The amount of heat that is generated by the DGT device should be adequate to 
keep the reaction going without the additional heat from the resistors.  This 
is somewhat different than Rossi's case because of the relative magnitude of 
the difference between the internal heat generated and that externally 
supplied.  Also, it appears that the heating elements are driven all of the 
time.  Perhaps Mats can verify the drive waveform that he saw being applied to 
the resistors to ensure this statement is correct.


If you assume that the resistors are driven continuously, then thermal control 
would not work effectively according to my model of a Rossi like device.  All 
indications are that the HV discharge in the DGT case supplies the fuel or 
perhaps tiny localize extreme heating regions where the reaction occurs.  The 
fuel supply could very well be modulated somewhat like fuel injection of a ICE 
if fresh ions are needed at the active sites.  The plasma would perform this 
function.  The localized heating might be seen as a result of the impact of the 
electrical discharge upon the nickel targets.  This should cause local high 
temperatures that are far greater than the average temperature at which the 
device operates.  One or both of these two processes might be taking place and 
controlling the reaction for DGT.


I suggest that consideration be given to the fact that DGT did continue to 
supply power to the resistive elements throughout the demonstration.  The level 
of this excitation was adjusted downward, but not entirely eliminated.  Could 
it be that the device needs the magnetic field being released by these devices? 
 Of course, it might be that some fine tuning of the input heating is required, 
but this seems strange considering the enormous heat being released by the core.


Dave



-----Original Message-----
From: Alain Sepeda <alain.sep...@gmail.com>
To: Vortex List <vortex-l@eskimo.com>
Sent: Mon, Jul 29, 2013 5:50 am
Subject: Re: [Vo]:DGT Really Has Something Big


Beside that question, one participant "ajb"  on lenr-forum make a quick 
optimistic computation,
 based on the safe assumption that Defkalion is fooling nobody... 
(I hear the moderate and hard skeptics moan already).


http://www.lenr-forum.com/showthread.php?2136-Defkalion-Demo-During-ICCF-18-(Milano-)&p=5594&viewfull=1#post5594



so :
Let us assume that LENR+ works, is not rocket science, and that Defkalion have 
simply said the truth.
I hear the moderate and hard skeptics moan already - 
since it is an erroneous assumption I propose the skeptics don't comment; 
So I invoke the vortex-rule , ah ah. ;-)


The goal is not to check if it is true, but what are the potential performance 
of Hyperion from the best data we have.
AJB use the data from the Italian test (I did not check/see the data, please 
correct him ),
 because the US test was compromised by argon.


from the data point he find COP of 20.9 and 18.


then he make an assumption : that only the plasma excitation is required .
It is rational since warming heat  could be provided by the reaction itself.
With that assumption, the COP could go to 167.


I anticipate some technical problems to remove warming during cruise , 
since the reactor need some specific thermal gradient,
 which the reaction many not create naturally. anyway, some engineers
may design the cooling and the reaction chamber, to enforce that gradient.
If not easy to do just by design, maybe some controlled tap of coolant 
may dynamically control the gradient...


I did not check the computation myself, and I imagine that you will do better 
than me.


note that the assumption are the optimistic/realistic one :


- no fraud
- dry steam at 150C 1athm
- good engineering to use reactor heat top heat itself


in that optimistic context, tell me if AJB got it right, or not.
Maybe there are errors in the measurements or computations, but the method 
seems a good start.








2013/7/29 Teslaalset <robbiehobbiesh...@gmail.com>

There is a discrepancy on the HV power indeed.
At some moment in the video Mats remarked that he measured 1100 Watt input 
power of the HV unit.
There was no instant response to that remark. The wall dispay indicated around 
200-250 Watt HV input power to the reactor.
Despite the fact that it was mentioned that HV is modulated, the 1100 W remains 
a high value.
HV units should have a higher efficiency than observed.




Op maandag 29 juli 2013 schreef Craig (cchayniepub...@gmail.com) het volgende:


On 07/28/2013 05:08 PM, Alan Fletcher wrote:
> There may well be a pressure (and temperature) drop down the output
> tube to outlet --- but from steam tables and a guess at the tube size
> and length I'd be surprised if it is more than about 0.5 bar -- so the
> COP is most likely at the 10+ level. (Presuming that Mats' calculation
> of the spark power is wrong).

I read that Defkalion answered Mats Lewan's objection to the HV power.
There is apparently a 20% duty cycle; so Mats calculated input power
should have been divided by 5.

I can't remember where I read this, however.

Craig







Reply via email to