Hi Paul

> > It got a bit garbled in transmission, not sure what this character
> > might have been: &#8594
>
>Keith looks like the mystery garble should have been an arrow or
>gives/yields.

Um, yes. Duh! I don't mind admitting it all looks like fly-shit to 
me. Well, not quite, I can follow it up to a point but easily get 
lost. Should've guessed the arrows though.

>ie :  2 Cl --   --->   Cl2  (gas) + 2 e --  (electrons)
>Whether the arrows are oneway or two way I'm not sure in all cases.
>Then below should read
>
>
> ... Consider the electrolysis of a water solution of sodium chloride
> (common table salt).  At the anode the product is, as one might
> expect, chlorine gas.
>
> anode :
>  2 Cl --  --->      Cl2  (gas) + 2 e --  (electrons)
>
> Bubbles of hydrogen form at the cathode; the solution immediately
> surrounding this electrode becomes strongly basic.  This evidence
> indicates that a water molecule rather than a sodium ion is being
> reduced :
>
> cathode :
>   2 H2O + 2 e --  --->    H2 (g) + 2 OH --
>
> It appears that the water molecule is more readily reduced than the
> Na+  ion. This is entirely reasonable when you consider the addition
> of sodium metal to water results in the spontaneous reaction :
>
> 2 Na (solid) + 2 H2O  --->     2 Na+ + H2 (g) + 2 OH --
>
> Thus, one can then argue that any sodium ions produced by
> electrolysis would immediately react with water to produce H2
>molecules and OH --  ions so the net reaction is that listed for the
> cathode.
>
> To obtain the overall reaction for the electrolysis of a water
> solution of sodium chloride, combine the anode and cathode reactions
> to give :
>
>   2  Cl --  + 2 H2O  --->   Cl2 (gas) + H2 (gas) + 2 OH --
>
> One effect of this cell reaction is the replacement of the chloride
> ions originally present by an equal number of hydroxide ions.
> Consequently, evaporation of the solution remaining after
> electrolysis yields a residue of sodium hydroxide:
>
> electrolysis :
>  2  Cl -- + 2 H2O  --->    Cl2 (g) +  H2 (g) + 2 OH --
>
> evaporation :
>   2 Na+ +  2 OH --   --->     2 NaOH (solid)
>
>
> ---------------------------------------------------------------
>
>      2 Na+ + 2  Cl -- +  2 H2O  --->  2 NaOH (s) + Cl2 (g) + H2 (g)
>
> The greater part of the sodium hydroxide and almost all the chlorine
> made is prepared by the electrolysis of aqueous sodium chloride;
> hydrogen is an important by-product.
>
> In electrolytic oxidation the number of electrode materials (anode)
> is more limited than in reduction processes.  Since, in general, it
> is important that the anode should be attacked as little as possible
> during electrolysis, we are confined to the use of platinum, iridium,
> palladium, carbon, iron, and nickel for processes that take place in
> alkaline solution, and to the platinum metals and carbon for those
> carried out in acid solution.  Anodes of lead dioxide may be employed
> in sulfuric acid solutions.  Of these anodes, iron and nickel have
> the lowest oxygen over-voltages.  For general work, the most suitable
> anodes are: (1) lead, for sulfate solutions; (2) Acheson graphite,
> for chloride solutions; and (3) pure nickel or a high-nickel steel
> for alkaline solutions.
>
>
>If memory serves me right (which is less often these days) in the commercial
>process mercury is used for one of the electrodes. It runs beneath a molten
>bath of sodium chloride. As the sodium is formed it dissolves in the
>mercury. The mercury is circulated through the cell and into another
>reaction vessel where water is added to the mercury. The sodium metal forms
>sodium hydroxide and hydrogen with the water.

That doesn't sound very kitchen-friendly Paul. Maybe there isn't a 
kitchen-friendly way, eh? Wood-ash KOH then I guess.

Best wishes

Keith


>Regards Paul.


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