As the competition is over I can reveal u the answer. There is only one
number satisfying given condition and that is 578 so the answer is 20 :)

On Fri, Feb 25, 2011 at 10:33 PM, vaibhav shukla <[email protected]>wrote:

> nothing to do with complexity...
> just the ans
>
>
> On Fri, Feb 25, 2011 at 10:23 PM, Rel Guzman Apaza <[email protected]>wrote:
>
>> Is there a maximum time complexity?
>>
>> 2011/2/25 vaibhav shukla <[email protected]>
>>
>>> Find the sum of digits of all the numbers whose digits are all in
>>> ascending order from left to right. All these numbers lie between 500 to
>>> 1000 and satisfy M divides (M-1)* !* + 1 , where M is any natural
>>> number.
>>> (* " ! " * denotes factorial of the number)
>>> --
>>>
>>>
>>>
>>> best wishes!!
>>> Vaibhav Shukla
>>>     DU-MCA
>>>
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>
>
>
> --
>   best wishes!!
> Vaibhav Shukla
>     DU-MCA
>
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-- 
Regards
Gunjan Sharma
Chairman IEEE Students Chapter IIT Roorkee
B.Tech IV year CSE

Contact No- +91 9997767077

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