What I am looking for is some recommendation that would simultaneously:
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