Ralf Hemmecke <[EMAIL PROTECTED]> writes: > On 02/14/2007 09:17 AM, Martin Rubey wrote: > >> As you know in phlethystic composition we need to "stretch" a given series. > > >> To say things in a more intuitive language: if f(x_1, x_2, x_3, ...) is a > >> formal power series in infinitely many variables, the k-th stretch is > >> f(x_{k}, x_{2k}, x_{3k}, ...). > > > Unfortunately, I only have a quarter of an answer, taking us into the realm > > of > > symmetric functions. > > > As you might know, the variables x_i in the cycle indicator series *should* > > be > > interpreted really as the i-th power sums, thus I'd prefer to write p_i. To > > avoid confusion, I write z1, z2, z3,... for the *arguments* of these > > symmetric > > functions. > > > p_i(z1,z2,z3,...) = z1^i+z2^i+z3^i+... > > > > Thus, the cycle index series is a symmetric function in the z1, z2, z3, ..., > > usually defined in terms of the power sum symmetric functions p_1, p_2, > > p_3... Unfortunately (in my current opinion), we denote the p_i currently > > with > > x_i, as BLL did. > > Sorry, but I cannot believe what you say.
I don't understand what you cannot believe? I just checked Stanley Enumerative Combinatorics II, Section 7.24, Enumeration under Group Action. I give a brief account here, but I'm not firm on this topic, currently... Stanley defines the cycle indicator for any subset K of the symmetric group \frac S_S as Z_K = 1/#K \sum_{w\in K} p_{\rho(w)} where \rho(w) is the cycle type of w and p_{i_1, i_2,...} is the product of the power sums p_{i_j}. He then writes: In the traditional exposition of Poly theory [...], the power sum symmetric functions p_i is replaced by an indeterminate t_i, and later one substitutes p_i or a specialization of p_i for t_i. This change of viewpoint has the following advantage: Consider the cycle indicator for graphs with 4 vertices, G the group permuting the vertices: Z_G = 1/24 (p1^6 + 9 p1^2 p2^2 + 8 p3^2 + 6 p2 p4) Then, Polya theory is supposed to tell us that the "store enumerator" is the same thing, expressing Z_G in the basis of monomial symmetric functions: F_G = m_6 + m_51 + 2 m_42 + 3 m_33 + 2 m_411 + 4 m_321 + 6 m_222 + 5 m 3111 + 9 m_2211 + 15 m_21111 + 30 m_111111 To obtain the generating function of nonisomorphic loopless graphs on 4 vertices, q encoding the number of edges, we can simply compute Z_G(1,q)=F_G(1,q)=1+q+2q^2+3q^3+2q^4+q^5+q^6. The arguments (1, q) are of course the arguments to the power sums and monomial symmetric functions. However, in our current notation, the arguments of Z_G are not the arguments of the power sums, but rather the power sums themselves. So we have to write Z_G(1+q, 1+q^2, 1+q^3, ...) I think the main argument favouring Stanley's notation is the beautiful way to spell out Polya's theorem: Z_G = F_G. (Remark: BLL writes P_G for Stanley's Z_G and roughly |\Phi..| for F_G, but I didn't work out the details) Martin ------------------------------------------------------------------------- Take Surveys. Earn Cash. Influence the Future of IT Join SourceForge.net's Techsay panel and you'll get the chance to share your opinions on IT & business topics through brief surveys-and earn cash http://www.techsay.com/default.php?page=join.php&p=sourceforge&CID=DEVDEV _______________________________________________ Aldor-combinat-devel mailing list Aldor-combinat-devel@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/aldor-combinat-devel