i think it is similar to finding max in a list  O(n) or sorting algorithm
O(n log n)

-- Prashant Kulkarni




On Tue, Sep 28, 2010 at 11:33 PM, Rahul Singal <[email protected]>wrote:

> A possible solution  i can think is create a directed graph where each
> vertex is a envelope and edges are from a bigger envelope to smaller
> envelope ( one which can fit in bigger envelope ) . Now the problem is
> reduce to finding longest path in the graph .
>
> Regards
> Rahul
>
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