ya...finding the longest subsequence is the simplest method...and its
nlogn..

It works...it similar to box stacking problem

On Fri, Oct 1, 2010 at 6:00 AM, [email protected]
<[email protected]>wrote:

> The problem here is more about finding the most optimal solution and not
> just solution.
> Rgds
> Adi
> -----Original Message-----
> From: Sathaiah Dontula
> Sent:  29/09/2010, 09:25
> To: [email protected]
> Subject: Re: [algogeeks] Algorithm to determine the largest number of
> envelopes that can be nested inside one another.
>
>
> I think we can do like this,
>
> 1. Sort all the xi's in ascending order -> nlog(n)
> 2. Then find the longest increasing sequence of yi's -> nlog(n)
> 3. complexity will be nlog(n).
>
> Thanks,
> Sathaiah Dontula
>
> On Tue, Sep 28, 2010 at 11:37 PM, Prashant Kulkarni <
> [email protected]> wrote:
>
> > i think it is similar to finding max in a list  O(n) or sorting algorithm
> > O(n log n)
> >
> > -- Prashant Kulkarni
> >
> >
> >
> >
> > On Tue, Sep 28, 2010 at 11:33 PM, Rahul Singal <[email protected]
> >wrote:
> >
> >> A possible solution  i can think is create a directed graph where each
> >> vertex is a envelope and edges are from a bigger envelope to smaller
> >> envelope ( one which can fit in bigger envelope ) . Now the problem is
> >> reduce to finding longest path in the graph .
> >>
> >> Regards
> >> Rahul
> >>
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-- 
S.Nishaanth,
Computer Science and engineering,
IIT Madras.

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