>>    p_n[g] = g[p_n]

>> Seemingly, plethysm is commutative by definition, but my eyes don't see a
>> definition of a plethysm of two arbitrary elements of K[[p]].
> 
> No, if I'm not completely mistaken, the plethysm is not commutative. Only for
> power sums.

Oh, shame on me. I gave a polynomial example of non-commutativity myself 
in http://article.gmane.org/gmane.comp.mathematics.aldor-combinat.devel/605

f=x+x^2, g=x^2

f(g) = x^2 + (x^2)^2
g(f) = (x+x^2)^2

Just read x=p_1.

>> I can only see a definition f[g] where at least one (either f or g) is a
>> polynomial. Don't you agree?

> No. Expand f and g in terms of the power sum symmetric functions and apply the
> definitions above.

Sorry, but I don't agree. And you probably see it if you Assume that we 
would not have K[[p]] but K[p]. The definition only says something about 
*finite* sums.

I cannot see something that allows me for

f = \sum_{t\in T} c_t t

(where T is the (commutative) monoid of powerproducts in x_1,x_2,x_3,...)
and another g \in K[[p]] to say

f[g] = \sum_{t\in T} c_t t[g].

This "extended by" of Mishna p.29 I usually read as a *finite* iteration.

Ralf

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