Hi everybody!
I need a tip about how sqlite3_column_double works. I hoped it returns a pointer to a 8-byte-real, but it don't.
Here is what i do:
CREATE TABLE [tblTyped] ([a] TEXT, [n] NUMERIC, [i] INTEGER, [b] BLOB)
Insert into tblTyped values('helo,,,', 1.1121, '8.0001', 'blob!!!')then sqlite3_prepare 'Select * from tblTyped' then sqlite3_step
now for each column: sqlite3_column_type returns 3 2 2 3 it means SQLITE_TEXT SQLITE_FLOAT SQLITE_FLOAT SQLITE_TEXT
sqlite3_column_text returns a pointer to a string, as espected: helo,,,|1.1121|8.0001|blob!!!
SQLITE3.sqlite3_column_int returns values as espected: 0|1|8|0
but sqlite3_column_double never returns a pointer: 68|8|8|62 (hexadecimal values)
and to get me even more confused, if called inmediatelly after sqlite3_column_text, sqlite3_column_double returns: 68|22A|22A|62 (hexadecimal values)
Thank you in advance! Marcelo
