One thing to note is that, this graph is a directed acyclic graph,
since by definition there can be no edge from a smaller or equal sized
envelope to a large one. In this setting it is possible to find the
longest path, by a topological sort and dynamic programming in linear
time O(V+E). Funny though If it wasn't "strictly smaller" than finding
the longest path would be NP-Complete.

On Sep 28, 9:03 pm, Rahul Singal <[email protected]> wrote:
> A possible solution  i can think is create a directed graph where each
> vertex is a envelope and edges are from a bigger envelope to smaller
> envelope ( one which can fit in bigger envelope ) . Now the problem is
> reduce to finding longest path in the graph .
>
> Regards
> Rahul

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