In reply to Jones Beene's message of Sun, 8 May 2011 05:52:04 -0700:
Hi,
[snip]
More like 6 minutes than 6 months - for nanopowder degradation from current
flow
This may be relevant. http://mpac.engr.ucdavis.edu/publications/FAS1.PDF
-Original Message-
From: mix...@bigpond.com
: Re: [Vo]:RE: Supersizing the BJT
The Principle of operation: (the secret process that makes the Cat-E go)
between
the small 2.5 kw reactor in which the band heater is used and the 10 kw Cat-E
in
which only the internal heater is used is the same.
Logically, the band heater does not drive
More like 6 minutes than 6 months - for nanopowder degradation from current
flow
-Original Message-
From: mix...@bigpond.com
As I understand the dynamics of this situation, one cannot pass a current
through a nanopowder without promoting instant agglomeration - which over
time
From: Axil Axil
* The Principle of operation: (the secret process that makes the Cat-E go)
between the small 2.5 kw reactor in which the band heater is used and the 10
kw Cat-E in which only the internal heater is used is the same.
There is no evidence for that at all. If anything,
Jones Beene jone...@pacbell.net wrote:
Everything seen so far – when exposed looks nearly identical, and the only
reason to suggest that there ever was a larger model is for Rossi to hide
the fact that the results of the January test (Focardi tribute) were wet
steam and three times more than
On Sun, May 8, 2011 at 12:15 AM, Mark Iverson zeropo...@charter.net wrote:
Do we have any idea on what kinds of voltages the heaters are being subjected
to???
Assuming no transforming of the mains, only rectification, the peak
voltage would 2^-2 x 230 or ~325 V.
T
So when did Levi authorize you to speak for him?
After all, Levi is no longer independent, and is apparently Rossi's top
technical advisor. Plus, he has every incentive to be disingenuous on this
point - since he does not want to be blamed for the gross measurement error.
The results in
Hello Jed
Do you know if there is a independent report about the flow test in February in
which the water was not heated to the boilingpoint?
Peter
- Original Message -
From: Jed Rothwell
To: vortex-l@eskimo.com
Sent: Sunday, May 08, 2011 4:03 PM
Subject: Re: [Vo]:RE
Jones sez:
...
I know, it is too bizarre to mention in polite company, but where is the
sanity in a great society like our own that pays out millions for a stupid
horse race, or an illiterate baseball star, and yet cannot support basic
RD
in this vitally important field This technology
Jones sez:
...
I know, it is too bizarre to mention in polite company, but where is the
sanity in a great society like our own that pays out millions for a
stupid
horse race, or an illiterate baseball star, and yet cannot support basic
RD
in this vitally important field This
On Sun, May 8, 2011 at 11:37 AM, OrionWorks - Steven Vincent Johnson
orionwo...@charter.net wrote:
I'm steamed.
Don't be steamed, be steam punked. Steam power is seeing a
renaissance today even without Rossi. Here are several steam punked
devices including a steam powered PC:
Jones Beene jone...@pacbell.net wrote:
So when did Levi authorize you to speak for him?
That's what he said; take it or leave it. When did you look inside the
machine?
The results in February cannot be trusted because of incorrect thermocouple
placement.
That can't be. A 5 deg C
Terry sez:
orionwo...@charter.net wrote:
I'm steamed.
Don't be steamed, be steam punked. Steam power is seeing a
renaissance today even without Rossi. Here are several steam punked
devices including a steam powered PC:
For those who have not paid particular attention to the images which started
the hypothesis of the last two days - that the precise operation of the
E-Cat reactor could be either a triode (MAHG) type of accelerator, or a
massive semiconductor bipolar junction transistor (as opposed to simply a
-Original Message-
From: Terry Blanton
When Terry noticed the single lead, it was pointed out that there are
similar
heaters available online with two leads.
Good find, Jones. However, it is evident from the piccy that the band
heater does actually have two wires. See the cable on
Yes, I caught that too...
Here is the end of the band heater leads for the middle reactor...
You can clearly see two (dirty-whitish) wires exiting the braided steel sheath.
-Mark
Outlook.jpg
On Sat, May 7, 2011 at 4:23 PM, Jones Beene jone...@pacbell.net wrote:
But, going back to your other observation, how would you flow current
between two heaters, exactly? Have one at higher potential?
Sure. But to know if it is being done, one has to see inside the reactor.
I assume the
The axial wires look like typical leads to a cartridge heater
http://www.tempco.com/new/products5.html
A long version off this kind of heater could contact the reactor at the end,
and then it could transfer some heat to it, but most of the heat would lost
to the water which flows all around it,
A quick and dirty test comes to mind.
Anybody got two of the immersion water heaters used by travelers?
http://www.amazon.com/Bush-CH-101-Energy-Saving-Immersion-Heater/dp/B003DLB5
KW
The idea would be to place two of them in a semi-conductive liquid (water
with a dash of salt), and
On 2011-05-07 23:11, Jones Beene wrote:
The axial wires look like typical leads to a cartridge heater
http://www.tempco.com/new/products5.html
They do look like those.
A long version off this kind of heater could contact the reactor at the end,
and then it could transfer some heat to it,
Thanks, Akira
A schematic view of the E-Cat would be something like this:
http://i.imgur.com/llVoU.png
Yes, This is exactly the way it appeared to me at first, given all that is
known from the images - with only an internal cooling tube and NO external
water flow around the outside of the
If you missed this old post, here is s repeat:
When the Cat-E was downsized, the reaction chamber was greatly reduced in
size. So was the internal heater in like proportion. But the copper pipes in
the water loop are standard commercial grade sizes and therefore stayed the
same size. Remaining
On 2011-05-08 00:47, Axil Axil wrote:
If you missed this old post, here is s repeat:
[...]
So, are you suggesting there is a core surrounded by water, like this?
http://i.imgur.com/pwZW2.png
(Both versions together: http://i.imgur.com/Kf7mO.png )
Cheers,
S.A.
The dubble pipe configuration is pictured in the patent with the addition
of the external band heater
http://worldwide.espacenet.com/publicationDetails/originalDocument?FT=Ddate=20091015DB=EPODOClocale=en_EPCC=WONR=2009125444A1KC=A1
On Sat, May 7, 2011 at 7:09 PM, Akira Shirakawa
This is not physically possible. The heat (temperature) transferable from
the heaters to the core, even with the lowest possible water flow, cannot
greatly exceed 100 C with a design where water separates the exterior heater
from the reactor; and water is also surrounding the interior heater for
From Jones,
A schematic view of the E-Cat would be something like this:
http://i.imgur.com/llVoU.png
Yes, This is exactly the way it appeared to me at first, given all that is
known from the images - with only an internal cooling tube and NO external
water flow around the outside of the
Yeah, we all have been speculumating. Now that the patent is issued,
maybe we will get to look to see what is really inside that dark area.
:-)
T
I should add that in this second image, if the external water flow was via
channels which are machined into a tight fitting internal reactor, such that
the internal reactor has good electrical contact with the heater, then this
is consistent with the transistor hypothesis, but not with resistive
Akira Shirakawa shirakawa.ak...@gmail.com wrote:
So, are you suggesting there is a core surrounded by water, like this?
http://i.imgur.com/pwZW2.png
That is how Rossi described it. There might be a language problem, but I am
pretty sure that is what he meant.
He also said emphatically that
Steven - I did not remember that you were a toroidista :) - but in the end,
I think you agree that either it is a toroid or else there has to be some
kind of current going through the powder, otherwise - it is not going to
heat up.
Electrical current directly through the nanopowder has
07, 2011 5:55 PM
To: vortex-l@eskimo.com
Subject: RE: [Vo]:RE: Supersizing the BJT
Steven - I did not remember that you were a toroidista :) - but in the end, I
think you agree that
either it is a toroid or else there has to be some kind of current going
through the powder,
otherwise
In reply to Mark Iverson's message of Sat, 7 May 2011 19:39:32 -0700:
Hi,
[snip]
2) The only way I see to generate a signif potential between the two heaters
is to leave one of the
leads floating, thus, BOTH heater leads are at the same potential. However,
this means there is no
current flow
the resistivity of Ni/NiO
-Mark
-Original Message-
From: mix...@bigpond.com [mailto:mix...@bigpond.com]
Sent: Saturday, May 07, 2011 7:51 PM
To: vortex-l@eskimo.com
Subject: Re: [Vo]:RE: Supersizing the BJT
In reply to Mark Iverson's message of Sat, 7 May 2011 19:39:32 -0700:
Hi
In reply to Mark Iverson's message of Sat, 7 May 2011 19:58:17 -0700:
Hi,
[snip]
Several thoughts:
1) If there are ANY dielectrics in the path from one heater to the other, then
this is a NO GO since
one would need a low resistance path.
2) That would require a low resistance (a few ohms at
-Original Message-
From: Mark Iverson
If I might provide some additional thoughts/analysis...
1) The only way the resistance heaters can 'heat' is if there's a low
resistance path thru the heating element (i.e., a large current flow). If
that's the case, then I doubt you could
-Original Message-
From: Mark Iverson
1) If there are ANY dielectrics in the path from one heater to the other,
then this is a NO GO since one would need a low resistance path.
Agreed. One thought that came up in the original posting was the negative,
or very low bandgap suggestion,
-Original Message-
From: mix...@bigpond.com
Surely the whole point would be to create a current through the Ni? Ni is
a
metal and as such is a reasonable conductor. As a powder it would be less
than a
solid, but it also has lots of parallel paths.
Robin,
As I understand the
The Principle of operation: (the secret process that makes the Cat-E go)
between the small 2.5 kw reactor in which the band heater is used and the 10
kw Cat-E in which only the internal heater is used is the same.
Logically, the band heater does not drive or in any way affect the “secret”
'evidence'.
-Mark
-Original Message-
From: Jones Beene [mailto:jone...@pacbell.net]
Sent: Saturday, May 07, 2011 8:18 PM
To: vortex-l@eskimo.com
Subject: RE: [Vo]:RE: Supersizing the BJT
-Original Message-
From: Mark Iverson
If I might provide some additional thoughts
In reply to Jones Beene's message of Sat, 7 May 2011 20:47:11 -0700:
Hi,
[snip]
As I understand the dynamics of this situation, one cannot pass a current
through a nanopowder without promoting instant agglomeration - which over
time proceeds progressively back into a bulk conductor.
...perhaps
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