You appear to have recovered.  I am happy for you.




-----Original Message-----
From: Horace Heffner <hheff...@mtaonline.net>
To: Vortex-L <vortex-l@eskimo.com>
Sent: Wed, Sep 21, 2011 4:19 pm
Subject: [Vo]:Review of Travel report by Hanno Essén and Sven Kullander, 3 
April 2011


INTRODUCTION

This is a highly belated review of the Travel report by Hanno Essén  
and Sven Kullander, 3 April 2011, and created April 7, 2011, to be  
found at:

http://www.lenr-canr.org/acrobat/EssenHexperiment.pdf


FIG 1 & 2 NOTES

It appears the thermometer wells, "thermocouple holders", are only  
partially completed on the left 3 E-cats. Fig. 4 shows a completed  
thermocouple holder with probe inserted.  Note that the exit for the  
thermocouple holder is located below the level of the steam/water  
exit port.  If the brass fitting is not a pressure fit or o-ring  
sealing device, then if water leaks out of the exit port and down the  
hose, it should also leak around the probe.  Steam should leak around  
the probe fitting as well.

E&K: "... according to Rossi, the reaction chamber is hidden inside  
in the central part and made of stainless steel."

E&K: "Note that on the main heating resistor which is positioned  
around the copper tube and made of stainless steel (Figure 3) you can  
read the dimensions and nominal power (50mm diameter and 300W).

E&K: "At the end of the horizontal section there is an auxiliary  
electric heater to initialize the burning and also to act as a safety  
if the heat evolution should get out of control."

The auxiliary (preheater) element wire leads are clearly visible at  
the entrance to two of the three unused E-cats in Fig. 2.


FIG. 3 NOTES

It appears the heating chamber goes from the 34 cm to the 40 cm mark  
in length, not 35 cm to 40 cm as marked. Maybe the band heater  
extends beyond the end of the copper.  It appears 5 cm is the length  
to be used for the heating chamber. Using the 50 mm diameter above,  
and 5 cm length we have heating chamber volume V:

    V = pi*(2.4 cm)^2*(5 cm) = 90 cm^3

If we use 46 mm for the internal diameter we obtain an internal  
volume of:

    V = pi*(2.4 cm)^2*(5 cm) = 83 cm^3

Judging from the scale of picture, determined by the ruler, the OD of  
the heating chamber appears to actually be 6.1 cm.  The ID thus might  
be 5.7 cm.  This gives:

    V = pi*(2.85 cm)^2*(5 cm) = 128 cm^3

The nickel container is stated to be about 50 cm^3, leaving 78 cm^3  
volume in the heating chamber through which the water is heated.

If the Ni containing chamber is 50 cm^3, and 4.5 cm long, then its  
radius r is:

    r = sqrt(V/(Pi L) = sqrt((50 cm^3)/(Pi*(4.5 cm)) = 3.5 cm

total surface are S is:

    S = 2*Pi*r^2 + 2*Pi*r*L = 2*Pi*(r^2+r*L) = 2*Pi*((3.5 cm)^2 +  
(3.5 cm)*(4.5 cm))

    S = 180 cm^2

The surface material is stainless steel.


FIG. 4 NOTES

It is notable the 2 cm of lead is not evident.   The insulation looks  
more like a polyester than fiberglass, and if so its melting  
temperature is around 250°C.


FIG. 5 NOTES

It looks like there may be two white power wires going into the E- 
cat. Hard to tell.   It looks like some kind of straight white tubes  
of short length go through the insulation as well. No notes made of  
their function.


FIG. 6 NOTES

The slopes on leading side and trailing side of the inflection point  
(elbow or kink) at 10:37 are 6.7°C/min, 9.4 °C/min respectively.


FIG. 7 NOTES

The temperature reading might be interpreted to mean an equilibrium  
was possibly reached, but this not known since the water overflow was  
not measured and independent calorimetry was not performed on the  
output mass flow.  The thermometer is subject to heat wicking through  
the well, other error producing effects which may or may not exist  
depending on the structure of the device inside which is not  
permitted to be observed.

FIG. 10 NOTES

There appears to be two power cords running from two receptacles on  
the rightmost (in the photo) back side of the blue box. This could  
indicate that both the main band heater and the auxiliary heater were  
in use, indicating more than 300 W was in use at some point.


REVIEWING THE CALIBRATION CALCS

E&K: "Calibrations. The flow of the inlet water was calibrated in the  
following way. The time for filling up 0.5 liters of water in a  
carafe was measured to be 278 seconds."

Flow is thus (500 gm)/(278 s) = 1.80 gm/s.

E&K:"Visual checks showed that the water flow was free from bubbles.  
Scaled to flow per hour resulted in a flow of 6.47 kg/hour (Density 1  
kg/liter assumed). The water temperature was 18 °C. The specific heat  
of water, 4.18 joule/gram/ °C which is equal to 1.16 Wh/kg/ °C ..."

The heat capacity of water is 4.18 J/(gm K) near 45°C, but is above  
4.2 J/(gm K) below 5°C and above 81°C.   The average is probably  
closer to 4.19, but I have simply used 4.2 in my prior calcs, which  
gives a slight edge to a free energy conclusion. This I consider a  
non-issue, but simply of general interest.

(4.18 J/(gm K)) * (1000 gm/kg) * (3600 s/hr) = 1.16 Wh/(kg °C)

E&K:" ... is used to calculate the energy needed to bring 1 kg of  
water from 18 to 100 °C. The result is 1.16(100-18)=95 Wh/kg. "

(1.16 Wh/(kg °C)) * (100°C - 18°C) = 95 Wh/kg

E&K: "The heat of vaporization is 630 Wh/kg."

E&K: "Assuming that all water will be vaporized, the energy required  
to bring 1 kg water of 18 °C to vapor is 95+630=725 Wh/kg. To heat up  
the adjusted water flow of 6.47 kg/hour from 18 °C to vapor will  
require 7256.47=4.69 kWh/hour."

(6.47 kg/hour)*(95 Wh/kg + 630 Wh/kg) = 4690 Wh/hr = 4.69 kW


E&K: "The power required for heating and vaporization is thus 4.69  
kW. It should be noted that no error analysis has been done but  
according to Giuseppe Levi, a 5% error in the measurement of the  
water flow is a conservative estimate. Even with this error, the  
conclusions will not change due to the magnitude of the observed  
effects."

This number is not applicable unless all water flow is converted to  
steam. It is also not applicable if the power is even slightly  
larger, or the flow ever even slightly smaller than estimated,  
because the extra power, by conservation of energy, necessarily goes  
into superheating the steam.  If the steam is superheated in the  
device then this should be reflected in the thermometer reading being  
well over 100°C.


ELECTRIC POWER

E&K: "The electric heater was switched on at 10:25, and the meter  
reading was 1.5 amperes corresponding to 330 watts for the heating  
including the power for the instrumentation, about 30 watts. The  
electric heater thus provides a power of 300 watts to the nickel- 
hydrogen mixture. This corresponds also to the nominal power of the  
resistor."

No mention was made of continual monitoring of the power. No mention  
is made of variable power, or power factors, or use of the auxiliary  
heater, which pre-heats the water prior to the main heating chamber.   
No mention is made of any operation of the power selection switch on  
the blue box which is used to prevent overheating etc.?  The same E- 
cat device (it appears to me, the one on the right, less the wide  
chimney part) in the Krivit demo consumed over 700 watts. Certainly  
power was neither computer recorded nor integrated for the test run.  
No kWh meter was used.


INITIAL RUNNING

E&K: "The heater was connected at 10:25 and the boiling point was  
reached at 10:42. The detailed temperature-time relation is shown in  
figure 6. The inlet water temperature was 17.3 °C and increased  
slightly to 17.6 °C during this initial running. The outlet water  
temperature increased from 20 °C at 10:27 to 60 °C at 10:36. This  
means a temperature increase by 40 °C in 9 minutes which is  
essentially due to the electric heater."

No mention was made of what time the pump was started. Also, the  
total water containing volume of the device is not specified.

The flow rate is 1.80 gm/s, so for the 9 minutes that is (1.80 gm/s)* 
(9 min)*(60 s/min) = 972 gm. The water heating energy E1 required is:

    E1 = (40°C)*(972 gm)*(4.18 J/(gm K)) = 162.5 kJ

Total heat applied  = (300 W)*(9 min)*(60 s/min) = 162 kJ.

One problem is not knowing which was turned on first, the water or  
the heater. Another problem is not knowing whether the second heater  
was turned on after the power measurement was made, or whether power  
adjustments were later made on the blue box.

It is not known for sure the water was flowing by the thermometer at  
this time, overflowing into the rubber tube. That seems likely  
though. It is not known how much thermal wicking directly from the  
band heater to the thermometer well occurs through the copper. It  
appears it is not known for sure the thermometer well actually is  
situated such that, or made such that, water actually comes in  
contact with the thermometer.  If the well is closed ended, or if the  
probe seal is air (steam) tight, then even if the well end is  
submerged, the air in the well itself may act as a locked in bubble,  
preventing water from ever reaching the thermometer.  The thermometer  
is then subject to some direct heating from the band heater through  
the copper. This might account for the 102°C reading in another run  
even if atmospheric pressure steam/water was produced.

E&K: "It is worth noting that at this point in time and temperature,  
10:36 and 60°C, the 300 W from the heater is barely sufficient to  
raise the temperature of the flowing water from the inlet temperature  
of 17.6 °C to the 60 °C recorded at this time. If no additional heat  
had been generated internally, the temperature would not exceed the  
60 °C recorded at 10:36."

This makes sense within the author's context. At a flow rate of 1.8  
gm./s, input temp 18°C, the overflow output water temperature should  
reach an equilibrium temperature of 57.7°C.  However, the graph makes  
no sense.  There is no sign of things coming asymptotically to an  
equilibrium as would be expected.

Suppose for a moment it takes no energy to bring the temperature of  
the copper etc. up to equilibrium temperature of 60°C, that the  
copper is a perfect insulator (except for the heating chamber walls),  
and thus has no heat capacity, and that there is no heat loss through  
the insulation.  If the device has no water in it initially, the  
outlet temperature would remain at room temperature until the water  
reached it, and then it would instantly jump to 60°C, because the  
heater *continually* provides enough heat to send the water out of  
the heating chamber at 60°C.

Now, assume that the temperature rise is slow and constant because  
the device metal and possibly some residual water requires heating.  
There is a problem with this because it would be expected that as the  
copper comes up to equilibrium with the water temperature, the delta  
T between the water and copper at each point decreases, and the  
output temperature curve would asymptotically approach 60 degrees  
instead of heading there as a flat line.

Similarly, the elbow, the increase in temperature curve slope to a  
new constant value, appears to be an instantaneous increase in power  
output.  If there were a sudden increase in power applied to the  
heating chamber, it would seem that the copper between the chamber  
and the temperature sensor would again have to be heated, as well as  
the water in the device.

The temperature curve almost looks like what would be expected if a  
well stirred pot of water were being heated.  It should not look like  
this.  There is a water flow in and out.

Suppose the device were initially full of a liter of water at 18°C,  
when the flow and power were turned on.  This means, for the 300 W to  
bring the inflow of water to exactly 60°C in the 9 minutes, the  
existing pool of water could have been heated at all. It would all  
have to flow out the port at exactly 18°C until the 60°C water  
arrived at the  thermometer.  This does not happen, as shown in the  
temperature graph.  The vicinity of the thermometer gradually warms up.

It is questionable that the device should suddenly turn on hydrogen  
energy at 60°C.  In the (later) water only test which was not public  
a mere 5°C sustained rise in water temperature was enough to maintain  
the supposed hydrogen energy production.


THE "KINK" ELBOW OF HEAT RISE AT 60°C

E&K: "Instead the temperature increases faster after 10:36, as can be  
seen as a kink occurring at 60 °C in the temperature-time relation.  
(Figure 6). A temperature of 97.5 °C is reached at 10:40. The time  
taken to bring the water from 60 to 97.5 °C is 4 minutes."

The slope of the lower elbow section was (60°C)/(9 min) = 6.7°C/min.   
The slope of the upper elbow is (37.5°C)/(4 min) = 9.4 °C/min.  If  
the first slope represents 300 W, then the second slope represents  
(9.4/6.7)*(300 W) = 421 W.


A KEY STATEMENT

E&K: "The 100 °C temperature is reached at 10:42 and at about 10:45  
all the water is completely vaporized found by visual checks of the  
outlet tube and the valve letting out steam from the chimney. This  
means that from this point in time, 10:45, 4.69 kW power is delivered  
to the heating and vaporization, and 4.69 – 0.30 = 4.39 kW would have  
to come from the energy produced in the internal nickel-hydrogen  
container."

This looks absurd.  The power suddenly goes from 421 W to 4.69 kW  
when the water temperature reaches 100°C??

The most notable part of this E&K statement is the phrase: "visual  
checks of the outlet tube".  This appears to mean periodic checks of  
the end of the rubber tube, in a manner similar to that done in the  
Krivit demonstration. Obviously only steam would come out of the top  
port, because the liquid water is separated, flowing out the hose.  
Further, if 4.69 kW of steam would produce a steam flow of about 3000  
cc/sec, given 1.8 gm/s input flow at 18*C. Through a 1 cm^2 opening  
this would have been a velocity of 30 m/sec, certainly highly notable  
by the observers!  What a great photo or video that huge flow of  
steam would make! No corresponding note or recording was made.

It is highly unlikely the power output was sustained at *exactly*  
4.69 kW for the entire run. This would be necessary to fulfill both  
conditions noted in the report, namely (1) all water flow was  
converted to steam, and (2) the outlet temperature remained between  
100°C and 100.4°C.  If a mere 10 W additional were added beyond the  
perfect 2 conditions noted, then the steam temperature would increase  
to 108°C.  This did not happen.  The only logical conclusion is all  
the water was not converted to steam.  Water was flowing out of the  
exit port. In fact, based on the elbow and two slopes of the  
temperature curve, it could be expected that very little power was  
actually involved in steam formation at 10:45.  Water was likely  
pouring out of the exit port at near 1.8 cm^3/sec.

Based on the T vs t slopes it seems possible the power for most of  
the first part of the elbow, for abut 9 minutes, was around 533 W,  
and the  second part of the elbow, and maybe beyond, it was about 748  
W, the power applied in the Krivit demonstration.  This is certainly  
more credible than a nearly instant power surge of 4 kW when the  
temperature hit 100°C.  It looks as if power was possibly switched to  
the preheater element at some initial point and then the band heater  
kicked in at a later point.   There is no way of knowing exactly what  
electrical power was applied throughout because it was not recorded,  
and most importantly not integrated via a kWh meter. There is no way  
of knowing the actual enthalpy was generated because the output heat  
flow was not measured.

Despite having access to much of the E-cat device, to make credible  
measurements Essén and Kullander would have had to come prepared with  
their own calorimetry equipment and a kWh meter in order to make good  
use of that access.


OPERATION

E&K: "The system to measure the non-evaporated water was a certified  
Testo System, Testo 650, with a probe guaranteed to resist up to 550° 
C. The measurements showed that at 11:15 1.4% of the water was non- 
vaporized, at 11:30 1.3% and at 11:45 1.2% of the water was non- 
vaporized."

This is nonsense because the Testo 650 is a relative humidity meter

http://www.instrumart.com/products/28689/testo-650-humidity-meter? 
s_kwcid=TC|23075|testo%20650||S|p| 
7377156844&gclid=CNmO966qr6sCFRAaQgodCD0zJQ

http://tinyurl.com/3hdw68c

The relative humidity of steam is 100%.  If less than 100% was  
measured it means there is air in the probe well. Further, this  
measurement ignores the water which can pour out of the exit port, or  
bubble or spurt out by a percolator effect, and which is not measured.

E&K: "The energy produced inside the device is calculated to be  
(1.000-0.013)(16:30-10:45)4.39 =25 kWh."

This calculation is utterly without foundation.


DISCUSSION

E&K: "Any chemical process for producing 25 kWh from any fuel in a 50  
cm3 container can be ruled out. The only alternative explanation is  
that there is some kind of a nuclear process that gives rise to the  
measured energy production."

This conclusion is without foundation because the 25 kWh number is  
without foundation. Due to inadequate instrumentation there is not  
even solid evidence the the power out is greater than the electrical  
power in.  There are various inconsistencies in the report that can  
not be resolved without more detailed knowledge of the inside of the  
E-cat at the time, and better instrumentation for the test.



HEAT FLOW THROUGH THE NICKEL CONTAINING STAINLESS STEEL COMPARTMENT

If the stainless steel compartment has a surface area of  
approximately S = 180 cm^2, as approximated above, and 4.39 kW heat  
flow through it occurred, as specified in the report, then the heat  
flow was (4390 W)/(180 cm^2) = 24.3 W/cm^2 = 2.4x10^5 W/m^2.

The thermal conductivity of stainless steel is 16 W/(m K).  The  
compartment area is 180 cm^2 or 1.8x10^-2 m^2. If the wall thickness  
is 2 mm = 0.002 m, then the thermal resistance R of the compartment is:

    R = (0.002 m)/(16 W/(m K)*(1.8x10^-2 m^2) = 1.78 °C/W

Producing a heat flow of 4.39 kW, or 4390 W then requires a delta T  
given as:

    delta T = (1.78 °C/W) * (4390 W) = 7800 °C

The melting point of Ni is 1453°C.  Even if the internal temperature  
of the chamber were 1000°C above water temperature then power out  
would be at best (1000°C)/(1.78 °C/W) = 561 W.

Most of the input water mass flow necessarily must have continued on  
out the exit port without being converted to steam.


CONCLUSION

The report has various inconsistencies which prevent any solid  
conclusions from being drawn.  The E-cat only has value if the total  
energy out for a long operation is much greater than total energy  
in.  It is feasibly inexpensive and not complex to directly measure  
total energy in vs total energy out for long runs of this sized  
device, measuring only the electrical input and thermal output of the  
device independent of the device itself.   Such a long term total  
energy balance measurement eliminates any need to know the internals  
of the device or to account for the extreme complexities of thermal  
dynamics to determine its energy generating capacity.

This report is not a scientific paper, but a travel report as stated  
in the article. It is an excellent report of what happened. However,  
for the conclusions of the report to be scientifically credible a  
great deal more is required in the way of calorimetry and data  
collection.

The standard of evaluation of this kind of device for commercial  
purposes, which could entail the investment of millions or billions  
of dollars, should rise to a much higher standard than requirements  
for publishing a scientific paper.  Further, because the field itself  
has such a controversial history, and yet has a colossal potential to  
do much good for billions of people, there is a duty to rise to the  
highest possible standard of data acquisition to avoid the extensive  
damage failure of such a highly visible public affair can have on  
what little research is now funded, and to reach that high standard  
as quickly as possible.

Best regards,

Horace Heffner
http://www.mtaonline.net/~hheffner/





 

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