Hi Randy,

Thanks for the code.

As I play with this data I am learning. The proximity approach evolved as I 
realized it would be nice to find al the citrus within a certain distance. Yea 
Google does this all the time but I need it to be non-web based. Thus the 
millions of database records.

Interesting challenge that for sure.

Appreciate,
John…


> On Apr 12, 2020, at 9:17 AM, Randy Kaempen <[email protected]> wrote:
> 
> John,
> 
>> On Apr 12, 2020, at 10:33 AM, John J Foster via 4D_Tech 
>> <[email protected] <mailto:[email protected]>> wrote:
>> 
>> If you happen to find any 4D bearing/distance code (anything related to 
>> searching using longitude/latitude or both) I would enjoy looking at it.
> 
> I had worked out these calculations with a mathematician called C. E. 
> Tiedemann many years ago.  Here is an except from our emails, entitled 
> 'Ellipsoid Radius Calculation’.
> 
> 
> Now I see what's going on.  The figures in the table are merdianally
> oriented radii of hypothetical spheres for which the surface curvature
> matches the (a, b, e) ellipsoid at the specified latitude.  Knowing these
> allows use of fairly simple spherical formulae for computing distances
> between points not too far apart on surfaces of ellipsoids.
> 
> - - - -
> 
> OK, I took a look at the URL and found my comment just below the material
> we're looking at.  In fact I remember having made those observations, but
> it was a LONG time ago and at the momen I've no recollection of the context
> in which they were made.
> 
> But, all may not be lost:  bouncing up a way in the text I found the 
> following:
> 
> R' = a * (1 - e^2) / (1 - e^2 * (sin(lat))^2)^(3/2)
> 
> The additional "^(3/2) will have the effect of increasing the denominator
> and maybe bring things into agreement with your/our expectations.
> 
> 
> This is the routine we came up with, which seems to work well.
> 
> 
>   // CalcDistance  11/24/02
>   //
> C_REAL($0;$1;$2;$3;$4;$Lat1;$Long1;$Lat2;$Long2;$DegToRad;$Work;$Distance)  
> // 11/24/02
>   //
> $Lat1:=$1  // 11/23/02
> $Long1:=$2  // 11/23/02
> $Lat2:=$3  // 11/23/02
> $Long2:=$4  // 11/23/02
>   //
> $DegToRad:=57.29577951308  // 11/23/02
>   //
> $Work:=(Sin($Lat1/$DegToRad)*Sin($Lat2/$DegToRad))+(Cos($Lat1/$DegToRad)*Cos($Lat2/$DegToRad))*Cos(($Long2/$DegToRad)-($Long1/$DegToRad))
>   // 11/23/02
> $Distance:=3958.75*Arctan(Square root(1-($Work^2))/$Work)  // 11/23/02
>   //
> $0:=$Distance  // 11/23/02
> 
> 
> Feel free to use this if it’s of help to you.
> 
> 
> Randy Kaempen
> Intellex Corporation
> 

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