Hi Richard, "GROUP=10380?page=2" isn't a well formed query and therefore can't be parsed even in relaxed mode. akka/akka#18479 <https://github.com/akka/akka/pull/18715> provides a way to prevent parsing of the query component and to just look at the raw query string. You can access your query via the queryString() method and parse it youself.
HTH André On Sunday, October 9, 2016 at 6:38:34 PM UTC+2, Richard Imaoka wrote: > > Hi, > > While I tried to work on akka/akka-http#276 > <https://github.com/akka/akka-http/issues/276>, and looked at > akka/akka#18479 <https://github.com/akka/akka/pull/18715> (PR to fix > #18479 = akka/akka#18715 <https://github.com/akka/akka/pull/18715>), > I found that the following code: > > Query("GROUP=10380?page=2",mode = Uri.ParsingMode.Relaxed) > > > throws an exception: > > IllegalUriException: Illegal query: Invalid input '=', expected '+', > query-char, 'EOI', '&' or pct-encoded (line 1, column 17): GROUP=10380?page= > > > Wasn't akka/akka#18479 <https://github.com/akka/akka/pull/18715> (PR= > akka/akka#18715 <https://github.com/akka/akka/pull/18715>) intended to > make this a valid query string, with Uri.ParsingMode.Relaxed ? > > > *Additional Info* > 1. I looked for a test case for this. > According to UriSpec.scala > <https://github.com/akka/akka-http/blob/b7f13dc36918c870662e5434b15a45ab94594c8e/akka-http-core/src/test/scala/akka/http/scaladsl/model/UriSpec.scala#L508L514>, > > Uri("?a=b=c").query() is still invalid, although query() method has default > mode = Uri.ParsingMode.Relaxed. > > > 2. I didn't fully understand how parsing works .... but probably it's > because CharacterClases.scala > <https://github.com/akka/akka-http/blob/b7f13dc36918c870662e5434b15a45ab94594c8e/akka-http-core/src/main/scala/akka/http/impl/model/parser/CharacterClasses.scala#L51> > defines: > > val `relaxed-query-char` = VCHAR -- "%&=#" > > where ('=') is made invalid? > > UriParser has > > private[this] val `query-char` = uriParsingMode match { > case Uri.ParsingMode.Strict ⇒ `strict-query-char` > case Uri.ParsingMode.Relaxed ⇒ `relaxed-query-char` > } > > where `relaxed-query-char` is defined as above. > > Thanks, > Richard > > -- >>>>>>>>>> Read the docs: http://akka.io/docs/ >>>>>>>>>> Check the FAQ: >>>>>>>>>> http://doc.akka.io/docs/akka/current/additional/faq.html >>>>>>>>>> Search the archives: https://groups.google.com/group/akka-user --- You received this message because you are subscribed to the Google Groups "Akka User List" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To post to this group, send email to [email protected]. Visit this group at https://groups.google.com/group/akka-user. For more options, visit https://groups.google.com/d/optout.
