On 1/30/21, Ben Goertzel <[email protected]> wrote: > Unless I remember wrong (which is possible), function application in a > Scott domain is not associative, e.g. > > (f(g) ) (h) > > is not in general equal to > > f( g(h) ) > > However function composition is associative, and the standard products > on vectors in Hilbert space are associative > > So it seems what you're doing may not be quite right, and you need to > be looking at some sort of fairly general nonassociative algebras over > Hilbert space instead ... or something... > > Or am I misunderstanding something?
Damn... you're right 😆 I have no idea how to make one function "apply" to another, except by function composition, so that was what I did. But I forgot about associativity... I don't know if I should pursue along this any further.... it seems computer-implementable but it's very complicated... and I currently don't know how to make non-associative algebras.... Thanks for pointing out my mistake, it's helpful 😅 YKY ------------------------------------------ Artificial General Intelligence List: AGI Permalink: https://agi.topicbox.com/groups/agi/T54594b98b5b98f83-M99359ed01b92bc6c13b54601 Delivery options: https://agi.topicbox.com/groups/agi/subscription
