I am looking at the Josephson version of the Defkalion video, here: http://www.youtube.com/watch?v=HHEtnTO3h6s
It is a little more blurry than the original. At time 39:03 the numbers on the screen can be read. Total input is 1918 W. Output is 4295 W. T_in is 25.29°C, T_out 132.13°C, and the flow rate is 0.569 liters/min. 132.13°C - 25.29°C = 106.9°C 0.569 liters/min = 9.5 ml/s 106.9°C * 9.5 ml = 1014 calories 1014 cal * 4.2 = 4258 W That is approximately what is shown in the Output Power section of the screen. I have heard that the device produced steam. This is shown at various times in the whole video. From the numbers here, I conclude that the people at Defkalion treated the output as hot water, ignoring the heat of vaporization. The heat of vaporization of water is 2260 kJ/kg, or 2260 J/g, so for 9.5 ml that would be an extra 21,470 J/s (watts). I gather there have been some disputes over whether this water was fully vaporized. It might have been somewhat wet. It might have included unboiled water. I don't see how it could have, at 132°C, but in any case that is irrelevant since they ignored the heat of vaporization. This is very conservative estimate of the heat output. - Jed
